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ECE 3336 Introduction to Circuits & Electronics
MORE on Operational Amplifiers
Spring 2015,TUE&TH 5:30-7:00 pmDr. Wanda Wosik
Set #14
2
Basics of Operational AmplifiersNoninverting Case
We will focus on operational amplifiers, specifically on
• Ideal Operational Amplifiers, definitions and requirements for
their ideal operation in noninverting configuration
• Negative Feedback that allows for op-amp to be controlled by
external elements
3
Solving Op Amp Circuits
As for inverting configuration we will have two assumptions for the analysis and design. We will again treat the op amps as ideal circuits. We will again call these assumptions golden rules.
iin=0A• The first assumption: i- = i+ = 0. results from large resistances at the inputs. Currents do not flow into the op-amp.
• The second assumption v+≈v- deals with the output that makes the input voltages equal v+≈v-. This is realized by introducing negative feedback loop, which spans the output and the inverting input. negative feedback loop
4
A Note on the Second Assumption
The second golden rule v- = v+ results in the virtual short, or the summing-point constraint. The constrain refers to the input voltages, which become the same v- = v+ if there is the negative feedback and the open loop gain Av(OL) is large.
Without negative feedback, even a small input voltage will cause saturation of the output either at V+ or V-. That depends on the sign of vin.
Inverting Input
Noninverting Input
+ dc V supply
Output
NO NEGATIVE FEEDBACK yet
This is open loop configuration
Negative dc power supply
5
Op Amp Circuits with the Negative Feedback Loop
Golden Rules
1) i- = i+ = 0.
2) v- = v+. Virtual short
Negative feedback
Negative feedback adds a portion of the output signal to the inverting input. Since the signs of these voltages are opposite, the negative feedback acts as if the signal applied to the input decreases.
The net result is that the output voltage can be controlled by the external elements and does not saturate.
For ideal op-amps we will apply two golden rules to solve circuits
ideal
6
Op Amp in the Non-inverting Configuration
An op amp operates in the noninverting configuration when the input voltage is applied to the noninverting terminal.
RF is the feedback resistorRs is the source resistor
•There is a negative feedback thanks to RF
•Negative feedback gives the virtual short:v-=v+. Since v+=Vs also v-=Vs.
•The op-amp does not draw currents iin=0A
These comments are identical as for the inverting configuration
ideal
Av(OL)≈∞
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Solving op-amp in the Non-Inverting Configuration Closed Loop
As earlier, to find vout we have to find vRF. To find vRF we have to know current iF which can be calculated from is. The current is is given by the voltage v-=Vs and Rs.
ideal
v+=vSAv(OL)≈∞
0A
0A
Since we have golden rules (iin=0, v+=v-)v+=vS
Closed loop voltage GAIN:
8
Significance of the Closed Loop Gain
The negative feedback loop, combined with ideal properties of the op-amp (high open loop gain 105-107 and large input resistance) ensures that
• the gain does not depend on the op amp
• the gain is the determined by a ratio of two resistors
connected to the op-amp.
No phase change ideal
9
Voltage Follower
• Important application of the noninverting configuration is obtained when there is no resistance in the negative feedback loop.
ideal
VS
VS
So, the voltage at the input is the same as the voltage at the output vout=vS.
Do we gain anything here by doing that?
We do! We have a very large input resistance of this circuit:
•Such op-amps do not show loading effects (i.e. voltage drop due to low resistance connected to an output of a circuit). •They work as voltage follower but they also act as impedance buffers.
RF=0ΩGolden rules apply:
v+=v- and iin=0A
10
The Differential Amplifier
• This is a combination of inverting and noninverting configuration. As earlier we have negative feedback and the
op-amp is ideal. i2=-i1
v-=v+
iin=0
Group and arrange:
Rearrange
11
Instrumentation Amplifier (IA)
iR1
v2
v1
iin=0
iin=0iin=0
Now use the results from differential op-amp with vout1 and vout2 replacing original
v1 and v2
vout2
vout1
Advantages:Very high input resistanceVery high common-mode-rejection-ratio CMMR (goal: CMMR for perfectly matched resistors. That results in vout≈0V for v1=v2)
IA are made as integrated circuits
12
Integrator
Now we add the op-amp and we get an integrator. It also constitutes a part of an analog computer
The Golden Rules are used for the op-amp
Virtual short
The integrating circuit was used earlier
Now we integrate both sides and we have the integrator
13
Differentiator
Now we add the op-amp and we get a differentiator. It also constitutes a part of an analog computer.
The Golden Rules are used for the op-amp
The differentiating circuit was used earlier
14
Active Filters
The concept of frequency dependence of the signals seen in the filters (remember that we had |H(j)|max=1 for those filters) is here combined with the signal amplification.
•We will use here the negative feedback configuration•We will also use impedances instead of resistors
We still have the same golden rules: • no input currents (high Rin)• virtual short
15
Active Low-Pass Filter
0V
So the cutoff frequency is also the 3dB frequency (as before)-3dB
Phase is just like for the simple filter
The voltage gain ALP is calculated using Golden Rules
Amplification
Cutoff frequencyAmplification
16
Active High-Pass Filter
Phase is just like for the simple high pass filter
The voltage gain calculated using Golden Rules
Negative feedbackInverting configuration
cutoff
3dB frequency
Phase:
Amplification
17
Op-Amp as a Level Shifter
A useful circuit to adjust DC voltage level = to remove the DC offset from the signal
inverting noninverting
220kΩ
10kΩ
We want this to be equal 0VThat gives Vref=1.714V
We can design such precision voltage sources using Rp
Potentiometer
Power supply
Use the superposition principle (one source at a time)
18
Active Band-Pass FilterThe voltage gain ABP is again calculated using Golden Rules
Magnitude of ABP
Negative feedbackInverting configuration
1 is the unity gain frequency
@1
Relations between the frequencies
Three characteristic frequencies
19
Characteristic Frequencies in the Band-Pass Filters
Cancel off 0 -3dB
-3dB
So LP and HP are 3dB frequencies while 1 is the unity gain frequency
The voltage gain has 3 characteristic frequencies: 1, LP and HP
Gain around LP
Gain around HP
=0 =0
20
Bode Plots for the Active Band-Pass Filter
1
LP HP
LP HP1
We can plot the magnitude of the voltage gain as a function of frequency
Relations between the frequencies
The phase is like for simple bandpass filters LP HP
Linear scale dB scale
45°
-45°
21
Limitations of the Op-Amps
Saturation of the voltage at the output occurs at about ±Vs.
Small signals at the input are required
22
Limitations of the Op-Amps
Frequency Response Limits refer to the voltage gain of the open loop and closed loop configuration
Open loop gain decreases very quickly with frequency
The voltage gain decreases in the closed loop configuration but the cutoff frequency increasesThe gain-bandwidth product is constant K
23
Limitations of the Op-Amps
Slew rate limitation of op-amp means that the op-amp output voltage does not respond with the same slope as the input signal
Increasing frequency means faster changing or steeper slopes at the zero crossing
Slew rate is limited by the frequency and amplitude product
As the result of limited slew there is a distortion of the output signal.