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STANDING WAVES ON VIOLIN STRINGS

Standing waves

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Page 1: Standing waves

STANDING WAVESONVIOLIN STRINGS

Page 2: Standing waves

STANDING WAVES• Are stationary (as opposed to travelling waves)

• Vs

STANDING WAVE TRAVELLING WAVE

Page 3: Standing waves

STANDING WAVES

• Are the superposition of two harmonic waves with equal amplitude, frequency and wavelengths but moving in opposite direction

v

v

Resulting Standing Wave from adding the two harmonic waves

Page 4: Standing waves

STANDING WAVES• Can be generated by plucking a string with

both ends fixed• Nodes are points with zero amplitudes• Antinodes are points with maximum

amplitudes

Page 5: Standing waves

STANDING WAVES ON STRINGS• Strings with two fixed ends can only produce

standing waves with an integral number of half wavelength called normal modes• =

where L = string length n = number of antinodes = 1, 2, 3, 4, …

• The fundamental frequency (1st harmonic) is the lowest frequency (longest wavelength)• =

where T = tension in the string = linear mass density of the string =

• The allowed frequencies are called harmonics• = n n = 1, 2, 3, 4, …

Page 6: Standing waves

QUESTION PART 1Tom wants to make a violin for his sister as a birthday present. Violins usually make sound frequencies ranging from 200~3000Hz. He has a few 30 cm long strings with linear mass densities:A 2.8 kg/m B 4.0 kg/mC 0.62 g/mWhich string should he use to make the violin in order to get a fundamental frequency of 700Hz if the tension in the string is kept at 70 N?

Page 7: Standing waves

Hints

• What variables are given in the question?• The fundamental frequency (), tension (T), and string length (L)

Page 8: Standing waves

Hints

• What variables are given in the question?• The fundamental frequency (), tension (T), and string length (L)

• Which equation to use when solving for linear mass density?• =

where T = tension in the string = linear mass density of the string =

Page 9: Standing waves

Solution — Tom should use string B = 700 Hz T = 70 N L = 30 cm = 0.30 m = Solve for

= = = = 3.97 kg/ m 4.0 kg/m

Page 10: Standing waves

QUESTION PART 2

The violin string broke after a few weeks, but Tom doesn’t have anymore of the same string. If he uses a string with linear mass density of 4.7 kg/m, what should the tension be in the string in order to produce the same sound frequency (700 Hz)?

Page 11: Standing waves

Hints

•What variables are given in the question?• The fundamental frequency (), linear mass density (), and

string length (L)

Page 12: Standing waves

Hints

•What variables are given in the question?• The fundamental frequency (), linear mass density (), and

string length (L)•Which equation to use when solving for tension?• =

where T = tension in the string = linear mass density of the string =

Page 13: Standing waves

Solution = 700 Hz = 4.7 kg/m L = 30 cm = 0.30 m = Solve for T

= T = = 4.7 kg/m = 82.9 N 83 N

Page 14: Standing waves

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