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This topic is based on subneting. I interoduce about how to devide network into subnetwork so that we can manage the wastege of IP address
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A seminar on Subnetting
The Institution of electronics and telecommunication engineers, Delhi centre.
Presented by: SanjayStream: CS
Guided by: Mr. Nibhesh kr. Das
What was that masked address?
To break the network down into pieces, each of which can be addressed separately.Controls network trafficReduces broadcastsOrganization of IP address space
Default Class C address is divided into network and host portions as follows:
N . N . N . H To subnet we “borrow” bits from the host
portion of the address (8 bits for Class C)N . N . N . x x x x x x x x
Borrowing n bits yields 2n – 2 subnets. Leaving n bits yields 2n – 2 hosts. For a class C, we can borrow from 2 to 6
bits. Why not 1 bit? (How many usable subnets?) Why not 7 bits? (How many usable hosts?)
Suppose we need 14 usable subnets, how many bits do we borrow?Remember, borrowing n bits give us:
2n – 2 subnetsTry borrowing 3 bits (n = 3):
23 – 2 = 8 – 2 = 6 usable subnets (not
enough)Try borrowing 4 bits
24 – 2 = 16 – 2 = 14 usable subnets (enough)
Write it with the network octet in binary:
200.129.41.0000 0000 break here
Borrowing 4 bits yields 14 usable subnets How many usable hosts per subnet?
Same formula as subnets (2n – 2) 4 host bits (n = 4)24 – 2 = 16 – 2
= 14 usable hosts per subnet
subnet bits host bits
Examples: First usable 200.129.41.0001 ^ 0000
subnet address: 200.129.41.16 First usable host 200.129.41.0001 ^ 0001 on the first subnet: 200.129.41.17 Second usable host 200.129.41.0001 ^ 0010
on the first subnet: 200.129.41.18...
Last usable host 200.129.41.0001 ^ 1110on the first subnet: 200.129.41.30
Broadcast address 200.129.41.0001 ^ 1111for the first subnet: 200.129.41.31
Examples:Second usable 200.129.41.0010 ^ 0000
subnet address: 200.129.41.32Third usable 200.129.41.0011 ^ 0000
subnet address: 200.129.41.48Fourth usable 200.129.41.0100 ^ 0000
subnet address: 200.129.41.64...
Last usable 200.129.41.1110 ^ 0000subnet address: 200.129.41.224
The subnet mask (in binary) has:all ones in the network and subnet portion of the
addressall zeros in the host potion of the addressThe subnet mask for the previous example is:
255.255.255. 240255.255.255. 1111^ 0000 (128 + 64 + 32 + 16 =240)
ANDing this mask with any valid host address on the network will always yield the subnet address for that host.
Example (our subnet mask is 255.255.255.240)IP host address: 200.129. 41.23Last octet to binary: 200.129. 41.0001 0111AND subnet mask: 255.255.255.1111 0000 200.129. 41.0001 0000Subnet Address: 200.129. 41.16
So the host address 200.129. 41.23 is on the 200.129.41.16 subnet.
Default Class B address is divided into network and host portions as follows:
N . N . H . H To subnet we “borrow” bits from the
host portion of the address (16 bits for Class B)
N . N . x x x x x x x x . x x x x
x x x x For a class B, we can borrow from 2 to
14 bits.
Suppose we need 80 usable subnets, how many bits do we borrow?Remember, borrowing n bits give us:
2n – 2 subnetsTry borrowing 6 bits (n = 6):
26 – 2 = 64 – 2 = 62 usable subnets (not
enough)Try borrowing 7 bits
27 – 2 = 128 – 2 = 126 usable subnets
(enough)
Write it with the network octets in binary:
132.178.0000000 0.00000000
break here
Borrowing 7 bits yields 126 usable subnets How many usable hosts per subnet?
Same formula as subnets (2n – 2) 9 host bits (n = 9)29 – 2 = 512 – 2
= 510 usable hosts per subnet
subnet bits host bits
Examples: First usable 132.178.0000001 ^ 0.00000000
subnet address: 132.178.2.0 First usable host 132.178.0000001 ^ 0.00000001
on the first subnet: 132.178.2.1 Second usable host 132.178.0000001 ^ 0.00000010
on the first subnet: 132.178.2.2 .
.
.
Last usable host 132.178.0000001 ^ 1.11111110
on the first subnet: 132.178.3.254 Broadcast address 132.178.0000001 ^ 1.11111111
for the first subnet: 132.178.3.255
Examples: Second usable 132.178.0000010 ^
0.00000000 subnet address: 132.178.4.0 Third usable 132.178.0000011 ^
0.00000000 subnet address: 132.178.6.0 . . .
Ninety-first usable 132.178.1011011 ^ 0.00000000subnet address: 132.178.182.0
. . .
Last usable 132.178.1111110 ^ 0.00000000subnet address: 132.178.252.0
The subnet mask for this example is:255.255.254.0255.255.1111111 ^ 0.00000000
ANDing this mask with any valid host address on this network will always yield the subnet address.
Example:IP host address: 132.178.119.112
Last octets to binary: 132.178.0111011 ^ 1.01110000
AND subnet mask: 255.255.1111111 ^ 0.00000000
132.178.0111011 ^ 0.00000000
Subnet Address: 132.178.118.0
Thank You….