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1.8: Intro to Equations Equation: A mathematical sentence that uses the equal ( = ) sign. Ex: 3x=12, -1(x + 5) = 8, Open Sentence: An equation that contains one or more variables. Ex: 3x+ 7 = 21, 2y -5 = y + 8

1.8: Intro to Equations

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Equation: A mathematical sentence that uses the equal ( = ) sign. Ex: 3x=12, -1(x + 5) = 8, . 1.8: Intro to Equations. Open Sentence: An equation that contains one or more variables. Ex : 3x+ 7 = 21, 2y -5 = y + 8 . - PowerPoint PPT Presentation

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Page 1: 1.8:  Intro to Equations

1.8: Intro to EquationsEquation: A mathematical sentence that uses the equal ( = ) sign.

Ex: 3x=12, -1(x + 5) = 8,

Open Sentence: An equation that contains one or more variables.

Ex: 3x+ 7 = 21, 2y -5 = y + 8

Page 2: 1.8:  Intro to Equations

Solution: The value of the variable that makes the equation true.

Ex: 3x+5 = 20

3x = 20-5 x = 15/3

x = 5

Page 3: 1.8:  Intro to Equations

GOAL:

Page 4: 1.8:  Intro to Equations

Identifying solutions:

Ex: Decide if the given number is a solution:5b + 1 = 16; -3

Solution: To show if b=3 is a solution, we must substitute:

5( -3 ) + 1 = 16 -15 + 1 = 16 –14= 16

Since -14 is not equal to 16, b=-3 is not a solution to the equation.

We must be able to show if a digit is a solution to an equation.

Page 5: 1.8:  Intro to Equations

Ex: is m = ½ a solution to 6m – 8 = -5?

Solution: To show if m= ½ is a solution, we must substitute:

6( ½ ) – 8 = –5 3– 8 = –5 – 5 = –5

Since -5 is equal to -5, m=½ is a solution to the equation.

Page 6: 1.8:  Intro to Equations

REAL-WORLD:The equation 25 + 0.25p = c gives the cost in dollars that a store charges to deliver an appliance that weights p pounds. Use the equation an a table to find the weight of an appliance that costs $55 to deliver.

Page 7: 1.8:  Intro to Equations

SOLUTION: Using the given equation and the table we have:

P in lbs 25 + 0.25p c 50 25 + 0.25(50) $ 37.5

100 25 + .25(100) $50110 25 + .25(110) $52.50120 25 + .25(120) $55

Therefore an appliance that weights 120 lbs will cost $55 to deliver.

Page 8: 1.8:  Intro to Equations

Solving Equations: To solve an equation we must ISOLATE the variable involved by using opposite math operations to the ones the equation has.

Ex: Find the solution to the equations:

a) 2x - 3 = 11 b) x + 4 = - 2

Page 9: 1.8:  Intro to Equations

Solution:

a) 2x – 3 = 11 + 3 + 3

– 4 = –4 b) x + 4 = – 2

2x = 14

x = 14/2

x = 7

x = –6

Don’t forget to CHECK to make sure you got the correct solution.

Page 10: 1.8:  Intro to Equations

CHECK: Replace your answer in the original equation to make sure you got the correct solution.Ex: a) 2x - 3 = 11 b) x + 4 = – 2

2(7) – 3 = 11

14 – 3 = 11 – 2 = –2

(– 6 )+ 4 = – 2

11 = 11

Both integers, the left and the right, coincide thus we have gotten the correct solution.

Page 12: 1.8:  Intro to Equations

Class Work:

Pages: 56 – 58

Problems: As many as you need to master

the concepts.