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2.3 Product & Quotient Rules and Higher-Order Derivatives Objective: Find the derivative of a function using the Product Rule and the Quotient Rule Ms. Battaglia AB/BC Calculus

Ms. Battaglia AB/BC Calculus

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2.3 Product & Quotient Rules and Higher-Order Derivatives Objective: Find the derivative of a function using the Product Rule and the Quotient Rule. Ms. Battaglia AB/BC Calculus. Theorem 2.7 The Product Rule. - PowerPoint PPT Presentation

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Page 1: Ms.  Battaglia AB/BC Calculus

2.3 Product & Quotient Rules and Higher-Order Derivatives

Objective: Find the derivative of a function using the Product Rule and the Quotient Rule

Ms. BattagliaAB/BC Calculus

Page 2: Ms.  Battaglia AB/BC Calculus

Theorem 2.7 The Product Rule

The product of two differentiable functions f and g is itself differentiable. Moreover, the derivative of fg is the first function times the derivative of the second, plus the second function times the derivative of the first.

Page 3: Ms.  Battaglia AB/BC Calculus

Using the Product Rule Find the derivative of

Page 4: Ms.  Battaglia AB/BC Calculus

Using the Product Rule Find the derivative of

Page 5: Ms.  Battaglia AB/BC Calculus

Using the Product Rule Find the derivative of

Page 6: Ms.  Battaglia AB/BC Calculus

Theorem 2.8 The Quotient RuleThe quotient f/g of two differentiable functions f

and g is itself differentiable at all values of x for which g(x)≠0. Moreover, the derivative of f/g is given by the denominator times the derivative of the numerator minus the numerator times the derivative of the denominator, all divided by the square of the denominator.

Page 7: Ms.  Battaglia AB/BC Calculus

Using the Quotient Rule Find the derivative of

Page 8: Ms.  Battaglia AB/BC Calculus

Rewriting Before Differentiating

Find the equation of the tangent line to the

graph of at x = -1.

Page 9: Ms.  Battaglia AB/BC Calculus

Original Function

Rewrite Differentiate

Simplify

Using the Constant Multiple Rule

Page 10: Ms.  Battaglia AB/BC Calculus

Derivatives of Trig Functions

Page 11: Ms.  Battaglia AB/BC Calculus

a. y = x – tanx b. y = xsecx

Differentiating Trig Functions

Page 12: Ms.  Battaglia AB/BC Calculus

Different Forms of a Derivative

Differentiate both forms of

Page 13: Ms.  Battaglia AB/BC Calculus

You can obtain an acceleration function by differentiating a velocity function.

Higher-order derivatives: differentiating more than once

Higher-Order Derivatives

Page 14: Ms.  Battaglia AB/BC Calculus

Finding the Acceleration Due to GravityBecause the moon has no atmosphere, a falling object on the moon encounters no air resistance. In 1971, astronaut David Scott proved that a feather and a hammer fall at the same rate of the moon. The position function for each of these falling objects is given by

s(t)=-0.81t2 + 2 where s(t) is the height in meters and t is the time in seconds. What is the ratio of Earth’s gravitational force to the moon’s?

Page 15: Ms.  Battaglia AB/BC Calculus

Read 2.3, Page 126 #19-53 odd, 81, 82, 87, 99, 103, 131-136

Classwork/Homework