© Copyright Avfacts 2016. All rights reserved worldwide ... · Flight Planning Practice exam 1 - Working ... FP exam 1 working/page 2. Mach 0.84 TAS 485 GS 534 FF 3802 kg/hr SGR

PRODUCT CODE Av3 FLIGHT PLANNING EXAM 1 WORKING

by

Rob Avery

© Copyright Avfacts 2016. All rights reserved worldwide.

robavery.com.au Av3:FPEx1work Plane Logic 01082016

© INTELLECTUAL PROPERTY OF ROB AVERY

PLEASE SHOW PROFESSIONALISM BY NOT MAKING ILLEGAL COPIES.

FP exam 1 working.

Flight Planning Practice exam 1 - Working


Step 1. Refer B727 manual page 2-9.

64000 kg

FL370 2650 kg

Step 2. Find TopC GW.

BRW 64000 kg - 2650 kg = 61350 kg. (Answer ‘b’ best)

Q1.

Q2.

FP exam 1 working/page 1.

Mach 0.796

TAS 450 kt

GS 488 kt

FF 3546 kg/hr

SGR 7.266 kg/gnm

FBO Required 7200 kg

LRC

YPAS

Optimum GW

for FL370

59800 kg

EMZW

63T

991 nm

38 kt

ISA –5° (CASA ISA-6)= -63°C

FL370

67000 kg

Step 1. Refer B727 manual page 2-14. Maximum FL EAST is FL370 @ ISA-5.

Step 2. Refer B727 manual page 2-14. Optimum GW for FL370/LRC is 59800 kg.

Step 3. FBO required to burn off is 67000 kg - 59800 kg = 7200 kg.

Step 4. EMZW is half way between current GW and Optimum GW = 63000 kg (rounded).

Step 5. Find TAS, GS, FF, and SGR data as in above profile.

Step 6. Divide FBO required (7200 kg) by SGR (7.274) to get distance. In this case 990 nm past YPAS.

INTELLECTUAL PROPERTY OF AVFACTS

(ROB AVERY)

Flight profile

www.robavery.com.au Av3:FPEx1work Plane Logic 01082016

FAQ 1. Why does optimum GW not effected by ISA Dev → Answer: Because as temperature changes it

effects fuel flow and TAS to almost the same extent so they cancel each other out, and SAR re-mains about the same. Optimum FL gives the best SAR, which is the fuel flow/TAS relationship.


Mach 0.84

TAS 485

GS 534

FF 3802 kg/hr

SGR 7.121 kg/gnm

FBO 3439 kg

TANGO

TopD GW 56844 kg EMZW

58T

483 nm

49 kt ISA +4 (CASA +3)

FL370 EMZW calculation.

Mach 0.84 SAR 10.3

TWC (49 x .02) - 0.98

Approx SGR 9.32

So EMZW = 60, 284 kg - (483nm/2 x 9.32) = 58T ROUNDED.

FF at 58T/FL370/M 0.84/ISA+3 = 3802 kg/hr.

Zone FBO = 483 nm x 7.121 kg/nm = 3439 kg.

Check rough EMZW was okay → 60284 -(3439/2) = 58565 →

So in this rare case the EMZW of 58T was not quite right—59T

would be used by CASA. See revised profile below.

Step 1. Answers ‘a’, ‘b’, and ‘c’ are

Easterly IFR Levels so reject these first.

Step 2. Refer B727 manual page 2-14.

FL Optimum GW

350 67, 400 kg

Current GW 68, 000 kg

310 81, 600 kg

Step 3. Assess which levels optimum GW is closest

to the current GW of 68, 000 kg.

In this case FL350 is optimum FL at this weight.

Answer ‘d’ best !

Refer B727 manual page 2-14.

ISA +10

FL350/M 0.82 70500 kg Answer ‘e’ best !

60284 kg


Q3.

Q4.

Q5. INTELLECTUAL PROPERTY OF AVFACTS

(ROB AVERY)

Flight profile

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Mach 0.84

TAS 485

GS 534

FF 3869 kg/hr

SGR 7.245 kg/gnm

FBO 3500 kg

TANGO

EMZW

59T

483 nm

49 kt ISA +4 (CASA +3)

FL370

60284 kg

Flight profile

So TopD GW = 60284 - 3500 kg = 56784 kg

Answer ‘a’ closest !

Av3:FPEx1work Plane Logic 01082016

FAQ 1. Using the rough SAR/SGR to get EMZW,

does it often happen that the guessed MZW is different to the actual EMZW. → Answer: Very rarely. Perhaps only check through actual FOB/2 if your rough MZW was close to call (within say 150 kg), otherwise get on with the next question.



70000 kg

FL330

Lower 225 KIAS

Upper 297 KIAS

Answer ‘a’ best !


When using descent data CASA want you to round to the nearest 5000 kg (i.e. 64999 = LW 60000, 65000 or

higher round to LW 70000 kg). In this case use 70000 kg data.

FL Time (min) Dist (air nm)

370 24 124

Add for 30 kt TWC for 24 min +12

Total 136 gnm Answer ‘b’ is best !

Step 1. Refer B727 manual page 2-14 for FL vs Mach/Temp/Acceleration GW. Find Max acceleration GW.

FL Crz Schedule ISA

330 0.84 76500 kg

Step 2. Find EMZW which is half way

between current GW and acceleration

weight. EMZW rounds to 77000 kg

Step 3. Find SGR and divide it into the

FBO required. This will define the position

at which the aircraft can accelerate directly

to M 0.84.

Mach 0.82

TAS 477 kt

GS 537 kt

FF 4728 kg/hr

SGR 8.804

FBO required 1500 kg

Distance 170 nm

EMZW

77.0T

1200 UTC

78000 kg

M 0.84

Acceleration point

Answer ‘b’

76500 kg

1500 kg

8.804 = 170 nm


Q6.

Q7.

Q8.

M 0.82


(ROB AVERY)

Flight profile

www.robavery.com.au

60 kt/ISA


FAQ 1. Can CASA ask you to find upper/lower stall

buffet speeds expressed as TAS or Mach number ? → Answer: Yes so best look back over your Navigation notes and get active on the circular Nav computer.


Step 1. Refer to B727 manual page 3-106. Find ISA value for Mach 0.80/FL350.

FL ISA temp (static air) Mach 0.80

TAT

350 -54°C -26°C

Step 2. Ram Rise is difference between

static ISA air temp, and the Mach 0.80

indicated temp. In this case 28°C.


Step 1. Refer to B727 manual page 1-17. Fuel policy, Normal ops Departure to Destination.

Item Fuel (kg)

Flight fuel 9320

VR (10%) 932

FR 3300

Wx hold 2000

Traffic hold 1333

F/taxi 100

I/taxi 150

Min ramp FOB 17135 kg Answer ‘a’ best !

Step 1. Eliminate answers a, and e as they are Easterly IFR levels.

Step 2. Refer B727 manual page 2-14 (3 engine altitude capability table).

FL Mach ISA +10C

FL350 0.80 72900 kg NOT possible

FL310 0.80 82900 kg Available

FL280 0.80 88550 kg Available

Flight Level 310 is the highest IFR level available. Answer ‘d’ best.


Q9.

Q10.

Q11.

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FAQ: What is the difference between Indicated Mach Number (IMN) and True Mach Number (TMN, or just M) ? → The difference is the sum of instrument error and position error, which for the Flight Plan-ning exam is said by CASA to be nothing, so read IMN as M, or TMN—they are the same thing !

FAQ Which operations do we carry traffic holding for ? → ANSWER: Normal ops only.

FAQ: According to the ERC charts FL310 is an easterly level, how come the answer is FL310 if heading West ? → ANSWER: Because the B727 is not approved for RVSM operations. See introduction for the levels you can use in the exam.


Refer B727 manual page 1-3, yaw damper limits. FL290 max KIAS 280 kt. Answer ‘b’ best !

Mach 0.82

TAS 481 kt

GS 439 kt

FF 4431 kg/hr

SGR 10.093

FBO 2210 kg

ETI 30 min

ISKUX

1310 UTC

68790 kg

APENA

1240 UTC

71000 kg

Track 341M

Dist 219 nm

FL310

42 kt/ISA EMZW

70T

Answer ‘b’ best !

1310 UTC/68, 800 kg


Q12.

Q13.


(ROB AVERY)

Flight profile

www.robavery.com.au




FAQ 1. Can CASA ask you to find upper/lower stall buffet speeds expressed as TAS or Mach number ?

→ Answer: Yes so best look back over your Navigation notes and get active on the circular Nav computer.

FAQ 1. Why am I so far out on my TAS (about 30 kt faster) ?→ Answer: This could be because you

took the Indicated Outside Air Temp (IOAT) as True Outside Air Temp. IOAT (also called TAT) has ram rise error in it due to compressibilty at high altitude. You should use the green curved IOAT line on your navigation computer here, not the book TAS figure, or the speed of sound scientific formula. Check out you navigation course notes on this.

Fix

GW 74148 kg 10 kt/ISA

FL230 9 kt/ISA+3

(CASA +3)

EMZW

73T

EMZW

71T

EMZW

69T

15 kt/+5

CASA +6

Mt Isa Cairns Alice Springs

Fuel in the Box

3670 kg

LRC 1 Inop

Mach 0.665

TAS 408 kt

GS 423 kt

FF 4301

SGR 10.168

FBO 3468 kg

18’

610 kg 400 kg

85 gnm

TopC

FL185

13 kt

341 nm

183 nm


Step 1. FOB at BR is 17150 kg (at ramp) - 150 kg = 17000 kg.

Step 2. Calculate fuel available for FLIGHT. FOB at BR 17000 kg

FR 1 Inop 1500 kg

Final taxi 100 kg

110 % fuel avail 15400 kg

100% fuel avail 14000 kg

Step 3. Find LW Cairns.

BR 80000 kg - flight fuel 14000 kg = 66000 kg.

Step 4. Find descent data FL230.

LW 66000 kg + APP 400 + Descent 610 = 67010 kg.

Step 5. Find EMZW and then find 1 Inop cruise data from

Mt Isa to TopD (refer profile above) FBO 3468 kg.

Step 6. Find GW o/head Mt Isa at end of ‘BOX’ (TopD

GW 67010 + 3468 kg = 70478 kg).

Step 7. Find Fuel in BOX.

GW at Fix 74148 kg - 70478 kg = 3670 kg.

Step 8. Find EMZW OUT and BACK by dividing

the Fuel in the BOX by 4.

Step 9. Find data OUT Normal Ops/FL310, and data

home 1 Eng Inop FL230 → refer next page →→

70478 kg


Q14.

Flight profile



Data OUT Normal Ops. Data HOME 1 Eng Inoperative.

LRC 1 Inop

Mach 0.672

TAS 410 kt

GS 419 kt

FF 4378

SGR 10.471

Mach 0.79

TAS 463 kt

GS 453 kt

FF 4317

SGR 9.530

Step 10. Find length of BOX.

Fuel in BOX

(SGR OUT + SGR Home)

3670 kg

(9.530 + 10.471)

= = 183 nm past Mt Isa

Answer ‘d’ best.

1. We do NOT care what the weather is like at Alice Springs or Mt Isa if we are planning to return to Cairns

following the loss of an engine, which is the scenario this PNR is based on. It is Cairns weather that will effect

our operation in this case.

2. Watch out for distance from MUSEY to Cairns - it is NOT shown on ERC chart ... refer TAC chart. CASA

should have quoted this in the question but take your TAC charts in just the same as this has been missed from

exam question before.

Flight profile

Continued on next page →→→


Q14. Cont...

Q15. INTELLECTUAL PROPERTY OF AVFACTS

(ROB AVERY)

www.robavery.com.au

CAS 280 kt

Mach 0.73

TAS 435 kt

GS 498 kt

FF 3937

SGR 7.907

FBO 775 kg

400 kg 17.5’

2325 kg

103 anm

21’

640 kg

117 nm 98 nm 115 nm

Mackay Cairns

BRW 71431 kg

46 kt/ISA+5

FL290 63 kt/ISA +2 (CASA +3 used)

EMZW

69T

FL185 44 kt

TopC

69106 kg


FAQ We are going to Alice Springs, so why do we not take out the holding fuel for Alice ? Answer → Be-cause the assumption is we will return to Cairns if we lose an engine at the PNR. In this case you will not be going on to Alice Springs. The PNR2E defines the last point in the journey where a safe return to Cairns is possible - this is what CASA want. It may be a data entry question, not multi-choice.


Item Kg

Flight Fuel 4140

VR 414

FR 3300

Taxi OUT 150

Taxi IN 100

Min FOB at ramp 8104 kg

Fuel Summary • Refer page 1-3 for max speed/FL info. FL290 available IFR.

• Refer page 5-25 for yaw damper FF data.

• Use nav computer to get Mach No, then TAS from it.


Note:

• The climb tables are based on a BRW, NOT a weight at 1500 ft as you will likely be given in an exam

question. Add 400 kg to the 1500 ft GW to get an “as if” BRW. In this case BRW would be 68000 kg.

• Use normal ops climb data, then reduce this by the climb from RWY to 1500 ft. Then add the 1 Eng Inop

penalty from page 2-2a.

• FR now 1500 kg for 1 Inop, and no final taxi fuel required as we are in flight at the fix.

LRC 1 Inop

Mach 0.658

TAS 407 kt

GS 388 kt

FF 4054

SGR 10.448

FBO 1661 kg

25 min 2400 kg 130 anm

400 kg

18.5 min 615 kg 82 anm

Mt Isa

FL185 10 kt/ISA+10

TopC GW

65200 kg EMZW

64T

159 nm 126 nm

FL185 10 kt

Alice Springs

FL240 19 kt/ISA+11 (CASA +12 - used)

67600 kg

1500 ft

Refer next page for working.


Q16.

79 nm


(ROB AVERY)

Flight profile


FAQ 1. Do we use 45 minutes (3300 kg) for pre-fight fixed reserve

for Yaw Damper Inop ? Answer → Yes, but if you lost a yaw damper in flight only 30 minutes (2250 kg).

2. How did we know the airports did not need weather holding → Answer because they were CAVOK.

3. How did you get Mach number and TAS ? Answer → Using the Yaw Damper max IAS at FL290 from page 1-3 and outting this opposite FL290 on you nav wheel you see Mach 0.73 in the Mach window. Use speed of sound formula thereafter to get YD inop TAS.


Step 1. Climb data 68000 kg/ISA+10

N/ops 0-FL240 13’/1800 kg/70 anm

Less 0-1, 500 ft 2’/400 kg/0 anm

N/ops 1, 500-FL240 11’/1, 400 kg/70 anm

Plus 1 Inop penalty 14’/1, 000 kg/60 anm

1 Inop climb 1500-FL240 25’/2400 kg/130 anm

HWC deducts 4 nm to give 126 gnm.

Step 2. Find descent data at approx LW of 60000 kg.

18.5 min/615 kg/82 anm

HWC of 10 kt reduces descent distance to 79 gnm.

Step 3. Cruise distance is 159 gnm.

Refer flight profile data for 1 Eng Inop cruise.

Fuel Summary

Item Kg

Flight Fuel 5076

VR 508

FR 1500

Wx Hold YPAS 2000

Traffic Hold YPAS NIL

Taxi IN NIL

Min FOB at ramp 9084 kg

Answer ‘a’ is best !


Q17.

WORKING:

Step1. Find track from Horn Is to Port Moresby. It is about 071°M. Use the current actual spot wind for the

flight out to the PNR not the forecasted one which could be hours old. It gives a tailwind component of about

81 kt. For any other levels and sectors use forecasted winds.

Step 2. Note that from the DPNR you are to track back to Horn Island and then turn toward Cairns.

Step 3. Track/distance to Cairns is on average 146°M/425 nm.

Step 4. Get the wind component/Isa deviation at FL330 OUT to the PNR. It is about 81 kt TAIL/ISA.

Step 5. Note the GW was not given at the Horn Island fix, but at BRW Darwin. The flight fuel used from Dar-

win out to Horn Island is given as 7130 kg so GW overhead Horn Island must be 70000 kg.

Step 6. The FOB was given at the Darwin RAMP, not at Horn Is, so the FOB at Horn Is must be 18500 kg -

(taxi out fuel 150 kg + flight fuel out to Horn Island of 7130 kg) = 11220 kg.

Refer next page →→

www.robavery.com.au

For earlier version Q17 please refer to the last 2 pages of this file.




FAQ 1. Why did we add 400 kg to 1500 ft GW ? Answer → Because

climb data is based on BRW, not 1500 ft GW. Adding 400 kg gets you a notional BRW as if you released the brakes at that GW. Enter the climb tables with BRW rounded to nearest even tonne.

2. Why was FR 1500 kg added (not 2250 or 3300 kg) ? Answer → Because this was a 1 Engine inop scenario.

3. Why FL185 for climb wind/temp data used. Answer → because for 1 Inop climbs that is the nearest level we will round to (2/3rds the way to TopC which is typically in mid 20’s ! Inop.)

FP exam 1 working/page 10. © Copyright Avfacts 2013. All rights reserved worldwide.

See next page →→

Step 7. Subtract the depressurised reserves to get

flight fuel. Remember the PNR assumes a diver-

sion to Cairns, so Port Moresby or Darwin

weather is not a consideration in this case.

Step 8. Find LW at Cairns. It is current GW at

Horn Island (70000 kg) less the flight fuel of 8970

kg = 61030 kg.

Step 9. Being asked to cruise depressurised at a FL

is a bit of tricky wording. Always use FL130 when

depressurised irrespective of the track direction.

Step 10.Now work backwards from LW at Cairns

(61030 kg) to get GW overhead Horn Is on the

return from the PNR. See flight profile. The fuel

in the box is the GW overhead Horn Island going

out to the PNR, less the GW on return from it. In

this case 70000 kg - 66089 kg = 3911 kg.

Usable FOB 11220

Less Dep Fixed Res 2250

Less Wx holding Cairns

NO

Less Traffic @ Cairns NO

Less taxi IN fuel NO

100% fuel available 8970

Profile from above.

Horn Is

DP

NR

From Darwin

Cairns

LW 61030 kg

From

Darwin

CAIRNS

114 nm Trk 146°M/425 nm

Fix @ 0045Z

GW 70000 kg

Total FOB 11220 kg

Usable FOB 8970 kg

400 kg

58 nm

13 min

520 kg

50 anm

TopD GW

61950 kg

LW

61030 kg

IAS/FL 310 KIAS/FL310

= Mach 0.59

TAS 378 kt

GS 417 kt

FF 4703 kg/hr

SGR 11.278

FBO 4139 kg

367 nm

Horn Is

81 kt/ISA

26 kt/ISA+15 = +4°C

(CASA ISA+15 → used here)

FL130 39 kt/ISA+10 = -1°C

(CASA use ISA+9 → used here)

39 kt

FL130 64T

GW

66089 kg

Fuel in the Box

3911 kg

69T

67T

Trk OUT 071°M/299nm

Flight Profile.

DP

NR

LRC OUT

Depressurised HOME

185 nm

www.robavery.com.au

Pt Moresby

Pt Moresby



Refer to page 1-22 for fuel dumping rates, and page 2-2a for 1 Inop climb penalty data.

Step 1. Using BRW given, get climb data.

N/ops 0-10, 000 ft 6’/1, 000 kg

Less 0-1, 500 ft 3’/450 kg

N/ops 1, 500-10, 000 ft 3’/550 kg

Plus 1 Inop penalty 6’/500 kg

1 Inop climb 1500-10, 000 ft 9’/1, 050 kg

Step 2. ETA at TopC 1309 UTC/GW

at TopC 74550 kg.

Step 3. Fuel to dump is 74550 - 73500 kg = 1050 kg

= 1 minute. So ETA to start approach is 1310 UTC. Answer ‘c’ best !


FL250 1230 kg/Eng/Hr @ ISA

70000 kg

So 3 Eng FF @ ISA is 3690 kg/hr.

Correct for ISA-5 by reducing FF by 1%.

ISA-5 FF in racetrack pattern is 3653 kg/hr. Answer d best !


Q19.

Q18.


(ROB AVERY)

Data HOME via Horn Is FL130

LRC

Mach 0.787

TAS 458 kt

GS 539 kt

FF 3960 kg/hr

SGR 7.347

Data OUT FL330

Distance from Horn Is to DPNR =

Fuel in the box

(SGR O + SGR H)

=

3911 kg

(7.347 + 13.710) = 185 nm past Horn Is.

Measured from Port Moresby as requested in the question this is 114 nm. To be conservative, always round

UP answers for PNR’s when measuring from airport ahead (Port Moresby in this case).

So 125 nm answer is best !

IAS 310 kt

Mach 0.59

TAS 381 kt

GS 355 kt

FF 4867 kg/hr

SGR 13.710


FAQ 1. How do you get TAS using LRC ? An-

swer → Refer page 3-79 for EMZW and find Mach number (below fuel flow). As this in-flight fix quotes TAT, set Mach number for EMZW in Mach window, and use the green curved IOAT (TAT) line on your navigation computer here, not the book TAS fig-ure, or the speed of sound scientific formula. Check out you navigation course notes on this.


Mach 0.80

TAS 469 kt

GS 409 kt

FF 4491 kg/hr

SGR 10.980

FBO required 2000 kg

Step 1. Refer B727 manual page 2-14 an find maximum arrival weight at FL350/Mach 0.80 in ISA+5

conditions is 74800 kg.

Step 2. Add 50 kg per 1000 ft climbed to get start of step climb GW. In this case 74800 + 200 kg = 75000 kg.

Step 3. Find FBO required before the start can be commenced. (i.e. 77000 kg - 75000 kg) = 2000 kg.

Step 4. Find EMZW. It is half way between GW at LINGO and Start climb weight. EMZW is 76000 kg.

Step 5. Find cruise data to get SGR, then divide the FBO required of 2000 by the SGR. This gives distance to

step climb position. (Refer flight profile below). Step climb position is 182 nm. Answer ‘d’ best !

LINGO

77000 kg

EMZW

76T 200 kg

FL350

ISA+5

FL310 60 kt/ISA

182 nm

TopC GW 74800 kg

Start climb

GW 75000 kg

Note well:

• CASA say you may disregard distance and any time lost in the climb.

• CASA would use ISA+6 for fuel flow and TAS calculations, which would make no real difference to the

model answer as the extra 1° effects TAS and fuel flow figures roughly equally. Try it for yourself.

• CASA would use ISA+5 to check max GW on arrival at FL350 - in this case 74800 kg.

• Be carful to ADD the step climb fuel to the max arrival GW at FL350 - so 74800 + 200 kg, not minus 200

kg. Getting this wrong means a double error and would put you about 40 nm off the model correct answer,

and CASA would likely have an answer to cater to this classic mistake..

End of Flight Planning Exam 1 working.


Q20.

2000 kg

10.980 = 182 nm

INTELLECTUAL PROPERTY OF AVFACTS (ROB AVERY)

Flight profile

www.robavery.com.au

For earlier version Q17 please refer to the next two pages of this file →→→


Perth LW 65325 kg

LRC 1 Inop

Mach 0.659

TAS 405 kt

GS 355 kt

FF 4363

SGR 12.290

FBO 5593 kg

74T

72T

FL330 64 kt/ISA +7 TAPAX

GW 73933 kg

FL220 48 kt/ISA +6

97 nm 1018 nm

GW 71918 kg

70T

17.5’

600 kg

79 anm

65 nm

FL185 45 kt

50 kt/+5

455 nm

Hobart

Fuel in the Box

2015 kg

400 kg

Answer

Step 1. FOB at BR Perth is 19893 kg - Taxi Out 150 kg

= 19743 kg. Step 2. Calculate flight fuel.

Item Kg

FOB at BR 19743

FR 1 Inop 1500

Perth Wx hold 2000

Final taxi 100

110 % fuel 16143 kg

100% fight fuel 14675 kg

Step 3. LW Perth = BR 80000 - flight fuel 14675 kg

= 65325 kg.

Step 4. Find descent data (page 4-3) FL 220/70000 kg.

17.5 min/600 kg/79 anm/65 gnm.

Step 5. Find TopD GW.

LW 65325 kg + 400 + 600 = 66325 kg.

Step 6. Find EMZW TopD to below TAPAX, then

calculate the cruise data for this zone. It is 5, 593 kg.

Step 7. GW at end of box below TAPAX is

TopD GW of 66325 kg + 5593 kg = 71918 kg.

Step 8. Find fuel in box starting at TAPAX.

TAPAX GW 73933 kg - GW below TAPAX 71918 kg = 2015 kg.

Step 9. Find EMZW OUT/HOME.

Q17. Cont...

Flight profile Q17. OLD

www.robavery.com.au




Flight profile


Step 10. Data OUT Normal ops, and HOME 1 Eng Inop.

Data OUT Data HOME

LRC 1 Inop

Mach 0.665

TAS 410 kt

GS 362 kt

FF 4509 kg/hr

SGR 12.290

Mach 0.80

TAS 472 kt

GS 536 kt

FF 4415 kg/hr

SGR 8.236

Step 11. Find length of box.

Fuel in Box

SGR OUT + HOME =

2105 kg

(8.236 + 12.443) = 97 nm past TAPAX, which is 1018 nm from Hobart.

Answer ‘e’ is best !

Q17. OLD CONTINUED ...

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END





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© Copyright Avfacts 2016. All rights reserved worldwide ... · Flight Planning Practice exam 1 - Working ... FP exam 1 working/page 2. Mach 0.84 TAS 485 GS 534 FF 3802 kg/hr SGR