12
POWER POINT PRESENTATION ON SURFACE AREA AND VOLUME OF FRUSTUM. NAME –MUDIT VINAYAK PANDEY CLASS – 10 th B ROLL NO. – 27 SUBMITTED TO: MR. AP PATEL SIR.

ppt on frustum

Embed Size (px)

Citation preview

Page 1: ppt on frustum

POWER POINT PRESENTATION ON SURFACE AREA AND VOLUME OF FRUSTUM.

NAME –MUDIT VINAYAK PANDEY

CLASS – 10th BROLL NO. – 27

SUBMITTED TO:MR. AP PATEL SIR.

Page 2: ppt on frustum

AUTUMN BREAK HOLIDAY HOME WORK

FRUSTUM AND IT’S MENSURATION.

Page 3: ppt on frustum

CONTENTS FRUSTUM BASIC INFORMATION

ABOUT FRUSTUM SURFACE AREA OF

FRUSTUM VOLUME OF FRUSTUM SMALL INFORMATION ON

VOLUME OF FRUSTUM FRUSTUM IN DAILY LIFE. QUESTION BASED ON

FRUSTUM.

Page 4: ppt on frustum

FRUSTUM

Page 5: ppt on frustum

FRUSTUM CONE RELATIONSHIP.

Page 6: ppt on frustum

BASIC INFORMATION ABOUT FRUSTUM.

• In geometry, a frustum (plural: frusta or frustums) is the portion of a solid (normally a cone or pyramid) that lies between two parallel planes cutting it. A right frustum is a parallel truncation of a right pyramid.

Page 7: ppt on frustum

SURFACE AREA OF FRUSTUM

TOTAL SURFACE AREA OF A FRUSTUM:П(R+R)L + ПR 2 + ПR 2

=П(R+R)L + П(R 2+ R2)CURVED SURFACE AREA OF A FRUSTUM:

П(R+R)L

Page 8: ppt on frustum

VOLUME OF FRUSTUM

VOLUME OF A FRUSTUM:1/3 ПH(R 2+R 2+RR)

Page 9: ppt on frustum

A FRUSTUM MAY BE FORMED FROM A RIGHT CIRCULAR CONE BY CUTTING OFF THE TIP OF THE CONE WITH A CUT PERPENDICULAR TO THE HEIGHT, FORMING A LOWER BASE AND AN UPPER BASE THAT ARE CIRCULAR AND PARALLEL. CONSIDER THE RIGHT CIRCULAR CONE.LET H BE THE HEIGHT, R THE RADIUS OF THE LOWER BASE, AND R THE RADIUS OF THE UPPER BASE. ONE PICTURE OF THE FRUSTUM IS THE FOLLOWING.GIVEN R, R, AND H, THE VOLUME OF THE FRUSTUM WILL BE-1/3 ПH(R 2+R 2+RR)

Page 10: ppt on frustum

FRUSTUM IN DAILY LIFE.

• CUP OF COLD DRINKS.

• POPCORN CARRIER.

• PYRAMIDS.

• BUCKET

• FOOD BOWL

Page 11: ppt on frustum

QUESTION BASED ON FRUSTUM.

• Question 1: A drinking glass is in the shape of a frustum of a cone of height 14 cm. The diameters of its two

circular ends are 4 cm and 2 cm. Find the capacity of the glass.• ANSWER- Capacity of glass = Volume of frustum of cone

• Therefore, the capacity of the glass is.

Page 12: ppt on frustum