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University Electromagnetism:Course slides: Part 3: Electromagnetic fields and waves
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1
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ElectromagnetismElectromagnetism
University of TwenteDepartment Applied Physics
First-year course on
Part III: Electromagnetic Waves : SlidesPart III: Electromagnetic Waves : Slides
©F.F.M. de Mul
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Electromagnetic WavesElectromagnetic Waves
• Gauss’ and Faraday’s Laws for E (D)-field• Gauss’ and Maxwell’s Laws for B (H)-field• Maxwell’s Equations and The Wave Equation• Harmonic Solution of the Wave Equation• Plane waves (1): orientation of field vectors• Plane waves (2): complex wave vector• Plane waves (3): the B - E correspondence• The Poynting Vector
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Gauss’ and Faraday’s Laws for Gauss’ and Faraday’s Laws for EE
0
E
div
B
c
dS
Faraday’s Law :
S S Sc
ind rotdt
dV dSEdlEdSB n
dt
drot
BE
E
S V dV VS V
dVdivdV .11
00
EdSE
Gauss’ Law :
Div = micro-flux perunit of volume
Rot = micro-circulationper unit of area
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Gauss’ and Maxwell’s Law for Gauss’ and Maxwell’s Law for BB
SV
dV
B
0. VS
dVdivBdSB
Gauss’ Law :
0Bdiv
j SSL dt
ddSEdSjdlB 000
S
L
Maxwell’s Fix for Ampere’s Law :
dt
drot
EjB 0 00
dt
drot f
DjH
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Maxwell’s Equations and the Maxwell’s Equations and the Wave EquationWave Equation
0
E
dt
dBE 0 B
dt
df
DjH
In vacuum ( = 0 and j = 0):
EEEE 22 )(
This is a 3-Dimensional Wave Equation 00
1
v
v = 2.99… x 108 m/s = light velocity
2
2
002
dt
d EE }2
2
00 dt
d
dt
d EBE
0 E
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Harmonic Solution of the Harmonic Solution of the Wave Equation: Plane WavesWave Equation: Plane Waves
2
2
002
dt
d EE
E may have 3 components: Ex Ey Ez
Choose x-axis // E Ey = Ez = 0(Polarization direction = x-axis).
Does a plane-wave expression for Ex satisfy the wave equation?
Ex = Ex0 exp{i (t-kz)} : Ex0 = amplitude + polarization vector +z-axis = direction of propagation
Insertion into wave equation: k2 = 0 0 2 = 2 / c2
k = / c = 2 / k = wave number ; = wavelength(in 3D-case: k = wave vector )
Analogously: By = By0 exp{i (t-kz)}
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-ik ez .E = 0
-ik ez .H = 0
-ik ez xE = -iH
-ik ez xH = E+iE
Plane waves (1): orientation of fieldsPlane waves (1): orientation of fieldsSuppose: E // x-axis; .. propagation // +z-axis: k // ez
.. Ex = Ex0 exp i (t-kz)
x
zy
EPropag-ation
(1) div E = 0
(2) div B = 0
(3) rot E = - dB/dt
(4) rot H = jf + dD/dtjf = E
Consequences:(1)+(2): E and H ez
(3)+(4): E H
If E chosen // x-axis, then H // y-axis
H
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Plane waves (2): complex wave vectorPlane waves (2): complex wave vector
(1) -ik ez .E = 0(2) -ik ez .H = 0(3) -ik ez xE = -iH(4) -ik ez xH = E+iE
(1)+(2): E and H ez
(3)+(4): E H
Suppose: E // x-axis; .. propagation // +z-axis: k // ez
.. Ex = Ex0 exp i (t-kz)
x
zy
EPropag-ation
H
).(
)(
i
kik
i
ik
EeeHeE zzz ez x ez x E = -E ik2=(+i).
Result: k complex: k = kRe+ ikIm
exp (-ikz) = exp (-ikRe z) . exp (kIm z)}harmonic
}
kIm<0 : absorption >0 : amplification (“laser”)
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Plane waves (3): Plane waves (3): B-EB-E correspondence correspondenceSuppose: E // x-axis; B // y-axis; .. propagation // +z-axis: k // ez
.. Ex = Ex0 exp i (t-kz)
.. By = By0 exp i (t-kz)
x
zy
EPropag-ation
BFaraday: rot E = - dB/dt
0
0
00y
x
dzd
dyd
dxd B
dt
d
E
zyx eeeyxydt
dxdz
d BkEBE 00
000 :Result cBBk
E
Maxwell (for j=0): rot H = dD/dt: similar result
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The Poynting vector The Poynting vector SSDefinition (for free space) : S = E x H
S = (EH) = H(E) - E(H) =
= H(-dB/dt) - E(jf+dD/dt) ft
E
t
BjE
2
20
2
2
0 22
1
Apply Divergence Theorem to integrate over wave surface A:
vv vA
dvdvEB
dt
ddvS )()( 2
00
2
21
fjEdAS
{Change in Electro- magnetic field energy
{
Joule heatinglosses [J/s]
{
Outflux of energy [J/s] = [W]
S = energy outflux per m2 = Intensity [W/m2]
Direction of S : // k
E
Hk
S