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Application of Integration Business and Economics

Application of integration

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Page 1: Application of integration

Application of Integration

Business and Economics

Page 2: Application of integration

Derivative as rate of change

• Measurements described as a rate of change is a derivative

• Key words:Cost PER unit produced, profit PER unit soldCost FOR EVERY YEAR, value PER yearMarginal cost: additional cost for producing one

extra item of a product. Additional cost per unit of production

Page 3: Application of integration

Derivative as rate of change

Key words: Marginal revenue: additional revenue by

increasing product sales by 1 unit: extra revenue PER 1 unit increase in sales

Marginal profit: additional profit for each unit sold: MP=MR-MC.

Page 4: Application of integration

Demand curve as a rate of change

Demand function: Quantity a consumer is willing to buy for each unit

increase in price

Page 5: Application of integration

Supply curve as a rate of change

Supply functionThe quantity of goods a producer is willing to

produce for every unit increase in price

Page 6: Application of integration

Integral as Anti derivative

dxxFxF '

axdxaC

adxdCadxdC

COST PER UNIT PRODUCED

Page 7: Application of integration

Integral as an antiderivative

Example 1.1If cost of printing 1 book is 90 pesos, what is the

cost of printing 500 books?

xC

dxdCdxdC

90

9090

Php 000,4550090

500At

C

x

Page 8: Application of integration

Integral as antiderivative

If cost of printing 1 book is 90 pesos, what is the cost of printing 500 books?

000,450000,45

90 90 5000

500

0

C

xdxC

Page 9: Application of integration

Integral as antiderivative

Example 1.2If the cost of producing 1 book unit is 90+0.01x,

what is the cost of producing 500 books?

dxxdCxdxdC 01.09001.090

500

0

Php 250,46200

000,250000,452

90 5000

2

1001

xxC

Page 10: Application of integration

Integral as antiderivative

Example 1.3In a certain factory the marginal cost of is 3(q-4)^2 when the level of production is q units.How much would the total cost increase if

production is increased from 6 to 10?

3

22

4

4343

qC

dqqdCqdqdC

Page 11: Application of integration

Integral as antiderivative

Example 1.3Increase in total cost when production is

increased from 6 to 10.

dqqCC 210

643610

Php 208

8216264cost Total 33106

3

q

Page 12: Application of integration

Definite Integral as area between curves

Example 1.4 (Area between curves)If the marginal revenue from selling books is

And the marginal cost is

xRdxdR 05.01'

22' xCdxdC

Page 13: Application of integration

Definite integral as area between curves

Find the net profit when production is increased from 1 to 3?

Page 14: Application of integration

Definite integral as area between curves

3

1P

dxxdxxP 23

1

3

12 05.01

Php 22

13

2

205.01

51

51

31

401

31

409

31

3312

401

23

1

xxx

dxxxP

Page 15: Application of integration

Interpretation of graphs

Example 1.5 (Area between curves)Suppose that t years from now, investment A

will generate a profit per year according to

While investment B will generate a profit per year according to

21 5' ttP

ttP 520'2

Page 16: Application of integration

Interpretation of graphs

a. What information is revealed by the two functions?

Page 17: Application of integration

Graphs and definite integral

b. What is the accumulated profit of investment A after 6 years?

c. What is the accumulated profit of investment B after 6 years?

Page 18: Application of integration

Definite integral and area under the curve

Php 1027230

55

1

60

3312

6

01

P

ttdttP

Page 19: Application of integration

Definite integral and area under the curve

Php 21090120

20 520

2

60

225

6

02

P

ttdttP

Page 20: Application of integration

Definite integral and area between curves

c. Identify the region in the graph which represents the excess profit earned by investment A over investment B over 6 years.

Page 21: Application of integration

Definite integral and area between curves

108729090

15515

5 520

60

3312

252

6

0

26

0

6

0

n

n

n

P

tttdtttP

dttdttP