1. The ultimate Frisbee team won 10 of its 14 games.

Algebra I Concept Test # 19 – Ratios, Rates and Percents Practice Test

10 games won

4 games lost

÷ 2

÷ 2 =

5 wins or 5 to 2

2 losses

a) Find the ratio of wins to losses.

300 miles

5 hours =

2. A car travels 300 miles in 5 hours. Find the unit rate.

4 games lost

14 games played

÷ 2

÷ 2 =

2 losses or 2 to 7

7 played

b) Find the ratio of losses to games.

÷ 5

÷ 5

60 miles or 60 mph

1 hour

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3. Convert the units: 6 hours to minutes.

Algebra I Concept Test # 19 – Ratios, Rates and Percents Practice Test

6 hours • 60 =

360 minutes

7.5520

5. You earn $ 7.55 per hour and work 20 hours per week.How much do you earn per week?

151.00 $ 151.00

4. Convert the units: 90 inches to feet.

90 inches

12 =

7.5 feet

6. An order of french fries in Mexico costs 18 pesos.1 peso = $ 0.09 US dollars. How much would the price be in US dollars?

Algebra I Concept Test # 19 – Ratios, Rates and Percents Practice Test

1 peso .09 dollars =

=

7. Solve: 15% of 110 is what number?

15% •

The number is 17.5

18 pesos • .09 =

$ 1.62

110 x Convert % to decimal

Multiply =

.15 • 110 x

=

17.5 x

Algebra I Concept Test # 19 – Ratios, Rates and Percents Practice Test

5. Solve: 40% of what number is 62?

40% x = 62

.4 x = 62

Convert % to decimal

Divide .4 .4

x = 620 4

Shift decimal point

x = 155 Simplify

Algebra I Concept Test # 19 – Ratios, Rates and Percents Practice Test

9. 42 out of 75 students prefer bananas to apples.

42 bananas

75 students÷ 3

÷ 3 =

a) What percent of students prefer bananas?

Note: Percent means per 100.

14

25• 4

• 4 =

56

100

=

56% prefer bananas

56%

b) What percent of students prefer apples?

Note: The percent of people who prefer bananas and apple must add up to 100%.

56% prefer bananas, so 100% – 56% prefer apples.

44% prefer apples

Algebra I Concept Test # 19 – Ratios, Rates and Percents Practice Test

5 cm

4 cm

2 cm

8 cm

10. Find the percent of the shaded region.

Note: Percent means per 100.

Note: The percent of the shaded region is the area of the shaded region divided by the area of the

whole region.

Area = L • W

Area(shaded) = 4 cm • 2cm =

8 cm2

Area(whole) = 8 cm • 5 cm =

40 cm2

8 cm2

40 cm2 =

8 40

÷ 8

÷ 8 =

1 5

• 20

• 20 =

20 100

20%

Algebra I Concept Test # 19 – Ratios, Rates and Percents Practice Test

=

11. Jeans are on sale for 20% off. The original price is $ 120. What is the price of the jeans with the

discount?

20% •

The jeans cost $ 96.00

120 x Convert % to decimal

Multiply =

.2 • 120 x

=

24 x

Note: The discount is $ 18.00. Subtract the discount amount form the original price to get the new cost.

=

120 – 24 96

Algebra I Concept Test # 19 – Ratios, Rates and Percents Practice Test

12. Based on the pie chart below, what percent of the high school graduates completed Precalculus as their highest math course?

Note: Percent means per 100.

Note: Create a fraction with the number of students who completed Precalculus over the total number of students on the pie chart.

50 completed Precalculus

500 total students÷ 5

÷ 5 =

10100

10%

Highest Completed Math Course of High School Graduates

Alg I 15

Calculus 60

Precalc 50

Geometry 210

Algebra II 165

10% completed Precalculus

Your future looks bright