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Section 7.1 The Law of Sines

Lecture 18 section 7.1 & 7.3 laws of sin & cos

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Page 1: Lecture 18   section 7.1 & 7.3 laws of sin & cos

Section 7.1

The Law of Sines

Page 2: Lecture 18   section 7.1 & 7.3 laws of sin & cos

A

B

Ca

c

b

Page 3: Lecture 18   section 7.1 & 7.3 laws of sin & cos

c

C

b

B

a

A sinsinsin

Answers on next slide.

Page 4: Lecture 18   section 7.1 & 7.3 laws of sin & cos
Page 5: Lecture 18   section 7.1 & 7.3 laws of sin & cos

c

C

b

B

a

A sinsinsin

Solve the triangle: 4,80,45 bCB

45

80A

ac

4Answers on next slide.

Page 6: Lecture 18   section 7.1 & 7.3 laws of sin & cos

Section 7.3

The Law of Cosines

Page 7: Lecture 18   section 7.1 & 7.3 laws of sin & cos

ab

cbaC

ac

bcaB

bc

acbA

2cos

2cos

2cos

222

222

222

A

B

Ca

c

b

Page 8: Lecture 18   section 7.1 & 7.3 laws of sin & cos

8© 2011 Pearson Education, Inc. All rights reserved

EXAMPLE 1 Solving SAS Triangles

Solve triangle ABC with a = 15 inches, b = 10 inches, and C = 60º. Round each answer to the nearest tenth. Solution

Step 1 Find side c opposite the given angle C.

2 2 2

2 22

2

15 110 1

2 cos

2 c 6os

1225 100 2 15 10 175

2

175

0

1

.2

5

3

c

c

c

ba ab C

c

Page 9: Lecture 18   section 7.1 & 7.3 laws of sin & cos

9© 2011 Pearson Education, Inc. All rights reserved

Solution continued

1

sin sin

sinsin

10sin 60°sin

175

10sin 60°sin 40.9°

175

B C

b cb C

Bc

B

B

EXAMPLE 1 Solving the SAS Triangles

Step 2 Find the angle B opposite side b.

Page 10: Lecture 18   section 7.1 & 7.3 laws of sin & cos

10© 2011 Pearson Education, Inc. All rights reserved

Solution continued

EXAMPLE 1 Solving the SAS Triangles

Step 3 Use the angle sum formula to find the third angle.

Step 4 The solution of triangle ABC is

180° 60° 40.9° 79.1°A

A ≈ 79.1° a = 15 inches

B ≈ 40.9° b = 10 inches

C = 60° c ≈ 13.2 inches

Page 11: Lecture 18   section 7.1 & 7.3 laws of sin & cos

Set these up:1. B = 20o a = 10 c = 152. A = 25o b = 3 c = 63. C = 75o a = 5 b = 3

4. B = 45o a = 8 c = 825. A = 60o b = 3 c = 66. C = 30o a = 24 b =

123

Set these up

and solve:

Page 12: Lecture 18   section 7.1 & 7.3 laws of sin & cos

12© 2011 Pearson Education, Inc. All rights reserved

EXAMPLE 3 Solving the SSS Triangles

Solve triangle ABC with a = 3.1 feet, b = 5.4 feet, and c = 7.2 feet. Round answers to the nearest tenth. Solution

Step 1 Because c is the longest side, find C. 2 2 2

2 2 2

2 cos

2 cos

c a b ab C

ab C a b c

2 2 22 2 2 5cos

7.40.39

2

3.1

3.12 5.4

.2cb

ab

aC

1cos 0.39 113°C

Page 13: Lecture 18   section 7.1 & 7.3 laws of sin & cos

13© 2011 Pearson Education, Inc. All rights reserved

Solution continued

sin sinB C

b c

EXAMPLE 3 Solving the SSS Triangles

Step 2 Find B.

1

1

sinsin

sinsin

5.4sin113°sin 43.7°

7.2

b CB

cb C

Bc

Page 14: Lecture 18   section 7.1 & 7.3 laws of sin & cos

14© 2011 Pearson Education, Inc. All rights reserved

Solution continued

Step 3 A ≈ 180º − 43.7º − 113º ≈ 23.3º

Step 4 Write the solution.

EXAMPLE 3 Solving the SSS Triangles

A ≈ 23.3° a = 3.1 feet

B ≈ 43.7° b = 5.4 feet

C ≈ 113° c = 7.2 feet

Page 15: Lecture 18   section 7.1 & 7.3 laws of sin & cos

Example

a=5, b=7, c=8, find cosine of greatest angle.

15© 2011 Pearson Education, Inc. All rights reserved