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Solving simultaneous equations graphically

Lecture 2.2 graphs ii - solving simult.eqns graphically

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Page 1: Lecture 2.2   graphs ii - solving simult.eqns graphically

Solving simultaneous

equations graphically

Page 2: Lecture 2.2   graphs ii - solving simult.eqns graphically

y = 2x + 1y = 4 - x

Solve the simultaneous equations graphically.

The Question:

Page 3: Lecture 2.2   graphs ii - solving simult.eqns graphically

y = 2x + 1 y = 4 - x

Begin by constructing a table of values:

x

y

y = 2x + 1

-2 0 2 4

Use the equation to fill in the y value when x = -2

-3

Now fill in the rest of the table

1 5 9

Page 4: Lecture 2.2   graphs ii - solving simult.eqns graphically

y = 2x + 1 y = 4 - x

x

y

-2

-3

0

1

2

5

4

9

y = 2x + 1Use the table to draw the graph of the equation.

-4

-2

0

2

4

6

8

10

-3 -2 -1 0 1 2 3 4 5x

y

y = 2x + 1

Page 5: Lecture 2.2   graphs ii - solving simult.eqns graphically

y = 2x + 1 y = 4 - x Now construct a second table of values:

6 4 2

x

y

-2 0 2 4

0

Y = 4 - x

Plot this line on the axes you used earlier...

Page 6: Lecture 2.2   graphs ii - solving simult.eqns graphically

-4

-2

0

2

4

6

8

10

-3 -2 -1 0 1 2 3 4 5x

y

y = 2x + 1

y = 4 - x

The solution is where the 2 lines cross:

Read the x-value from the x-axis...1

Now read off the y-value...3

Page 7: Lecture 2.2   graphs ii - solving simult.eqns graphically

So the solution of y = 2x + 1 and y = 4 - x is...

x = 1 y = 3 and