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10. Plastic Instability10. Plastic Instability
Assoc.Prof.Dr. Ahmet Zafer Şenalpe-mail: e-mail: [email protected]@gmail.com
Mechanical Engineering DepartmentGebze Technical University
ME 612ME 612 Metal Forming and Theory of Plasticity Metal Forming and Theory of Plasticity
General instability classification:• Elastic instability• Plastic instability
The instability behavior of columns under compression is an example of elastic instability (determination of load that instability starts).
Plastic instability anaylsis searches for the load or pressure that will cause rupture or crack in plastic deformation zone.
In this section the plastic instabillity anaylsis for:• Simple tension test• Thin walled cylinder• Thin walled pipe will be presented.
Dr. Ahmet Zafer Şenalp ME 612
2Mechanical Engineering Department, GTU
10. Plastic Instability10. Plastic Instability
Figure 10.1. Load elongation curve for tensile test
Dr. Ahmet Zafer Şenalp ME 612
3Mechanical Engineering Department, GTU
10. Plastic Instability10. Plastic Instability
10.1.10.1. Tensile Plastic Instability Tensile Plastic Instability
Stress and strain states in tension test:
Dr. Ahmet Zafer Şenalp ME 612
4Mechanical Engineering Department, GTU
10. Plastic Instability10. Plastic Instability
10.1.10.1. Tensile Plastic Instability Tensile Plastic Instability
A
F1
02 03
01 ln
02 w
wln
03 t
tln
(10.1)
(10.2)
(10.3)
(10.4)
(10.5)
(10.6)
Levy-Mises equations:
If related equalities are placed in Levy-Mises equations:
Dr. Ahmet Zafer Şenalp ME 612
5Mechanical Engineering Department, GTU
10. Plastic Instability10. Plastic Instability
10.1.10.1. Tensile Plastic Instability Tensile Plastic Instability
(10.7)
(10.8)
(10.9)
(10.12)
(10.10)
(10.11)
3211 2
1d
3
2d
3122 2
1d
3
2d
2133 2
1d
3
2d
11 d3
2d
12 2
1d
3
2d
13 2
1d
3
2d
From here:
is obtained. The equalities (10.2) and (10.3) are placed in the equivalent stress equation:
As a result:
is obtained.
Dr. Ahmet Zafer Şenalp ME 612
6Mechanical Engineering Department, GTU
10. Plastic Instability10. Plastic Instability
10.1.10.1. Tensile Plastic Instability Tensile Plastic Instability
(10.13)
(10.14)
(10.15)
(10.18)
(10.19)
2d
d
2
1
2d
d
3
1
32
21
231
232
221
2
1
1
To find equivalent strain equalities (10.13) and (10.14) are placed into the equivalent strain equation:
As a result:
is obtained. Eq (10.1) is written as:
If ln is applied to both sides of the equality:
Dr. Ahmet Zafer Şenalp ME 612
7Mechanical Engineering Department, GTU
10. Plastic Instability10. Plastic Instability
10.1.10.1. Tensile Plastic Instability Tensile Plastic Instability
(10.20)
(10.21)
(10.22)
(10.23)
21
231
232
221 dddddd
3
2d
1dd
AF 1
AlnlnFln 1
A
dAd
F
dF
1
1
(10.24)
At maximum load ( F=Fmax) :
At instability point work hardening rate is equal to the area reduction rate. From constancy of volume:
As volume is constant the term defining volume change:
Dr. Ahmet Zafer Şenalp ME 612
8Mechanical Engineering Department, GTU
10. Plastic Instability10. Plastic Instability
10.1.10.1. Tensile Plastic Instability Tensile Plastic Instability
(10.25)
(10.26)
(10.27)
(10.28)
(10.29)
0F
dF
A
dAd
A A V 00
lnAlnVln
d
A
dA
V
dV
0V
dV (10.30)
If Eq (10.26) and (10.31) are equated:
instability equation is obtained. This equation can be written in terms of equivalent stress and equivalent strain:
Dr. Ahmet Zafer Şenalp ME 612
9Mechanical Engineering Department, GTU
10. Plastic Instability10. Plastic Instability
10.1. Tensile Plastic Instability10.1. Tensile Plastic Instability
(10.31)
(10.32)
d
A
dA
11
1 ddd
11
1
d
d
d
d
It is assumed that material obeys Swift equation:
is obtained. Eq (10.32) and (10.34) are equated:
term is obtained, simplifying this:
strain instability equation is obtained.In this equation;n : Work hardening powerB : Prestrain coefficient
Dr. Ahmet Zafer Şenalp ME 612
10Mechanical Engineering Department, GTU
10. Plastic Instability10. Plastic Instability
10.1.10.1. Tensile Plastic Instability Tensile Plastic Instability
(10.33)
(10.35)
n)B(C
)B(
n
)B(
)B(nC
d
d n
(10.34)
)B(
n
Bn (10.36)
If n is high work hardenening is high,if n is low work hardenening is less.If B is high small deformationIf B is small large deformation occurs
Strain instability equation given in Eq (10.36)is placed into Swift equation:
is obtained. At the same time:
If Eq (10.38) is placed into Eq (10.39):
is obtained.
Dr. Ahmet Zafer Şenalp ME 612
11Mechanical Engineering Department, GTU
10. Plastic Instability10. Plastic Instability
10.1.10.1. Tensile Plastic Instability Tensile Plastic Instability
(10.37)
(10.39)
(10.38)
(10.40)
nnn Cn)BnB(C)B(C
n1 Cn
AF 1
ACnF n
A
Alnln 0
01
1e
AA 0
(10.41)
Eq (10.41) is placed into Eq (10.40):
Term is obtained. This term is force instability term. Figure 10.2. shows generelized instability strain. Here z is defined as:
For simple tension test the above obtained term is placed into z equation z=1 is obtained.
Dr. Ahmet Zafer Şenalp ME 612
12Mechanical Engineering Department, GTU
10. Plastic Instability10. Plastic Instability
10.1. Tensile Plastic Instability10.1. Tensile Plastic Instability
(10.42)
(10.43)
1e
ACnF 0n
n
)B(z
Bn
Figure 10.2. Generalized instability strain
Dr. Ahmet Zafer Şenalp ME 612
13Mechanical Engineering Department, GTU
10. Plastic Instability10. Plastic Instability
10.1.10.1. Tensile Plastic Instability Tensile Plastic Instability
Stress and strain states of a thin walled sphere is:
Dr. Ahmet Zafer Şenalp ME 612
14Mechanical Engineering Department, GTU
10. Plastic Instability10. Plastic Instability10.2. Plastic Instability Analysis10.2. Plastic Instability Analysis
for Thin Walled Spherefor Thin Walled Sphere
(10.44)
(10.45)t2
Pr21
03 (Plane stress problem)
021 r
rln
03 t
tln
(10.46)
(10.47)
Figure 10.3. Free body diagram of a spherical shell subjected to internal pressure
Instability analysis will be conducted on maximum pressure criteria.Maximum P means maximum Levy-Mises equations:
If Eq (10.44) and (10.45) are placed into Eq (10.48) and (10.50):
Dr. Ahmet Zafer Şenalp ME 612
15Mechanical Engineering Department, GTU
10. Plastic Instability10. Plastic Instability10.2. Plastic Instability Analysis10.2. Plastic Instability Analysis
for Thin Walled Spherefor Thin Walled Sphere
(10.51)
(10.48)
(10.49)
(10.50)
1
3211 2
1d
3
2d
3122 2
1d
3
2d
2133 2
1d
3
2d
11 2
1d
3
2d
13 d3
2d (10.52)
From Eq (10.51) and (10.52)
From Eq (10.44)
is obtained. For maximum pressure criteria at instabilitydP=0If Eq (10.46) and (10.47) are used in Eq (10.55)
is obtained.
Dr. Ahmet Zafer Şenalp ME 612
16Mechanical Engineering Department, GTU
10. Plastic Instability10. Plastic Instability10.2. Plastic Instability Analysis10.2. Plastic Instability Analysis
for Thin Walled Spherefor Thin Walled Sphere
(10.56)
(10.53)
(10.54)
(10.55)
(10.57)
312
2lntlnrlnPlnln 1
0t
dt
r
dr
P
dPd
1
1
311
1 ddd
If Eq (10.53) is placed into the above Eq:
Equivalent stress:
If Eq (10.44) and (10.45) are placed into Eq (10.59) :
Equivalent strain:
Dr. Ahmet Zafer Şenalp ME 612
17Mechanical Engineering Department, GTU
10. Plastic Instability10. Plastic Instability10.2. Plastic Instability Analysis10.2. Plastic Instability Analysis
for Thin Walled Spherefor Thin Walled Sphere
(10.60)
(10.58)
(10.59)
(10.61)
11
1 d3d
21
231
232
221
2
1
1
21
231
232
221 dddddd
3
2d
If Eq (10.47) and (10.53) are placed into Eq (10.61)
If Eq (10.60) and (10.62) are placed into Eq (10.58)
It is assumed that material obeys Swift’s Law:
Dr. Ahmet Zafer Şenalp ME 612
18Mechanical Engineering Department, GTU
10. Plastic Instability10. Plastic Instability10.2. Plastic Instability Analysis10.2. Plastic Instability Analysis
for Thin Walled Spherefor Thin Walled Sphere
(10.64)
(10.62)
(10.63)
(10.65)
dd2 1
d2
3d
2
3
d
d
n)B(C
B
n
B
)B(nC
d
dn
(10.66)
From Eq (10.64) and (10.65)
By simplifying:
If Eq (10.68) is placed into Swift equation:
is obtained. Using Eq (10.60) and (10.69):
Dr. Ahmet Zafer Şenalp ME 612
19Mechanical Engineering Department, GTU
10. Plastic Instability10. Plastic Instability10.2. Plastic Instability Analysis10.2. Plastic Instability Analysis
for Thin Walled Spherefor Thin Walled Sphere
(10.69)
(10.67)
(10.68)
(10.79)
B
n
2
3
B3
n2
n
3
n2C
n
1 3
n2C
and using Eq (10.44) and (10.79)
is obtained. Using Eq (10.62), (10.68) and (10.46), (10.47)
is obtained. Here the value obtained in Eq (19.80) is the critical pressure value according to maximum pressure criteria obeying Swift’s law. After this pressure value a crack or rupture or explosion in the material should be expected.
Dr. Ahmet Zafer Şenalp ME 612
20Mechanical Engineering Department, GTU
10. Plastic Instability10. Plastic Instability10.2. Plastic Instability Analysis10.2. Plastic Instability Analysis
for Thin Walled Spherefor Thin Walled Sphere
(10.82)
(10.80)
(10.81)
r
t2
3
n2CP
n
2
B
3
n
0err
B
3
n2
0ett
Plastic instability analysis will be performed according to maximum pressure criteria. For a thin walled pipe stess, strain states are:
Hoop stress:
Longitudinal stress:
Max. P Max
Dr. Ahmet Zafer Şenalp ME 612
21Mechanical Engineering Department, GTU
10. Plastic Instability10. Plastic Instability10.3. Plastic Instability Analysis10.3. Plastic Instability Analysis
for Thin Walled Pipefor Thin Walled Pipe
(10.85)
(10.83)
(10.84)t
Pr1
t2
Pr2
03
21
2
(Plane stress problem)
1(10.86)
01 r
rln
0l
lln
02
03 t
tln
(Plane strain problem)
(10.87)
(10.88)
(10.89)
This problem can be accepted as both plane stress and plane strain problem.
Levy-Mises equations:
If Eq (10.85) and (10.86) are placed into (10.90) and (10.91)
Dr. Ahmet Zafer Şenalp ME 612
22Mechanical Engineering Department, GTU
10. Plastic Instability10. Plastic Instability10.3. Plastic Instability Analysis10.3. Plastic Instability Analysis
for Thin Walled Pipefor Thin Walled Pipe
(10.91)
(10.90)
(10.92)
(10.93)
(10.94)
3211 2
1d
3
2d
3122 2
1d
3
2d
2133 2
1d
3
2d
11 4
3d
3
2d
13 4
3d
3
2d
is obtained. From Eq (10.93) and (10.94)
From Eq (10.83)
For maximum pressure criteria at instability:dP=0Eq (10.87),(10.89) and (10.98) are replaced into Eq (10.97):
is obtained. If Eq (10.95) is placed into Eq (10.99):
Dr. Ahmet Zafer Şenalp ME 612
23Mechanical Engineering Department, GTU
10. Plastic Instability10. Plastic Instability10.3. Plastic Instability Analysis10.3. Plastic Instability Analysis
for Thin Walled Pipefor Thin Walled Pipe
(10.96)
(10.95)
(10.97)
(10.99)
(10.98)
31
tlnrlnPlnln 1
t
dt
r
dr
P
dPd
1
1
311
1 ddd
11
1 d2d
(10.100)
Equivalent stress is:
Eq (10.85) and (10.86) are placed into Eq (10.101) :
Equivalent strain is:
If Eq (10.88) and (10.95) are placed into Eq (10.103) :
Placing Eq (10.102) and (10.104) into Eq (10.100):
Dr. Ahmet Zafer Şenalp ME 612
24Mechanical Engineering Department, GTU
10. Plastic Instability10. Plastic Instability10.3. Plastic Instability Analysis10.3. Plastic Instability Analysis
for Thin Walled Pipefor Thin Walled Pipe
(10.101)
(10.102)
(10.104)
(10.103)
(10.105)
21
231
232
221
2
1
3
21
21
231
232
221 dddddd
3
2d
d2
3d 1
d3d
From Eq (10.105)
is obtained. From Eq (10.106) and (10.107)
is obtained. From here:
is obtained. If Eq (10.110) is placed into Eq (10.107) :
Dr. Ahmet Zafer Şenalp ME 612
25Mechanical Engineering Department, GTU
10. Plastic Instability10. Plastic Instability10.3. Plastic Instability Analysis10.3. Plastic Instability Analysis
for Thin Walled Pipefor Thin Walled Pipe
(10.106)
(10.107)
(10.109)
(10.108)
(10.110)
3d
d
n)B(C
)B(
n
)B(
)B(nC
d
d n
)B(
n3
B3
n
n
3
nC
(10.111)
Using Eq (10.102) and (10.111) :
is obtained. Using Eq (10.83) and (10.112)
term is obtained. Using Eq (10.104), (10.110) and (10.87), (10.89)
Equations are obtained. Here the value obtained in Eq (10.113) is the critical pressure value. After this pressure value a crack or rupture or explosion in the material should be expected.Eq (10.114) and (10.115) give the critical radius and critical thickness values respectively.
Dr. Ahmet Zafer Şenalp ME 612
26Mechanical Engineering Department, GTU
10. Plastic Instability10. Plastic Instability10.3. Plastic Instability Analysis10.3. Plastic Instability Analysis
for Thin Walled Pipefor Thin Walled Pipe
(10.112)
(10.114)
(10.113)
(10.115)
n
13
nC
3
2
r
t
3
nC
3
2P
n
B
3
n
2
3
0err
B
3
n
2
3
0ett