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Exam 2 covers Ch. 27-33,Lecture, Discussion, HW, Lab
Chapter 27: The Electric Field Chapter 29: Electric potential & work Chapter 30: Electric potential & field
(exclude 30.7) Chapter 31: Current & Resistance Chapter 32: Fundamentals of Circuits
(exclude 32.8) Chapter 33: The Magnetic Field
(exclude 33.5-33.6, 33.9-10, & Hall effect)
Exam 2 is Tue. Oct. 27, 5:30-7 pm, 145 Birge
Tue. Oct. 27, 2009 Physics 208 Lecture 16 2
Law of Biot-Savart
Each short length of current produces contribution to magnetic field.r
I in plane of pageds
€
dr B =
μo
4π
Idr s × ˆ r
r2
B out of page
ds
dB
r
€
μo = 4π ×10−7 N / A2= permeability of free space
r = distance from current element
Field from very short section of current
€
dr s
Vector cross product
Tue. Oct. 27, 2009 Physics 208 Lecture 16 3
€
rC
€
rD
€
rC ×
r D
€
dr B =
μo
4π
Idr s × ˆ r
r2
€
dr B =
μoI
4π r2dr s × ˆ r
Short length of current
Unit vector toward point at which field is evaluated
Dist. to point at which field is evaluated
€
dr B
€
dr s
€
rr
Tue. Oct. 27, 2009 Physics 208 Lecture 16 4
Field from a circular loop
Each current element produce dB All contributions add as vectors Along axis, all
components cancelexcept for x-comp
Tue. Oct. 27, 2009 Physics 208 Lecture 16 5
Magnetic field from loop of current
Looks like magnetic dipole
Tue. Oct. 27, 2009 Physics 208 Lecture 16 6
Building a solenoid
Tue. Oct. 27, 2009 Physics 208 Lecture 16 7
Solenoid: many current loops
€
Bsolenoid =μoNI
L= μonI
Tue. Oct. 27, 2009 Physics 208 Lecture 16 8
Magnetic Force on a Current
S
N
I
Current
Magnetic field
Magnetic force
€
rF =
r I ×
r B L
€
qr v ×
r B Force on each charge
Force on length of wire
€
dr s
€
Idr s ×
r B
Force on straight section of wire, length L
Tue. Oct. 27, 2009 Physics 208 Lecture 16 9
Quick Quiz
A current I flows in a square loop of wire with side length L.
A constant B field points in the x-direction, perpendicular to the plane of the loop. What is the net force on the wire loop?
x
y
I
I
I
I
L
A. 4LB
B. 2LB
C. LB
D. 0
No force, but torque
Torque is Net torque can be nonzero even when
net force is zero.
Tue. Oct. 27, 2009 Physics 208 Lecture 16 10
€
rr ×
r F
Lever armForce
12/09/2002 U. Wisconsin, Physics 208, Fall 2006 11
Which of these loop orientations has the largest magnitude torque? Loops are identical apart from orientation.
(A) a (B) b (C) c
Question on torque
a bc
Quick QuizWhich of these different sized current loops has
the greatest torque from a uniform magnetic field to the right? All have same current.
Tue. Oct. 27, 2009 Physics 208 Lecture 16 12
L
W
L/2
2W
2L
W/2
A. B.
C. D. All same
€
rB
Tue. Oct. 27, 2009 Physics 208 Lecture 16 13
Torque on current loop
€
rτ =
rr ×
r F
€
rτ =2
l
2F sinθ
⎛
⎝ ⎜
⎞
⎠ ⎟
€
F = IBl ⇒ τ = AIBsinθ
€
A = l 2 =loop area
B
F
B
I
€
rr
I
F
Torque proportional to
• Loop area
• Current
• sinθ
Tue. Oct. 27, 2009 Physics 208 Lecture 16 14
Current loops & magnetic dipoles Current loop produces magnetic dipole field. Magnetic dipole moment:
€
rμ
€
rμ =IA
currentArea of loop
€
rμ
magnitude direction
In a uniform magnetic field
Magnetic field exerts torqueTorque rotates loop to align with
€
rτ =
rμ ×
rB ,
€
rμ
€
rB
€
rτ =
rμ
rB sinθ
Works for any shape planar loop
Tue. Oct. 27, 2009 Physics 208 Lecture 16 15
I
€
rμ =IA
€
rμ perpendicular to loop
Torque in uniform magnetic field
€
rτ =
rμ ×
rB ,
€
rτ =
rμ
rB sinθ
Potential energy of rotation:
€
U = −r μ ⋅
r B = −μBcosθ
Lowest energy aligned w/ magnetic field
Highest energy perpendicular to magnetic field
Tue. Oct. 27, 2009 Physics 208 Lecture 16 16
Magnetic flux Magnetic flux is defined
exactly as electric flux (Component of B surface) x (Area element)
€
ΦB = B • dA∫
zero flux Maximum flux
SI unit of magnetic flux is the Weber ( = 1 T-m2 )
Tue. Oct. 27, 2009 Physics 208 Lecture 16 17
Magnetic Flux Magnetic flux Φ through a surface:
(component of B-field surface) X (surface area) Proportional to
# B- field lines penetrating surface
Tue. Oct. 27, 2009 Physics 208 Lecture 16 18
Why perpendicular component? Suppose surface make angle surface normal
ΦB = BA cos ΦB =0 if B parallel A ΦB = BA (max) if B A
Flux SI units are T·m2=Weber
€
rB = B||
ˆ s + B⊥ˆ n
€
ˆ n
€
ˆ s
€
rA = A ˆ n
Component || surface
Component surface
Only component‘goes through’ surface
€
ΦM =r B •
r A
Tue. Oct. 27, 2009 Physics 208 Lecture 16 19
Total flux E not constant
add up small areas where it is constant
Surface not flat add up small areas
where it is ~ flat
€
δΦBi = BiδA icosθ =
r B i • δ
r A i
Add them all up:
€
ΦB =r B • d
r A
surface
∫
Tue. Oct. 27, 2009 Physics 208 Lecture 16 20
Magnetic flux
What is that magnetic flux through this surface?
A. Positive
B. Negative
C. Zero
Tue. Oct. 27, 2009 Physics 208 Lecture 16 21
Properties of flux lines Net magnetic flux through any closed
surface is always zero:
€
Φmagnetic = 0
No magnetic ‘charge’, so right-hand side=0 for mag.
Basic magnetic element is the dipole
€
Φelectric =Qenclosed
εo
For electric charges, and electric flux
Tue. Oct. 27, 2009 Physics 208 Lecture 16 22
Time-dependent fields Up to this point, have discussed only magnetic
and electric fields constant in time. E-fields arise from charges B-fields arise from moving charges (currents)
Faraday’s discovery
Another source of electric field Time-varying magnetic field creates
electric field
Tue. Oct. 27, 2009 Physics 208 Lecture 16 23
Measuring the induced field
A changing magnetic flux produces an EMF around the closed path.
How to measure this? Use a real loop of wire for the closed path.
The EMF corresponds to a current flow:
€
ε=IR