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1
Linear Triangular System
bLx L – lower triangular matrix, nonsingular
2212122
1111
2
1
2
1
2221
11
/)(
/
0
axabx
abx
b
b
x
x
aa
a
Lx=bL: nxn nonsingular lower triangularb: known vector
b(1) = b(1)/L(1,1)For i=2:n b(i) = (b(i)-L(i,1:i-1)b(1:i-1))/L(i,i)end
Forward substitution, row version
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Triangular System
Column version (column sweep method): As soon as a variable is solved, its effect can be subtracted from subsequent equations
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1
7
13
5
2
89
05
3
5
2
6
897
051
002
3
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1
3
2
1
x
x
x
x
x
x Lx = b
for j=1:n-1 b(j) = b(j)/L(j,j) b(j+1:n) = b(j+1:n)-b(j)L(j+1:n,j)endb(n) = b(n)/L(n,n)
Forward substitution, column version
Column version is more amenable to parallel computing
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Triangular System: Parallel
L b
As soon as x_i (or a few x_i variables) is computed, the value is passed downward to neighboring cpus;As soon as a cpu receives x_i value, it passes the value downward to neighboring cpus;Then local b vector is updated.
Disadvantage: load imbalance, about 50% cpus are active on averageRemedy: cyclic or block cyclic distribution of rows.
L b
block Block cyclic
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Triangular System: Inversion
113
12
12
111
23
1
0
0
AAAX
AX
AA
AA
AA
A – NxN lower triangularDivide A into equal blocks
Can inverse A recursively:Inverse A1;Inverse A2;Compute X by matrix multiplication
Matrix multiplication
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Triangular System: Inversion1
4 2
-2 3 1
7 2 -3 3
-1 4 3 0 -1
0 1 2 5 -2 1
6 -1 3 0 0 1 -2
4 1 5 -3 2 0 0 1
1
4 1/2
-2 3 1
7 2 -3 1/3
-1 4 3 0 -1
0 1 2 5 -2 1
6 -1 3 0 0 1 -1/2
4 1 5 -3 2 0 0 1
1
-2 1/2
-2 3 1
7 2 1 1/3
-1 4 3 0 -1
0 1 2 5 -2 1
6 -1 3 0 0 1 -1/2
4 1 5 -3 2 0 0 1
First phase: invert diagonal elements of A2nd phase: compute 2x2 diagonal blocks of A^(-1)…K-th phase: compute diagonal 2^(k-1) x 2^(k-1) blocks of A^(-1)
Essentially matrix multiplications;K-th phase: N/2^(k-1) pairs of 2^(k-2)x2^(k-2) matrix multiplications
Can do in parallel on P=K^3 processors
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Gaussian Elimination
476
953
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21
xx
xx
143
953
2
21
x
xx
30
53
12
01
76
53
Ax = b
A = LU, L – unit lower triangular U – upper triangular
Ax = b LUx = b Ly = b, Ux = y
Especially with multiple rhs or solve same equations (same coefficient matrix) many times
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A = LUA – nxn matrixA(1:k,1:k) nonsingular for k=1:n-1
(kij) versionFor k=1:n-1 for i=k+1:n A(i,k) = A(i,k)/A(k,k) for j=k+1:n A(i,j) = A(i,j) – A(i,k)A(k,j) end endend
orFor k=1:n-1 A(k+1:n,k) = A(k+1:n,k)/A(k,k) A(k+1:n,k+1:n) = A(k+1:n,k+1:n)- A(k+1:n,k)A(k,k+1:n)end
LU Factorization
After factorization, L is in strictly lower triangular part of A, U is in upper triangular part of A (including diagonal)
A(k,k) is the pivot
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Factorization Breakdown
If A(k,k)=0 at any stage breakdown, LU factorization may not exist even if A is nonsingular
Theorem:Assume A is nxn matrix. (1) A has an LU factorization if A(1:k,1:k) is non-singular for all k=1:n-1.(2) If the LU factorization exists and A is non-singular, then the LU factorization is unique.
Avoid method breakdown pivotingPivoting is also necessary to improve accuracy. Small pivot increased errorsMake sure no large entries appear in L or U. Use large pivots.
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Block LU Factorization
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1211
2221
11
2221
1211
0
0
U
UU
LL
L
AA
AAA
A – nxn matrix, n = r*NA11 – rxr matrix, A22 – (n-r)x(n-r) matrix, A12 – rx(n-r) matrix, A21 – (n-r)xr
A11 = L11*U11A12 = L11*U12 U12A21 = L21*U11 L21A22 = L21*U12+L22*U22 A22-L21*U12 = A’ = L22*U22
LU factorization iteratively
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Block LU Factorization
A – nxn matrixA(1:k,1:k) is non-singular for k=1:n-11<= r <= nUpon completion, A(i,j) overwritten by L(i,j) for i>j; A(i,j) overwritten by U(i,j) for i<=j
s = 1While s <= n q = min(n,s+r-1) Use scalar algorithm to LU-factorize A(s:q,s:q) into L and U Solve LZ = A(s:q,q+1:n) for Z and overwrite A(s:q,q+1:n) with Z Solve WU = A(q+1:n,s:q) for W and overwrite A(q+1:n,s:q) with W A(q+1:n,q+1:n) = A(q+1:n,q+1:n) – WZ s = q+1End
Matrix multiplication accounts for significant fraction of operations
11
Permutation MatrixPermutation matrix: identity matrix with its rows re-ordered.
0010
0100
0001
1000
P
p = [4 1 3 2] encodes permutation matrix P
p(k) is the column index of the “1” in k-th row
PA: row-permuted version of AAP: column-permuted version of A
0001
0100
0010
1000
E
Interchange permutation matrix: identity matrix with two rows swapped
Row 1 and 4 swapped
EA: swap rows 1 and 4 of AAE: swap columns 1 and 4 of A
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Permutation Matrix
A permutation matrix can be expressed as a series of row interchanges:
12EEEP nIf E_{k} is the interchange permutation matrix with rows k and p(k) interchanged,Then P can be encoded by vector p(1:n).
If x(1:n) is a vector, then Px can be computed using p(1:n)
For k=1:n swap x(k) and x(p(k))End
p(1:n) vector is useful for pivoting
13
Partial PivotingPivoting is crucial to preventing breakdown and improving accuracy
Partial pivoting: choose largest element in a column (or row) and interchange rows (columns)
12186
242
10173
ASwap rows 1 and 3
10173
242
12186
1680
220
12186
Swap rows 2 and 3
220
1680
12186
600
1680
1286
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LU Factorization with Row Partial Pivoting
A – nxn matrixAfter factorization, strictly lower triangular part of A contains L; upper triangular part contains U; vector p(1:n-1) contains permutation operations in partial pivoting
Algorithm F2:For k=1:n-1 Determine s with k<=s<=n s.t. |A(s,k)| is largest among |A(k:n,k)| swap A(k,1:n) and A(s,1:n) p(k) = s if A(k,k) != 0 A(k+1:n,k) = A(k+1:n,k)/A(k,k) A(k+1:n,k+1:n) = A(k+1:n,k+1:n)-A(k+1:n,k)A(k,k+1:n) endend
15
How to Use Factorized ASolve Ax = bUsing LU factorization of row partial pivoting
Need to swap elements of b according to partial pivoting information in p(1:n-1)
Assume A is LU factorized with row partial pivoting using algorithm F2:
For k=1:n-1 swap b(k) and b(p(k))EndSolve Ly = bSolve Ux = y
L - unit lower triangular matrix whose lower triangular part is the same as that of A; U - upper triangular part of A (including diagonal)
16
LU Factorization With Row Partial Pivoting
A – nxn matrixAfter factorization, strictly lower triangular part of A contains multipliers; upper triangular part contains U; vector p(1:n-1) contains permutation operations in partial pivoting
Algorithm F1:For k=1:n-1 Determine s with k<=s<=n s.t. |A(s,k)| is largest among |A(k:n,k)| swap A(k,k:n) and A(s,k:n) // only difference with F2 p(k) = s if A(k,k) != 0 A(k+1:n,k) = A(k+1:n,k)/A(k,k) A(k+1:n,k+1:n) = A(k+1:n,k+1:n)-A(k+1:n,k)A(k,k+1:n) endend
17
How to Use Factorized ASolve Ax = bUsing LU factorization of partial pivoting
Need to swap elements of b according to partial pivoting information in p(1:n-1)Need to multiply appropriate coefficients information in lower triangular part of A
Assume A is LU factorized with partial pivoting using algorithm F1:
For k=1:n-1 swap b(k) and b(p(k)) b(k+1:n) = b(k+1:n) – b(k)A(k+1:n,k)EndSolve Ux = b
U - upper triangular part of A (including diagonal)
18
Column Partial PivotingColumn partial pivoting: search row k for the largest element, exchange that columnwith column k.
A – nxn matrixAfter factorization, strictly lower triangular part of A contains L; upper triangular part contains U; vector p(1:n-1) contains permutation operations in partial pivoting
Algorithm G:For k=1:n-1 Determine s with k<=s<=n s.t. |A(k,s)| is largest among |A(k,k:n)| swap A(1:n,k) and A(1:n,s) p(k) = s if A(k,k) != 0 A(k+1:n,k) = A(k+1:n,k)/A(k,k) A(k+1:n,k+1:n) = A(k+1:n,k+1:n)-A(k+1:n,k)A(k,k+1:n) endend
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How to Use Factorized ASolve Ax = bUsing LU factorization with column partial pivoting
Need to swap elements of x according to partial pivoting information in p(1:n-1)
Assume A is LU factorized with column partial pivoting using algorithm G:
Solve Ly = bSolve Ux = yFor k=n-1:-1:1 swap x(k) and x(p(k))end
L - unit lower triangular matrix whose lower triangular part is the same as that of A; U - upper triangular part of A (including diagonal)
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Complete Pivoting
Complete pivoting: the largest element in submatrix A(k:n,k:n) is permuted into (k,k) as the pivot
Need a row interchange and a column interchange
A – nxn matrixp(1:n-1) – vector encoding row interchangesq(1:n-1) – vector encoding column interchanges
After factorization, lower triangular part of A contains L, upper triangular part of A contains U (including diagonal)
21
LU Factorization with Complete Pivoting
LU factorization with complete pivoting
For k=1:n-1 Determine s (k<=s<=n) and t (k<=t<=n) s.t. |A(s,t)| is largest among |A(i,j)| for i=k:n, j=k:n swap A(k,1:n) and A(s,1:n) swap A(1:n,k) and A(1:n,t) p(k) = s q(k) = t if A(k,k) != 0 A(k+1:n,k) = A(k+1:n)/A(k,k) A(k+1:n,k+1:n) = A(k+1:n,k+1:n)-A(k+1:n,k)A(k,k+1:n) endend
22
How to Use Factorized ASolve Ax = b By LU factorization with complete pivoting
Suppose A is LU factorized with complete pivoting, p(1:n-1) and q(1:n-1) are permutation encoding vectors
for k=1:n-1 swap b(k) and b(p(k))EndSolve Ly = b for ySolve Ux = y for xFor k=n-1:-1:1 swap x(k) and x(q(k))End
L and U are lower and upper triangular parts of factorized A
23
Parallelization of Gaussian Elimination
A(k,k)
Row-wise 1D block decomposition
At step k, the processor holding the pivot sends row k: A(k,k:n) to bottom neighboring processor;At each processor, forward data immediately to bottom neighbor upon receiving data from top processor; then update its own data; then wait for data from top neighbor
Disadvantage: load imbalanceRemedy: row-wise block cyclic distribution
24
Parallelization with Partial Pivoting
Row-wise block/block-cyclic decomposition
Gaussian elimination with column partial pivotingMore difficult with row partial pivoting
Pivoting search on the processor holding row k, no communication among processors;
Column index of the new pivot element together with row k: A(k:n) need to be sent out;
On each processor, upon receiving data from top neighbor, forward immediately to bottom neighbor, and swap column k and new pivot column of own data; update own data; wait data from top neighbor;