Ms. Battaglia AB/BC Calculus

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2.3 Product & Quotient Rules and Higher-Order Derivatives Objective: Find the derivative of a function using the Product Rule and the Quotient Rule. Ms. Battaglia AB/BC Calculus. Theorem 2.7 The Product Rule. - PowerPoint PPT Presentation

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2.3 Product & Quotient Rules and Higher-Order Derivatives

Objective: Find the derivative of a function using the Product Rule and the Quotient Rule

Ms. BattagliaAB/BC Calculus

Theorem 2.7 The Product Rule

The product of two differentiable functions f and g is itself differentiable. Moreover, the derivative of fg is the first function times the derivative of the second, plus the second function times the derivative of the first.

Using the Product Rule Find the derivative of

Using the Product Rule Find the derivative of

Using the Product Rule Find the derivative of

Theorem 2.8 The Quotient RuleThe quotient f/g of two differentiable functions f

and g is itself differentiable at all values of x for which g(x)≠0. Moreover, the derivative of f/g is given by the denominator times the derivative of the numerator minus the numerator times the derivative of the denominator, all divided by the square of the denominator.

Using the Quotient Rule Find the derivative of

Rewriting Before Differentiating

Find the equation of the tangent line to the

graph of at x = -1.

Original Function

Rewrite Differentiate

Simplify

Using the Constant Multiple Rule

Derivatives of Trig Functions

a. y = x – tanx b. y = xsecx

Differentiating Trig Functions

Different Forms of a Derivative

Differentiate both forms of

You can obtain an acceleration function by differentiating a velocity function.

Higher-order derivatives: differentiating more than once

Higher-Order Derivatives

Finding the Acceleration Due to GravityBecause the moon has no atmosphere, a falling object on the moon encounters no air resistance. In 1971, astronaut David Scott proved that a feather and a hammer fall at the same rate of the moon. The position function for each of these falling objects is given by

s(t)=-0.81t2 + 2 where s(t) is the height in meters and t is the time in seconds. What is the ratio of Earth’s gravitational force to the moon’s?

Read 2.3, Page 126 #19-53 odd, 81, 82, 87, 99, 103, 131-136

Classwork/Homework

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