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Resonant CircuitsResonant Circuits

SEE 1023 Circuit TheorySEE 1023 Circuit Theory

ExperimentsExperiments

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Series RLC Circuit: Impulse Response

1 2 3

C1

Vpulse

R1

0

L1

3

Series RLC Circuit in PSpice: Trans

Series resonant CircuitVs 1 0 PULSE(0 1V 0.1u 1n 1n 0.1u 1s)

R1 1 2 10mL1 2 3 100nHC1 3 0 10nF.Tran 10n 20u 0 5n.Probe.end

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Series RLC Circuit in PSpice: AC Sweep

Series resonant Circuit.Param R1=10mVs 1 0 PULSE(0 1V 1u 0.1n 0.1n 0.01u 1s)R1 1 2 {R1}L1 2 3 100nHC1 3 0 10nF.Tran 10n 20u 0 1n.Step param R1 LIST 10m 50m 100m.Probe.end

Sweep R1

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Series RLC Circuit in PSpice: AC Sweep

Series resonant CircuitVs 1 0 AC 1VR1 1 2 10mL1 2 3 100nHC1 3 0 10nF.AC DEC 1001 10k 10MEG.Probe.end

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Series RLC Circuit in PSpice: AC Sweep

Series resonant Circuit.Param R1=10mVs 1 0 AC 1VR1 1 2 {R1}L1 2 3 100nHC1 3 0 10nF.AC LIN 1001 4.96MEG 5.1MEG.Step param R1 LIST 10m 50m 100m.Probe.end

Sweep R1

7

Series RLC Circuit: A Band-pass Filter

1 2 3

C1

Vpulse

R1

0

L1

)5002sin(10)3002sin(10)1002sin(10)( ktktkttv

)11002sin(10)9002sin(10)7002sin(10 ktktkt

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Series RLC Circuit in PSpice: AC Sweep

Resonant as bandpass filter.param pi=3.14159265V1 1 1a SIN(0 10 {10k/(2*pi)} 0 0 60) ; vin = V(1)V2 1a 1b SIN(0 10 {80k/(2*pi)} 0 0 45)V3 1b 1c SIN(0 10 {100k/(2*pi)} 0 0 0)V4 1c 1d SIN(0 10 {120k/(2*pi)} 0 0 -60)V5 1d 0 SIN(0 10 {600k/(2*pi)} 0 0 -30)L1 1 2 10uC1 2 3 10uR1 3 0 10m ; Vout = V(3).TRAN 0.1u 2m 1.4m 0.1u.PROBE V(1) V(3).END