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MATH 107
Section 5.4
Graphs of the Sine and Cosine Functions
2© 2011 Pearson Education, Inc. All rights reserved
GRAPH OF THE SINE FUNCTIONPlotting y = sin x for common values of x and connecting the points with a smooth curve yields the following:
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GRAPH OF THE COSINE FUNCTIONPlotting y = cos x for common values of x and connecting the points with a smooth curve yields the following:
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KEY POINTS OF THE SINEAND COSINE GRAPHS
***Trigonometric Transformations***
All sine and cosine transformations can be written in the forms:
a* sin[b(x-c)] +d or a* cos[b(x-c)] +d ,
Where a, b, c, and d are numbers used as such:
The amplitude (vertical stretch) = |a|, the period (cycle) = 2 / b, the phase (horizontal) shift = c, and the vertical shift = d.
Example: 7sin(4x-4)-5 = 7sin[4(x-)]-5Amplitude = 7, period = /2, phase shift is units to the right,
vertical shift is 5 units down.
Example: -2cos[(x/3)+1] = -2cos[ (x+3)] Amplitude = 2, graph is flipped over the x-axis (a is negative), period = 6, phase shift is 3 units to the left, no vertical shift.
3
1
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EXAMPLE 2 Graphing y = a sin x
Graph y = 3 sin x, and y = sin x
on the same coordinate system over theinterval [−2π, 2π].
Solution
Begin with the graph of y = sin x and multiply the y-coordinate of each point (including the key points) on this graph by 3 to get the graph of y = 3 sin x.
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This stretches the graph vertically by a factor of 3 without changing the x-intercepts.
Then, multiply the y-coordinate of each
point on the graph of y = sin x by to get
the graph of This compresses the graph.
EXAMPLE 2 Graphing y = a sin x
Solution continued
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EXAMPLE 2 Graphing y = a sin x
Solution continued
x
3x
2 223
2
2
3
3
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EXAMPLE 4 Graphing y = sin bx
Sketch one cycle of the graphs of y = sin 3x,
and y = sin x on the same
coordinate system.
Solution
Begin with the graph of y = sin x and divide
its period, 2π, by 3 to get the period of
y = sin 3x. One cycle of y = sin 3x will be
compressed into the interval
Period: 2 b
*Divide each key x-value by 3 and keep the y-values the same.*
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EXAMPLE 4 Graphing y = sin bxSolution continued
Divide this interval into four equal parts to find the x-coordinates for the key points:
. (y values do not change.)
To find the period of divide 2π by
to get 6π. This yields an interval of [0, 6π]
with these x-coordinates for the key points:
.3
2 and ,
2 ,
3 ,
6 ,0
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EXAMPLE 4 Graphing y = sin bx
Solution continued
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EXAMPLE 5 Graphing y = a cos bx
Graph over a one-period interval.
13cos
2y x
Solution
Amplitude is 3. Period is .
Divide the period, 4π, into four quarters:0 to ππ to 2π2π to 3π3π to 4π
The five endpoints give the highest and lowest points and the x-intercepts of the graph.
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EXAMPLE 5
Solution continued
Graphing y = a cos bx
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EXAMPLE 6 Graphing y = a sin (x – c)
Graph over a one-period
interval.
Solution
The graph of f (x – c) is the graph of f (x) shifted right c units if c > 0 and left |c| units if c < 0.
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EXAMPLE 6 Graphing y = a sin (x – c)
Solution continued
; so the graph of is
the graph of y = sin x shifted right units.
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PROCEDURE FOR GRAPHING y = a sin [b(x – c)] & y = a cos [b(x – c)]
Step 1 Find the amplitude, period, and phase shift.
amplitude = |a| phase shift = c
period =
If c > 0, shift to the right. If c < 0, shift to the left.
Step 2 The cycle begins at x = c. One complete
cycle occurs over the interval .
bcc
2,
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Step 3 Divide the interval into four
equal parts, each of length
. This gives the
x-coordinates for the five key points:
PROCEDURE FOR GRAPHING y = a sin [b(x – c)] AND y = a cos
[b(x – c)]
bcc
2,
b
2
4
1period
4
1
.2
and ,2
4
3 ,
2
2
1 ,
2
4
1 ,
bc
bc
bc
bcc
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PROCEDURE FOR GRAPHING y = a sin [b(x – c)] AND y = a cos
[b(x – c)]
Step 4 If a > 0, for y = a sin [b(x – c)], sketch one cycle of the sine curve through the key
, ,2
c ab
points (c,0), ,0 ,cb
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PROCEDURE FOR GRAPHING y = a sin [b(x – c)] AND y = a cos
[b(x – c)]Step 4 continued
For y = a cos [b(x – c)], sketch one cycle of the cosine curve through the key points
,0 ,2
cb
(c,a),
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PROCEDURE FOR GRAPHING y = a sin b(x – c) AND y = a cos b(x – c) Step 4 continued
For a < 0, reflect the graph ofy = |a| sin b(x – c) or y = |a| cos b(x – c), in the x-axis.
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EXAMPLE 10 Graphing y = a sin b(x – k)
Graph over a one-period interval.
3sin 22
y x
Solution
Rewrite in standard form as
Amplitude = 3
PeriodPhase shift
Starting point
One cycle5
, ,4 4 4 4
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EXAMPLE 10 Graphing y = a sin b(x – k)
Solution continued
1 1period
4 4 4
starting point 4
12nd pt
4 4 2
1 33rd pt
4 2 4
34th pt
4 4
5
end pt 4 4
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EXAMPLE 10 Graphing y = a sin b(x – k)
Solution continued