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Quadratics and Polynomials Perfect Square Difference of two squares

05 perfect square, difference of two squares

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Quadratics and Polynomials

Perfect Square

Difference of two squares

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Remember Expanding and factorising

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What is a perfect square?

A perfect square is a number which can be

expressed as a square:

9 (because 32 = 9)

16 (because 42 = 16)

81 (because 92 = 81)

We could also use expressions!

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Perfect Square

Therefore, any expression, such as:

a2

(a+b)2

(k-h)2

Is a perfect square!!!

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Why is this helpful?

Try expanding this perfect square:

(c + d)2 = (c + d)(c + d) (now the Distribution Law)

= c2 + cd + dc + d2 (Commutative Law: ab = ba)

= c2 + cd + cd + d2

= c2 + 2cd + d2

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What ?!?

That doesn’t look like a quadratic!

OK, expand:

(x+7)2

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x2 + 14x +49

So, if you see a quadratic that could be

factorised using Perfect Squares, use it!

x2 + 2x + 1 = …

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Perfect Squares are helpful!

Particularly when working with areas:

This is a perfect square:

Area of a square? A = x2

x

x

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How to find an area of a square with sides: (a + b)

We use perfect squares in optimisation

problems. How to find a maximum area

covered by the (a+b) square:

(or – how to find an area when you add a slice

of size b to the square a)

ab

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ab

a + b

???

???

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a + b (side width)

ab

aba2

b2

So, the area of the entire shape is a sum of

individual areas of each shape…

Area of a square with side a+b=

Area of a square = its side squared (a+b)2

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ab

ab

a2

b2

a + b (side width)

Area:

(a+b)2 = a2 + 2ab + b2

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(a+b)2 = a2 + 2ab + b2

This is the general model for expanding a

perfect square. It means that we can expand

them very easily.

e.g. (x + 3)2 = x2 + 2*3*x + 32

= x2 + 6x + 9

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Try these

Try these

1) (x + 2)2 =

2) (x + 4)2 =

3) (x + 1)2 =

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Application Problem

• A quadrangle has one side four units longer

than the other. Its area is 60 square units.

What are the dimensions of the quadrangle?

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If we denote the length of one side of the

quadrangle as x units, then the other

must be x + 4 units in length.

We must solve the equation: x *( x+4) =

60, which is equivalent to solving the

quadratic equation:

x2 + 4x -60 = 0

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What about negative?

What about when there is a negative square?

e.g. (x - 3)2

Can our area model still work? How would

we label it?

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(x-3)2

What does it mean: reduce square x by a slice

of size 3.x

a

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Difference of two squares

• One Square: x2

• Second Square: 42

• Difference: subtraction

• Difference of two squares:

x2 – 4

Factorise?

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Factorise

x2 – 4 = 0

x2 = 4

x1,2 = √4

x1,2 = ± 2

x1 = 2, x2 = -2

Hence:

x2 – 4 = (x-2)(x+2)