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GATE Life Sciences (XL)2010 Save paper… Save trees… For more Questions and Resources for your CSIR/ICMR/DBT/ICAR/GATE/UGC/JRF NET Life Science Examination please visit: www.easybiologyclass.com 1 GATE Life Sciences (XL) 2010 (Graduate Aptitude Test in Engineering: Original Question Paper) Microbiology (K) Optional Question Paper Questions 1 – 10 carries 1 mark each 1. A electron microscope has higher resolution as compared to the light microscope. This is because: a. The wavelength of an electron is longer than the wavelength of light b. The wavelength of an electron is shorter than the wavelength of light c. The electrons can penetrate the sample better d. They use different stains 2. Bacterial cell lysis by lysozyme is due to the: a. Hydrolysis of α‐1,4‐glycosidic bonds between the N‐acetylglucosamine and N‐acetylmuramic acid b. Inhibition of cell wall synthesis c. Hydrolysis of pentapeptide bridges d. Hydrolysis of β‐1,4‐glcosidic bonds between the N‐acetylglucosamine and N‐ acetylmuramic acid 3. The recombination frequencies between three genes x, y, and z are as follows: X – y = 2.6%, y – z = 1.4% and x – z = 1.2%. Then the gene order is: a. x–z–y b. x–y–z c. y–x–z d. z–x–y 4. A mutant phenotype due to a nonsense mutation can be rescued by a mutation in tRNA gene. This rescue is an example of: a. Induced mutation b. Suppressor mutation c. Spontaneous mutation d. Deletion mutation 5. Ames test is performed to detect: a. Mutagen b. pH c. nutrient stress d. salinity www.easybiologyclass.com

GATE Life Sciences (XL) 2010 Question Paper Part 5 Microbiology (Optional Paper) by Easybiologyclass

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Page 1: GATE Life Sciences (XL) 2010 Question Paper Part 5 Microbiology (Optional Paper) by Easybiologyclass

GATELifeSciences(XL)‐2010 Savepaper…Savetrees…

FormoreQuestionsandResourcesforyourCSIR/ICMR/DBT/ICAR/GATE/UGC/JRFNETLifeScienceExaminationpleasevisit:

www.easybiologyclass.com 1

GATELifeSciences(XL)2010(GraduateAptitudeTestinEngineering:OriginalQuestionPaper)

Microbiology(K)OptionalQuestionPaper

Questions1–10carries1markeach

1. Aelectronmicroscopehashigherresolutionascomparedtothelightmicroscope.Thisisbecause:

a. Thewavelengthofanelectronislongerthanthewavelengthoflightb. Thewavelengthofanelectronisshorterthanthewavelengthoflightc. Theelectronscanpenetratethesamplebetterd. Theyusedifferentstains

2. Bacterialcelllysisbylysozymeisduetothe:a. Hydrolysis of α‐1,4‐glycosidic bonds between theN‐acetylglucosamine and

N‐acetylmuramicacidb. Inhibitionofcellwallsynthesisc. Hydrolysisofpentapeptidebridgesd. Hydrolysisofβ‐1,4‐glcosidicbondsbetweentheN‐acetylglucosamineandN‐

acetylmuramicacid3. Therecombinationfrequenciesbetweenthreegenesx,y,andzareasfollows:

X–y=2.6%,y–z=1.4%andx–z=1.2%.Thenthegeneorderis:

a. x–z–yb. x–y–zc. y–x–zd. z–x–y

4. Amutantphenotypedue toanonsensemutationcanberescuedbyamutation intRNAgene.Thisrescueisanexampleof:

a. Inducedmutationb. Suppressormutationc. Spontaneousmutationd. Deletionmutation

5. Amestestisperformedtodetect:a. Mutagenb. pHc. nutrientstressd. salinitywww.ea

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6. WildtypeE.coliformspurplecolouredcoloniesonEMB‐lactoseplate.Thisisduetoa. IncreaseinpHofthemediumb. DecreaseinthepHofthemediumc. Secretionofpurplecolouredpigmentd. Secretionofβ‐galactosidase

7. TheresistanceofalambdalysogenicE.colitoreinfectionbylambdaismediatedby:a. BlockingentryoftheincominglambdaDNAb. DegradingtheincominglambdaDNAc. BlockingtranscriptionoftheincominglambdaDNAd. Triggeringmutationofthelambdareceptorofthehost

8. Pasteurizationofmilkiscarriedoutby:a. Boilingfor5minb. Heatingat72oCfor30minutesc. Heatingat63oCfor15minutesd. Heatingat63oCfor30minutes

9. Agrowingbacterialculturewithadoublingtimeof20minutesreachescelldensityof2X108cells/mlin3hours.Howmuchtimewouldittaketoreachthecelldensityof1X108cells/ml?

a. 200minb. 180minc. 160mind. 90min

10. Thequickestwaytodeterminebacterialgrowthintermsofviablecellsisthrough:a. Mostprobablenumber(MPN)techniqueb. Spreadplatemethodc. Pourplatemethodd. Slideculturetechnique

Questions1–10carries1markeach

11. Match the scientist from Group I with the corresponding contribution listed inGroupIIGroupI GroupIIP.RobertKoch 1.DiscoveryofendosporesQ.WalterHesse 2.DisprovedspontaneousgenerationR.LouisPasteur 3.DiscoveryofcausativeagentoftuberculosisS.FerdinandCohn 4.Useofagarassolidmedia 5.Inventionofmicroscopewww.ea

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a. P–5,Q–3,R–4,S–2b. P–3,Q–4,R–2,S–5c. P–3,Q–4,R–1,S‐5d. P–3,Q–4,R–2,S–1

12. Super‐antigenselicitaverystrongTcellresponsebecausethey:a. BindtothespecificantigenbindingsiteontheTcellreceptor(TCR)b. BindtothesiteonTcellreceptor(TCR)that isoutsidetheantigen‐specific

bindingsitec. DirectlyactivatetheTcellwithoutthehelpofantigenpresentingcellsd. Directlyinducecytokinesecretionbymacrophages

13. MHC‐Igroovecanbelocatedwithpeptidesononly8‐10aminoacidsbecause:a. MHC‐Igrooveisclosedonbothendsb. Fragmentsofonly8‐10aminoacidsaregeneratedinMHC‐Ibearingcellsc. β2‐microglobulinofMHCIpreventsthebindingoflargepeptidestoMHC‐Id. βpolypeptidesofMHC‐Ipreventsbindingof8‐10aminoacid longpeptides

toMHC‐I14. inalacOcLacZ‐/lacO+lacZ+partialdiploidofthetwolacZenzymes,onlythemutant

enzyme (lacZ‐) is synthesized constitutively. This observation shows that lacOcmutationis:

a. trans‐dominantb. trans‐recessivec. cis‐dominantd. cis‐recessive

15. Whichoneofthefollowingeventsoccursinprokaryotesbutnotineukaryotes?a. Proteinphosphorylationb. RNApolymeraseandpromoterinteractionc. Controloftranscriptionbyattenuationd. FormationofOkazakifragments

16. MatchthepathogeninGroupIwiththecorrespondingdiseaseinGroupIIGroupI GroupIIP.Bacteria 1.MeaslesQ.Virus 2.CandidiasisR.Fungi 3.MalariaS.Protozoa 4.Bovinespongiformencephalitis 5.Tuberculosisa. P–1,Q–2,R–4,S–5b. P–1,Q–4,R–2,S–3www.ea

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c. P–5,Q–1,R–4,S–2d. P–5,Q–1,R–2,S–3

17. A bacterial culture was diluted 1000 fold and 0.1 ml of this diluted sample wasspreadperplateonnutrientagar.Inatriplicaterun,thenumberofcoloniesformedis 121, 93, 86. The number of colony forming units/ml in the original bacterialcultureis:

a. 106b. 105c. 103d. 102

18. MatchthemicroorganisminGroupIwiththeapplicationinGroupIIGroupI GroupIIP.Aspergillusoryzae 1.MetaloreleachingQ.Brevibacteriumflavum 2.GlucoamylaseproducerR.Thiobacillusferroxidans 3.BreadmakingS.Saccharomycescervisiae 4.GlutamicacidproducerT.Rhizobiummeliloti 5.Penicilliumproducer 6.Symbioticnitrogenfixera.P–1,Q–6,R–4,S–5,T–2b.P–2,Q–4,R–1,S–3,T–6c.P–4,Q–1,R–6,S–3,T–5d.P–6,Q–2,R–3,S–5,T–1

19. AmutantofE.coligrowsnormallyonglucoseoronglycerolbutnotonacetate.Themostlikelymetabolicpathwaythatisdefectiveinthismutantis:

a. Glyoxalatecycleb. Hexosemonophosphateshuntc. Krebscycled. Entner–Doudoroffpathway

20. MatchtheresistancemechanisminGroupIwiththeantibioticingroupIIGroupI GroupIIP.β‐Lactamase 1.AminoglycosidesQ.Enhancedfolatemetabolism 2.PenicillinsR.Drugefflux 3.SulfadrugsS.Phosphorylationofthedrug 4.TetracyclinsT.MutantRNAPolymerase 5.Naladixicacid 6.Rifamycin

a. P–2,Q–3‐R–4,S–5,T–6b. P–3,Q–4,R–1,S–6,T–5www.ea

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c. P–2,Q–3,R–4,S–1,T–6d. P–1,Q–2,R–3,S–4,T–6

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