5
1 Cylinders and Cones

1 Cylinders and Cones. 2 Surface Area (SA) = ph + 2B = 2πrh + 2πr 2 Cylinders are right prisms with circular bases. Therefore, the formulas for prisms

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Page 1: 1 Cylinders and Cones. 2 Surface Area (SA) = ph + 2B = 2πrh + 2πr 2 Cylinders are right prisms with circular bases. Therefore, the formulas for prisms

1

Cylinders and Cones

Page 2: 1 Cylinders and Cones. 2 Surface Area (SA) = ph + 2B = 2πrh + 2πr 2 Cylinders are right prisms with circular bases. Therefore, the formulas for prisms

2r

2r h

2r h

2

Surface Area (SA) = ph + 2B = 2πrh + 2πr2

Cylinders are right prisms with circular bases.Therefore, the formulas for prisms can be used for cylinders.

Volume (V) = Bh =

The base area is the area of the circle:

The lateral area is the area of the rectangle: 2πrh

h

2πr

h

Formulas: S.A. = 2πrh + 2πr2

V =

Page 3: 1 Cylinders and Cones. 2 Surface Area (SA) = ph + 2B = 2πrh + 2πr 2 Cylinders are right prisms with circular bases. Therefore, the formulas for prisms

3

For the cylinder shown, find the surface area and volume.

4 cm

3 cmS.A.= 2πr•h + 2•πr2

S.A.= 2π(3)•(4) + 2•π(3)2

S.A.= 24π + 18π

S.A.= 42π sq. cm.

V = πr2•h

V = π(3)2•(4)

V = 36π

Page 4: 1 Cylinders and Cones. 2 Surface Area (SA) = ph + 2B = 2πrh + 2πr 2 Cylinders are right prisms with circular bases. Therefore, the formulas for prisms

2r

21 1

3 3Bh r h

21

3r h

4

Surface Area (SA) = B + LA = π r (r + l)

Cones are right pyramids with a circular base.

Therefore, the formulas for pyramids can be used for cones.

Volume (V) =

The base area is the area of the circle:

Notice that the height (h) (altitude), the radius and the slant height create a right triangle.

l

r

h

Formulas: S.A. = π r l + πr2

V =

Page 5: 1 Cylinders and Cones. 2 Surface Area (SA) = ph + 2B = 2πrh + 2πr 2 Cylinders are right prisms with circular bases. Therefore, the formulas for prisms

2

2

1

31

6 83

V r h

V

5

For the cone shown, find the surface area and volume.

Note: We must use the Pythagorean theorem to find l.

6 cm

8 10

S.A.= πr (r + l )

S.A.= π•6 (6 + 10)

S.A.= 6π (16)

S.A.= 96π sq. cm.

V= 96π cubic cm.