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SECTION 4-5 Proving Congruence: ASA, AAS Wednesday, February 8, 2012

Geometry Section 4-5 1112

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Proving Congruence: ASA, AAS

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Page 1: Geometry Section 4-5 1112

SECTION 4-5Proving Congruence: ASA, AAS

Wednesday, February 8, 2012

Page 2: Geometry Section 4-5 1112

ESSENTIAL QUESTIONS

How do you use the ASA Postulate to test for triangle congruence?

How do you use the AAS Postulate to test for triangle congruence?

Wednesday, February 8, 2012

Page 3: Geometry Section 4-5 1112

VOCABULARY1. Included Side:

Postulate 4.3 - Angle-Side-Angle (ASA) Congruence:

Theorem 4.5 - Angle-Angle-Side (AAS) Congruence:

Wednesday, February 8, 2012

Page 4: Geometry Section 4-5 1112

VOCABULARY1. Included Side: The side between two consecutive

angles in a triangle

Postulate 4.3 - Angle-Side-Angle (ASA) Congruence:

Theorem 4.5 - Angle-Angle-Side (AAS) Congruence:

Wednesday, February 8, 2012

Page 5: Geometry Section 4-5 1112

VOCABULARY1. Included Side: The side between two consecutive

angles in a triangle

Postulate 4.3 - Angle-Side-Angle (ASA) Congruence: If two angles and the included side of one triangle are congruent to two angles and included side of a second triangle, then the triangles are congruent

Theorem 4.5 - Angle-Angle-Side (AAS) Congruence:

Wednesday, February 8, 2012

Page 6: Geometry Section 4-5 1112

VOCABULARY1. Included Side: The side between two consecutive

angles in a triangle

Postulate 4.3 - Angle-Side-Angle (ASA) Congruence: If two angles and the included side of one triangle are congruent to two angles and included side of a second triangle, then the triangles are congruent

Theorem 4.5 - Angle-Angle-Side (AAS) Congruence: If two angles and the nonincluded side of one triangle are congruent to the corresponding angles and nonincluded side of a second triangle, then the triangles are congruent

Wednesday, February 8, 2012

Page 7: Geometry Section 4-5 1112

WHAT ABOUT SSA?

Try drawing a triangle with two sides that are 5 inches and 3 inches. Then, draw a nonincluded angle that is 30°. See

how many different triangles you can draw.

Wednesday, February 8, 2012

Page 8: Geometry Section 4-5 1112

EXAMPLE 1Prove the following.

Prove: WRL ≅EDLGiven: L is the midpoint of WE, WR ED

Wednesday, February 8, 2012

Page 9: Geometry Section 4-5 1112

EXAMPLE 1Prove the following.

Prove: WRL ≅EDLGiven: L is the midpoint of WE, WR ED

1. L is the midpoint of WE, WR ED

Wednesday, February 8, 2012

Page 10: Geometry Section 4-5 1112

EXAMPLE 1Prove the following.

Prove: WRL ≅EDL

1. Given

Given: L is the midpoint of WE, WR ED

1. L is the midpoint of WE, WR ED

Wednesday, February 8, 2012

Page 11: Geometry Section 4-5 1112

EXAMPLE 1Prove the following.

Prove: WRL ≅EDL

1. Given

Given: L is the midpoint of WE, WR ED

2. WL ≅ EL

1. L is the midpoint of WE, WR ED

Wednesday, February 8, 2012

Page 12: Geometry Section 4-5 1112

EXAMPLE 1Prove the following.

Prove: WRL ≅EDL

1. Given

Given: L is the midpoint of WE, WR ED

2. WL ≅ EL 2. Def. of midpoint

1. L is the midpoint of WE, WR ED

Wednesday, February 8, 2012

Page 13: Geometry Section 4-5 1112

EXAMPLE 1Prove the following.

Prove: WRL ≅EDL

1. Given

Given: L is the midpoint of WE, WR ED

2. WL ≅ EL 2. Def. of midpoint3. ∠WLR ≅ ∠ELD

1. L is the midpoint of WE, WR ED

Wednesday, February 8, 2012

Page 14: Geometry Section 4-5 1112

EXAMPLE 1Prove the following.

Prove: WRL ≅EDL

1. Given

Given: L is the midpoint of WE, WR ED

2. WL ≅ EL 2. Def. of midpoint3. ∠WLR ≅ ∠ELD 3. Vertical Angles

1. L is the midpoint of WE, WR ED

Wednesday, February 8, 2012

Page 15: Geometry Section 4-5 1112

EXAMPLE 1Prove the following.

Prove: WRL ≅EDL

1. Given

Given: L is the midpoint of WE, WR ED

2. WL ≅ EL 2. Def. of midpoint3. ∠WLR ≅ ∠ELD 3. Vertical Angles4. ∠LWR ≅ ∠LED

1. L is the midpoint of WE, WR ED

Wednesday, February 8, 2012

Page 16: Geometry Section 4-5 1112

EXAMPLE 1Prove the following.

Prove: WRL ≅EDL

1. Given

Given: L is the midpoint of WE, WR ED

2. WL ≅ EL 2. Def. of midpoint3. ∠WLR ≅ ∠ELD 3. Vertical Angles4. ∠LWR ≅ ∠LED 4. Alternate Interior Angles

1. L is the midpoint of WE, WR ED

Wednesday, February 8, 2012

Page 17: Geometry Section 4-5 1112

EXAMPLE 1Prove the following.

Prove: WRL ≅EDL

1. Given

Given: L is the midpoint of WE, WR ED

2. WL ≅ EL 2. Def. of midpoint3. ∠WLR ≅ ∠ELD 3. Vertical Angles4. ∠LWR ≅ ∠LED 4. Alternate Interior Angles5. WRL ≅EDL

1. L is the midpoint of WE, WR ED

Wednesday, February 8, 2012

Page 18: Geometry Section 4-5 1112

EXAMPLE 1Prove the following.

Prove: WRL ≅EDL

1. Given

Given: L is the midpoint of WE, WR ED

2. WL ≅ EL 2. Def. of midpoint3. ∠WLR ≅ ∠ELD 3. Vertical Angles4. ∠LWR ≅ ∠LED 4. Alternate Interior Angles5. WRL ≅EDL 5. ASA

1. L is the midpoint of WE, WR ED

Wednesday, February 8, 2012

Page 19: Geometry Section 4-5 1112

EXAMPLE 2Prove the following.

Prove: LN ≅ MNGiven: ∠NKL ≅ ∠NJM, KL ≅ JM

Wednesday, February 8, 2012

Page 20: Geometry Section 4-5 1112

EXAMPLE 2Prove the following.

Prove: LN ≅ MNGiven: ∠NKL ≅ ∠NJM, KL ≅ JM

1. ∠NKL ≅ ∠NJM, KL ≅ JM

Wednesday, February 8, 2012

Page 21: Geometry Section 4-5 1112

EXAMPLE 2Prove the following.

Prove: LN ≅ MNGiven: ∠NKL ≅ ∠NJM, KL ≅ JM

1. ∠NKL ≅ ∠NJM, KL ≅ JM 1. Given

Wednesday, February 8, 2012

Page 22: Geometry Section 4-5 1112

EXAMPLE 2Prove the following.

Prove: LN ≅ MNGiven: ∠NKL ≅ ∠NJM, KL ≅ JM

1. ∠NKL ≅ ∠NJM, KL ≅ JM 1. Given

2. ∠JNK ≅ ∠KNJ

Wednesday, February 8, 2012

Page 23: Geometry Section 4-5 1112

EXAMPLE 2Prove the following.

Prove: LN ≅ MNGiven: ∠NKL ≅ ∠NJM, KL ≅ JM

1. ∠NKL ≅ ∠NJM, KL ≅ JM 1. Given

2. ∠JNK ≅ ∠KNJ 2. Reflexive

Wednesday, February 8, 2012

Page 24: Geometry Section 4-5 1112

EXAMPLE 2Prove the following.

Prove: LN ≅ MNGiven: ∠NKL ≅ ∠NJM, KL ≅ JM

1. ∠NKL ≅ ∠NJM, KL ≅ JM 1. Given

2. ∠JNK ≅ ∠KNJ 2. Reflexive

3. JNM ≅KNL

Wednesday, February 8, 2012

Page 25: Geometry Section 4-5 1112

EXAMPLE 2Prove the following.

Prove: LN ≅ MNGiven: ∠NKL ≅ ∠NJM, KL ≅ JM

1. ∠NKL ≅ ∠NJM, KL ≅ JM 1. Given

2. ∠JNK ≅ ∠KNJ 2. Reflexive

3. JNM ≅KNL 3. AAS

Wednesday, February 8, 2012

Page 26: Geometry Section 4-5 1112

EXAMPLE 2Prove the following.

Prove: LN ≅ MNGiven: ∠NKL ≅ ∠NJM, KL ≅ JM

1. ∠NKL ≅ ∠NJM, KL ≅ JM 1. Given

2. ∠JNK ≅ ∠KNJ 2. Reflexive

3. JNM ≅KNL 3. AAS

4. LN ≅ MN

Wednesday, February 8, 2012

Page 27: Geometry Section 4-5 1112

EXAMPLE 2Prove the following.

Prove: LN ≅ MNGiven: ∠NKL ≅ ∠NJM, KL ≅ JM

1. ∠NKL ≅ ∠NJM, KL ≅ JM 1. Given

2. ∠JNK ≅ ∠KNJ 2. Reflexive

3. JNM ≅KNL 3. AAS

4. LN ≅ MN 4. CPCTC

Wednesday, February 8, 2012

Page 28: Geometry Section 4-5 1112

EXAMPLE 3On a template design for a certain envelope, the top

and bottom flaps are isosceles triangles with congruent bases and base angles. If EV = 8 cm and the height of

the isosceles triangle is 3 cm, find PO.

Wednesday, February 8, 2012

Page 29: Geometry Section 4-5 1112

EXAMPLE 3On a template design for a certain envelope, the top

and bottom flaps are isosceles triangles with congruent bases and base angles. If EV = 8 cm and the height of

the isosceles triangle is 3 cm, find PO.

EV ≅ PL, so each segment has a measure of 8 cm. If an auxiliary line is drawn

from point O perpendicular to PL, you will have a right triangle formed.

Wednesday, February 8, 2012

Page 30: Geometry Section 4-5 1112

EXAMPLE 3On a template design for a certain envelope, the top

and bottom flaps are isosceles triangles with congruent bases and base angles. If EV = 8 cm and the height of

the isosceles triangle is 3 cm, find PO.

EV ≅ PL, so each segment has a measure of 8 cm. If an auxiliary line is drawn

from point O perpendicular to PL, you will have a right triangle formed.

In the right triangle, we have one leg (the height) of 3 cm. The auxiliary line will bisect PL, as point O is equidistant

from P and L.

Wednesday, February 8, 2012

Page 31: Geometry Section 4-5 1112

EXAMPLE 3

Wednesday, February 8, 2012

Page 32: Geometry Section 4-5 1112

EXAMPLE 3

a2 + b2 = c2

Wednesday, February 8, 2012

Page 33: Geometry Section 4-5 1112

EXAMPLE 3

a2 + b2 = c2

42 + 32 = (PO)2

Wednesday, February 8, 2012

Page 34: Geometry Section 4-5 1112

EXAMPLE 3

a2 + b2 = c2

42 + 32 = (PO)2

16 + 9 = (PO)2

Wednesday, February 8, 2012

Page 35: Geometry Section 4-5 1112

EXAMPLE 3

a2 + b2 = c2

42 + 32 = (PO)2

16 + 9 = (PO)2

25 = (PO)2

Wednesday, February 8, 2012

Page 36: Geometry Section 4-5 1112

EXAMPLE 3

a2 + b2 = c2

42 + 32 = (PO)2

16 + 9 = (PO)2

25 = (PO)2

25 = (PO)2

Wednesday, February 8, 2012

Page 37: Geometry Section 4-5 1112

EXAMPLE 3

a2 + b2 = c2

42 + 32 = (PO)2

16 + 9 = (PO)2

25 = (PO)2

25 = (PO)2

PO = 5 cm

Wednesday, February 8, 2012

Page 38: Geometry Section 4-5 1112

CHECK YOUR UNDERSTANDING

Review p. 276 #1-5

Wednesday, February 8, 2012

Page 39: Geometry Section 4-5 1112

PROBLEM SET

Wednesday, February 8, 2012

Page 40: Geometry Section 4-5 1112

PROBLEM SET

p. 277 #7-23 odd, 35

“There is only one you...Don’t you dare change just because you’re outnumbered.” - Charles Swindoll

Wednesday, February 8, 2012