University of Texas Pan Am Dr. John P. Abraham
Information Technology
Computer ArchitectureDr. John P. Abraham
University of Texas Pan Am Dr. John P. Abraham
Computer Architecture
• The computer architecture is a branch of study that deals with
• designing of processors• their instruction sets• organizing various components to facilitate
most efficient communication between them• without significantly increasing cost.
University of Texas Pan Am Dr. John P. Abraham
Digital Computers
• Analog• Digital
– Distinct binary signals
• Instruction set– Predetermined by circuitry
University of Texas Pan Am Dr. John P. Abraham
CISC/RISC
• CISC– More instructions in the instruction set
• Easier for programmers• More complex and slower machines
• RISC– Simpler instructions
– Fewer instructions
University of Texas Pan Am Dr. John P. Abraham
A computer
• Input/output • Processor
– ALU
– Control Unit
– Registers
– Connecting busses
University of Texas Pan Am Dr. John P. Abraham
Basic Operation of a CPU
• Obtain instructions kept in the memory, one at a time
• Decode• Execute• Write the result back
University of Texas Pan Am Dr. John P. Abraham
Binary number system• Calculate value of 11110101 in decimal • Number from right to left Digit value Value
• 1 1 1 x 1 = 1• 0 2 0 x 2 = 0• 1 4 1 x 4 = 4• 0 8 0 x 8 = 0• 1 16 1 x 16 = 16• 1 32 1 x 32 = 32• 1 64 1 x 64 = 64• 1 128 1 x 128 = 128 • Total 245
University of Texas Pan Am Dr. John P. Abraham
Signed binary• signed-magnitude
• The most significant bit (MSB) is set aside to indicate the sign, zero for positive and 1 for negative.
• One’s-complement• The MSB of a negative number will begin with a one
and a positive number with a zero. 0011 will represent +3 and 1100 (complement of the positive 3) will represent -3.
• Two’s-complement. • a negative number is represented by complementing the
bits of the positive number and adding a 1. a –3 is represented as 1101 (complement of 0011 is 1100, and add a 1).
University of Texas Pan Am Dr. John P. Abraham
Two’s complement• a binary number’s MSB is a zero then it is a
positive and no further action is necessary. • If the MSB is 1, it is a negative number. • Suppose the number is 10000001, we know it is
a negative number. Complement the bits and add a 1, we get 01111110 +1 = 01111111 which is 127.
• The sign is already determined to be negative it is –127.
University of Texas Pan Am Dr. John P. Abraham
ASCII Character Set• a specific binary sequence must be established for
representing the alphabets, numeric symbols and other special symbols that are in use in English as well as other languages of the world.
• An agreement was reached in 1968 to represent all English alphabets
• The standard ASCII character set consists of 128 decimal numbers ranging from zero through 127
• The Extended ASCII Character Set also consists of 128 decimal numbers and ranges from 128 through 255 representing additional special, mathematical, graphic, and some foreign characters.
University of Texas Pan Am Dr. John P. Abraham
ASCII Character Set• The first 32 (0 to 31) ASCII codes are for
special purposes such as line feed, carriage return, form feed, bell, etc.
• The ASCII can only represent languages that use Roman Alphabets such as English.
• To represent an ASCII character we need 7 bits and an extended ASCII character requires 8 bits; therefore, we set aside a byte for it and a byte happens to be the smallest addressable memory unit.
University of Texas Pan Am Dr. John P. Abraham
Unicode
• Unicode provides a unique number for every character regardless of the platform, the program, or the language.
• Unicode uses two bytes to represent one character. This means we can have 65,536 possible symbols in a given alphabet.
• encoding scheme that IBM mainframes used is the Extended Binary Coded Decimal Interchange Code (EBCDIC).
University of Texas Pan Am Dr. John P. Abraham
Numbering schemes
• Binary• Octal
– Since the basic addressable memory unit is a byte an octal (base eight) makes sense and some early computers used the octal system. Octal numbering system uses 8 symbols, 0 to 7. The next number after 7 is 10.
• Hexadecimal
University of Texas Pan Am Dr. John P. Abraham
Hexadecimal• Hexadecimal (base 16) numbers give more compactly
written numbers and programmers use it very often.• It uses 15 symbols 0-9 and A-F. The A stands for
decimal 10, B for 11, C for 12, D for 13, E for 14 and F for 15.
• These 15 symbols can be represented using four bits or a nibble. For example , 1111 will represent F (decimal 15).
• Two hexadecimal digits can be represented in one byte; FF representing 255.
• After the F, the next number is 10 (decimal 16).
University of Texas Pan Am Dr. John P. Abraham
Boolean Operations
• The mathematics used in digital systems is the special case of Boolean Algebra.– the variables only assumes only two values (0 or
1). • The basic operations of Boolean Algebra are:
NOT, AND, OR, XOR, NAND and NOR.
University of Texas Pan Am Dr. John P. Abraham
Not gate
• The NOT operation gives the inverse (complement) of a Boolean variable. For example NOT(True) is false.
University of Texas Pan Am Dr. John P. Abraham
AND gate• The AND operation is a logical multiplication. • An example: IF US CITIZEN AND AGE GREATER
THAN OREQUAL TO 18 THEN ELIGIBLE TO VOTE.
• There are two inputs, citizenship and age, and one output, voting eligibility, in this example.
• In a situation where a person is a US citizen and 20 years of age, the inputs will be TRUE and TRUE. The output also will be TRUE. If one or both of the inputs are FALSE then the output will be FALSE.
University of Texas Pan Am Dr. John P. Abraham
OR gate
• The OR operation is a local addition. • An example: If grade == 90 or grade >90 then
Grade = ‘A’. • In an OR operation only one condition has to be
true for the output to be true.
University of Texas Pan Am Dr. John P. Abraham
Half Adder#include <iostream.h> void main() { short x,y, sum, carry; bool a,b,c,d; cout <<"Enter two bits to add seperated by a space ";cin >> x>>y; a=x==1; b=y==1; //actually c++ assigns 0 for false and 1 for true,
we could have read these directly; c=(a||b) && !(a&&b); d=(a&&b); 9sum=c?1:0; //if c is true then sum gets 1 else sum gets 0 carry=d?1:0; cout <<x <<"+"<<y <<"="<<carry<<sum<<endl; if (a = true) cout <<"it is true"; if (a) cout << "it is ture"; }
University of Texas Pan Am Dr. John P. Abraham
Computer Programming Languages
• Computers perform operations such as moving data and data manipulation by activating switches and gates.
• Instructions to do that also must be given in the form of 1s and 0s or on and off.
• When we program computers using just ones and zeros we are using the “machine language”.
University of Texas Pan Am Dr. John P. Abraham
Structure of 8088 Microprocessor
• execution unit (EU) • the bus interface unit (BIU)
University of Texas Pan Am Dr. John P. Abraham
Execution Unit (EU)
• the control logic for decoding and executing instructions
• ALU for performing arithmetic and logic operations
• A set of general purpose registers
University of Texas Pan Am Dr. John P. Abraham
Bus interface unit (BIU)• A bus is a set of wires that connects the
various components of a computer together and transfers signals and data between them.
• The number of lines a bus has depends on the architecture of the microprocessor and is directly proportional to the CPU speed.
– ControlDataAddress
University of Texas Pan Am Dr. John P. Abraham
3 Functions of the BUS
• memory address transfers, data transfers and control signal transfers.
• One set of physical wires may handle all three operations one at a time, or there may be different sets of wires for each, the address bus, data bus and the control bus.
• If we say that the hypothetical processor is 16 bit, then 16 bits of data should be transferred at the same time.
University of Texas Pan Am Dr. John P. Abraham
Major microprocessor components
• PC- Program Counter• MBR- Memory Buffer Register• MAR- Memory Address Register• ALU- Arithmetic Logic Unit• IR- Instruction Register• General Purpose Registers.
University of Texas Pan Am Dr. John P. Abraham
Microprocessor operation
• When a program begins execution, the program counter (PC, a register inside the CPU) has the address of the next instruction to fetch.
• this address is placed there initially by the operating system and updated automatically by the CPU.
• There are three additional registers, the instruction register (IR), memory address register (MAR) and the memory buffer register (MBR) that work together to fetch the instruction.
University of Texas Pan Am Dr. John P. Abraham
Microprocessor Operation (2)
• The address from the PC is moved to the MAR.– The reason for this is that the address bus is
connected to the MAR and all addresses issued must go through this register.
• Then the address contained in the MAR is placed on the address bus and the READ line is asserted on the control bus.
University of Texas Pan Am Dr. John P. Abraham
Microprocessor Operation(3)
• The memory whose address is found on the address bus places its contents on the data bus.
• The only register that is connected to the data bus is the MBR, and all data should go in an out through this register.
• Thus the data on the data bus is copied into the MBR. The instruction is now copied on to the IR to free up the MBR to handle another transfer.
University of Texas Pan Am Dr. John P. Abraham
Microprocessor Operation(4)
• The contents of the PC will be now incremented by one instruction.
• The instruction is then decoded and executed.
• In practice, more than one instruction is read during an instruction cycle. Additional instructions are kept in temporary storage registers such as the Instruction Buffer Register (IBR).
University of Texas Pan Am Dr. John P. Abraham
The Program Counter
• The size of the PC depends on the number of address lines of the CPU.
• Let us assume that the CPU has 16 address lines. Then the PC should be able to address 65,536 locations.
• Initially the CPU starts its operation based on the contents of the PC. Assume that initially the PC contains the value 0000h where “h” stands for hexadecimal notation.
University of Texas Pan Am Dr. John P. Abraham
The Fetch Cycle
• MAR holds the address of the memory location from which the instruction is to be fetched.
• At the start up, the CPU performs an instruction fetch.
• Instruction fetch involves reading the instruction stored in the memory.
• The location from which the instruction is read is derived from the PC.
University of Texas Pan Am Dr. John P. Abraham
The Decode Cycle
• An instruction will have an opcode and none, one or more operands (data to operate on)
• The opcode is defined as the type of operation the CPU has to perform.
• The number of bits assigned to the opcode will determine the maximum number of instructions that processor is allowed to have.
University of Texas Pan Am Dr. John P. Abraham
Opcode
• suppose that the length of an instruction (opcode and operand) is 16 bits, 4 bits are allocated for the instructions and the remaining 12 bits are allocated for an operand.
• Four bits can give us a maximum of sixteen instructions. Each of these 16 bit patterns, ranging from decimal 0 to 15, or binary 0 to 1111, or hexadecimal 0 to F will stand for a particular instruction.
University of Texas Pan Am Dr. John P. Abraham
Operations of a Microprocessor
• This hypothetical computer has only one user addressable register, which is the accumulator (AC).
• When a load (LD) is executed, the contents of the location as indicated by the operand is brought into the AC
• The reverse happens in a store (ST).
University of Texas Pan Am Dr. John P. Abraham
Operations of a Microprocessor(2)
• When an add (A) is executed, the value contained in the memory location as indicated by the operand is added to the contents of the AC, and the result is placed back in the AC.
• The add immediate (AI) differs from the add (A) in that the operand is what is added, not the content of the memory pointed by the operand.
University of Texas Pan Am Dr. John P. Abraham
Program Example
• B = B + A • C = B + 2• The variable A is kept in memory location 200h• Variable B in 201h• Variable C in 202h. • The values in each are 5, 3 and 0 respectively.
University of Texas Pan Am Dr. John P. Abraham
Program Example (2)
• There are three registers that need watching, the Accumulator (AC), Program Counter (PC), and the Instruction Register (IR).
• The PC contains 100h, which means that the next instruction should be fetched from memory location 100 hexadecimal.
University of Texas Pan Am Dr. John P. Abraham
Program Example (4)
• The control unit fetches the instruction contained in the address indicated by the PC, which is 100h.
• The instruction 0200 is brought into the IR.• The IR now contains 0200. The instruction is decoded
and separated in opcode of 0 and operand of 200. This is based on the assumption that 4 bits (one hexadecimal digit) are used for the opcode and 12 bits (three hexadecimal digits) are used for the operand.
University of Texas Pan Am Dr. John P. Abraham
Program Example (5)
• Once the instruction is fetched the PC is automatically incremented, and now contains 101h.
• The opcode 0 indicates a load, and the operand is fetched from memory location 200h and loaded into the accumulator (AC).
• Now the accumulator contains 5.
University of Texas Pan Am Dr. John P. Abraham
Program Example (6)
• The instruction from 101h is fetched and placed in the IR.
• The PC is incremented to 102h. • The content of IR is decoded and based on the
opcode of 2, the operand located in address 201h is added to the AC.
• The AC now has a value of 8.
University of Texas Pan Am Dr. John P. Abraham
Program Example (7)
• The next instruction whose address is contained in the PC is fetched and placed in the IR giving it a value of 1201.
• The PC is incremented to 103h. • The contents of IR (1201) is decoded and based on the
opcode of 1, the contents of the AC is saved in the address indicated by the operand, which is 201h.
• Address 201 (variable B) now has a value of 8.
University of Texas Pan Am Dr. John P. Abraham
Program Example (8)
• The instruction contained in 103h (PC content) is fetched next and placed in the IR giving it a value of 3002.
• The PC is incremented to 104h The contents of IR is decoded, and based on the opcode of 3 it is an add immediate.
• No data fetching is necessary and the 2 is added to the AC.
• The new value of the accumulator is now 10.
University of Texas Pan Am Dr. John P. Abraham
Program Example (9)
• The last instruction is now fetched and placed in IR.• The PC is incremented to 105h. • The PC now contains 1202, and it is decoded to give the
opcode of 1 and operand of 202. • Since hex 1 is a store, the value of AC (the value is 10)
is stored in memory location 202h.• It was already mentioned that 202h is the memory
location assigned to C.
University of Texas Pan Am Dr. John P. Abraham
Slides from textbook
• The following are taken from Dale and Lewis book
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Chapter Goals
• List the operations that a computer can perform• Describe the important features of the Pep/8 virtual
machine• Distinguish between immediate addressing mode
and direct addressing mode• Write a simple machine-language program• Distinguish between machine language and
assembly language
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Computer Operations
Computer
A programmable electronic device that can store, retrieve, and process data
Data and instructions to manipulate the data are logically the same and can be stored in the same place
What operations can a computer execute?
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Machine Language
Machine language The language made up of binary coded instructions built into the hardware of a particular computer and used directly by the computer
Why would anyone choose to use machine language?
(Hint: they had no choice. Why?)
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Machine Language
Characteristics of machine language:– Every processor type has its own set
of specific machine instructions
– The relationship between the processor and the instructions it can carry out is completely integrated
– Each machine-language instruction does only one very low-level task
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Pep/8 Virtual Computer
Virtual computer
A hypothetical machine designed to contain the important features of a real computer that we want to illustrate
Pep/8
A virtual computer designed by Stanley Warford that has 39 machine-language instructions No; we are not going to cover all of them!
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Features in Pep/8
Pep/8 Registers/Status Bits Covered
– The program counter (PC) (contains the address of the next instruction to be executed)
– The instruction register (IR) (contains a copy of the instruction being executed)
– The accumulator (A register)
The memory unit is made up of 65,636 bytes of storage
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Architecture of Pep/8
Figure 6.1 Pep/8’s Architecture
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Instruction Format
Figure 6.2 Pep/8 Instruction Format
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Instruction Format
Operation codeSpecifies which instruction is to be carried outRegister specifier Specifies which register is to be used (only use A in this chapter)Addressing-mode specifierSays how to interpret the operand part of the instruction
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Instruction Format
Figure 6.3 Difference between immediate addressing mode and direct addressing mode
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Some Sample Instructions
Figure 6.4 Subset of Pep/8 instructions
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Sample InstructionsWhat do these instructions mean?
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Sample InstructionsWhat do these instructions mean?
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Sample InstructionsWhat do these instructions mean?
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Sample InstructionsWhat do these instructions mean?
Why is there only one on this page?
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Sample InstructionsWhat do these instructions mean?
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Hand Simulation
What is the fetch/execute cycle?How much is the PC incremented?
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Hand Simulation
What is the fetch/execute cycle here?
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Pep/8 Simulator
Pep8/Simulator
A program that behaves just like the Pep/8 virtual machine behaves
To run a program
Enter the hexadecimal code, byte by byte with blanks between each
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Pep/8 SimulatorWhat is a loader? What does it do?
Where does execution begin?
replace
E0 with
50 in 5
places
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Assembly Language
Assembly language A language that uses mnemonic codes to represent machine-language instructions
AssemblerA program that reads each of the instructions in mnemonic form and translates it into the machine-language equivalent
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Pep/8 Assembly Language
Rememberthedifferencebetweenimmediateanddirectaddressing?
i : immediated: direct
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Pep/8 Assembly Language
What is the difference between operations and pseudo operations?
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Pep/8 Assembly LanguageProgram "Hello"
CHARO 0x0048,i; Output an 'H'CHARO 0x0065,i;Output an 'e'CHARO 0x006C,i; Output an 'l'CHARO 0x006C,i; Output an 'l'CHARO 0x006F,i;Output an 'o'STOP.END
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A New Program
Problem: Read and sum three values and print the sum
How would you do it by hand?
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Our Completed ProgramBR main
sum: .WORD 0x0000num1: .BLOCK 2num2: .BLOCK 2num3: .BLOCK 2main: LDA sum,d
DECI num1,d ADDA num1,d DECI num2,d ADDA num2,d DECI num3,d ADDA num3,d STA sum,d DECO sum,d STOP .END
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Decision MakingBRLT i Set PC to operand if A < 0
BREQ I Set PC to operand if A = 0
negMsg: CHARO 0x0045,i BR finish
main: LDA sum,d…BRLT negMsgSTA sum,dDECO sum,d
finish: STOP How many ways to finish?
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Decision MakingProblem: Read and sum limit values.
How many values?Where does this value come from?Will require repeating the reading and
summingHow do we know when we are done?
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Pseudocode
PseudocodeA mixture of English and formatting to make the steps in an algorithm explicit
Algorithm to Convert base-10 number to other bases
While ( the quotient is not zero )Divide the decimal number by the new baseMake the remainder the next digit to the left in the answerReplace the original decimal number with the quotient
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Following an Algorithm
Algorithm for preparing a Hollandaise sauceIF concerned about cholesterol
Put butter substitute in a potELSE
Put butter in a potTurn on burnerPut pot on the burnerWHILE (NOT bubbling)
Leave pot on the burnerPut other ingredients in the blenderTurn on blenderWHILE (more in pot)
Pour contents into lender in slow steamTurn off blender
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Developing an Algorithm
Two methodologies used to develop computer solutions to a problem
– Top-down design focuses on the tasks to be done
– Object-oriented design focuses on the data involved in the solution
But first, let's look at a way to express algorithms: pseudocode
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Pseudocode
Pseudocode
A way of expressing algorithms that uses a mixture of English phrases and indentation to make the steps in the solution explicit
There are no grammar rules in pseudocode
Pseudocode is not case sensitive
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Following Pseudocode
What is 93 in base 8?93/8 gives 11 remainder 511/6 gives 1 remainder 31/ 8 gives 0 remainder 1
answer 1 3 5
While ( the quotient is not zero )Divide the decimal number by the new baseMake the remainder the next digit to the left in the answerReplace the original decimal number with the quotient
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Following Pseudocode
Easier way to organize solution
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Pseudocode for Complete Computer Solution
Write "Enter the new base"
Read newBase
Write "Enter the number to be converted"
Read decimalNumber
Set quotient to 1
WHILE (quotient is not zero)
Set quotient to decimalNumber DIV newBase
Set remainder to decimalNumber REM newBase
Make the remainder the next digit to the left in the answer
Set decimalNumber to quotient
Write "The answer is "
Write answer
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Pseudocode FunctionalityVariablesNames of places to store values
quotient, decimalNumber, newBase
AssignmentStoring the value of an expression into avariable
Set quotient to 64quotient <-- 64quotient <-- 6 * 10 + 4
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Pseudocode Functionality
Output
Printing a value on an output deviceWrite, Print
Input
Getting values from the outside word and storing them into variables
Get, Read
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Pseudocode Functionality
Repetition
Repeating a series of statements Set count to 1
WHILE ( count < 10)
Write "Enter an integer number"
Read aNumber
Write "You entered " + aNumber
Set count to count + 1
How many values were read?
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Pseudocode FunctionalitySelectionMaking a choice to execute or skip a statement (or group of statements)
Read numberIF (number < 0)
Write number + " is less than zero."or
Write "Enter a positive number."Read numberIF(number < 0)
Write number + " is less than zero."Write "You didn't follow
instructions."
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Pseudocode Functionality
SelectionChoose to execute one statement (or group of statements) or another statement (or group of statements)
IF ( age < 12 )Write "Pay children's rate"Write "You get a free box of popcorn"
ELSE IF ( age < 65 )Write "Pay regular rate"
ELSEWrite "Pay senior citizens rate"
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Pseudocode Example
Problem: Read in pairs of positive numbers and print each pair in order.
WHILE (not done)Write "Enter two values separated by blanks"Read number1Read number2
Print them in order
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Pseudocode ExampleHow do we know when to stop?
Let the user tell us how many
Print them in order?
If first number is smaller
print first, then second
If first number if larger
print second, then first
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Pseudocode Example
Write "How many pairs of values are to be entered?"
Read numberOfPairs
Set numberRead to 0
WHILE (numberRead < numberOfPairs)
Write "Enter two values separated by a blank; press return"
Read number1
Read number2
IF(number1 < number2)
Print number1 + " " + number2
ELSE
Print number2 + " " number1
Increment numberRead
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Walk Through
Data Fill in values during each iteration3 numberRead
number1 number2
55 70
2 1
33 33
numberOfPairs
What is the output?
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Translating Pseudocode
To What?
Assembly language
Very detailed and time consuming
High-level language
Easy as you'll see in Chapter 9
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Testing
Test plan A document that specifies how many times and with what data the program must be run in order to thoroughly test itCode coverage An approach that designs test cases by looking atthe codeData coverage An approach that designs test cases by looking at the allowable data values
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Testing
Test plan implementationUsing the test cases outlined in the test plan to verify that the program outputs the predicted results
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Important Threads
Operations of a ComputerComputer can store, retrieve, and process data
Computer’s Machine LanguageA set of instructions the machine’s hardware is built to recognize and execute
Machine-language Programs Written by entering a series of these instructions in binary form
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University of Texas Pan Am Dr. John P. Abraham
Important ThreadsPep/8: A Virtual Computer with One Register (A) and two-part instructions:One part tells which action the instruction performs; the other part details where the data to be used can be found
Pep/8 Assembly LanguageA language that permits the user to enter mnemonic codes for each instruction rather than binary numbers
PseudocodeShorthand-type language people use to express algorithms
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Important Threads
Testing ProgramsAll programs must be tested; code coverage testing and data coverage (black-box testing) two common approaches
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