MASS HAUL DIAGRAMMASS HAUL DIAGRAM

tutorial 3tutorial 3

PREPARED BY : KMASZ

QUESTION 1

Chainage , m

Cut volume (m3)

Fill volume (m3)(+ 10 %

shrinkage)

Corrected volume(+) CUT(-) FILL

Cumulative volumes,m3

0  100 290200 760300 1680400 620480 120500   20600   110700   350800   600900   780

1000   6901100   4001200   120

0 0290 290760 1050

1680 2730620 3350120 3470-20 3450

-110 3340-350 2990-600 2390-780 1610-690 920-400 520-120 400

+

+

Chainage (m) Volume of cutt (m3)

Volume of fill (m3) Shrinkage volume (20%)

Shrinkage volume corrected

Corrected volume Cumulative volume (m3)

(1) (2) (3) (4) (5)= (3)+(4) + for cut-for fill

0        50 13000      

100 22500      250 7500      300   4375 350   13646400   16979450 30500     500 93250     550 163250     600 229500     

QUESTION 2

875.02729.23395.8

52501637520375

013000225007500-5250-16375-203753050093250

163250229500

01300035500430003775021375

100031500

124750288000517500

Chainage , mCumulative volumes,m3

0 0100 290200 1050300 2730400 3350480 3470500 3450600 3340700 2990800 2390900 1610

1000 9201100 5201200 400

Analysis of MHD; Analysis of MHD; GivenGiven•Freehaul distance is 600 m ,Freehaul distance is 600 m ,•Balance line at 400 m3 of Balance line at 400 m3 of aggregate volume.aggregate volume.

From the data, draw a mass –haul From the data, draw a mass –haul diagram using the scale below:diagram using the scale below:X axis : 1 cm = 100 mX axis : 1 cm = 100 mY axis: 1 cm = 250 mY axis: 1 cm = 250 m33

Agregate volume for setting out circular curves proposed as follows:

QUESTION 3

Estimate of freehaul, haul and Estimate of freehaul, haul and overhaul.overhaul.

Cumulative volume mCumulative volume m33

Chainage ,mChainage ,m

Draw a MHD using Draw a MHD using the scale below:the scale below:X axis : 1 cm = 100 X axis : 1 cm = 100 mmY axis: 1 cm = 250 Y axis: 1 cm = 250 mm33

X axis : 1 cm = 100 mX axis : 1 cm = 100 m

Y a

xis

: 1 c

m =

250 m

Y a

xis

: 1 c

m =

250 m

33

STEP 1STEP 1

STEP 2STEP 2

GivenGiven•Freehaul distance is Freehaul distance is 600 m ,600 m ,•Balance line at 400 Balance line at 400 m3 of cumulative m3 of cumulative volume.volume.

Cumulative volume mCumulative volume m33

Chainage ,mChainage ,m

Measuring freehaul line = 6 cm

Freehaul line

Balance line

400m3 Cumulative

volume

6 cm

Freehaul volume = 6cm x 250 m3

= 1500 m3

Freehaul distance = 600m (given)

Axis y; Measurement line = 6 cm

Freehaul = Freehaul = Freehaul volume x freehaul distance Freehaul volume x freehaul distance stn.m stn.m 100 100 Freehaul = Freehaul = 1500 x 600 1500 x 600 = 9000 stn.m = 9000 stn.m 100 100

Axis x; Measurement line = 6 cm Freehaul distance = 6cm x 100 m = 600 m

E F

480 m – max point

STEP 3 – STEP 3 – determine free hauldetermine free haul

Cumulative volume mCumulative volume m33

Chainage ,mChainage ,m

Axis y; Measurement line AB = 12.3 cm Haul volume = 12.3cm x 250 m3

= 3075 m3

Axis x; Measurement line EF = 6.1 cm

How to determine average haul distance???

Average haul distance = Line AB /2 = 12.3 / 2 = 6.15

A

BAt the point line parallel with axis-x = Line EF

E F Average haul distance = 6.1 cm x 100 m = 610 m

Haul = Haul = Haul volume x average haul distance Haul volume x average haul distance stn.m stn.m 100 100 Haul = Haul = 3075 x 610 3075 x 610 = 18757.5 stn.m = 18757.5 stn.m 100 100

480 m – max point Chainage ,mChainage ,m

Cumulative volume mCumulative volume m33 STEP 4 – STEP 4 – determine hauldetermine haul

Axis y; Measurement line AB = 6.3 cm Overhaul volume = 6.3cm x 250 m3

= 1575 m3

How to determine average over haul distance???

Average overhaul distance = Line AB /2 = 6.3 / 2 = 3.15

At the point line parallel with axis-x = Line EF

A

B

E F

Axis x; Measurement line EF = 7.5 cmAverage overhaul distance = 7.5 cm x 100 m = 750 m

Overhaul = Overhaul = Overhaul volume (average overhaul distance – freehaul distance) Overhaul volume (average overhaul distance – freehaul distance) stn.mstn.m 100 100

Overhaul = Overhaul = 1575 (750 – 600) 1575 (750 – 600) = 2362.5 stn.m = 2362.5 stn.m 100 100

480 m – max point

STEP 5 – determine overhaulSTEP 5 – determine overhaul

Chainage ,mChainage ,m

Cumulative volume mCumulative volume m33

QUESTION 4

Distance

HAULHAUL 5.6cm X 50 = 280m

FREEHAULFREEHAUL 4 cm x 50 = 200m

OVERHAULOVERHAUL 6 cm x 50 = 300m

Volume

HAULHAUL 4.4cm x 10000 44000m3

FREEHAULFREEHAUL 0.8 cm x 10000 8000m3

OVERHAULOVERHAUL 3.6 cm x 10000 36000m3

WASTEWASTE 13 cm x 10000 130000m3

Cumulative volume mCumulative volume m33

Chainage ,mChainage ,mHAULHAUL 44000 x 280

100123200 Stn. m

FREEHAULFREEHAUL 8000 x 200100

16000Stn. m

OVERHAULOVERHAUL 36000 x (300-200)100

36000Stn. m

QUESTION 5

Distance

FREEHAULFREEHAUL 4 cm x 50 200 m

OVERHAULOVERHAUL 4.9 cm x 50 245 m

FREEHAULFREEHAUL 4 cm x 50 200 m

OVERHAULOVERHAUL 7.2 cm x 50 360 m

Volume

FREEHAULFREEHAUL 4.4 cm x 5000 22 000m3

OVERHAULOVERHAUL 3.6 cm x 5000 18 000m3

FREEHAULFREEHAUL 2 cm x 5000 10 000m3

OVERHAULOVERHAUL 4.3 cm x 5000 21 500m3

BORROWBORROW 4.5 cm x 5000 22 500m3

Cumulative volume mCumulative volume m33

Chainage ,mChainage ,m

TOTAL COST OF EARTHWORKTOTAL COST OF EARTHWORK

Freehaul prices in freehaul distance

= freehaul volume x freehaul distance x freehaul prices= (22 000 + 10 000) x 200 x RM1.25/200= RM 40 000

Overhaul prices in freehaul distance

= overhaul volume x freehaul distance x freehaul prices= (18 000 + 21 500) x 200 x RM1.25/200= RM 49 375

Overhaul prices in overhaul distance

= overhaul volume x (average overhaul distance – freehaul distance) x overhaul prices= [(18 000 x (245 – 200) x (RM1.25 + RM0.40)/100) + (21 500x (360 – 200) x (RM1.25 + RM0.40)/100)]=RM 70 125

Borrow prices = borrow volume x borrow prices= 22500 x RM 0.75 = RM 16 875

TOTAL COST OF EARTHWORK TOTAL COST OF EARTHWORK = RM 176 375= RM 176 375