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Fluid Mechanics and Thermodynamics Weekly Assessed Tutorial Sheets, Student Sheets: WATS 5 The WATS approach to assessment was developed as part of an LTSN Engineering Mini-Project, funded at the University of Hertfordshire which aimed to develop a set of 'student unique' tutorial sheets to actively encourage and improve student participation within a first year first ‘fluid mechanics and thermodynamics’ module. Please see the accompanying Mini-Project Report “Improving student success and retention through greater participation and tackling student-unique tutorial sheets” for more information. The WATS cover core Fluid Mechanics and Thermodynamics topics at first year undergraduate level. 11 tutorial sheets and their worked solutions are provided here for you to utilise in your teaching. The variables within each question can be altered so that each student answers the same question but will need to produce a unique solution. FURTHER INFORMATION Please see http://tinyurl.com/2wf2lfh to access the WATS Random Factor Generating Wizard. There are also explanatory videos on how to use the Wizard and how to implement WATS available at © University of Hertfordshire 2009 This work is licensed under a Creative Commons Attribution 2.0 License .

WATS 5 (1-50) Fluid Mechanics and Thermodynamics

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The WATS approach to assessment was developed as part of an LTSN Engineering Mini-Project, funded at the University of Hertfordshire which aimed to develop a set of 'student unique' tutorial sheets to actively encourage and improve student participation within a first year first ‘fluid mechanics and thermodynamics’ module. Please see the accompanying Mini-Project Report “Improving student success and retention through greater participation and tackling student-unique tutorial sheets” for more information. The WATS cover core Fluid Mechanics and Thermodynamics topics at first year undergraduate level. 11 tutorial sheets and their worked solutions are provided here for you to utilise in your teaching. The variables within each question can be altered so that each student answers the same question but will need to produce a unique solution. What follows is a set of STUDENT UNIQUE SHEETS for WATS 5.

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Page 1: WATS 5 (1-50) Fluid Mechanics and Thermodynamics

Fluid Mechanics and ThermodynamicsWeekly Assessed Tutorial Sheets,

Student Sheets: WATS 5

The WATS approach to assessment was developed as part of an LTSN Engineering Mini-Project, funded at the University of Hertfordshire which aimed to develop a set of 'student unique' tutorial sheets to actively encourage and improve student participation within a first year first ‘fluid mechanics and thermodynamics’ module. Please see the accompanying Mini-Project Report “Improving student success and retention through greater participation and tackling student-unique tutorial sheets” for more information.

The WATS cover core Fluid Mechanics and Thermodynamics topics at first year undergraduate level. 11 tutorial sheets and their worked solutions are provided here for you to utilise in your teaching. The variables within each question can be altered so that each student answers the same question but will need to produce a unique solution.

FURTHER INFORMATION

Please see http://tinyurl.com/2wf2lfh to access the WATS Random Factor Generating Wizard.

There are also explanatory videos on how to use the Wizard and how to implement WATS available at http://www.youtube.com/user/MBRBLU#p/u/7/0wgC4wy1cV0 and http://www.youtube.com/user/MBRBLU#p/u/6/MGpueiPHpqk.

For more information on WATS, its use and impact on students please contact Mark Russell, School of Aerospace, Automotive and Design Engineering at University of Hertfordshire.

© University of Hertfordshire 2009 This work is licensed under a Creative Commons Attribution 2.0 License.

Page 2: WATS 5 (1-50) Fluid Mechanics and Thermodynamics

Fluid Mechanics and Thermodynamics.Weekly Assessed Tutorial Sheet 5.

Student Number 1

Name

Hand out date Hand in date

Q1. Given the table below calculate –

i) the density (kg/m3) of air at 16.00°C (3dp) (1 mark)ii) the dynamic viscosity (N s /m2) of air at 9.80°C (9dp) (1 mark)iii) the kinematic viscosity (m2/s) of air at 11.00°C (9dp) (1 mark)iv) the density (kg/m3) of air at 4.70°C (3dp) (1 mark)v) the dynamic viscosity (N s /m2)of air at 13.40°C (9dp) (1 mark)vi) the kinematic viscosity (m2/s) of air at 7.40°C (9dp) (1 mark)vii) the air temperature (ºC) when its density is 1.268kg/m3 (2dp) (1 mark)viii) the air temperature (ºC) when its dynamic viscosity is 18.00 x 10-6 N s/m2 (2dp)

(1 mark)

Table 1. Properties of air at standard sea level atmospheric conditions.Temperature (°C) Density (kg/m3) Dynamic Viscosity (10-6 N s/m2)

0 1.293 17.110 1.248 17.620 1.205 18.130 1.165 18.6

Q2. If Calculate C when - i) AB = constant, A1 = 265750, B1= 4.10 and A2 = 273000 (1dp) (1 mark)ii) AB1.40 = constant, A1 = 240500.00, B1= 9.00 and A2 = 449250 (1dp) (1 mark)iii) A = constant = 356750.00, B1= 8.00 and B2 = 9.20 (1dp) (1 mark)iv) B = constant = 2.00, A1= 326500 and A2 = 469000 (1dp) (1 mark)

WATS 5. Student number 1

Page 3: WATS 5 (1-50) Fluid Mechanics and Thermodynamics

Fluid Mechanics and Thermodynamics.Weekly Assessed Tutorial Sheet 5.

Student Number 2

Name

Hand out date Hand in date

Q1. Given the table below calculate –

i) the density (kg/m3) of air at 8.70°C (3dp) (1 mark)ii) the dynamic viscosity (N s /m2) of air at 4.60°C (9dp) (1 mark)iii) the kinematic viscosity (m2/s) of air at 10.60°C (9dp) (1 mark)iv) the density (kg/m3) of air at 12.90°C (3dp) (1 mark)v) the dynamic viscosity (N s /m2)of air at 4.90°C (9dp) (1 mark)vi) the kinematic viscosity (m2/s) of air at 17.60°C (9dp) (1 mark)vii) the air temperature (ºC) when its density is 1.291kg/m3 (2dp) (1 mark)viii) the air temperature (ºC) when its dynamic viscosity is 18.40 x 10-6 N s/m2 (2dp)

(1 mark)

Table 1. Properties of air at standard sea level atmospheric conditions.Temperature (°C) Density (kg/m3) Dynamic Viscosity (10-6 N s/m2)

0 1.293 17.110 1.248 17.620 1.205 18.130 1.165 18.6

Q2. If Calculate C when - i) AB = constant, A1 = 109750, B1= 7.20 and A2 = 436250 (1dp) (1 mark)ii) AB1.20 = constant, A1 = 133500.00, B1= 5.10 and A2 = 362250 (1dp) (1 mark)iii) A = constant = 138250.00, B1= 5.40 and B2 = 4.30 (1dp) (1 mark)iv) B = constant = 8.80, A1= 165750 and A2 = 89000 (1dp) (1 mark)

WATS 5. Student number 2

Page 4: WATS 5 (1-50) Fluid Mechanics and Thermodynamics

Fluid Mechanics and Thermodynamics.Weekly Assessed Tutorial Sheet 5.

Student Number 3

Name

Hand out date Hand in date

Q1. Given the table below calculate –

i) the density (kg/m3) of air at 23.20°C (3dp) (1 mark)ii) the dynamic viscosity (N s /m2) of air at 3.10°C (9dp) (1 mark)iii) the kinematic viscosity (m2/s) of air at 17.80°C (9dp) (1 mark)iv) the density (kg/m3) of air at 2.20°C (3dp) (1 mark)v) the dynamic viscosity (N s /m2)of air at 18.00°C (9dp) (1 mark)vi) the kinematic viscosity (m2/s) of air at 15.00°C (9dp) (1 mark)vii) the air temperature (ºC) when its density is 1.208kg/m3 (2dp) (1 mark)viii) the air temperature (ºC) when its dynamic viscosity is 18.40 x 10-6 N s/m2 (2dp)

(1 mark)

Table 1. Properties of air at standard sea level atmospheric conditions.Temperature (°C) Density (kg/m3) Dynamic Viscosity (10-6 N s/m2)

0 1.293 17.110 1.248 17.620 1.205 18.130 1.165 18.6

Q2. If Calculate C when - i) AB = constant, A1 = 192250, B1= 8.70 and A2 = 88000 (1dp) (1 mark)ii) AB1.30 = constant, A1 = 425750.00, B1= 2.50 and A2 = 230500 (1dp) (1 mark)iii) A = constant = 94750.00, B1= 1.70 and B2 = 4.70 (1dp) (1 mark)iv) B = constant = 4.60, A1= 332000 and A2 = 454750 (1dp) (1 mark)

WATS 5. Student number 3

Page 5: WATS 5 (1-50) Fluid Mechanics and Thermodynamics

Fluid Mechanics and Thermodynamics.Weekly Assessed Tutorial Sheet 5.

Student Number 4

Name

Hand out date Hand in date

Q1. Given the table below calculate –

i) the density (kg/m3) of air at 22.80°C (3dp) (1 mark)ii) the dynamic viscosity (N s /m2) of air at 20.70°C (9dp) (1 mark)iii) the kinematic viscosity (m2/s) of air at 8.10°C (9dp) (1 mark)iv) the density (kg/m3) of air at 25.00°C (3dp) (1 mark)v) the dynamic viscosity (N s /m2)of air at 29.70°C (9dp) (1 mark)vi) the kinematic viscosity (m2/s) of air at 17.50°C (9dp) (1 mark)vii) the air temperature (ºC) when its density is 1.256kg/m3 (2dp) (1 mark)viii) the air temperature (ºC) when its dynamic viscosity is 18.10 x 10-6 N s/m2 (2dp)

(1 mark)

Table 1. Properties of air at standard sea level atmospheric conditions.Temperature (°C) Density (kg/m3) Dynamic Viscosity (10-6 N s/m2)

0 1.293 17.110 1.248 17.620 1.205 18.130 1.165 18.6

Q2. If Calculate C when - i) AB = constant, A1 = 145250, B1= 1.30 and A2 = 172000 (1dp) (1 mark)ii) AB1.30 = constant, A1 = 178750.00, B1= 7.00 and A2 = 173750 (1dp) (1 mark)iii) A = constant = 137250.00, B1= 8.00 and B2 = 6.60 (1dp) (1 mark)iv) B = constant = 6.20, A1= 379000 and A2 = 249750 (1dp) (1 mark)

WATS 5. Student number 4

Page 6: WATS 5 (1-50) Fluid Mechanics and Thermodynamics

Fluid Mechanics and Thermodynamics.Weekly Assessed Tutorial Sheet 5.

Student Number 5

Name

Hand out date Hand in date

Q1. Given the table below calculate –

i) the density (kg/m3) of air at 21.20°C (3dp) (1 mark)ii) the dynamic viscosity (N s /m2) of air at 5.60°C (9dp) (1 mark)iii) the kinematic viscosity (m2/s) of air at 17.30°C (9dp) (1 mark)iv) the density (kg/m3) of air at 0.70°C (3dp) (1 mark)v) the dynamic viscosity (N s /m2)of air at 26.60°C (9dp) (1 mark)vi) the kinematic viscosity (m2/s) of air at 24.40°C (9dp) (1 mark)vii) the air temperature (ºC) when its density is 1.251kg/m3 (2dp) (1 mark)viii) the air temperature (ºC) when its dynamic viscosity is 18.00 x 10-6 N s/m2 (2dp)

(1 mark)

Table 1. Properties of air at standard sea level atmospheric conditions.Temperature (°C) Density (kg/m3) Dynamic Viscosity (10-6 N s/m2)

0 1.293 17.110 1.248 17.620 1.205 18.130 1.165 18.6

Q2. If Calculate C when - i) AB = constant, A1 = 487750, B1= 4.70 and A2 = 413000 (1dp) (1 mark)ii) AB1.20 = constant, A1 = 175500.00, B1= 2.90 and A2 = 152750 (1dp) (1 mark)iii) A = constant = 146250.00, B1= 3.70 and B2 = 8.60 (1dp) (1 mark)iv) B = constant = 5.60, A1= 117250 and A2 = 455500 (1dp) (1 mark)

WATS 5. Student number 5

Page 7: WATS 5 (1-50) Fluid Mechanics and Thermodynamics

Fluid Mechanics and Thermodynamics.Weekly Assessed Tutorial Sheet 5.

Student Number 6

Name

Hand out date Hand in date

Q1. Given the table below calculate –

i) the density (kg/m3) of air at 12.40°C (3dp) (1 mark)ii) the dynamic viscosity (N s /m2) of air at 14.10°C (9dp) (1 mark)iii) the kinematic viscosity (m2/s) of air at 27.90°C (9dp) (1 mark)iv) the density (kg/m3) of air at 28.50°C (3dp) (1 mark)v) the dynamic viscosity (N s /m2)of air at 28.40°C (9dp) (1 mark)vi) the kinematic viscosity (m2/s) of air at 17.40°C (9dp) (1 mark)vii) the air temperature (ºC) when its density is 1.261kg/m3 (2dp) (1 mark)viii) the air temperature (ºC) when its dynamic viscosity is 18.00 x 10-6 N s/m2 (2dp)

(1 mark)

Table 1. Properties of air at standard sea level atmospheric conditions.Temperature (°C) Density (kg/m3) Dynamic Viscosity (10-6 N s/m2)

0 1.293 17.110 1.248 17.620 1.205 18.130 1.165 18.6

Q2. If Calculate C when - i) AB = constant, A1 = 327000, B1= 4.40 and A2 = 421500 (1dp) (1 mark)ii) AB1.40 = constant, A1 = 102500.00, B1= 7.00 and A2 = 104500 (1dp) (1 mark)iii) A = constant = 232250.00, B1= 7.10 and B2 = 4.00 (1dp) (1 mark)iv) B = constant = 1.50, A1= 382750 and A2 = 296750 (1dp) (1 mark)

WATS 5. Student number 6

Page 8: WATS 5 (1-50) Fluid Mechanics and Thermodynamics

Fluid Mechanics and Thermodynamics.Weekly Assessed Tutorial Sheet 5.

Student Number 7

Name

Hand out date Hand in date

Q1. Given the table below calculate –

i) the density (kg/m3) of air at 23.70°C (3dp) (1 mark)ii) the dynamic viscosity (N s /m2) of air at 12.80°C (9dp) (1 mark)iii) the kinematic viscosity (m2/s) of air at 24.20°C (9dp) (1 mark)iv) the density (kg/m3) of air at 11.60°C (3dp) (1 mark)v) the dynamic viscosity (N s /m2)of air at 25.20°C (9dp) (1 mark)vi) the kinematic viscosity (m2/s) of air at 3.70°C (9dp) (1 mark)vii) the air temperature (ºC) when its density is 1.218kg/m3 (2dp) (1 mark)viii) the air temperature (ºC) when its dynamic viscosity is 17.40 x 10-6 N s/m2 (2dp)

(1 mark)

Table 1. Properties of air at standard sea level atmospheric conditions.Temperature (°C) Density (kg/m3) Dynamic Viscosity (10-6 N s/m2)

0 1.293 17.110 1.248 17.620 1.205 18.130 1.165 18.6

Q2. If Calculate C when - i) AB = constant, A1 = 76750, B1= 1.40 and A2 = 189750 (1dp) (1 mark)ii) AB1.20 = constant, A1 = 184000.00, B1= 7.30 and A2 = 253500 (1dp) (1 mark)iii) A = constant = 388500.00, B1= 1.40 and B2 = 1.00 (1dp) (1 mark)iv) B = constant = 6.30, A1= 494250 and A2 = 336500 (1dp) (1 mark)

WATS 5. Student number 7

Page 9: WATS 5 (1-50) Fluid Mechanics and Thermodynamics

Fluid Mechanics and Thermodynamics.Weekly Assessed Tutorial Sheet 5.

Student Number 8

Name

Hand out date Hand in date

Q1. Given the table below calculate –

i) the density (kg/m3) of air at 28.80°C (3dp) (1 mark)ii) the dynamic viscosity (N s /m2) of air at 22.50°C (9dp) (1 mark)iii) the kinematic viscosity (m2/s) of air at 12.20°C (9dp) (1 mark)iv) the density (kg/m3) of air at 26.90°C (3dp) (1 mark)v) the dynamic viscosity (N s /m2)of air at 13.60°C (9dp) (1 mark)vi) the kinematic viscosity (m2/s) of air at 16.10°C (9dp) (1 mark)vii) the air temperature (ºC) when its density is 1.277kg/m3 (2dp) (1 mark)viii) the air temperature (ºC) when its dynamic viscosity is 17.80 x 10-6 N s/m2 (2dp)

(1 mark)

Table 1. Properties of air at standard sea level atmospheric conditions.Temperature (°C) Density (kg/m3) Dynamic Viscosity (10-6 N s/m2)

0 1.293 17.110 1.248 17.620 1.205 18.130 1.165 18.6

Q2. If Calculate C when - i) AB = constant, A1 = 258500, B1= 4.60 and A2 = 496250 (1dp) (1 mark)ii) AB1.20 = constant, A1 = 139000.00, B1= 3.20 and A2 = 322250 (1dp) (1 mark)iii) A = constant = 51000.00, B1= 4.70 and B2 = 1.40 (1dp) (1 mark)iv) B = constant = 4.50, A1= 121250 and A2 = 197250 (1dp) (1 mark)

WATS 5. Student number 8

Page 10: WATS 5 (1-50) Fluid Mechanics and Thermodynamics

Fluid Mechanics and Thermodynamics.Weekly Assessed Tutorial Sheet 5.

Student Number 9

Name

Hand out date Hand in date

Q1. Given the table below calculate –

i) the density (kg/m3) of air at 1.80°C (3dp) (1 mark)ii) the dynamic viscosity (N s /m2) of air at 24.60°C (9dp) (1 mark)iii) the kinematic viscosity (m2/s) of air at 14.80°C (9dp) (1 mark)iv) the density (kg/m3) of air at 24.70°C (3dp) (1 mark)v) the dynamic viscosity (N s /m2)of air at 24.60°C (9dp) (1 mark)vi) the kinematic viscosity (m2/s) of air at 22.00°C (9dp) (1 mark)vii) the air temperature (ºC) when its density is 1.175kg/m3 (2dp) (1 mark)viii) the air temperature (ºC) when its dynamic viscosity is 18.00 x 10-6 N s/m2 (2dp)

(1 mark)

Table 1. Properties of air at standard sea level atmospheric conditions.Temperature (°C) Density (kg/m3) Dynamic Viscosity (10-6 N s/m2)

0 1.293 17.110 1.248 17.620 1.205 18.130 1.165 18.6

Q2. If Calculate C when - i) AB = constant, A1 = 171750, B1= 4.50 and A2 = 254750 (1dp) (1 mark)ii) AB1.20 = constant, A1 = 143250.00, B1= 6.90 and A2 = 72750 (1dp) (1 mark)iii) A = constant = 455000.00, B1= 9.60 and B2 = 3.00 (1dp) (1 mark)iv) B = constant = 9.60, A1= 344500 and A2 = 84750 (1dp) (1 mark)

WATS 5. Student number 9

Page 11: WATS 5 (1-50) Fluid Mechanics and Thermodynamics

Fluid Mechanics and Thermodynamics.Weekly Assessed Tutorial Sheet 5.

Student Number 10

Name

Hand out date Hand in date

Q1. Given the table below calculate –

i) the density (kg/m3) of air at 10.90°C (3dp) (1 mark)ii) the dynamic viscosity (N s /m2) of air at 3.30°C (9dp) (1 mark)iii) the kinematic viscosity (m2/s) of air at 4.10°C (9dp) (1 mark)iv) the density (kg/m3) of air at 6.70°C (3dp) (1 mark)v) the dynamic viscosity (N s /m2)of air at 12.40°C (9dp) (1 mark)vi) the kinematic viscosity (m2/s) of air at 29.50°C (9dp) (1 mark)vii) the air temperature (ºC) when its density is 1.226kg/m3 (2dp) (1 mark)viii) the air temperature (ºC) when its dynamic viscosity is 18.10 x 10-6 N s/m2 (2dp)

(1 mark)

Table 1. Properties of air at standard sea level atmospheric conditions.Temperature (°C) Density (kg/m3) Dynamic Viscosity (10-6 N s/m2)

0 1.293 17.110 1.248 17.620 1.205 18.130 1.165 18.6

Q2. If Calculate C when - i) AB = constant, A1 = 329000, B1= 6.30 and A2 = 100750 (1dp) (1 mark)ii) AB1.30 = constant, A1 = 493500.00, B1= 3.20 and A2 = 121750 (1dp) (1 mark)iii) A = constant = 176750.00, B1= 4.50 and B2 = 5.70 (1dp) (1 mark)iv) B = constant = 9.60, A1= 156500 and A2 = 114250 (1dp) (1 mark)

WATS 5. Student number 10

Page 12: WATS 5 (1-50) Fluid Mechanics and Thermodynamics

Fluid Mechanics and Thermodynamics.Weekly Assessed Tutorial Sheet 5.

Student Number 11

Name

Hand out date Hand in date

Q1. Given the table below calculate –

i) the density (kg/m3) of air at 23.00°C (3dp) (1 mark)ii) the dynamic viscosity (N s /m2) of air at 4.60°C (9dp) (1 mark)iii) the kinematic viscosity (m2/s) of air at 5.40°C (9dp) (1 mark)iv) the density (kg/m3) of air at 27.30°C (3dp) (1 mark)v) the dynamic viscosity (N s /m2)of air at 20.00°C (9dp) (1 mark)vi) the kinematic viscosity (m2/s) of air at 0.60°C (9dp) (1 mark)vii) the air temperature (ºC) when its density is 1.263kg/m3 (2dp) (1 mark)viii) the air temperature (ºC) when its dynamic viscosity is 17.20 x 10-6 N s/m2 (2dp)

(1 mark)

Table 1. Properties of air at standard sea level atmospheric conditions.Temperature (°C) Density (kg/m3) Dynamic Viscosity (10-6 N s/m2)

0 1.293 17.110 1.248 17.620 1.205 18.130 1.165 18.6

Q2. If Calculate C when - i) AB = constant, A1 = 59750, B1= 4.60 and A2 = 475250 (1dp) (1 mark)ii) AB1.30 = constant, A1 = 379500.00, B1= 1.70 and A2 = 292500 (1dp) (1 mark)iii) A = constant = 473750.00, B1= 4.10 and B2 = 1.70 (1dp) (1 mark)iv) B = constant = 7.20, A1= 56000 and A2 = 96750 (1dp) (1 mark)

WATS 5. Student number 11

Page 13: WATS 5 (1-50) Fluid Mechanics and Thermodynamics

Fluid Mechanics and Thermodynamics.Weekly Assessed Tutorial Sheet 5.

Student Number 12

Name

Hand out date Hand in date

Q1. Given the table below calculate –

i) the density (kg/m3) of air at 17.80°C (3dp) (1 mark)ii) the dynamic viscosity (N s /m2) of air at 5.70°C (9dp) (1 mark)iii) the kinematic viscosity (m2/s) of air at 20.40°C (9dp) (1 mark)iv) the density (kg/m3) of air at 20.10°C (3dp) (1 mark)v) the dynamic viscosity (N s /m2)of air at 0.20°C (9dp) (1 mark)vi) the kinematic viscosity (m2/s) of air at 23.20°C (9dp) (1 mark)vii) the air temperature (ºC) when its density is 1.208kg/m3 (2dp) (1 mark)viii) the air temperature (ºC) when its dynamic viscosity is 17.60 x 10-6 N s/m2 (2dp)

(1 mark)

Table 1. Properties of air at standard sea level atmospheric conditions.Temperature (°C) Density (kg/m3) Dynamic Viscosity (10-6 N s/m2)

0 1.293 17.110 1.248 17.620 1.205 18.130 1.165 18.6

Q2. If Calculate C when - i) AB = constant, A1 = 258750, B1= 9.80 and A2 = 125250 (1dp) (1 mark)ii) AB1.30 = constant, A1 = 336000.00, B1= 3.00 and A2 = 68750 (1dp) (1 mark)iii) A = constant = 241500.00, B1= 9.80 and B2 = 5.90 (1dp) (1 mark)iv) B = constant = 3.00, A1= 212250 and A2 = 300750 (1dp) (1 mark)

WATS 5. Student number 12

Page 14: WATS 5 (1-50) Fluid Mechanics and Thermodynamics

Fluid Mechanics and Thermodynamics.Weekly Assessed Tutorial Sheet 5.

Student Number 13

Name

Hand out date Hand in date

Q1. Given the table below calculate –

i) the density (kg/m3) of air at 9.00°C (3dp) (1 mark)ii) the dynamic viscosity (N s /m2) of air at 26.10°C (9dp) (1 mark)iii) the kinematic viscosity (m2/s) of air at 19.50°C (9dp) (1 mark)iv) the density (kg/m3) of air at 0.50°C (3dp) (1 mark)v) the dynamic viscosity (N s /m2)of air at 17.70°C (9dp) (1 mark)vi) the kinematic viscosity (m2/s) of air at 7.70°C (9dp) (1 mark)vii) the air temperature (ºC) when its density is 1.184kg/m3 (2dp) (1 mark)viii) the air temperature (ºC) when its dynamic viscosity is 18.00 x 10-6 N s/m2 (2dp)

(1 mark)

Table 1. Properties of air at standard sea level atmospheric conditions.Temperature (°C) Density (kg/m3) Dynamic Viscosity (10-6 N s/m2)

0 1.293 17.110 1.248 17.620 1.205 18.130 1.165 18.6

Q2. If Calculate C when - i) AB = constant, A1 = 205500, B1= 2.50 and A2 = 152000 (1dp) (1 mark)ii) AB1.40 = constant, A1 = 455250.00, B1= 8.40 and A2 = 436250 (1dp) (1 mark)iii) A = constant = 117750.00, B1= 1.70 and B2 = 3.30 (1dp) (1 mark)iv) B = constant = 6.20, A1= 124500 and A2 = 230250 (1dp) (1 mark)

WATS 5. Student number 13

Page 15: WATS 5 (1-50) Fluid Mechanics and Thermodynamics

Fluid Mechanics and Thermodynamics.Weekly Assessed Tutorial Sheet 5.

Student Number 14

Name

Hand out date Hand in date

Q1. Given the table below calculate –

i) the density (kg/m3) of air at 19.40°C (3dp) (1 mark)ii) the dynamic viscosity (N s /m2) of air at 21.80°C (9dp) (1 mark)iii) the kinematic viscosity (m2/s) of air at 23.30°C (9dp) (1 mark)iv) the density (kg/m3) of air at 6.40°C (3dp) (1 mark)v) the dynamic viscosity (N s /m2)of air at 20.30°C (9dp) (1 mark)vi) the kinematic viscosity (m2/s) of air at 3.00°C (9dp) (1 mark)vii) the air temperature (ºC) when its density is 1.245kg/m3 (2dp) (1 mark)viii) the air temperature (ºC) when its dynamic viscosity is 18.10 x 10-6 N s/m2 (2dp)

(1 mark)

Table 1. Properties of air at standard sea level atmospheric conditions.Temperature (°C) Density (kg/m3) Dynamic Viscosity (10-6 N s/m2)

0 1.293 17.110 1.248 17.620 1.205 18.130 1.165 18.6

Q2. If Calculate C when - i) AB = constant, A1 = 456250, B1= 3.00 and A2 = 405500 (1dp) (1 mark)ii) AB1.20 = constant, A1 = 58500.00, B1= 6.10 and A2 = 207250 (1dp) (1 mark)iii) A = constant = 284500.00, B1= 5.40 and B2 = 9.30 (1dp) (1 mark)iv) B = constant = 7.60, A1= 81250 and A2 = 206500 (1dp) (1 mark)

WATS 5. Student number 14

Page 16: WATS 5 (1-50) Fluid Mechanics and Thermodynamics

Fluid Mechanics and Thermodynamics.Weekly Assessed Tutorial Sheet 5.

Student Number 15

Name

Hand out date Hand in date

Q1. Given the table below calculate –

i) the density (kg/m3) of air at 8.40°C (3dp) (1 mark)ii) the dynamic viscosity (N s /m2) of air at 7.80°C (9dp) (1 mark)iii) the kinematic viscosity (m2/s) of air at 2.60°C (9dp) (1 mark)iv) the density (kg/m3) of air at 13.40°C (3dp) (1 mark)v) the dynamic viscosity (N s /m2)of air at 8.70°C (9dp) (1 mark)vi) the kinematic viscosity (m2/s) of air at 24.00°C (9dp) (1 mark)vii) the air temperature (ºC) when its density is 1.220kg/m3 (2dp) (1 mark)viii) the air temperature (ºC) when its dynamic viscosity is 18.30 x 10-6 N s/m2 (2dp)

(1 mark)

Table 1. Properties of air at standard sea level atmospheric conditions.Temperature (°C) Density (kg/m3) Dynamic Viscosity (10-6 N s/m2)

0 1.293 17.110 1.248 17.620 1.205 18.130 1.165 18.6

Q2. If Calculate C when - i) AB = constant, A1 = 62500, B1= 2.20 and A2 = 331250 (1dp) (1 mark)ii) AB1.20 = constant, A1 = 131750.00, B1= 7.70 and A2 = 283250 (1dp) (1 mark)iii) A = constant = 468750.00, B1= 7.10 and B2 = 7.30 (1dp) (1 mark)iv) B = constant = 2.70, A1= 316750 and A2 = 317000 (1dp) (1 mark)

WATS 5. Student number 15

Page 17: WATS 5 (1-50) Fluid Mechanics and Thermodynamics

Fluid Mechanics and Thermodynamics.Weekly Assessed Tutorial Sheet 5.

Student Number 16

Name

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Q1. Given the table below calculate –

i) the density (kg/m3) of air at 24.70°C (3dp) (1 mark)ii) the dynamic viscosity (N s /m2) of air at 24.80°C (9dp) (1 mark)iii) the kinematic viscosity (m2/s) of air at 17.20°C (9dp) (1 mark)iv) the density (kg/m3) of air at 8.70°C (3dp) (1 mark)v) the dynamic viscosity (N s /m2)of air at 13.20°C (9dp) (1 mark)vi) the kinematic viscosity (m2/s) of air at 22.50°C (9dp) (1 mark)vii) the air temperature (ºC) when its density is 1.191kg/m3 (2dp) (1 mark)viii) the air temperature (ºC) when its dynamic viscosity is 17.20 x 10-6 N s/m2 (2dp)

(1 mark)

Table 1. Properties of air at standard sea level atmospheric conditions.Temperature (°C) Density (kg/m3) Dynamic Viscosity (10-6 N s/m2)

0 1.293 17.110 1.248 17.620 1.205 18.130 1.165 18.6

Q2. If Calculate C when - i) AB = constant, A1 = 336500, B1= 8.40 and A2 = 289500 (1dp) (1 mark)ii) AB1.20 = constant, A1 = 495500.00, B1= 7.00 and A2 = 179500 (1dp) (1 mark)iii) A = constant = 420500.00, B1= 5.50 and B2 = 8.00 (1dp) (1 mark)iv) B = constant = 4.60, A1= 195000 and A2 = 398500 (1dp) (1 mark)

WATS 5. Student number 16

Page 18: WATS 5 (1-50) Fluid Mechanics and Thermodynamics

Fluid Mechanics and Thermodynamics.Weekly Assessed Tutorial Sheet 5.

Student Number 17

Name

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Q1. Given the table below calculate –

i) the density (kg/m3) of air at 29.50°C (3dp) (1 mark)ii) the dynamic viscosity (N s /m2) of air at 23.70°C (9dp) (1 mark)iii) the kinematic viscosity (m2/s) of air at 12.40°C (9dp) (1 mark)iv) the density (kg/m3) of air at 25.50°C (3dp) (1 mark)v) the dynamic viscosity (N s /m2)of air at 11.10°C (9dp) (1 mark)vi) the kinematic viscosity (m2/s) of air at 13.90°C (9dp) (1 mark)vii) the air temperature (ºC) when its density is 1.278kg/m3 (2dp) (1 mark)viii) the air temperature (ºC) when its dynamic viscosity is 18.00 x 10-6 N s/m2 (2dp)

(1 mark)

Table 1. Properties of air at standard sea level atmospheric conditions.Temperature (°C) Density (kg/m3) Dynamic Viscosity (10-6 N s/m2)

0 1.293 17.110 1.248 17.620 1.205 18.130 1.165 18.6

Q2. If Calculate C when - i) AB = constant, A1 = 499750, B1= 5.00 and A2 = 381000 (1dp) (1 mark)ii) AB1.40 = constant, A1 = 445250.00, B1= 2.10 and A2 = 493000 (1dp) (1 mark)iii) A = constant = 142250.00, B1= 8.10 and B2 = 1.00 (1dp) (1 mark)iv) B = constant = 4.00, A1= 296000 and A2 = 338750 (1dp) (1 mark)

WATS 5. Student number 17

Page 19: WATS 5 (1-50) Fluid Mechanics and Thermodynamics

Fluid Mechanics and Thermodynamics.Weekly Assessed Tutorial Sheet 5.

Student Number 18

Name

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Q1. Given the table below calculate –

i) the density (kg/m3) of air at 6.90°C (3dp) (1 mark)ii) the dynamic viscosity (N s /m2) of air at 13.50°C (9dp) (1 mark)iii) the kinematic viscosity (m2/s) of air at 4.50°C (9dp) (1 mark)iv) the density (kg/m3) of air at 10.40°C (3dp) (1 mark)v) the dynamic viscosity (N s /m2)of air at 10.20°C (9dp) (1 mark)vi) the kinematic viscosity (m2/s) of air at 19.70°C (9dp) (1 mark)vii) the air temperature (ºC) when its density is 1.177kg/m3 (2dp) (1 mark)viii) the air temperature (ºC) when its dynamic viscosity is 18.10 x 10-6 N s/m2 (2dp)

(1 mark)

Table 1. Properties of air at standard sea level atmospheric conditions.Temperature (°C) Density (kg/m3) Dynamic Viscosity (10-6 N s/m2)

0 1.293 17.110 1.248 17.620 1.205 18.130 1.165 18.6

Q2. If Calculate C when - i) AB = constant, A1 = 354500, B1= 6.90 and A2 = 221750 (1dp) (1 mark)ii) AB1.30 = constant, A1 = 454000.00, B1= 5.40 and A2 = 357500 (1dp) (1 mark)iii) A = constant = 172750.00, B1= 3.60 and B2 = 1.20 (1dp) (1 mark)iv) B = constant = 10.00, A1= 55500 and A2 = 92000 (1dp) (1 mark)

WATS 5. Student number 18

Page 20: WATS 5 (1-50) Fluid Mechanics and Thermodynamics

Fluid Mechanics and Thermodynamics.Weekly Assessed Tutorial Sheet 5.

Student Number 19

Name

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Q1. Given the table below calculate –

i) the density (kg/m3) of air at 29.30°C (3dp) (1 mark)ii) the dynamic viscosity (N s /m2) of air at 24.00°C (9dp) (1 mark)iii) the kinematic viscosity (m2/s) of air at 29.60°C (9dp) (1 mark)iv) the density (kg/m3) of air at 25.70°C (3dp) (1 mark)v) the dynamic viscosity (N s /m2)of air at 29.10°C (9dp) (1 mark)vi) the kinematic viscosity (m2/s) of air at 4.60°C (9dp) (1 mark)vii) the air temperature (ºC) when its density is 1.224kg/m3 (2dp) (1 mark)viii) the air temperature (ºC) when its dynamic viscosity is 17.50 x 10-6 N s/m2 (2dp)

(1 mark)

Table 1. Properties of air at standard sea level atmospheric conditions.Temperature (°C) Density (kg/m3) Dynamic Viscosity (10-6 N s/m2)

0 1.293 17.110 1.248 17.620 1.205 18.130 1.165 18.6

Q2. If Calculate C when - i) AB = constant, A1 = 490750, B1= 6.20 and A2 = 79500 (1dp) (1 mark)ii) AB1.30 = constant, A1 = 395500.00, B1= 3.20 and A2 = 195500 (1dp) (1 mark)iii) A = constant = 76750.00, B1= 8.00 and B2 = 1.30 (1dp) (1 mark)iv) B = constant = 6.80, A1= 360750 and A2 = 265000 (1dp) (1 mark)

WATS 5. Student number 19

Page 21: WATS 5 (1-50) Fluid Mechanics and Thermodynamics

Fluid Mechanics and Thermodynamics.Weekly Assessed Tutorial Sheet 5.

Student Number 20

Name

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Q1. Given the table below calculate –

i) the density (kg/m3) of air at 16.00°C (3dp) (1 mark)ii) the dynamic viscosity (N s /m2) of air at 6.20°C (9dp) (1 mark)iii) the kinematic viscosity (m2/s) of air at 8.30°C (9dp) (1 mark)iv) the density (kg/m3) of air at 17.90°C (3dp) (1 mark)v) the dynamic viscosity (N s /m2)of air at 7.90°C (9dp) (1 mark)vi) the kinematic viscosity (m2/s) of air at 18.70°C (9dp) (1 mark)vii) the air temperature (ºC) when its density is 1.201kg/m3 (2dp) (1 mark)viii) the air temperature (ºC) when its dynamic viscosity is 17.30 x 10-6 N s/m2 (2dp)

(1 mark)

Table 1. Properties of air at standard sea level atmospheric conditions.Temperature (°C) Density (kg/m3) Dynamic Viscosity (10-6 N s/m2)

0 1.293 17.110 1.248 17.620 1.205 18.130 1.165 18.6

Q2. If Calculate C when - i) AB = constant, A1 = 98250, B1= 7.50 and A2 = 286250 (1dp) (1 mark)ii) AB1.40 = constant, A1 = 210250.00, B1= 3.80 and A2 = 387500 (1dp) (1 mark)iii) A = constant = 166500.00, B1= 7.20 and B2 = 2.20 (1dp) (1 mark)iv) B = constant = 9.60, A1= 379500 and A2 = 195500 (1dp) (1 mark)

WATS 5. Student number 20

Page 22: WATS 5 (1-50) Fluid Mechanics and Thermodynamics

Fluid Mechanics and Thermodynamics.Weekly Assessed Tutorial Sheet 5.

Student Number 21

Name

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Q1. Given the table below calculate –

i) the density (kg/m3) of air at 29.90°C (3dp) (1 mark)ii) the dynamic viscosity (N s /m2) of air at 11.00°C (9dp) (1 mark)iii) the kinematic viscosity (m2/s) of air at 14.10°C (9dp) (1 mark)iv) the density (kg/m3) of air at 28.20°C (3dp) (1 mark)v) the dynamic viscosity (N s /m2)of air at 20.00°C (9dp) (1 mark)vi) the kinematic viscosity (m2/s) of air at 22.90°C (9dp) (1 mark)vii) the air temperature (ºC) when its density is 1.244kg/m3 (2dp) (1 mark)viii) the air temperature (ºC) when its dynamic viscosity is 18.30 x 10-6 N s/m2 (2dp)

(1 mark)

Table 1. Properties of air at standard sea level atmospheric conditions.Temperature (°C) Density (kg/m3) Dynamic Viscosity (10-6 N s/m2)

0 1.293 17.110 1.248 17.620 1.205 18.130 1.165 18.6

Q2. If Calculate C when - i) AB = constant, A1 = 212750, B1= 3.30 and A2 = 465500 (1dp) (1 mark)ii) AB1.20 = constant, A1 = 495500.00, B1= 4.00 and A2 = 90000 (1dp) (1 mark)iii) A = constant = 333500.00, B1= 6.30 and B2 = 8.50 (1dp) (1 mark)iv) B = constant = 5.60, A1= 495250 and A2 = 454250 (1dp) (1 mark)

WATS 5. Student number 21

Page 23: WATS 5 (1-50) Fluid Mechanics and Thermodynamics

Fluid Mechanics and Thermodynamics.Weekly Assessed Tutorial Sheet 5.

Student Number 22

Name

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Q1. Given the table below calculate –

i) the density (kg/m3) of air at 0.60°C (3dp) (1 mark)ii) the dynamic viscosity (N s /m2) of air at 10.40°C (9dp) (1 mark)iii) the kinematic viscosity (m2/s) of air at 13.80°C (9dp) (1 mark)iv) the density (kg/m3) of air at 0.60°C (3dp) (1 mark)v) the dynamic viscosity (N s /m2)of air at 27.90°C (9dp) (1 mark)vi) the kinematic viscosity (m2/s) of air at 11.00°C (9dp) (1 mark)vii) the air temperature (ºC) when its density is 1.257kg/m3 (2dp) (1 mark)viii) the air temperature (ºC) when its dynamic viscosity is 18.10 x 10-6 N s/m2 (2dp)

(1 mark)

Table 1. Properties of air at standard sea level atmospheric conditions.Temperature (°C) Density (kg/m3) Dynamic Viscosity (10-6 N s/m2)

0 1.293 17.110 1.248 17.620 1.205 18.130 1.165 18.6

Q2. If Calculate C when - i) AB = constant, A1 = 97250, B1= 2.80 and A2 = 214250 (1dp) (1 mark)ii) AB1.30 = constant, A1 = 164750.00, B1= 8.00 and A2 = 98000 (1dp) (1 mark)iii) A = constant = 337250.00, B1= 1.30 and B2 = 2.90 (1dp) (1 mark)iv) B = constant = 4.00, A1= 406000 and A2 = 168000 (1dp) (1 mark)

WATS 5. Student number 22

Page 24: WATS 5 (1-50) Fluid Mechanics and Thermodynamics

Fluid Mechanics and Thermodynamics.Weekly Assessed Tutorial Sheet 5.

Student Number 23

Name

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Q1. Given the table below calculate –

i) the density (kg/m3) of air at 3.10°C (3dp) (1 mark)ii) the dynamic viscosity (N s /m2) of air at 12.80°C (9dp) (1 mark)iii) the kinematic viscosity (m2/s) of air at 28.30°C (9dp) (1 mark)iv) the density (kg/m3) of air at 18.00°C (3dp) (1 mark)v) the dynamic viscosity (N s /m2)of air at 17.50°C (9dp) (1 mark)vi) the kinematic viscosity (m2/s) of air at 10.00°C (9dp) (1 mark)vii) the air temperature (ºC) when its density is 1.234kg/m3 (2dp) (1 mark)viii) the air temperature (ºC) when its dynamic viscosity is 17.40 x 10-6 N s/m2 (2dp)

(1 mark)

Table 1. Properties of air at standard sea level atmospheric conditions.Temperature (°C) Density (kg/m3) Dynamic Viscosity (10-6 N s/m2)

0 1.293 17.110 1.248 17.620 1.205 18.130 1.165 18.6

Q2. If Calculate C when - i) AB = constant, A1 = 211250, B1= 6.40 and A2 = 302000 (1dp) (1 mark)ii) AB1.40 = constant, A1 = 135500.00, B1= 7.10 and A2 = 260000 (1dp) (1 mark)iii) A = constant = 160750.00, B1= 9.60 and B2 = 8.10 (1dp) (1 mark)iv) B = constant = 2.70, A1= 432750 and A2 = 367750 (1dp) (1 mark)

WATS 5. Student number 23

Page 25: WATS 5 (1-50) Fluid Mechanics and Thermodynamics

Fluid Mechanics and Thermodynamics.Weekly Assessed Tutorial Sheet 5.

Student Number 24

Name

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Q1. Given the table below calculate –

i) the density (kg/m3) of air at 23.90°C (3dp) (1 mark)ii) the dynamic viscosity (N s /m2) of air at 1.60°C (9dp) (1 mark)iii) the kinematic viscosity (m2/s) of air at 5.30°C (9dp) (1 mark)iv) the density (kg/m3) of air at 19.20°C (3dp) (1 mark)v) the dynamic viscosity (N s /m2)of air at 5.40°C (9dp) (1 mark)vi) the kinematic viscosity (m2/s) of air at 22.60°C (9dp) (1 mark)vii) the air temperature (ºC) when its density is 1.241kg/m3 (2dp) (1 mark)viii) the air temperature (ºC) when its dynamic viscosity is 17.40 x 10-6 N s/m2 (2dp)

(1 mark)

Table 1. Properties of air at standard sea level atmospheric conditions.Temperature (°C) Density (kg/m3) Dynamic Viscosity (10-6 N s/m2)

0 1.293 17.110 1.248 17.620 1.205 18.130 1.165 18.6

Q2. If Calculate C when - i) AB = constant, A1 = 141500, B1= 7.00 and A2 = 403750 (1dp) (1 mark)ii) AB1.30 = constant, A1 = 63750.00, B1= 2.10 and A2 = 67500 (1dp) (1 mark)iii) A = constant = 499250.00, B1= 5.30 and B2 = 2.70 (1dp) (1 mark)iv) B = constant = 2.10, A1= 266250 and A2 = 388000 (1dp) (1 mark)

WATS 5. Student number 24

Page 26: WATS 5 (1-50) Fluid Mechanics and Thermodynamics

Fluid Mechanics and Thermodynamics.Weekly Assessed Tutorial Sheet 5.

Student Number 25

Name

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Q1. Given the table below calculate –

i) the density (kg/m3) of air at 1.50°C (3dp) (1 mark)ii) the dynamic viscosity (N s /m2) of air at 6.30°C (9dp) (1 mark)iii) the kinematic viscosity (m2/s) of air at 10.30°C (9dp) (1 mark)iv) the density (kg/m3) of air at 21.30°C (3dp) (1 mark)v) the dynamic viscosity (N s /m2)of air at 24.30°C (9dp) (1 mark)vi) the kinematic viscosity (m2/s) of air at 12.10°C (9dp) (1 mark)vii) the air temperature (ºC) when its density is 1.227kg/m3 (2dp) (1 mark)viii) the air temperature (ºC) when its dynamic viscosity is 17.60 x 10-6 N s/m2 (2dp)

(1 mark)

Table 1. Properties of air at standard sea level atmospheric conditions.Temperature (°C) Density (kg/m3) Dynamic Viscosity (10-6 N s/m2)

0 1.293 17.110 1.248 17.620 1.205 18.130 1.165 18.6

Q2. If Calculate C when - i) AB = constant, A1 = 225250, B1= 5.20 and A2 = 302000 (1dp) (1 mark)ii) AB1.30 = constant, A1 = 459500.00, B1= 1.20 and A2 = 347500 (1dp) (1 mark)iii) A = constant = 419000.00, B1= 7.80 and B2 = 9.70 (1dp) (1 mark)iv) B = constant = 3.00, A1= 281500 and A2 = 94000 (1dp) (1 mark)

WATS 5. Student number 25

Page 27: WATS 5 (1-50) Fluid Mechanics and Thermodynamics

Fluid Mechanics and Thermodynamics.Weekly Assessed Tutorial Sheet 5.

Student Number 26

Name

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Q1. Given the table below calculate –

i) the density (kg/m3) of air at 11.50°C (3dp) (1 mark)ii) the dynamic viscosity (N s /m2) of air at 27.90°C (9dp) (1 mark)iii) the kinematic viscosity (m2/s) of air at 11.90°C (9dp) (1 mark)iv) the density (kg/m3) of air at 1.80°C (3dp) (1 mark)v) the dynamic viscosity (N s /m2)of air at 13.50°C (9dp) (1 mark)vi) the kinematic viscosity (m2/s) of air at 10.90°C (9dp) (1 mark)vii) the air temperature (ºC) when its density is 1.270kg/m3 (2dp) (1 mark)viii) the air temperature (ºC) when its dynamic viscosity is 17.40 x 10-6 N s/m2 (2dp)

(1 mark)

Table 1. Properties of air at standard sea level atmospheric conditions.Temperature (°C) Density (kg/m3) Dynamic Viscosity (10-6 N s/m2)

0 1.293 17.110 1.248 17.620 1.205 18.130 1.165 18.6

Q2. If Calculate C when - i) AB = constant, A1 = 413000, B1= 6.80 and A2 = 351500 (1dp) (1 mark)ii) AB1.20 = constant, A1 = 129750.00, B1= 7.30 and A2 = 58250 (1dp) (1 mark)iii) A = constant = 128000.00, B1= 5.00 and B2 = 4.40 (1dp) (1 mark)iv) B = constant = 7.70, A1= 314500 and A2 = 136000 (1dp) (1 mark)

WATS 5. Student number 26

Page 28: WATS 5 (1-50) Fluid Mechanics and Thermodynamics

Fluid Mechanics and Thermodynamics.Weekly Assessed Tutorial Sheet 5.

Student Number 27

Name

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Q1. Given the table below calculate –

i) the density (kg/m3) of air at 28.40°C (3dp) (1 mark)ii) the dynamic viscosity (N s /m2) of air at 25.10°C (9dp) (1 mark)iii) the kinematic viscosity (m2/s) of air at 2.10°C (9dp) (1 mark)iv) the density (kg/m3) of air at 6.00°C (3dp) (1 mark)v) the dynamic viscosity (N s /m2)of air at 1.50°C (9dp) (1 mark)vi) the kinematic viscosity (m2/s) of air at 20.50°C (9dp) (1 mark)vii) the air temperature (ºC) when its density is 1.219kg/m3 (2dp) (1 mark)viii) the air temperature (ºC) when its dynamic viscosity is 18.30 x 10-6 N s/m2 (2dp)

(1 mark)

Table 1. Properties of air at standard sea level atmospheric conditions.Temperature (°C) Density (kg/m3) Dynamic Viscosity (10-6 N s/m2)

0 1.293 17.110 1.248 17.620 1.205 18.130 1.165 18.6

Q2. If Calculate C when - i) AB = constant, A1 = 375750, B1= 2.50 and A2 = 266250 (1dp) (1 mark)ii) AB1.30 = constant, A1 = 152250.00, B1= 3.00 and A2 = 292500 (1dp) (1 mark)iii) A = constant = 269250.00, B1= 6.70 and B2 = 8.20 (1dp) (1 mark)iv) B = constant = 1.40, A1= 362500 and A2 = 188000 (1dp) (1 mark)

WATS 5. Student number 27

Page 29: WATS 5 (1-50) Fluid Mechanics and Thermodynamics

Fluid Mechanics and Thermodynamics.Weekly Assessed Tutorial Sheet 5.

Student Number 28

Name

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Q1. Given the table below calculate –

i) the density (kg/m3) of air at 12.10°C (3dp) (1 mark)ii) the dynamic viscosity (N s /m2) of air at 24.10°C (9dp) (1 mark)iii) the kinematic viscosity (m2/s) of air at 11.00°C (9dp) (1 mark)iv) the density (kg/m3) of air at 5.40°C (3dp) (1 mark)v) the dynamic viscosity (N s /m2)of air at 17.70°C (9dp) (1 mark)vi) the kinematic viscosity (m2/s) of air at 6.20°C (9dp) (1 mark)vii) the air temperature (ºC) when its density is 1.275kg/m3 (2dp) (1 mark)viii) the air temperature (ºC) when its dynamic viscosity is 18.10 x 10-6 N s/m2 (2dp)

(1 mark)

Table 1. Properties of air at standard sea level atmospheric conditions.Temperature (°C) Density (kg/m3) Dynamic Viscosity (10-6 N s/m2)

0 1.293 17.110 1.248 17.620 1.205 18.130 1.165 18.6

Q2. If Calculate C when - i) AB = constant, A1 = 481000, B1= 4.10 and A2 = 347000 (1dp) (1 mark)ii) AB1.30 = constant, A1 = 56500.00, B1= 7.80 and A2 = 260000 (1dp) (1 mark)iii) A = constant = 54750.00, B1= 5.30 and B2 = 3.00 (1dp) (1 mark)iv) B = constant = 8.50, A1= 123250 and A2 = 188750 (1dp) (1 mark)

WATS 5. Student number 28

Page 30: WATS 5 (1-50) Fluid Mechanics and Thermodynamics

Fluid Mechanics and Thermodynamics.Weekly Assessed Tutorial Sheet 5.

Student Number 29

Name

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Q1. Given the table below calculate –

i) the density (kg/m3) of air at 4.90°C (3dp) (1 mark)ii) the dynamic viscosity (N s /m2) of air at 7.80°C (9dp) (1 mark)iii) the kinematic viscosity (m2/s) of air at 26.40°C (9dp) (1 mark)iv) the density (kg/m3) of air at 27.20°C (3dp) (1 mark)v) the dynamic viscosity (N s /m2)of air at 14.10°C (9dp) (1 mark)vi) the kinematic viscosity (m2/s) of air at 28.20°C (9dp) (1 mark)vii) the air temperature (ºC) when its density is 1.286kg/m3 (2dp) (1 mark)viii) the air temperature (ºC) when its dynamic viscosity is 17.70 x 10-6 N s/m2 (2dp)

(1 mark)

Table 1. Properties of air at standard sea level atmospheric conditions.Temperature (°C) Density (kg/m3) Dynamic Viscosity (10-6 N s/m2)

0 1.293 17.110 1.248 17.620 1.205 18.130 1.165 18.6

Q2. If Calculate C when - i) AB = constant, A1 = 216000, B1= 3.50 and A2 = 384500 (1dp) (1 mark)ii) AB1.20 = constant, A1 = 340000.00, B1= 2.00 and A2 = 283000 (1dp) (1 mark)iii) A = constant = 274250.00, B1= 9.40 and B2 = 9.50 (1dp) (1 mark)iv) B = constant = 9.20, A1= 261000 and A2 = 272000 (1dp) (1 mark)

WATS 5. Student number 29

Page 31: WATS 5 (1-50) Fluid Mechanics and Thermodynamics

Fluid Mechanics and Thermodynamics.Weekly Assessed Tutorial Sheet 5.

Student Number 30

Name

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Q1. Given the table below calculate –

i) the density (kg/m3) of air at 19.40°C (3dp) (1 mark)ii) the dynamic viscosity (N s /m2) of air at 20.80°C (9dp) (1 mark)iii) the kinematic viscosity (m2/s) of air at 17.80°C (9dp) (1 mark)iv) the density (kg/m3) of air at 7.70°C (3dp) (1 mark)v) the dynamic viscosity (N s /m2)of air at 25.10°C (9dp) (1 mark)vi) the kinematic viscosity (m2/s) of air at 22.70°C (9dp) (1 mark)vii) the air temperature (ºC) when its density is 1.250kg/m3 (2dp) (1 mark)viii) the air temperature (ºC) when its dynamic viscosity is 17.80 x 10-6 N s/m2 (2dp)

(1 mark)

Table 1. Properties of air at standard sea level atmospheric conditions.Temperature (°C) Density (kg/m3) Dynamic Viscosity (10-6 N s/m2)

0 1.293 17.110 1.248 17.620 1.205 18.130 1.165 18.6

Q2. If Calculate C when - i) AB = constant, A1 = 208250, B1= 7.30 and A2 = 130750 (1dp) (1 mark)ii) AB1.30 = constant, A1 = 366500.00, B1= 4.90 and A2 = 397000 (1dp) (1 mark)iii) A = constant = 223500.00, B1= 2.70 and B2 = 3.90 (1dp) (1 mark)iv) B = constant = 3.00, A1= 290500 and A2 = 126500 (1dp) (1 mark)

WATS 5. Student number 30

Page 32: WATS 5 (1-50) Fluid Mechanics and Thermodynamics

Fluid Mechanics and Thermodynamics.Weekly Assessed Tutorial Sheet 5.

Student Number 31

Name

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Q1. Given the table below calculate –

i) the density (kg/m3) of air at 12.40°C (3dp) (1 mark)ii) the dynamic viscosity (N s /m2) of air at 10.20°C (9dp) (1 mark)iii) the kinematic viscosity (m2/s) of air at 1.80°C (9dp) (1 mark)iv) the density (kg/m3) of air at 22.70°C (3dp) (1 mark)v) the dynamic viscosity (N s /m2)of air at 26.50°C (9dp) (1 mark)vi) the kinematic viscosity (m2/s) of air at 3.90°C (9dp) (1 mark)vii) the air temperature (ºC) when its density is 1.220kg/m3 (2dp) (1 mark)viii) the air temperature (ºC) when its dynamic viscosity is 18.50 x 10-6 N s/m2 (2dp)

(1 mark)

Table 1. Properties of air at standard sea level atmospheric conditions.Temperature (°C) Density (kg/m3) Dynamic Viscosity (10-6 N s/m2)

0 1.293 17.110 1.248 17.620 1.205 18.130 1.165 18.6

Q2. If Calculate C when - i) AB = constant, A1 = 145750, B1= 8.50 and A2 = 399250 (1dp) (1 mark)ii) AB1.40 = constant, A1 = 155250.00, B1= 6.80 and A2 = 368750 (1dp) (1 mark)iii) A = constant = 211000.00, B1= 8.10 and B2 = 4.90 (1dp) (1 mark)iv) B = constant = 1.00, A1= 239500 and A2 = 448250 (1dp) (1 mark)

WATS 5. Student number 31

Page 33: WATS 5 (1-50) Fluid Mechanics and Thermodynamics

Fluid Mechanics and Thermodynamics.Weekly Assessed Tutorial Sheet 5.

Student Number 32

Name

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Q1. Given the table below calculate –

i) the density (kg/m3) of air at 9.80°C (3dp) (1 mark)ii) the dynamic viscosity (N s /m2) of air at 3.40°C (9dp) (1 mark)iii) the kinematic viscosity (m2/s) of air at 4.40°C (9dp) (1 mark)iv) the density (kg/m3) of air at 4.70°C (3dp) (1 mark)v) the dynamic viscosity (N s /m2)of air at 3.40°C (9dp) (1 mark)vi) the kinematic viscosity (m2/s) of air at 7.10°C (9dp) (1 mark)vii) the air temperature (ºC) when its density is 1.166kg/m3 (2dp) (1 mark)viii) the air temperature (ºC) when its dynamic viscosity is 17.40 x 10-6 N s/m2 (2dp)

(1 mark)

Table 1. Properties of air at standard sea level atmospheric conditions.Temperature (°C) Density (kg/m3) Dynamic Viscosity (10-6 N s/m2)

0 1.293 17.110 1.248 17.620 1.205 18.130 1.165 18.6

Q2. If Calculate C when - i) AB = constant, A1 = 322000, B1= 6.70 and A2 = 362500 (1dp) (1 mark)ii) AB1.40 = constant, A1 = 280000.00, B1= 1.50 and A2 = 297500 (1dp) (1 mark)iii) A = constant = 260750.00, B1= 5.80 and B2 = 7.40 (1dp) (1 mark)iv) B = constant = 3.10, A1= 308750 and A2 = 252000 (1dp) (1 mark)

WATS 5. Student number 32

Page 34: WATS 5 (1-50) Fluid Mechanics and Thermodynamics

Fluid Mechanics and Thermodynamics.Weekly Assessed Tutorial Sheet 5.

Student Number 33

Name

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Q1. Given the table below calculate –

i) the density (kg/m3) of air at 6.30°C (3dp) (1 mark)ii) the dynamic viscosity (N s /m2) of air at 8.80°C (9dp) (1 mark)iii) the kinematic viscosity (m2/s) of air at 22.80°C (9dp) (1 mark)iv) the density (kg/m3) of air at 3.70°C (3dp) (1 mark)v) the dynamic viscosity (N s /m2)of air at 3.80°C (9dp) (1 mark)vi) the kinematic viscosity (m2/s) of air at 23.30°C (9dp) (1 mark)vii) the air temperature (ºC) when its density is 1.208kg/m3 (2dp) (1 mark)viii) the air temperature (ºC) when its dynamic viscosity is 17.60 x 10-6 N s/m2 (2dp)

(1 mark)

Table 1. Properties of air at standard sea level atmospheric conditions.Temperature (°C) Density (kg/m3) Dynamic Viscosity (10-6 N s/m2)

0 1.293 17.110 1.248 17.620 1.205 18.130 1.165 18.6

Q2. If Calculate C when - i) AB = constant, A1 = 236000, B1= 7.30 and A2 = 230250 (1dp) (1 mark)ii) AB1.20 = constant, A1 = 61250.00, B1= 3.90 and A2 = 186750 (1dp) (1 mark)iii) A = constant = 147500.00, B1= 6.10 and B2 = 2.00 (1dp) (1 mark)iv) B = constant = 8.60, A1= 63250 and A2 = 125500 (1dp) (1 mark)

WATS 5. Student number 33

Page 35: WATS 5 (1-50) Fluid Mechanics and Thermodynamics

Fluid Mechanics and Thermodynamics.Weekly Assessed Tutorial Sheet 5.

Student Number 34

Name

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Q1. Given the table below calculate –

i) the density (kg/m3) of air at 17.50°C (3dp) (1 mark)ii) the dynamic viscosity (N s /m2) of air at 16.80°C (9dp) (1 mark)iii) the kinematic viscosity (m2/s) of air at 4.20°C (9dp) (1 mark)iv) the density (kg/m3) of air at 25.60°C (3dp) (1 mark)v) the dynamic viscosity (N s /m2)of air at 15.00°C (9dp) (1 mark)vi) the kinematic viscosity (m2/s) of air at 3.10°C (9dp) (1 mark)vii) the air temperature (ºC) when its density is 1.285kg/m3 (2dp) (1 mark)viii) the air temperature (ºC) when its dynamic viscosity is 17.90 x 10-6 N s/m2 (2dp)

(1 mark)

Table 1. Properties of air at standard sea level atmospheric conditions.Temperature (°C) Density (kg/m3) Dynamic Viscosity (10-6 N s/m2)

0 1.293 17.110 1.248 17.620 1.205 18.130 1.165 18.6

Q2. If Calculate C when - i) AB = constant, A1 = 394000, B1= 6.00 and A2 = 153750 (1dp) (1 mark)ii) AB1.20 = constant, A1 = 197000.00, B1= 6.70 and A2 = 126250 (1dp) (1 mark)iii) A = constant = 156750.00, B1= 4.30 and B2 = 4.10 (1dp) (1 mark)iv) B = constant = 2.80, A1= 147750 and A2 = 473250 (1dp) (1 mark)

WATS 5. Student number 34

Page 36: WATS 5 (1-50) Fluid Mechanics and Thermodynamics

Fluid Mechanics and Thermodynamics.Weekly Assessed Tutorial Sheet 5.

Student Number 35

Name

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Q1. Given the table below calculate –

i) the density (kg/m3) of air at 13.70°C (3dp) (1 mark)ii) the dynamic viscosity (N s /m2) of air at 8.90°C (9dp) (1 mark)iii) the kinematic viscosity (m2/s) of air at 20.70°C (9dp) (1 mark)iv) the density (kg/m3) of air at 14.00°C (3dp) (1 mark)v) the dynamic viscosity (N s /m2)of air at 20.40°C (9dp) (1 mark)vi) the kinematic viscosity (m2/s) of air at 19.60°C (9dp) (1 mark)vii) the air temperature (ºC) when its density is 1.286kg/m3 (2dp) (1 mark)viii) the air temperature (ºC) when its dynamic viscosity is 17.70 x 10-6 N s/m2 (2dp)

(1 mark)

Table 1. Properties of air at standard sea level atmospheric conditions.Temperature (°C) Density (kg/m3) Dynamic Viscosity (10-6 N s/m2)

0 1.293 17.110 1.248 17.620 1.205 18.130 1.165 18.6

Q2. If Calculate C when - i) AB = constant, A1 = 68250, B1= 2.90 and A2 = 263750 (1dp) (1 mark)ii) AB1.30 = constant, A1 = 340250.00, B1= 8.10 and A2 = 149500 (1dp) (1 mark)iii) A = constant = 279750.00, B1= 5.30 and B2 = 2.60 (1dp) (1 mark)iv) B = constant = 9.40, A1= 189000 and A2 = 106500 (1dp) (1 mark)

WATS 5. Student number 35

Page 37: WATS 5 (1-50) Fluid Mechanics and Thermodynamics

Fluid Mechanics and Thermodynamics.Weekly Assessed Tutorial Sheet 5.

Student Number 36

Name

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Q1. Given the table below calculate –

i) the density (kg/m3) of air at 7.90°C (3dp) (1 mark)ii) the dynamic viscosity (N s /m2) of air at 9.30°C (9dp) (1 mark)iii) the kinematic viscosity (m2/s) of air at 15.50°C (9dp) (1 mark)iv) the density (kg/m3) of air at 7.00°C (3dp) (1 mark)v) the dynamic viscosity (N s /m2)of air at 1.60°C (9dp) (1 mark)vi) the kinematic viscosity (m2/s) of air at 24.70°C (9dp) (1 mark)vii) the air temperature (ºC) when its density is 1.247kg/m3 (2dp) (1 mark)viii) the air temperature (ºC) when its dynamic viscosity is 18.30 x 10-6 N s/m2 (2dp)

(1 mark)

Table 1. Properties of air at standard sea level atmospheric conditions.Temperature (°C) Density (kg/m3) Dynamic Viscosity (10-6 N s/m2)

0 1.293 17.110 1.248 17.620 1.205 18.130 1.165 18.6

Q2. If Calculate C when - i) AB = constant, A1 = 86750, B1= 2.30 and A2 = 112750 (1dp) (1 mark)ii) AB1.20 = constant, A1 = 242250.00, B1= 6.40 and A2 = 278750 (1dp) (1 mark)iii) A = constant = 161000.00, B1= 2.50 and B2 = 8.70 (1dp) (1 mark)iv) B = constant = 2.60, A1= 148250 and A2 = 198000 (1dp) (1 mark)

WATS 5. Student number 36

Page 38: WATS 5 (1-50) Fluid Mechanics and Thermodynamics

Fluid Mechanics and Thermodynamics.Weekly Assessed Tutorial Sheet 5.

Student Number 37

Name

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Q1. Given the table below calculate –

i) the density (kg/m3) of air at 11.40°C (3dp) (1 mark)ii) the dynamic viscosity (N s /m2) of air at 12.10°C (9dp) (1 mark)iii) the kinematic viscosity (m2/s) of air at 29.40°C (9dp) (1 mark)iv) the density (kg/m3) of air at 7.70°C (3dp) (1 mark)v) the dynamic viscosity (N s /m2)of air at 17.80°C (9dp) (1 mark)vi) the kinematic viscosity (m2/s) of air at 18.90°C (9dp) (1 mark)vii) the air temperature (ºC) when its density is 1.197kg/m3 (2dp) (1 mark)viii) the air temperature (ºC) when its dynamic viscosity is 17.90 x 10-6 N s/m2 (2dp)

(1 mark)

Table 1. Properties of air at standard sea level atmospheric conditions.Temperature (°C) Density (kg/m3) Dynamic Viscosity (10-6 N s/m2)

0 1.293 17.110 1.248 17.620 1.205 18.130 1.165 18.6

Q2. If Calculate C when - i) AB = constant, A1 = 484250, B1= 1.70 and A2 = 403500 (1dp) (1 mark)ii) AB1.30 = constant, A1 = 145250.00, B1= 7.60 and A2 = 496500 (1dp) (1 mark)iii) A = constant = 434250.00, B1= 5.10 and B2 = 2.50 (1dp) (1 mark)iv) B = constant = 6.60, A1= 365250 and A2 = 289250 (1dp) (1 mark)

WATS 5. Student number 37

Page 39: WATS 5 (1-50) Fluid Mechanics and Thermodynamics

Fluid Mechanics and Thermodynamics.Weekly Assessed Tutorial Sheet 5.

Student Number 38

Name

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Q1. Given the table below calculate –

i) the density (kg/m3) of air at 27.50°C (3dp) (1 mark)ii) the dynamic viscosity (N s /m2) of air at 12.30°C (9dp) (1 mark)iii) the kinematic viscosity (m2/s) of air at 2.10°C (9dp) (1 mark)iv) the density (kg/m3) of air at 1.70°C (3dp) (1 mark)v) the dynamic viscosity (N s /m2)of air at 23.40°C (9dp) (1 mark)vi) the kinematic viscosity (m2/s) of air at 27.10°C (9dp) (1 mark)vii) the air temperature (ºC) when its density is 1.209kg/m3 (2dp) (1 mark)viii) the air temperature (ºC) when its dynamic viscosity is 17.50 x 10-6 N s/m2 (2dp)

(1 mark)

Table 1. Properties of air at standard sea level atmospheric conditions.Temperature (°C) Density (kg/m3) Dynamic Viscosity (10-6 N s/m2)

0 1.293 17.110 1.248 17.620 1.205 18.130 1.165 18.6

Q2. If Calculate C when - i) AB = constant, A1 = 59750, B1= 4.10 and A2 = 100750 (1dp) (1 mark)ii) AB1.30 = constant, A1 = 271750.00, B1= 9.00 and A2 = 487500 (1dp) (1 mark)iii) A = constant = 339000.00, B1= 1.60 and B2 = 6.80 (1dp) (1 mark)iv) B = constant = 1.40, A1= 129500 and A2 = 140000 (1dp) (1 mark)

WATS 5. Student number 38

Page 40: WATS 5 (1-50) Fluid Mechanics and Thermodynamics

Fluid Mechanics and Thermodynamics.Weekly Assessed Tutorial Sheet 5.

Student Number 39

Name

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Q1. Given the table below calculate –

i) the density (kg/m3) of air at 18.80°C (3dp) (1 mark)ii) the dynamic viscosity (N s /m2) of air at 19.70°C (9dp) (1 mark)iii) the kinematic viscosity (m2/s) of air at 9.90°C (9dp) (1 mark)iv) the density (kg/m3) of air at 2.50°C (3dp) (1 mark)v) the dynamic viscosity (N s /m2)of air at 18.10°C (9dp) (1 mark)vi) the kinematic viscosity (m2/s) of air at 25.20°C (9dp) (1 mark)vii) the air temperature (ºC) when its density is 1.290kg/m3 (2dp) (1 mark)viii) the air temperature (ºC) when its dynamic viscosity is 17.80 x 10-6 N s/m2 (2dp)

(1 mark)

Table 1. Properties of air at standard sea level atmospheric conditions.Temperature (°C) Density (kg/m3) Dynamic Viscosity (10-6 N s/m2)

0 1.293 17.110 1.248 17.620 1.205 18.130 1.165 18.6

Q2. If Calculate C when - i) AB = constant, A1 = 50250, B1= 5.60 and A2 = 132500 (1dp) (1 mark)ii) AB1.20 = constant, A1 = 262750.00, B1= 1.60 and A2 = 456250 (1dp) (1 mark)iii) A = constant = 129500.00, B1= 4.00 and B2 = 1.40 (1dp) (1 mark)iv) B = constant = 3.50, A1= 146000 and A2 = 180500 (1dp) (1 mark)

WATS 5. Student number 39

Page 41: WATS 5 (1-50) Fluid Mechanics and Thermodynamics

Fluid Mechanics and Thermodynamics.Weekly Assessed Tutorial Sheet 5.

Student Number 40

Name

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Q1. Given the table below calculate –

i) the density (kg/m3) of air at 3.00°C (3dp) (1 mark)ii) the dynamic viscosity (N s /m2) of air at 28.40°C (9dp) (1 mark)iii) the kinematic viscosity (m2/s) of air at 20.40°C (9dp) (1 mark)iv) the density (kg/m3) of air at 8.10°C (3dp) (1 mark)v) the dynamic viscosity (N s /m2)of air at 27.80°C (9dp) (1 mark)vi) the kinematic viscosity (m2/s) of air at 4.20°C (9dp) (1 mark)vii) the air temperature (ºC) when its density is 1.244kg/m3 (2dp) (1 mark)viii) the air temperature (ºC) when its dynamic viscosity is 17.60 x 10-6 N s/m2 (2dp)

(1 mark)

Table 1. Properties of air at standard sea level atmospheric conditions.Temperature (°C) Density (kg/m3) Dynamic Viscosity (10-6 N s/m2)

0 1.293 17.110 1.248 17.620 1.205 18.130 1.165 18.6

Q2. If Calculate C when - i) AB = constant, A1 = 289000, B1= 6.90 and A2 = 252000 (1dp) (1 mark)ii) AB1.30 = constant, A1 = 442750.00, B1= 2.40 and A2 = 393250 (1dp) (1 mark)iii) A = constant = 241250.00, B1= 2.00 and B2 = 1.40 (1dp) (1 mark)iv) B = constant = 7.30, A1= 408500 and A2 = 189000 (1dp) (1 mark)

WATS 5. Student number 40

Page 42: WATS 5 (1-50) Fluid Mechanics and Thermodynamics

Fluid Mechanics and Thermodynamics.Weekly Assessed Tutorial Sheet 5.

Student Number 41

Name

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Q1. Given the table below calculate –

i) the density (kg/m3) of air at 20.80°C (3dp) (1 mark)ii) the dynamic viscosity (N s /m2) of air at 15.50°C (9dp) (1 mark)iii) the kinematic viscosity (m2/s) of air at 11.60°C (9dp) (1 mark)iv) the density (kg/m3) of air at 1.70°C (3dp) (1 mark)v) the dynamic viscosity (N s /m2)of air at 15.80°C (9dp) (1 mark)vi) the kinematic viscosity (m2/s) of air at 1.80°C (9dp) (1 mark)vii) the air temperature (ºC) when its density is 1.185kg/m3 (2dp) (1 mark)viii) the air temperature (ºC) when its dynamic viscosity is 17.90 x 10-6 N s/m2 (2dp)

(1 mark)

Table 1. Properties of air at standard sea level atmospheric conditions.Temperature (°C) Density (kg/m3) Dynamic Viscosity (10-6 N s/m2)

0 1.293 17.110 1.248 17.620 1.205 18.130 1.165 18.6

Q2. If Calculate C when - i) AB = constant, A1 = 182000, B1= 6.40 and A2 = 491250 (1dp) (1 mark)ii) AB1.30 = constant, A1 = 137500.00, B1= 3.20 and A2 = 223000 (1dp) (1 mark)iii) A = constant = 103000.00, B1= 2.80 and B2 = 6.70 (1dp) (1 mark)iv) B = constant = 7.00, A1= 416500 and A2 = 421000 (1dp) (1 mark)

WATS 5. Student number 41

Page 43: WATS 5 (1-50) Fluid Mechanics and Thermodynamics

Fluid Mechanics and Thermodynamics.Weekly Assessed Tutorial Sheet 5.

Student Number 42

Name

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Q1. Given the table below calculate –

i) the density (kg/m3) of air at 25.00°C (3dp) (1 mark)ii) the dynamic viscosity (N s /m2) of air at 17.50°C (9dp) (1 mark)iii) the kinematic viscosity (m2/s) of air at 26.20°C (9dp) (1 mark)iv) the density (kg/m3) of air at 15.00°C (3dp) (1 mark)v) the dynamic viscosity (N s /m2)of air at 14.70°C (9dp) (1 mark)vi) the kinematic viscosity (m2/s) of air at 3.90°C (9dp) (1 mark)vii) the air temperature (ºC) when its density is 1.286kg/m3 (2dp) (1 mark)viii) the air temperature (ºC) when its dynamic viscosity is 18.20 x 10-6 N s/m2 (2dp)

(1 mark)

Table 1. Properties of air at standard sea level atmospheric conditions.Temperature (°C) Density (kg/m3) Dynamic Viscosity (10-6 N s/m2)

0 1.293 17.110 1.248 17.620 1.205 18.130 1.165 18.6

Q2. If Calculate C when - i) AB = constant, A1 = 299000, B1= 6.80 and A2 = 305750 (1dp) (1 mark)ii) AB1.30 = constant, A1 = 95250.00, B1= 3.50 and A2 = 225750 (1dp) (1 mark)iii) A = constant = 485750.00, B1= 8.20 and B2 = 9.20 (1dp) (1 mark)iv) B = constant = 6.50, A1= 232250 and A2 = 93250 (1dp) (1 mark)

WATS 5. Student number 42

Page 44: WATS 5 (1-50) Fluid Mechanics and Thermodynamics

Fluid Mechanics and Thermodynamics.Weekly Assessed Tutorial Sheet 5.

Student Number 43

Name

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Q1. Given the table below calculate –

i) the density (kg/m3) of air at 16.30°C (3dp) (1 mark)ii) the dynamic viscosity (N s /m2) of air at 13.70°C (9dp) (1 mark)iii) the kinematic viscosity (m2/s) of air at 12.10°C (9dp) (1 mark)iv) the density (kg/m3) of air at 13.40°C (3dp) (1 mark)v) the dynamic viscosity (N s /m2)of air at 27.00°C (9dp) (1 mark)vi) the kinematic viscosity (m2/s) of air at 10.30°C (9dp) (1 mark)vii) the air temperature (ºC) when its density is 1.239kg/m3 (2dp) (1 mark)viii) the air temperature (ºC) when its dynamic viscosity is 18.10 x 10-6 N s/m2 (2dp)

(1 mark)

Table 1. Properties of air at standard sea level atmospheric conditions.Temperature (°C) Density (kg/m3) Dynamic Viscosity (10-6 N s/m2)

0 1.293 17.110 1.248 17.620 1.205 18.130 1.165 18.6

Q2. If Calculate C when - i) AB = constant, A1 = 484000, B1= 9.90 and A2 = 313250 (1dp) (1 mark)ii) AB1.40 = constant, A1 = 413250.00, B1= 9.80 and A2 = 345000 (1dp) (1 mark)iii) A = constant = 349250.00, B1= 1.60 and B2 = 2.70 (1dp) (1 mark)iv) B = constant = 6.20, A1= 81250 and A2 = 373750 (1dp) (1 mark)

WATS 5. Student number 43

Page 45: WATS 5 (1-50) Fluid Mechanics and Thermodynamics

Fluid Mechanics and Thermodynamics.Weekly Assessed Tutorial Sheet 5.

Student Number 44

Name

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Q1. Given the table below calculate –

i) the density (kg/m3) of air at 12.90°C (3dp) (1 mark)ii) the dynamic viscosity (N s /m2) of air at 8.50°C (9dp) (1 mark)iii) the kinematic viscosity (m2/s) of air at 16.50°C (9dp) (1 mark)iv) the density (kg/m3) of air at 24.70°C (3dp) (1 mark)v) the dynamic viscosity (N s /m2)of air at 28.80°C (9dp) (1 mark)vi) the kinematic viscosity (m2/s) of air at 1.70°C (9dp) (1 mark)vii) the air temperature (ºC) when its density is 1.223kg/m3 (2dp) (1 mark)viii) the air temperature (ºC) when its dynamic viscosity is 18.20 x 10-6 N s/m2 (2dp)

(1 mark)

Table 1. Properties of air at standard sea level atmospheric conditions.Temperature (°C) Density (kg/m3) Dynamic Viscosity (10-6 N s/m2)

0 1.293 17.110 1.248 17.620 1.205 18.130 1.165 18.6

Q2. If Calculate C when - i) AB = constant, A1 = 408250, B1= 7.20 and A2 = 400500 (1dp) (1 mark)ii) AB1.30 = constant, A1 = 347250.00, B1= 2.60 and A2 = 248000 (1dp) (1 mark)iii) A = constant = 403000.00, B1= 8.30 and B2 = 4.30 (1dp) (1 mark)iv) B = constant = 6.00, A1= 372250 and A2 = 253000 (1dp) (1 mark)

WATS 5. Student number 44

Page 46: WATS 5 (1-50) Fluid Mechanics and Thermodynamics

Fluid Mechanics and Thermodynamics.Weekly Assessed Tutorial Sheet 5.

Student Number 45

Name

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Q1. Given the table below calculate –

i) the density (kg/m3) of air at 15.10°C (3dp) (1 mark)ii) the dynamic viscosity (N s /m2) of air at 26.60°C (9dp) (1 mark)iii) the kinematic viscosity (m2/s) of air at 3.80°C (9dp) (1 mark)iv) the density (kg/m3) of air at 17.40°C (3dp) (1 mark)v) the dynamic viscosity (N s /m2)of air at 26.70°C (9dp) (1 mark)vi) the kinematic viscosity (m2/s) of air at 28.00°C (9dp) (1 mark)vii) the air temperature (ºC) when its density is 1.272kg/m3 (2dp) (1 mark)viii) the air temperature (ºC) when its dynamic viscosity is 18.50 x 10-6 N s/m2 (2dp)

(1 mark)

Table 1. Properties of air at standard sea level atmospheric conditions.Temperature (°C) Density (kg/m3) Dynamic Viscosity (10-6 N s/m2)

0 1.293 17.110 1.248 17.620 1.205 18.130 1.165 18.6

Q2. If Calculate C when - i) AB = constant, A1 = 498750, B1= 7.80 and A2 = 228250 (1dp) (1 mark)ii) AB1.20 = constant, A1 = 180500.00, B1= 1.60 and A2 = 324500 (1dp) (1 mark)iii) A = constant = 69750.00, B1= 7.70 and B2 = 4.20 (1dp) (1 mark)iv) B = constant = 7.70, A1= 64750 and A2 = 325500 (1dp) (1 mark)

WATS 5. Student number 45

Page 47: WATS 5 (1-50) Fluid Mechanics and Thermodynamics

Fluid Mechanics and Thermodynamics.Weekly Assessed Tutorial Sheet 5.

Student Number 46

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Q1. Given the table below calculate –

i) the density (kg/m3) of air at 13.90°C (3dp) (1 mark)ii) the dynamic viscosity (N s /m2) of air at 11.10°C (9dp) (1 mark)iii) the kinematic viscosity (m2/s) of air at 0.30°C (9dp) (1 mark)iv) the density (kg/m3) of air at 23.70°C (3dp) (1 mark)v) the dynamic viscosity (N s /m2)of air at 11.50°C (9dp) (1 mark)vi) the kinematic viscosity (m2/s) of air at 20.60°C (9dp) (1 mark)vii) the air temperature (ºC) when its density is 1.275kg/m3 (2dp) (1 mark)viii) the air temperature (ºC) when its dynamic viscosity is 17.60 x 10-6 N s/m2 (2dp)

(1 mark)

Table 1. Properties of air at standard sea level atmospheric conditions.Temperature (°C) Density (kg/m3) Dynamic Viscosity (10-6 N s/m2)

0 1.293 17.110 1.248 17.620 1.205 18.130 1.165 18.6

Q2. If Calculate C when - i) AB = constant, A1 = 384500, B1= 1.10 and A2 = 182000 (1dp) (1 mark)ii) AB1.40 = constant, A1 = 51000.00, B1= 8.20 and A2 = 315000 (1dp) (1 mark)iii) A = constant = 291500.00, B1= 1.50 and B2 = 8.10 (1dp) (1 mark)iv) B = constant = 7.00, A1= 431500 and A2 = 379000 (1dp) (1 mark)

WATS 5. Student number 46

Page 48: WATS 5 (1-50) Fluid Mechanics and Thermodynamics

Fluid Mechanics and Thermodynamics.Weekly Assessed Tutorial Sheet 5.

Student Number 47

Name

Hand out date Hand in date

Q1. Given the table below calculate –

i) the density (kg/m3) of air at 12.20°C (3dp) (1 mark)ii) the dynamic viscosity (N s /m2) of air at 8.90°C (9dp) (1 mark)iii) the kinematic viscosity (m2/s) of air at 27.60°C (9dp) (1 mark)iv) the density (kg/m3) of air at 29.20°C (3dp) (1 mark)v) the dynamic viscosity (N s /m2)of air at 12.10°C (9dp) (1 mark)vi) the kinematic viscosity (m2/s) of air at 11.70°C (9dp) (1 mark)vii) the air temperature (ºC) when its density is 1.214kg/m3 (2dp) (1 mark)viii) the air temperature (ºC) when its dynamic viscosity is 17.30 x 10-6 N s/m2 (2dp)

(1 mark)

Table 1. Properties of air at standard sea level atmospheric conditions.Temperature (°C) Density (kg/m3) Dynamic Viscosity (10-6 N s/m2)

0 1.293 17.110 1.248 17.620 1.205 18.130 1.165 18.6

Q2. If Calculate C when - i) AB = constant, A1 = 221750, B1= 5.70 and A2 = 474000 (1dp) (1 mark)ii) AB1.30 = constant, A1 = 192500.00, B1= 6.30 and A2 = 482000 (1dp) (1 mark)iii) A = constant = 438000.00, B1= 9.90 and B2 = 3.60 (1dp) (1 mark)iv) B = constant = 9.40, A1= 225000 and A2 = 199500 (1dp) (1 mark)

WATS 5. Student number 47

Page 49: WATS 5 (1-50) Fluid Mechanics and Thermodynamics

Fluid Mechanics and Thermodynamics.Weekly Assessed Tutorial Sheet 5.

Student Number 48

Name

Hand out date Hand in date

Q1. Given the table below calculate –

i) the density (kg/m3) of air at 1.80°C (3dp) (1 mark)ii) the dynamic viscosity (N s /m2) of air at 22.80°C (9dp) (1 mark)iii) the kinematic viscosity (m2/s) of air at 6.80°C (9dp) (1 mark)iv) the density (kg/m3) of air at 20.10°C (3dp) (1 mark)v) the dynamic viscosity (N s /m2)of air at 17.20°C (9dp) (1 mark)vi) the kinematic viscosity (m2/s) of air at 19.50°C (9dp) (1 mark)vii) the air temperature (ºC) when its density is 1.277kg/m3 (2dp) (1 mark)viii) the air temperature (ºC) when its dynamic viscosity is 17.80 x 10-6 N s/m2 (2dp)

(1 mark)

Table 1. Properties of air at standard sea level atmospheric conditions.Temperature (°C) Density (kg/m3) Dynamic Viscosity (10-6 N s/m2)

0 1.293 17.110 1.248 17.620 1.205 18.130 1.165 18.6

Q2. If Calculate C when - i) AB = constant, A1 = 466000, B1= 9.40 and A2 = 270750 (1dp) (1 mark)ii) AB1.30 = constant, A1 = 413000.00, B1= 4.20 and A2 = 440750 (1dp) (1 mark)iii) A = constant = 189250.00, B1= 9.10 and B2 = 2.10 (1dp) (1 mark)iv) B = constant = 7.30, A1= 314000 and A2 = 60250 (1dp) (1 mark)

WATS 5. Student number 48

Page 50: WATS 5 (1-50) Fluid Mechanics and Thermodynamics

Fluid Mechanics and Thermodynamics.Weekly Assessed Tutorial Sheet 5.

Student Number 49

Name

Hand out date Hand in date

Q1. Given the table below calculate –

i) the density (kg/m3) of air at 29.30°C (3dp) (1 mark)ii) the dynamic viscosity (N s /m2) of air at 18.10°C (9dp) (1 mark)iii) the kinematic viscosity (m2/s) of air at 5.70°C (9dp) (1 mark)iv) the density (kg/m3) of air at 22.00°C (3dp) (1 mark)v) the dynamic viscosity (N s /m2)of air at 14.80°C (9dp) (1 mark)vi) the kinematic viscosity (m2/s) of air at 29.00°C (9dp) (1 mark)vii) the air temperature (ºC) when its density is 1.282kg/m3 (2dp) (1 mark)viii) the air temperature (ºC) when its dynamic viscosity is 17.60 x 10-6 N s/m2 (2dp)

(1 mark)

Table 1. Properties of air at standard sea level atmospheric conditions.Temperature (°C) Density (kg/m3) Dynamic Viscosity (10-6 N s/m2)

0 1.293 17.110 1.248 17.620 1.205 18.130 1.165 18.6

Q2. If Calculate C when - i) AB = constant, A1 = 276000, B1= 9.00 and A2 = 172500 (1dp) (1 mark)ii) AB1.20 = constant, A1 = 339250.00, B1= 3.30 and A2 = 331750 (1dp) (1 mark)iii) A = constant = 273500.00, B1= 8.90 and B2 = 1.10 (1dp) (1 mark)iv) B = constant = 4.80, A1= 429500 and A2 = 180750 (1dp) (1 mark)

WATS 5. Student number 49

Page 51: WATS 5 (1-50) Fluid Mechanics and Thermodynamics

Fluid Mechanics and Thermodynamics.Weekly Assessed Tutorial Sheet 5.

Student Number 50

Name

Hand out date Hand in date

Q1. Given the table below calculate –

i) the density (kg/m3) of air at 11.70°C (3dp) (1 mark)ii) the dynamic viscosity (N s /m2) of air at 15.20°C (9dp) (1 mark)iii) the kinematic viscosity (m2/s) of air at 10.90°C (9dp) (1 mark)iv) the density (kg/m3) of air at 29.60°C (3dp) (1 mark)v) the dynamic viscosity (N s /m2)of air at 20.10°C (9dp) (1 mark)vi) the kinematic viscosity (m2/s) of air at 28.30°C (9dp) (1 mark)vii) the air temperature (ºC) when its density is 1.242kg/m3 (2dp) (1 mark)viii) the air temperature (ºC) when its dynamic viscosity is 18.10 x 10-6 N s/m2 (2dp)

(1 mark)

Table 1. Properties of air at standard sea level atmospheric conditions.Temperature (°C) Density (kg/m3) Dynamic Viscosity (10-6 N s/m2)

0 1.293 17.110 1.248 17.620 1.205 18.130 1.165 18.6

Q2. If Calculate C when - i) AB = constant, A1 = 242500, B1= 4.80 and A2 = 246250 (1dp) (1 mark)ii) AB1.20 = constant, A1 = 276250.00, B1= 9.20 and A2 = 133250 (1dp) (1 mark)iii) A = constant = 104500.00, B1= 7.80 and B2 = 4.20 (1dp) (1 mark)iv) B = constant = 5.30, A1= 457000 and A2 = 347250 (1dp) (1 mark)

WATS 5. Student number 50

Page 52: WATS 5 (1-50) Fluid Mechanics and Thermodynamics

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