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© 2012 Pearson Education, Inc. Lecture by Edward J. Zalisko PowerPoint Lectures for Campbell Biology: Concepts & Connections, Seventh Edition Reece, Taylor, Simon, and Dickey Chapter 10 Chapter 10 Molecular Biology of the Gene

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Page 1: Ch 10 Notes for website

© 2012 Pearson Education, Inc. Lecture by Edward J. Zalisko

PowerPoint Lectures forCampbell Biology: Concepts & Connections, Seventh EditionReece, Taylor, Simon, and Dickey

Chapter 10Chapter 10 Molecular Biology of the Gene

Page 2: Ch 10 Notes for website

Figure 10.0_1

Chapter 10: Big Ideas

The Structure of theGenetic Material

DNA Replication

The Genetics of Virusesand Bacteria

The Flow of GeneticInformation from DNA to

RNA to Protein

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10.1 SCIENTIFIC DISCOVERY: Experiments showed that DNA is the genetic material

Until the 1940s, the case for proteins serving as the genetic material was stronger than the case for DNA.

– Proteins are made from 20 different amino acids.

– DNA was known to be made from just four kinds of nucleotides.

Studies of bacteria and viruses

– ushered in the field of molecular biology, the study of heredity at the molecular level, and

– revealed the role of DNA in heredity.

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10.1 SCIENTIFIC DISCOVERY: Experiments showed that DNA is the genetic material

In 1928, Frederick Griffith discovered that a “transforming factor” could be transferred into a bacterial cell. He found that

– when he exposed heat-killed pathogenic bacteria to harmless bacteria, some harmless bacteria were converted to disease-causing bacteria and

– the disease-causing characteristic was inherited by descendants of the transformed cells.

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Griffith’s experiment

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10.1 SCIENTIFIC DISCOVERY: Experiments showed that DNA is the genetic material

In 1952, Alfred Hershey and Martha Chase used bacteriophages to show that DNA is the genetic material of T2, a virus that infects the bacterium Escherichia coli (E. coli).

– Bacteriophages (or phages for short) are viruses that infect bacterial cells.

– Phages were labeled with radioactive sulfur to detect proteins or radioactive phosphorus to detect DNA.

– Bacteria were infected with either type of labeled phage to determine which substance was injected into cells and which remained outside the infected cell.

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10.1 SCIENTIFIC DISCOVERY: Experiments showed that DNA is the genetic material

– The sulfur-labeled protein stayed with the phages outside the bacterial cell, while the phosphorus-labeled DNA was detected inside cells.

– Cells with phosphorus-labeled DNA produced new bacteriophages with radioactivity in DNA but not in protein.

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Animation: Hershey-Chase Experiment

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Figure 10.1A

Head

Tail

Tail fiber

DNA

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Figure 10.1B

Phage

Bacterium

Batch 2:RadioactiveDNA labeledin green

DNA

Radioactiveprotein

Centrifuge

PhageDNA

Emptyprotein shell

Pellet

The radioactivityis in the liquid.

RadioactiveDNA

Centrifuge

PelletThe radioactivityis in the pellet.

4321

Batch 1:Radioactiveproteinlabeled inyellow

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10.2 DNA and RNA are polymers of nucleotides

DNA and RNA are nucleic acids.

One of the two strands of DNA is a DNA polynucleotide, a nucleotide polymer (chain).

A nucleotide is composed of a

– nitrogenous base,

– five-carbon sugar, and

– phosphate group.

The nucleotides are joined to one another by a sugar-phosphate backbone.

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Each type of DNA nucleotide has a different nitrogen-containing base:

– adenine (A),

– cytosine (C),

– thymine (T), and

– guanine (G).

10.2 DNA and RNA are polymers of nucleotides

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10.2 DNA and RNA are Polymers of Nucleotides

RNA (ribonucleic acid) is unlike DNA in that it

– uses the sugar ribose (instead of deoxyribose in DNA) and

– RNA has the nitrogenous base uracil (U) instead of thymine.

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Watson and Crick reported that DNA consisted of two polynucleotide strands wrapped into a double helix.

– The sugar-phosphate backbone is on the outside.

– The nitrogenous bases are in the interior.

– Specific pairs of bases give the helix a uniform shape.

– A pairs with T, forming two hydrogen bonds, and

– G pairs with C, forming three hydrogen bonds.

10.3 SCIENTIFIC DISCOVERY: DNA is a double-stranded helix

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Figure 10.3D

Base pair

Hydrogen bond

Partial chemicalstructure

Computermodel

Ribbonmodel

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10.4 DNA replication depends on specific base pairing

DNA replication follows a semiconservative model.

– The two DNA strands separate.

– Each strand is used as a pattern to produce a complementary strand, using specific base pairing.

– Each new DNA helix has one old strand with one new strand.

– DNA replication ensures that all the somatic cells in a multicellular organism carry the same genetic information.

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Animation: DNA Replication Overview

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Figure 10.4A_s3

A parentalmoleculeof DNA

A

C

G C

A T

T A

The parental strandsseparate and serve

as templates

Freenucleotides

T A T

T

A

A

T

AG

G GC

C

A T

C G

C

Two identicaldaughter moleculesof DNA are formed

A T A T

A TA T

T A T A

C G C G

G C G C

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Figure 10.4B

Parental DNAmolecule

Daughterstrand

Parentalstrand

Daughter DNAmolecules

A T

G C

A T

A T

T A

T T

A

C

G

C

GC

G

A

T

A

T

G

CT

C G

T

C G

C G

AC

G C

A TA TG C

A T

G

A

A

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DNA replication begins at the origins of replication where

– DNA unwinds at the origin to produce a “bubble,”

– replication proceeds in both directions from the origin, and

– replication ends when products from the bubbles merge with each other.

10.5 DNA replication proceeds in two directions at many sites simultaneously

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Figure 10.5A

ParentalDNAmolecule Origin of

replication

“Bubble”

Parental strand

Daughter strand

TwodaughterDNAmolecules

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DNA replication occurs in the 5 to 3 direction.

– Replication is continuous on the 3 to 5 template.

– Replication is discontinuous on the 5 to 3 template, forming short segments.

10.5 DNA replication proceeds in two directions at many sites simultaneously

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10.5 DNA replication proceeds in two directions at many sites simultaneously

Two key proteins are involved in DNA replication.

1. DNA ligase joins small fragments into a continuous chain.

2. DNA polymerase

– adds nucleotides to a growing chain and

– proofreads and corrects improper base pairings.

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Animation: DNA Replication Review

Animation: Lagging Strand

Animation: Leading Strand

Animation: Origins of Replication

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Figure 10.5C

Overall direction of replication

DNA ligase

Replication fork

Parental DNA

DNA polymerasemolecule This daughter

strand is synthesizedcontinuously

This daughterstrand is synthesizedin pieces

35

35

3

5

35

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10.6 The DNA genotype is expressed as proteins, which provide the molecular basis for phenotypic traits

DNA specifies traits by dictating protein synthesis.

The molecular chain of command is from

– DNA in the nucleus to RNA and

– RNA in the cytoplasm to protein.

Transcription is the synthesis of RNA under the direction of DNA.

Translation is the synthesis of proteins under the direction of RNA.

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Figure 10.6A_s3

DNA

NUCLEUS

CYTOPLASM

RNA

Transcription

Translation

Protein

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10.7 Genetic information written in codons is translated into amino acid sequences

The sequence of nucleotides in DNA provides a code for constructing a protein.

– Protein construction requires a conversion of a nucleotide sequence to an amino acid sequence.

– Transcription rewrites the DNA code into RNA, using the same nucleotide “language.”

– Translation involves switching from the nucleotide “language” to the amino acid “language.”

– Each amino acid is specified by a codon.– 64 codons are possible.

– Some amino acids have more than one possible codon.

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10.9 Transcription produces genetic messages in the form of RNA

Overview of transcription

– An RNA molecule is transcribed from a DNA template by a process that resembles the synthesis of a DNA strand during DNA replication.

– RNA nucleotides are linked by the transcription enzyme RNA polymerase.

– Specific sequences of nucleotides along the DNA mark where transcription begins and ends.

– The “start transcribing” signal is a nucleotide sequence called a promoter.

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Figure 10.8B_s3

T

Strand to be transcribed

A C T T C AA

A A A T

DNAAA T C

T T T T G A G G

RNA

Transcription

A A A A U U U U U G G G

Translation

Polypeptide Met Lys Phe

Stopcodon

Startcodon

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10.9 Transcription produces genetic messages in the form of RNA

– Transcription begins with initiation, as the RNA polymerase attaches to the promoter.

– During the second phase, elongation, the RNA grows longer.

– As the RNA peels away, the DNA strands rejoin.

– Finally, in the third phase, termination, the RNA polymerase reaches a sequence of bases in the DNA template called a terminator, which signals the end of the gene.

– The polymerase molecule now detaches from the RNA molecule and the gene.

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Animation: Transcription

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Figure 10.9A

RNApolymerase

Free RNAnucleotides

Templatestrand of DNA

Newly made RNA

Direction oftranscription

TG

AG G

A

A

U C C AC

T TA

A

CC

GGU

T UTAACCT

A

TC

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Figure 10.9B

RNA polymerase

DNA of gene

PromoterDNA

Initiation1

2

TerminatorDNA

3

Elongation Area shownin Figure 10.9A

TerminationGrowingRNA

RNApolymerase

CompletedRNA

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10.10 Eukaryotic RNA is processed before leaving the nucleus as mRNA

Messenger RNA (mRNA)

– conveys genetic messages from DNA to the translation machinery of the cell

– Eukaryotic mRNA has

– introns, interrupting sequences that separate

– exons, the coding regions.

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10.10 Eukaryotic RNA is processed before leaving the nucleus as mRNA

Eukaryotic mRNA undergoes processing before leaving the nucleus.

– RNA splicing removes introns and joins exons to produce a continuous coding sequence.

– A cap and tail of extra nucleotides are added to the ends of the mRNA

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Figure 10.10

DNA

Cap

Exon Intron Exon

RNAtranscriptwith capand tail

ExonIntron

TranscriptionAddition of cap and tail

Introns removed Tail

Exons spliced together

Coding sequenceNUCLEUS

CYTOPLASM

mRNA

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10.8 The genetic code dictates how codons are translated into amino acids

Characteristics of the genetic code

– Three nucleotides specify one amino acid.

– 61 codons correspond to amino acids.

– AUG codes for methionine and signals the start of transcription.

– 3 “stop” codons signal the end of translation.

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Page 35: Ch 10 Notes for website

Figure 10.8A

Second base

Th

ird

bas

e

Fir

st b

ase

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10.11 Transfer RNA molecules serve as interpreters during translation

Transfer RNA (tRNA)

– converts the genetic message of mRNA into the language of proteins.

Transfer RNA molecules

pick up the appropriate amino acid

using a special triplet of bases, called an anticodon, recognize the appropriate codons in the mRNA.

Translation occurs on the surface of the ribosome.

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Figure 10.12B

tRNA binding sites

mRNA binding site

Large subunit

Small subunit

Psite

Asite

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Figure 10.12C

mRNA

Codons

tRNA

Growingpolypeptide

The next aminoacid to be addedto the polypeptide

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10.13 An initiation codon marks the start of an mRNA message

Translation can be divided into the same three phases as transcription:

1. initiation,

2. elongation, and

3. termination.

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10.13 An initiation codon marks the start of an mRNA message

Initiation establishes where translation will begin.

Initiation occurs in two steps.

1. An mRNA molecule binds to a small ribosomal subunit and the first tRNA binds to mRNA at the start codon.

– The start codon reads AUG and codes for methionine.

– The first tRNA has the anticodon UAC.

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Figure 10.13B

InitiatortRNA

mRNA

Start codon

Smallribosomalsubunit

Largeribosomalsubunit

Psite

Asite

Met

A U G

U A C

2

A U G

U A C

1

Met

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Each cycle of elongation has three steps.

1. Codon recognition: The anticodon of an incoming tRNA molecule, carrying its amino acid, pairs with the mRNA codon in the A site of the ribosome.

2. Peptide bond formation: The new amino acid is joined to the chain.

3. Translocation: tRNA is released from the P site and the ribosome moves tRNA from the A site into the P site.

10.14 Elongation adds amino acids to the polypeptide chain until a stop codon terminates translation

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Page 43: Ch 10 Notes for website

Elongation continues until the termination stage of translation, when– the ribosome reaches a stop codon,

– the completed polypeptide is freed from the last tRNA,

10.14 Elongation adds amino acids to the polypeptide chain until a stop codon terminates translation

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Animation: Translation

Page 44: Ch 10 Notes for website

Figure 10.14_s4

Polypeptide

mRNA

Codon recognition

Anticodon

Aminoacid

Codons

Psite

Asite

1

Peptide bond2

formation

Translocation3

Newpeptidebond

Stopcodon

mRNAmovement

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Figure 10.15

DNATranscription

mRNARNApolymerase

Transcription

Translation

Amino acid

Enzyme

CYTOPLASM

Amino acidattachment

2

1

3

4

tRNA

ATP

Anticodon

Initiation ofpolypeptide synthesis

Elongation

Largeribosomalsubunit

InitiatortRNA

Start Codon

mRNA

Growingpolypeptide

Smallribosomalsubunit

New peptidebond forming

Codons

mRNA

Polypeptide

Termination5

Stop codon

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10.16 Mutations can change the meaning of genes

A mutation is any change in the nucleotide sequence of DNA.

Mutations can involve

– large chromosomal regions or

– just a single nucleotide pair.

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10.16 Mutations can change the meaning of genes

Mutations within a gene can be divided into two general categories.

1. Base substitutions involve the replacement of one nucleotide with another. Base substitutions may

– have no effect at all, producing a silent mutation,

– change the amino acid coding, producing a missense mutation, which produces a different amino acid,

– lead to a base substitution that produces an improved protein that enhances the success of the mutant organism and its descendant, or

– change an amino acid into a stop codon, producing a nonsense mutation.

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Page 48: Ch 10 Notes for website

Figure 10.16A

Normal hemoglobin DNA Mutant hemoglobin DNA

mRNA mRNA

Sickle-cell hemoglobinNormal hemoglobin

Glu Val

C T T

G A A

C T

G A

A

U

Page 49: Ch 10 Notes for website

10.16 Mutations can change the meaning of genes

2. Mutations can result in deletions or insertions that may

– alter the reading frame (triplet grouping) of the mRNA, so that nucleotides are grouped into different codons,

– lead to significant changes in amino acid sequence downstream of the mutation, and

– produce a nonfunctional polypeptide.

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10.16 Mutations can change the meaning of genes

Mutations can be caused by

– spontaneous errors that occur during DNA replication or recombination or

– mutagens, which include

– high-energy radiation such as X-rays and ultraviolet light and

– chemicals.

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Page 51: Ch 10 Notes for website

Figure 10.16B

Normalgene

Nucleotidesubstitution

Nucleotidedeletion

Nucleotideinsertion

Inserted

Deleted

mRNAProtein Met

Met

Lys Phe

Lys Phe

Ala

Ala

Gly

Ser

A U G A A G U U U G G C G C A

G C G C AAG U U UA U G A A

Met Lys Ala HisLeu

G U UA U G A A G G C G C A U

U

Met Lys Ala HisLeu

G U UA U G A A G G CU G G C

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Viruses are not generally considered alive because they

– are not cellular and

– cannot reproduce on their own.

Viruses

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10.17 Viral DNA may become part of the host chromosome

A virus is essentially “genes in a box,” an infectious particle consisting of

– a bit of nucleic acid,

– wrapped in a protein coat called a capsid

– Viruses have two types of reproductive cycles.

1. In the lytic cycle,

– viral particles are produced using host cell components,

– the host cell lyses, and

– viruses are released.© 2012 Pearson Education, Inc.

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10.17 Viral DNA may become part of the host chromosome

2. In the Lysogenic cycle

– Viral DNA is inserted into the host chromosome by recombination.

– Viral DNA is duplicated along with the host chromosome during each cell division.

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Animation: Phage Lambda Lysogenic and Lytic Cycles

Page 55: Ch 10 Notes for website

The cell lyses,releasingphages

Figure 10.17_1

Phage

Attachesto cell

Phage DNA

The phage injects its DNA

Lytic cycle

The phage DNAcircularizes

1

New phage DNA andproteins are synthesized

Phages assemble 2

3

4

Bacterialchromosome

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Figure 10.17_2

Phage

Attachesto cell

Phage DNA Bacterialchromosome

The phage injects its DNA

The phage DNAcircularizes

Environmentalstress

Many celldivisions

The lysogenic bacteriumreplicates normally, copying theprophage at each cell division

Prophage

Phage DNA inserts into the bacterialchromosome by recombination

Lysogenic cycle

1

2

7

6

5

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10.19 EVOLUTION CONNECTION: Emerging viruses threaten human health

Viruses that appear suddenly or are new to medical scientists are called emerging viruses. These include the

– AIDS virus,

– Ebola virus,

– West Nile virus, and

– SARS virus.

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10.19 EVOLUTION CONNECTION: Emerging viruses threaten human health

Three processes contribute to the emergence of viral diseases:

1. mutation—RNA viruses mutate rapidly.

2. contact between species—viruses from other animals spread to humans.

3. spread from isolated human populations to larger human populations, often over great distances.

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Page 59: Ch 10 Notes for website

10.22 Bacteria can transfer DNA in three ways

Bacteria are also valuable.

– Bacterial DNA is found in a single, closed loop, chromosome.

– Bacterial cells divide by replication of the bacterial chromosome and then by binary fission.

– Because binary fission is an asexual process, bacteria in a colony are genetically identical to the parent cell.

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Page 60: Ch 10 Notes for website

Figure 10.22D

Donated DNA Crossovers Degraded DNA

Recombinantchromosome

Recipient cell’schromosome

Page 61: Ch 10 Notes for website

1. Describe the experiments of Griffith, Hershey, and Chase, which supported the idea that DNA was life’s genetic material.

2. Compare the structures of DNA and RNA.

3. Explain how the structure of DNA facilitates its replication.

4. Describe the process of DNA replication.

5. Describe the locations, reactants, and products of transcription and translation.

6. Explain how the “languages” of DNA and RNA are used to produce polypeptides.

7. Explain how mRNA is produced using DNA.

8. Explain how eukaryotic RNA is processed before leaving the nucleus.

9. Relate the structure of tRNA to its functions in the process of translation.

10. Describe the structure and function of ribosomes.

11. Describe the step-by-step process by which amino acids are added to a growing polypeptide chain.

12. Diagram the overall process of transcription and translation.

13. Describe the major types of mutations, causes of mutations, and potential consequences.

14. Compare the lytic and lysogenic reproductive cycles of a phage.

15. Describe three processes that contribute to the emergence of viral disease.

16. Define a plasmid

You should now be able to

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