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Solving Linear Systems Using Elimination HW1 Solve the linear systems using elimination. Write your final answer as (x,y) and check your solutions.

1) π‘₯ + 𝑦 = 3π‘₯ βˆ’ 𝑦 = βˆ’9

2) π‘₯ + 𝑦 = 30π‘₯ βˆ’ 𝑦 = 6

3) 3π‘₯ + 5𝑦 = 10π‘₯ βˆ’ 5𝑦 = βˆ’10

4) π‘₯ + 2𝑦 = 93π‘₯ + 2𝑦 = 7

5) βˆ’2π‘₯ + 3𝑦 = βˆ’9π‘₯ + 3𝑦 = 3

6) 9π‘₯ βˆ’ 3𝑦 = 247π‘₯ βˆ’ 3𝑦 = 20

Solving Linear Systems Using Elimination HW1 Solve the linear systems using elimination. Write your final answer as (x,y) and check your solutions.

1) π‘₯ + 𝑦 = 3π‘₯ βˆ’ 𝑦 = βˆ’9

2) π‘₯ + 𝑦 = 30π‘₯ βˆ’ 𝑦 = 6

3) 3π‘₯ + 5𝑦 = 10π‘₯ βˆ’ 5𝑦 = βˆ’10

4) π‘₯ + 2𝑦 = 93π‘₯ + 2𝑦 = 7

5) βˆ’2π‘₯ + 3𝑦 = βˆ’9π‘₯ + 3𝑦 = 3

6) 9π‘₯ βˆ’ 3𝑦 = 247π‘₯ βˆ’ 3𝑦 = 20

Solving Linear Systems Using Elimination HW1 Solve the linear systems using elimination. Write your final answer as (x,y) and check your solutions.

1) π‘₯ + 𝑦 = 3π‘₯ βˆ’ 𝑦 = βˆ’9

2) π‘₯ + 𝑦 = 30π‘₯ βˆ’ 𝑦 = 6

3) 3π‘₯ + 5𝑦 = 10π‘₯ βˆ’ 5𝑦 = βˆ’10

4) π‘₯ + 2𝑦 = 93π‘₯ + 2𝑦 = 7

5) βˆ’2π‘₯ + 3𝑦 = βˆ’9π‘₯ + 3𝑦 = 3

6) 9π‘₯ βˆ’ 3𝑦 = 247π‘₯ βˆ’ 3𝑦 = 20

Solving Linear Systems Using Elimination HW1 Solve the linear systems using elimination. Write your final answer as (x,y) and check your solutions.

1) π‘₯ + 𝑦 = 3π‘₯ βˆ’ 𝑦 = βˆ’9

2) π‘₯ + 𝑦 = 30π‘₯ βˆ’ 𝑦 = 6

3) 3π‘₯ + 5𝑦 = 10π‘₯ βˆ’ 5𝑦 = βˆ’10

4) π‘₯ + 2𝑦 = 93π‘₯ + 2𝑦 = 7

5) βˆ’2π‘₯ + 3𝑦 = βˆ’9π‘₯ + 3𝑦 = 3

6) 9π‘₯ βˆ’ 3𝑦 = 247π‘₯ βˆ’ 3𝑦 = 20

Solving Linear Systems Using Elimination HW1 Solve the linear systems using elimination. Write your final answer as (x,y) and check your solutions.

1) π‘₯ + 𝑦 = 3π‘₯ βˆ’ 𝑦 = βˆ’9

2) π‘₯ + 𝑦 = 30π‘₯ βˆ’ 𝑦 = 6

3) 3π‘₯ + 5𝑦 = 10π‘₯ βˆ’ 5𝑦 = βˆ’10

4) π‘₯ + 2𝑦 = 93π‘₯ + 2𝑦 = 7

5) βˆ’2π‘₯ + 3𝑦 = βˆ’9π‘₯ + 3𝑦 = 3

6) 9π‘₯ βˆ’ 3𝑦 = 247π‘₯ βˆ’ 3𝑦 = 20

Solving Linear Systems Using Elimination HW1 Solve the linear systems using elimination. Write your final answer as (x,y) and check your solutions.

1) π‘₯ + 𝑦 = 3π‘₯ βˆ’ 𝑦 = βˆ’9

2) π‘₯ + 𝑦 = 30π‘₯ βˆ’ 𝑦 = 6

3) 3π‘₯ + 5𝑦 = 10π‘₯ βˆ’ 5𝑦 = βˆ’10

4) π‘₯ + 2𝑦 = 93π‘₯ + 2𝑦 = 7

5) βˆ’2π‘₯ + 3𝑦 = βˆ’9π‘₯ + 3𝑦 = 3

6) 9π‘₯ βˆ’ 3𝑦 = 247π‘₯ βˆ’ 3𝑦 = 20

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