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Simple Truss AnalysisMethod of Joints
Engineering Mechanics: Statics * Dr. Yiheng Wang
Objective of this video:
To provide a step-by-step problem-solving strategy for simple truss analysis using the method of joints.
Engineering Mechanics: Statics * Dr. Yiheng Wang
F2
F1
F3
F4
F2
F1
F3
F4
particle equilibrium
Engineering Mechanics: Statics * Dr. Yiheng Wang
Compression: push towards the joint.
Tension: pull away from the joint.
Reminder: 2-D particle equilibrium:
enables solving for 2 unknowns at a time.
0
0
y
x
F
F
Engineering Mechanics: Statics * Dr. Yiheng Wang
200 lb
A BC
D
E
F
Example 1: Determine the force in each member of the truss and indicate if the member is in tension or compression.
45º45º
1 ft
1 ft
Engineering Mechanics: Statics * Dr. Yiheng Wang
200 lb
A BC
D
E
F
Step 1: Remove zero-force member by inspection.
45º45º
1 ft
1 ft
0
0
BE
DE
F
F
Engineering Mechanics: Statics * Dr. Yiheng Wang
200 lb
A BC
D
E
F
Step 2: Decide if support reactions need to be determined.
45º45º
1 ft
1 ft
hint: from each joint you can solve for maximum 2 reactions.
PAUSEPLEASE
Engineering Mechanics: Statics * Dr. Yiheng Wang
200 lb
A BC
D
E
F
Step 3: Solve each joint from easy to hard. Apply particle equilibrium.
45º45º
1 ft
1 ft45º
Engineering Mechanics: Statics * Dr. Yiheng Wang
200 lb F
Joint F:
67.5ºFEF
FDF
x
y
05.67cos
0lb2005.67sin
DFEFy
EFx
FFF
FF
Tlb216
Clb8.82
EF
DF
F
F
200 lb F
82.8 lb
216 lb
Tip: always draw unknown reactions as tensions.
Engineering Mechanics: Statics * Dr. Yiheng Wang
200 lb
A BC
D
E
F
45º45º
1 ft
1 ft
Engineering Mechanics: Statics * Dr. Yiheng Wang
216 lbE
Joint E:
FCEFAE
67.5º
05.67coslb216
05.67sinlb216
AEy
CEx
FF
FF
Clb8.82
Tlb200
AE
CE
F
F
216 lb
E
200 lb82.8 lb
x
y
Engineering Mechanics: Statics * Dr. Yiheng Wang
200 lb
A BC
D
E
F
45º45º
1 ft
1 ft
Cy
CxFBC
PAUSEPLEASE
Ay
Engineering Mechanics: Statics * Dr. Yiheng Wang
x
y
82.8 lb
A
Joint A:
FAB
Ay
045sinlb8.82lb8.82
045coslb8.82
yy
ABx
AF
FF
lb141
Tlb3.58
y
AB
A
F
82.8 lb45º
82.8 lb
A82.8 lb
58.3 lb
141 lb
Engineering Mechanics: Statics * Dr. Yiheng Wang
200 lb
A BC
D
E
F
45º45º
1 ft
1 ft
Engineering Mechanics: Statics * Dr. Yiheng Wang
200 lb
A BC
D
E
F
45º45º
1 ft
1 ft
Tlb3.58
Clb8.82
Tlb200
Clb8.82
Tlb216
0
0
BCAB
AE
CE
ADDF
EF
BE
DE
FF
F
F
FF
F
F
F
Engineering Mechanics: Statics * Dr. Yiheng Wang
Question 1: For the following truss structure (with members AB, BC, AD, DE, BE, CF
and FG all of 60 cm length each), determine the force in member CE.
(a) (b)
(c) (d)(T) N 257 (C) N 633
(T) N 79.9N 0
200 N
AB
C
DE
F
G
120 N160 N
45º
Engineering Mechanics: Statics * Dr. Yiheng Wang
(a) (b)
(c) (d)(T) N 257 (C) N 633
(T) N 79.9N 0
200 N
AB
C
DE
F
G
120 N160 N
45º
Engineering Mechanics: Statics * Dr. Yiheng Wang
Question 2: For the following truss structure (with members AB, BC, AD, DE, BE, CF
and FG all of 60 cm length each), determine the force in member DE.
(a) (b)
(c) (d)(T) N 257 (C) N 633
(T) N 79.9N 0
200 N
AB
C
DE
F
G
120 N160 N
45º
Engineering Mechanics: Statics * Dr. Yiheng Wang
Question 3: For the following truss structure (with members AB, BC, AD, DE, BE, CF
and FG all of 60 cm length each), determine the force in member AE.
CN283EGF
TN200FGF
TN9.87CFF
CN113EFF
CN120ADF
N0 EDBE FF
TN9.79CEF
CN363AEF
TN257 BCAB FF
N377yA
N313xC
N144yC
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