Management Aptitude Test 17 Nov

www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

MANAGEMENT APTITUDE TEST

AFTERSCHO☺OL – DEVELOPING CHANGE MAKERS

CENTRE FOR SOCIAL ENTREPRENEURSHIP PGPSE PROGRAMME –

World’ Most Comprehensive programme in social entrepreneurship & spiritual entrepreneurship

OPEN FOR ALL FREE FOR ALL


MANAGEMENT APTITUDE TEST

Dr. T.K. Jain.

AFTERSCHO☺OLCentre for social entrepreneurship

Bikaner M: [email protected]

www.afterschool.tk, www.afterschoool.tk

http://www.afterschool.tk/

http://www.afterschoool.tk/


A group of students decided to buy a gift for the class teacher on the ocassion of her birthday

costing between Rs.208 and 231 by contributing equally At the last moment, two students backed out of the decision and the

remaining students then had to contribute one rupee more than what they had earlier planned for. Find the price of the gift if all the students

contributed equally?

• Options: 222,218,220,215


Solution • SOLVE USING OPTIONS….• let us assume the price to be X and number of

students to be Y. • X/Y = X / (Y-1) + (Y-1)• Let us look at the factors of these numbers: 220

has two nearby factors : 22 and 20. when divided by 22, we have 10 to be contributed by each. suppose 2 students left out, now we have 20 students, each has to contribute Rs. 11. thus this amount is one rupee more. Thus this is the answer.


Four friends, A, B, C and D got the top four ranks in a competitive

examination, but A did not get the first, B did not get the second, C did not get the third and D did not get

the fourth rank. Who secured which rank?

• Statements : (A) Neither A nor D were among the first 2. (b) Neither B nor C was third or fourth.


SOLUTION

• WE CAN DRAW ANSWER FROM ANY OF THESE STATEMENTS.

• From the first statement the answer is : • B,C,D,A• From B statement : • B,C,D,A.• Thus the answer can be drawn from only

one (anyone ) statement from the two statements.


Is n odd?(A) n is divisible by 3, 5, 7 and 9.

(B) 0<n<400• There is only one such number which is

divisible by 3,5,7,9 and also less than 400. this number is 315. this is odd number, thus answer can be drawn with the help of both the statements together.

(find LCM of 5,7,9 and get the answer). Answer.


• We know that multiple of 4 is always 6 – if the power is in multiple of 2. So in both the cases the unit digit is 6.

• 6*6 = 36, so again the unit digit will be 6. However, in this case one of the power is 103, thus the unit digit here will be 4.

• 6*4 = 4. • Thus the unit digit will be 4. answer.


• Options: • 3,11, 17, 13• Let us take 4^61 as common • 1 + 4^1+4^2+4^3 = 85• 85 is divisible by 17, thus this number is

divisible by 17


Solve the following?


Solution

• Answer can be drawn from the first statement alone.

• We know that log (base10) 1000 is 3 and we know that log (base 10) 10 = 1.

• 3 – 1 = 2. Thus we know that X = 100. Thus we can say that X is not equal to 2. so answer can be drawn from the first statement alone.


The annual increase in the population of a town is 10%

and the present population be 13310, then what was it

three years ago?

• Suppose three years ago population was 100, today it should be 100*(1.1)^3

• =133.1• Thus population 3 years ago was :

100/133.1*13310 = 10000 answer.


In a mixed school, 20 percent of the scholars are children under 7 and the number of girls above 7 is 2/3

of the number of boys above 7 and amounts to 64. Find the number of

the scholars in the school.

• No. of girls above 7 = 64• No. of boys above 7 = 64*3/2 = 96• Total children above 7= 160.


Solution …

• Since 20%children are below 7, 80% are above 7 years of age .

• Thus total number of scholars are 100/80 *160

• =200 answer.


A reduction of 25% in the price of suger would enable a purchaser to obtain 25 kg more for Rs.45. What

is thereduced price per kg?

• Let us assume reduced price to be X. • Original price = 1.33X• 45/X - 45/1.33X = 25• (60 – 45) / 1.33X = 25• 15 = 100/3 X or X = 45/100 or .45 per KG• (original price 60, reduced price 45 paise per kg)


In astudent hostel the number of students increases at a

certain rate per annum Four years ago the number of

boarders was 49, now it is 196What will be the number of

students after 2 years. • Let us find the number of students 2 years ago: =

sqrt (49*196) = 98• Thus number of students after 2 years : =196/98 *

196 = 392 answer.


If X exceeds Y by 50% and Yis 50% less than Z, then whatpercentage is z of X? -

• Suppose Y = 100• X = 150 • Y is 50% less than Z, so z is 200. • Z is 200/150 *100 = 133%


What is the geometric mean of 9,12, and 2?

• Let us multiply 9, 12 and 2 and then find the geometric mean:

• = 216 ^1/3 • =6 answer.


A reduction of 40 percent in the price of eggs would enable

a purchaser to obtain 56 more for Rs.10. What is the initial

price?

• Let us assume that the initial price was X. • Reduced price = .6X• 10/.6x - `10/X = 56(10 - 6) = 56(.6X) = 33.6X = 4 or X =

4/33.6 = 12 paise


The product of the two numbers remains constant. If one of

them increases by 40%, then by what percent does the

second diminish?• Let us assume the two numbers to be 10

each. The product is 100. first number becomes 14. the second number is : 100/14 = 7.14

• Thus the second number reduces by 28.6%


The length of a rectangle increases by 10% and the breadth diminishes

by 25°/o. How does its area change?

• Let assume the length and breadeth to be 20 and 10. the area is 200.

• new length and breadth are : 22 and 7.5. The area becomes : 165. thus reduction in area is 17.5% answer.


There are 2 trains moving in opposite direction. They are of

equal length. Their speeds are also 90 KM per hour each. They 1

minute to cross each other. What is the length of each of these trains?


Solution

• Speed of 1 train : 90• Speed in meters / per second = 90*5/18• =25 meters per second. • The combined speed is 50 meters per

second. • Thus the two trains have taken 60 seconds

and have travelled : 60*50=3000• Thus length of one train = 1500 meters.

(each).


Ram Kap and goti start business with equal capital. Ram double the money every month. Kap trible the

capital every quarter and goti quadruple the capital every 6

month. What is their profit sharing ratio at the end of the year?


Solution

• Their capital ratio comes to : • 4095:120:84 answer.


3/4 th of 68 is less than2/3 of 114 by?

• ¾ *68 = 3*17 = 51• 2/3 *114 = 2*38 =76• Their difference is 25 answer.


LCM and HCF of 2 numbers are 84 and 21 respectively. If the ratio of the two numbers is 1:4, the larger

number is ? • The two numbers are X and 4X. • Let take factorisation of 84 and 21. • Factorisation of 84 = 2*2*3*7• Since HCF is 21, the numbers are 21 and

84 answer.


1/3rd of a number is 3 more than 1/4th of the number, what is the

number?

• Let us assume the number to be X. • X/3 – X/4 = 3 • (4X – 3X ) / 12 = 3• X = 36 Answer.


If 1/8th of a pencil is black, half of the remaining is yellow and

remaining 3.5 CM is blue, what is the total length of the pencil?

• Let us assume the length of the pencil to be 16 CM . 2CM is black. 7 CM is yellow. 7CM is blue. Thus if 7CM is blue, total length is 16, if 3.5 CM is blue, the total length is 16/7*3.5 = 8 CM Answer.


What is the next number in the sequence: 5,25,50,250,500?

• Let us first multiply a number by 5 and then multiply by 2 and so on. Thus we are able to get 2500 as the next number.


What is the value of (1/4)^-(1/2)?

• Let us first solve or – sign. We get 4^(1/2)• We know the answer now = 2*2 =4 so the

answer is 2


How many 5 digit multiples of 11 are there, If the 5 digits are

3,4,5,6,7?• We have only 5 digits, which we can

interchange. The total of these numbers is 25. for 11 to divide the difference of the alternate groups of numbers must be either 0 or 11. (25-11) = 14, dividing it in 2 parts, we get 7,7. thus alternate totals must be 7 and 18.

• Thus possible numbers are: 53647. We can inter-change 5,6,7 and also 3 and 4.

• Thus 3! *2! = 12 is the answer.


What will be the remainder when we divide 9^6+7 by 8?

• we can solve it as (1^6 +7)/ 8• (because when we divide 9 by 8, the

remainder is 1.). • Thus the remainder is 0. Answer.


In a bill the accountant transposed rupee for paise and vice versa. The

actual invoice amount was 5.42 more than 6 times of the bill. What

were the original invoice & bill amount?

• Options: (a) 44.06 and 6.44 (b) 18.25 and 25.18

• Solution try options and solve it?


Solution

• 6.44 * 6 = 38.64• Add 5.42 in this. • We get + 44.06. Thus this is the right

answer.


6 workers can make 270 units per minutes (together) How many units

can be made by10 workers for every 4 minutes.

• 270/6 *10 *4 = 1800


Sumit buys every year Bank s cash certificates of value exceeding the last year’s purchase by Rs. 300. After 20 years, he finds that the

total value of the certificates purchased by him is Rs. 83,000. Find the value of the certificates

purchased by him in the 13th year.


Solution

• Sum = n/2 (2a + (n-1)d)• =20/2 (2a + 19*300) = 83000• 2a + 5700 = 8300• 2a = 2600• A = 1300. • Thus 13th investment was : (A + 12 D)• = 1300 + (12*300) = 4900 answer.


BM started from his house one morning in a hurry. While moving out he looked at the mirror image of a wall clock. The clock had no number on its dial. It took him 10 minute to reach his office and then only he realised

his mistake as he could recollect that the time he saw while leaving home was exactly one hour behind that shown by the clock at ilie office. What was the time by the clock in

his office?Options: 5:25, 5:35,6:25, 6:35

answer: 6.35 answer.


In a showroom there is ‘Buy 2 Get Some Free” offer. The number of free shirts (of same type) is to be decided by tossing a

coin, on which numbers 2 and 3 are written on its sides. The number of free shirts is equal to the number that appears after tossing the coin. By how much percent

more than the cost price the selling price of a shirt is kept so that the showroom dealer

must not incure any loses?


Solution

• Let us assume that the cost of one shirt is 100.

• Expected value = 2 *.5 + 3*.5 = 2.5• Thus when he sells for 200, his cost is

450. he gets 225 per shirt. • He must keep at least 125% above the

cost to ensure no profit no loss.


What is the maximum number of soaps that can be produced in a

day?• A factozy uses two

machines, M1 and M2 to manufacture three types of soap, P, Q & R. The efficiency of the two machines with respect to the three types of soap is given in the table below. The numbers indicate the time taken (in min.) by the two machines to manul.lcture one unit each of the three types of soap.


Solution

• Let us assume that machine works for 12 hours. Machine M1 will make P (because the required is minimum) and M2 will make Q. Thus total production is :

• (12*60)/8 = 90• (12*60)/9 = 80• Thus they will make total 170 soaps.


If X is 90% of Y. what % of X is Y?

• Let us assume Y = 100• X = 90• Thus y = 100/90 *100 = 111% answer.


If X is 90% of Y. Y is 90% of Z what % of X is Z?

• Let us start with Z. Z is 100, Y is 90. Now being being 90, X is 90% of Y, thus X is 81.

• Z is 100/81*100 = 123.45 % of X. answer.


At what rate percent per annum will a sum of money doubles

itself in 12 years?(SI)

• This is a question on simple interest (SI)• We have 100 rupees now and we want

100 more in next 12 years. Thus annual interested expected is 100/12=8.33 approx. per annum answer.


At what rate percent per annum will a sum of money doubles

itself in 12 years?(CI)

• This is a question of compound interest. • Let us assume that the amount is X. • 100 (1+R)^12 = 200• (1+R)^12 = 2• Therefore the rate is 5.9% per annum.


the simple interest on a certain sum is 9/16 of the sum. Find

the rate percent and time, if both are equal.

• Let us assume that sum is 16. interest will be 9.

• PRT / 100 = I (p=principal,R=rate,T=time). • 16*R^2 / 100 = 9 (R = T)• R^2 = 900/16 • R = 30 / 4 or 7.5% per annum answer.


A sum when reckoned at simple interest at 3 per annum

amounts to Rs.364.80 after 4 years. Find the sum.

• Let us assume that the amount was Rs. 100.

• As per question : 100*3*4/100 = 12 or the amount becomes 112.

• Thus sum was 100/112 *364.8=325 (approx.)


Amount = Rs 1110, Time = 100 days, Rate = 5% p.a. what is

simple interest?

• 1110*100/365 *5/100 • =15.2 Rupees.


A is 20% more that B and B is 10% more than C. A is what % more

than C?

• Let us assume C = 100. B is 110. thus A is 120/100 *110 = 132.

• A = 132, C = 100. • Thus A is 32% more than C. Answer.


Goti spends 30% of his pocket money and has $210 left. How

much did he get as pocket money?• Money left out is 70%.

• 100/70 *210 = 300$


The average age of the boys in a class of 20 boys is 15.6

years. What will be the average age if 5 new boys come

whose average age is 15.4 years?

• Average = Total / Number• Total of 20 = 312. total of 5 = 77• Total of 25 = 389• New average = 389/25= 15.56 answer.


A sum of Rs.10,000 deposited at compound interest becomes double after 5 years. After 20 years, how

much will it become?

• Let us assume that money doubles in 5 years, from 1 we get 2 in 5 years, 4 in 10 years, and 8 in 15 years, and 16 in 20 years. Thus this amount will become 160000 in 20 years.


A sum of Rs.5000 was taken as a loan. This is to be paid in two equal installments. If the rate of interest is

20% compounded annually, then what is the value of each

instalment?

• Let us assume that there are 2 instalments of X amounts. Thus discounting them will give 5000.

• X /(1.2 )+ X / 1.44 = 5000


Solution

• X /(1.2 )+ X / 1.44 = 5000• 2.64X = 5000*1.2*1.44• X = (5000*1.2*1.44)/2.64• =3272.7 ANSWER.


—If a certain sum is doubled in 8

years on simple interest,then in how many years will it be

four times?

• Let us assume that Rs 100 becomes 200 in 8 years. Thus this money generates 100/8 = 12.5 per annum of interest

• We have to generate interest of Rs. 300 on Rs. 100 years. Thus years will be : 300/12.5 = 24 years. Answer.


A testator bequeathed by will 2/5 of his estate to his son,

‘’60% of the remainder to his daughter and the remainder to‘his widow, the son got Rs.750 more than the daughter. Howmuch did the widow receive?

• Let us assume that the total amount was Rs. 500. Son got 200 and daughter got 180. thus the difference was only 20.


• If the difference is 20, the total amount• is• 500/20 * 750 • 18750 is the total amount. • Share of widow : 18750*3/5 *40/100• Thus the widow got. Rs. 4500 answer.


A’s mother is sister of B and has a daughter C. How, can A be related

to B from among the following?

• (a) Niece (b) Uncle• (C) Daughter (d) Father

• (a)


Anil, introducing a girl in a party, said, She is the wife of the

grandson of my mother. How is Anil related to the

girl?

• Father in law.


A man said to a woman, Your mother’s husband’s sister is my

aunt. How is the woman related to the man?

(a) Grand daughter (b) Daughter(c)Sister(d) Aunt

• Sister


Showing a lady in the park, . Sumit said, ‘She is the daughter of my grandfather’s only son’. How is

Sumitrelated to that lady?(a) Father (b) SonBrother (d) Mother

• Brother


Puzzle

• (a) A x B means A is the brother of B.• (b) A + B means A is the mother of B.• (c) A ÷ B means A is the son of B.• (d) A — B means A is the husband of B.• Which of the following would mean M is

the father of N: (a) M ÷ N +0• (b) M x 0- N (c)M+0 ÷ N• (d)M-0+N


Solution

• Option D gives you correct answer.


Puzzle test….

• (1) In a family of six persons : A, B, C, D, E and F there are two married couples.

• (2) D is grand mother of A and mother of B.

• (3) C is the wife of B and mother of F.• (4) F is the grand daughter of E. What is C

to A?


Solution

• Grandmother is D, Grand father is E• Grandson / grand daughter are A and F.• Thus C is mother of A. answer.


Proper course of action?

• The exodus from villages, to cities is detrimental to both.

• Courses of Action:• I. Rural postings must be made

mandatory.• I!. There should be fewer trains linking

cities to smaller places.• III. Employment generation scheme should

be launched in rural areas.


Solution

• Only III is the proper course of action.


Which information is sufficient to answer the question?

• Has Smith ever won an award for literature?

• A. Smith won the only award existed during his time

• B. During smith’s time, writing was looked down upon let alone merit an award.


Solution

• Both the statements are not sufficient to answer the question.


Which is an appropriate course of action?

• Every year, at the beginning or at the end of the monsoons we have some cases of conjectivities, but this year,it seems to be a major epidemic witnessed after nearly four years.

Courses of action:• I. Precautionary measures should be taken

after four years to check this epidemic.• II. People should be advised to drink boiled

water


Solution

• Both the course of actions are appropriate and should be immediately taken up.


Which is the most logical idea?

• If an ant were as big as a horse, could it move mountains?

• No. A giant ant . . . . . (select from a,b,c,d)• (a) Would be a structural failure.• (b) Would never be able to move

mountains.• (c) Would be a mere curiosity.• (d) Would never be able to hunt for food.


Solution

• A giant Ant would not be able to move mountains because it is just a curoisity (we are not sure about what could it do). Other options are not logical – as logically we cannot say that it is structural failure or it cannot hunt for food or it cannot move mountains.


Puzzle test…• Nine cricket fans are watching a match in a

stadium. Seated in one row, they are J, K, L, M, N, 0, P, Q and R. L is at the right of M and at third place at the right of N. K is at one end of the row. Q is immediately next to 0 and P. 0 is at the third place at the left of K. J is right next to left of 0.

• Who is sitting in the centre of the row?• (a)L (b)O• (c)J (d)Q


Solution …

• NRMLJOPQK• J IS IN THE CENTRE


A and B start walking in opposite directions. A covers 3 km and B

covers 4 km. Then A turns right and walks 4 km while B turns left and walks 3 km. How far is each from

the starting point?• A is 3 KM in one direction and 4 KM in

right. Applying pythogorus, we find that A is 5 KM from the starting point. Similarly B is also 5 KM from the starting point. Ans.


Ram walks 10 m south from his house, turns left and walks

25 m, again turns left and walks 40 m, then turns right and. walks 5 m

to reach to school. In which direction the schoolis from his house?

• Draw a map and get the answer = north-east.


In a class of 35 students Kiran is placed 7th from the bottom

whereas Sohan is placed 9th from the top. Mohan is placed exactly in between the two. What is Kiran’s

position from Mohan?

• 10th

• From 9th to the top and 7th to the bottom, we have 21 candidates (35-(6+8) ). Mohan is just in the centre. So from Mohan, Kiran is at 10th place. Answer.


A watch reads 4 If the minute hand points towards the East, in which

direction does the hour hand point?

• The hour hand is towards South West.


Puzzle

• Goti and I started walking towards each other from two places lOO m apart. After walking 30m, Goti turns left and goes lO m, then he turns right and goes 20m then turns right again and comes back to the road and starts walking. If we walk with the same speed, what is the distance between us at this point of time


Solution

• (Goti walks 70 meters in all), so I walk 70 meters towards Goti’s starting point and now I am 30 meters from that. Goti takes only 30+20 meters on the road. Thus Goti is 50 meters from my starting point. Thus there is a gap of 20 meters between me and Goti. Answer.


Sum of 1st to 30th terms of a series in arithmetic

progèssion is 150. if the first term is A, what is 30th term of the series?

• Sum = 30/2 (2a + (29)D) = 150• 2a + 29d =150*2/30 = or 29 D = 10 – 2A • 30th term = A + 29D• 29 D = 10 – 2A, putting the value, we get the answer

= 10 – A answer


Question on number system

• Convert 252 into binary system • 252 / 2 = 126 / 2 = 63/2 = 31/2 = 15/2 =

7/2 = 3/2 =1 (starting from last remainder to the first)

• 11111100 answer. • Convert it again to decimal system: • 1*2^7+1*2^6+1*2^5+1*2^4+1*2^3+1*2^2+

0*2^1+0*2^0 = 128+64+32+16+8+4 = 252


Multiply 12 to 13 ( note - both are octal numbers, your outcomes must

also be in octal numbers)?

• Let us first convert them into decimal numbers: 12= 1*8^1 + 2*8^0 =10

• 13 = 1*8^1 + 3*8^0 =11• Now multiply 10 to 11 = 110• Now convert it into octal number: • 110/8 = 13 / 8 • =156 • Test = now convert 156 to decimal number


Convert 156 (octal) to decimal number …..

• 1*8^2 + 5*8^1 + 6*8^0• =64+40+6• =110 answer.


Multiply 5 (base 16) to 12 (base 7) and get the outcome in binary?

• (5*16^0 ) * (1*7^1 +2*7^0) • 5 *9 = 45• 45/2 = 22/2 = 11/2 = 5/2 =2/2 1• =101101 answer.


78.8% of a common medicine for stomach-upsets is absolute alcohol;

3.3% of it is mentha oil; 0.07% spear mint oil; and 0.177%

chloroform. How much of each of these compounds is there in a pack

of 30 ml?solution

alchol = 23.6 ml, 1 ml of menthol oil and so. On.


What is the sum of cubes of the first 5 natural numbers?

• Formula • = [N (N+1)/2 ]^2• = [5*6 / 2 ]^2• =225 answer.


What is the sum of squares of the first 13 natural numbers?

• Formula• =[n(n+1)(2n+1) ] /6• =(13*14*27)/6• =819 answer.


In a Class of 80 pupils, the number of boys is three-fifths the number of girls. Determine the number of girls

in the class.

• Let the number of girls be X• X + 3/5X = 80• 8/5 X = 80• X = 80 *5/8• X = 50 (the number of girls is 50, boys are

30) answer.


The difference between two numbers is 30. On dividing the

greater by the smller the quotient is 3. Find the numbers.

• Let the smaller number be X. • 3X – X = 30• 2X =30; X = 15, • Thus 2 numbers are 15 and 45 answer.


Gunpowder contains 75% nitre and 10% sulphur. The rest of it is

charcoal. What is the amount of charcoal in 9 kg of gunpowder.

• Charcoal is (100 – 75 – 10) = 15% • 9 KG = 9000 Grams • 9000*15/100• =1350 grams answer.


Question on profit

• At what percentage alove the Cost price must an article be marked so as to gain 33% after allowing the customer a discount of 5%?

• (a) 48% (b) 43%• (c) 40% (d) 38%• (e) None of the above


Solution …

• Let the cost be 100• Final price being realised 133• It is after discount, so price before

discount (marked price) is : • 133*100/95 =140 , so 40 is the answer.


A vertical pole PO is standing at the centre 0 of a square ABCD. If AC

subtends an angle 90° at point P of the pole then the angle subtended

by a side of the squareat Pis

(a) 35° (b) 45°(c) 30° (d) 60°

(e) None of the above


Solution

• When diagonal (in a square) makes angle of 90 degree in a pyrimidical shape, then sides make angles of 60 degree. (rule).

• So answer is 60 degrees.


Find the per cent of pure gold in 22 carat gold, if 24 carat gold is cent

per cent pure gold.

• 22/24 *100• =91.67 % answer.


In the diagram the two circles pass through each other’s centre. If the radius of each circle is 2, what is

the perimeter of the region marked B?


Solution

• Permieter of one circle is 2/3 now because, it is being cut by other circle.

• Thus 2/3 + 2/3 of perimeters added : • 2 * 2/3 * (formula of perimeter = 2pi *r)• =(8 * pi * r) /3 answer.


What is angle C?


Solution

• Angle O is double the angle A. Thus it is 100 degree. Thus C is (180 -100)/2 = 40 degrees answer.


What is angle a?


Solution • Angles from D and C are equal . • 180 – 60 – 37 – x• =83 – x• Let us sum up for two angles: • (180+180 ) = 360• 83-x + 83 – x + 180+2X = 360• 2Y +2X = 180 let us assume Y = 53 • 2X = 72 or X = 36 answer (solve by options,

so angle A = 53 ) answer.


ABOUT AFTERSCHO☺OL

Afterschoool conducts three year integrated PGPSE (after class 12th along with IAS / CA / CS) and 18 month PGPSE (Post Graduate Programme in Social Entrepreneurship) along with preparation for CS / CFP / CFA /CMA / FRM. This course is also available online also. It also conducts workshops on social entrepreneurship in schools and colleges all over India – start social entrepreneurship club in your institution today with the help from afterschoool and help us in developing society.


Why such a programme?

• To promote people to take up entrepreneurship and help develop the society

• To enable people to take up franchising and other such options to start a business / social development project

• To enable people to take up social development as their mission

• To enable people to promote spirituality and positive thinking in the world


Who are our supporters?

• Afterschoolians, our past beneficiaries, entrepreneurs and social entrepreneurs are supporting us.

• You can also support us – not necessarily by money – but by being promotor of our concept and our ideas.


About AFTERSCHO☺OL PGPSE – the best programme for developing great

entrepreneurs• Most flexible, adaptive but rigorous programme• Available in distance learning mode• Case study focused- latest cases • Industry oriented practical curriculum• Designed to make you entrepreneurs – not just

an employee• Option to take up part time job – so earn while

you learn • The only absolutely free course on internet


Workshops from AFTERSCHO☺OL

• IIF, Delhi• CIPS, Jaipur• ICSI Hyderabad Branch• Gyan Vihar, Jaipur• Apex Institute of Management, Jaipur• Aravali Institute of Management, Jodhpur• Xavier Institute of Management, Bhubaneshwar • Pacific Institute, Udaipur• Engineering College, Hyderabad


Flexible Specialisations:• Spiritualising business and society• Rural development and transformation• HRD and Education, Social Development• NGO and voluntary work• Investment analysis,microfinance and inclusion • Retail sector, BPO, KPO• Accounting & Information system (with CA / CS /CMA)• Hospital management and Health care• Hospitality sector and culture and heritage• Other sectors of high growth, high technology and social

relevance


Salient features:• The only programme of its kind (in the whole world)• No publicity and low profile course• For those who want to achieve success in life – not just a

degree• Flexible – you may stay for a month and continue the rest of

the education by distance mode. / you may attend weekend classes

• Scholarships for those from poor economic background• Latest and constantly changing curriculum – keeping pace

with the time• Placement for those who are interested• Admissions open throughout the year • Latest and most advanced technologies, books and study

material


Components • Pedagogy curriculum and approach based on IIM Ahmedabad and ISB

Hyderabad (the founder is alumnus from IIMA & ISB Hyderabad)• Meditation, spiritualisation, and self development • EsGotitial softwares for business• Business plan, Research projects• Participation in conferences / seminars• Workshops on leadership, team building etc. • Written submissions of research projects/articles / papers• Interview of entrepreneurs, writing biographies of entrepreneurs• Editing of journals / newsletters• Consultancy / research projects • Assignments, communication skill workshops• Participation in conferences and seminars• Group discussions, mock interviews, self development diaryng • Mind Power Training & writing workshop (by Dr. T.K.Jain)


Pedagogy • Case analysis,• Articles from Harvard Business Review • Quiz, seminars, workshops, games, • Visits to entrepreneurs and industrial visits• PreGotitations, Latest audio-visuals• Group discussions and group projects• Periodic self assessment• Mentoring and counselling• Study exchange programme (with institutions out of

India)• Rural development / Social welfare projects


Branches

• AFTERSCHO☺OL will shortly open its branches in important cities in India including Delhi, Kota, Mumbai, Gurgaon and other important cities. Afterschooolians will be responsible for managing and developing these branches – and for promoting social entrepreneurs.


Case Studies

• We want to write case studies on social entrepreneurs, first generation entrepreneurs, ethical entrepreneurs. Please help us in this process. Help us to be in touch with entrepreneurs, so that we may develop entrepreneurs.


Basic values at AFTERSCHO☺OL

• Share to learn more• Interact to develop yourself• Fear is your worst enemy• Make mistakes to learn • Study & discuss in a group• Criticism is the healthy route to mutual support

and help • Ask fundamental questions : why, when, how &

where?• Embrace change – and compete with yourself

only


www.afterschoool.tk social entrepreneurship for better

society

http://www.afterschoool.tk/

Technology

Management Aptitude Test 17 Nov