Slide 1 of 7

Type - 1

Sol. (d).We have : 7 × 2 + 1 = 15, 15 × 2 + 1 = 31, 31 ×

2 + 1 = 63, 63 × 2 + 1 = 127.

1.

(a) 190 (b) 221 (c) 236 (d) 255 Sol. (c).

Moving clockwise, we have :594 ÷ 3 = 198 ; 198 ÷ 3 = 66.So, missing number = 66 ÷ 3 = 22.

2.

(a) 11 (b) 12 (c) 22 (d) 33

Directions :Find the missing character in each of the following :

7215

31

?

12763

? 66

594 198

Slide 2 of 7

Sol. (d).We have : 149 + 26 = 175, 175 + 28 = 203.So, missing number = 203 + 30 = 233.

5.

(a) 148 (b) 208 (c) 213 (d) 233

Sol. (c).Moving clockwise, the terms are :23, 33, 43, 53, 63, 73.

3.

(a) 4 (b) 305 (c) 343 (d) 729

Sol. (a).The two ends of each line segment contain a

number and its square.So, missing number = 12 = 1.

4.

(a) 1 (b) 2 (c) 3 (d) 4

? 8

125 64

27216

25? 2

4 15

64 8

? 203

149 175

Slide 3 of 7

Sol. (b).

1.

(a) 21 (b) 25 (c) 35 (d) 45 Sol. (b).

2.

(a) 12 (b) 21 (c) 24 (d) 35

Directions :In each of the following questions, a set of figures carrying certain characters, is given. Assuming that the characters in each set follow a similar pattern, find the missing character in each case.

We have : 4 9 6, 9 16 12.Let, the missing number be . Then,16 20 5 25.

x

x x x

4 9

6

9 16

12

16 ?

20

27 54

9

22 24

43

26 27

?

27 54 42 84We have : 9; 9.9 14Let, the missing number be . Then,

42 9 21.7

xx x

Slide 4 of 7

Sol. (c).We have : 5 × 3 + 4 = 19 ; 6 × 4 + 5 = 29.So, missing number = 7 × 5 + 6 = 41.

10.

(a) 25 (b) 37 (c) 41 (d) 47

Sol. (c).We have : 42 × 32 = 144, (11)2 × 92 = 9801.So, missing number = (15)2 × 62 = 8100.

8.

(a) 1216 (b) 2250 (c) 8100 (d) 11036

Sol. (b).The above three numbers are multiples of the

number at the bottom.Clearly, 36, 18 and 27 are all multiples of 9. So,

the missing number is 9.

9.

(a) 6 (b) 9 (c) 12 (d) 18

4 3

144

11 9

9801

15 6

?

12 30

144

16 40

8

36 27

?

18 32 18

19 35

4

? 57

6

29 46

5

Slide 5 of 7

Sol. (b).In the first column, 6 × 5 × 4 = 120.In the second column, 6 × 7 × 3 = 126.Let, the missing number be x. Then, in the third

column, we have :

11.

(a) 4 (b) 8 (c) 12 (d) 16

Sol. (c).In the first column, (1 + 4 + 2)2 = 49. In the second column, (4 + 2 + 2)2 = 64.Let, the missing number be x. Then, in the third

column, we have :(x + 5 + 3)2 = 169 = (13)2 x + 5 + 3 = 13

x = 5.

12.

(a) 3 (b) 4 (c) 5 (d) 6

Directions :In each of the following questions, a matrix of certain characters is given. These characters follow a certain trend, row-wise or column-wise. Find out this trend and choose the missing character from the given alternatives.

3208 5 320 8.40x x

6 6 85 7 54 3 ?

120 126 320

1 4 ?4 2 52 2 3

49 64 169

Slide 6 of 7

Sol. (a).

13.

(a) 10 (b)12 (c) 13 (d) 20

5 2 8In the first column, 40.25 4 3In the second column, 302

2 1 10 Missing number = 10.2

5 5 22 4 18 3 10

40 30 ?

Sol. (a).In the first column, (6 + 7) × 5 = 65.In the second column, (3 + 2) × 4 = 20.Let, the missing number be x. Then, (4 + x) × 9 = 45 4 + x = 5 x

= 1.

14.

(a) 1 (b) 2 (c) 3 (d) 4

5 4 96 3 ?7 2 4

65 20 45

Slide 7 of 7

Sol. (b).In the first column, (5 × 9) + (3 × 100) = 345.In the second column, (6 × 10) + (4 × 100) =

460. Missing number = (7 × 11) + (5 × 100) = 577.

15.

(a) 535 (b) 577 (c) 755 (d) 775

5 6 73 4 59 10 11

345 460 ?