Contents 1. Problems on moving surfaces 2. Derivations of mass transport equations
2.1 Conservation law 2.2 Zero width limit
3. Derivation of diffusion equations 3.1 Energy law 3.2 Zero width limit
4. Derivation of the Euler and the Navier-Stokes equations
2
3
β’ Reaction-diffusion on biological cells β’ Fluid-flow on biological cell
Boussinesq (1913), L. E. Scriven (1960)
β’ Fluid-flow on rotating surface geophysics
1. Problems on moving surfaces
4
Ξ π‘ π‘β[0,π): evolving surface in π3
(1) How does one derive equations describing phenomena on a moving surface Ξ π‘ ?
(2) Is it related to zero-width limit of thin moving domain? π·π π‘ = π₯ β π3 dist π₯, Ξ π‘ < π .
Problems
7
πΞ : outer unit normal of Ξ π‘ π = π(π¦, π‘) : density of substance at π¦ β Ξ(π‘) π£ = π£(π¦, π‘) : velocity of substance at π¦ β Ξ π‘ (vector field on Ξ(π‘) not necessarily tangential)
2. Derivations of mass transport equations
2.1 Conservation law
8
Local mass conservation law
πΞ : normal velocity of Ξ π‘ in the direction of πΞ. β’ Ansatz: Normal component of π£ equals πΞ (There is no flow leaving from or coming to Ξ(π‘).)
πππ‘ β« ππ(π‘) πβ2 = 0 for any portion π(π‘) of Ξ(π‘)
(π(π‘) : relatively open set)
9
Leibniz formula πππ‘οΏ½ ππ(π‘)
πβ2 = οΏ½ (πβπ + divΞ π£ π)π(π‘)
πβ2
πβπ = ππ‘π + π£ β π» π (material derivative)
divΞπ£ : surface divergence Ansatz implies
π£ = πΞ π + π£π . π£π : tangential velocity (π£π β πΞ = 0)
10
Conservation law
The law
0 =πππ‘οΏ½ ππ(π‘)
πβ2
for all π(π‘) yields
πβπ + divΞ π£ π = 0 on Ξ(π‘).
11
Calculation of surface divergence
divΞπ£ = divΞ πΞ π + divΞ π£π = πΞ divΞ π + π»Ξ πΞ β π + divΞ π£π
π» : mean curvature
β΄ divΞ π£ = βπ» πΞ + divΞ π£π
Note : divΞ π π£π = π»Ξ π β π£π + π divΞ π£π
βπ» 0
12
Second expression of conservation law Since πβπ = πβπ + π£π β π»π with πβπ = ππ‘π + πΞ π β π»π, πβπ + divΞ π£ π = πβπ β π» πΞπ + divΞ(ππ£π).
Mass conservation: πβπ β π» πΞ π + divΞ ππ£π = 0
First two terms depend only on motion of Ξ(π‘), independent of π£π.
13
Mass conservation
πβπ + divΞ π£ π = 0 or
πβπ β π» πΞ π + divΞ ππ£π = 0
divΞπ€ : surface divergence
divΞπ€ = π»Ξ β π€
π»Ξ = πΞ π»
πΞ = πΌ β πΞ β πΞ : projection to tangent space of Ξ(π‘).
14
Mass conservation in a thin domain reads (CL) ππ‘ + div π π’ = 0 in π·π(π‘)
(B) π’ β ππ·π = ππ·ππ on ππ·π(π‘).
The substance in π·π(π‘) moves along the boundary of π·π(π‘). It does not go into or out of π·π(π‘).
ππ·ππ : normal velocity of ππ·π(π‘) in the
direction of unit outer normal ππ· of π·π(π‘)
2.2 Zero width limit
15
Problem π π₯, π‘ = π π π₯, π‘ , π‘ + π π₯, π‘ π1 π π₯, π‘ , π‘
+π π2 π’ π₯, π‘ = π£ π π₯, π‘ , π‘ + π π₯, π‘ π£1 π π₯, π‘ , π‘
+π π2 as π β 0
π π₯, π‘ : projection to Ξ(π‘) π π₯, π‘ : signed distance (π > 0 near space infinity)
π π₯, π‘ = π₯ β π π₯, π‘ πΞ π, π‘
If π solves (CL), what equation π solves?
16
Equation derived from zero width limit
Theorem 1 (T.-H. Miura, C. Liu, Y. G.). Let (π,π’) solve (CL) in π·π with (B). Let π, π£ be the first term of the expansion. Then
π£ = πΞ πΞ + π£π and π solves
(CS) πβπ β π» πΞ π + divΞ ππ£π = 0.
A
Differentiate π π₯, π‘
= π π π₯, π‘ , π‘ + π π₯, π‘ π1 π π₯, π‘ , π‘ + π(π2) in time.
Note ππ‘ π π π₯, π‘ , π‘ = πβπ π π₯, π‘ , π‘ ,
ππ‘ = βπΞ.
We observe ππ‘ = πβπ π, π‘ β πΞ π1 π, π‘ + π π .
17
Idea of the proof
π₯
Ξ(π‘)
π(π₯, π‘)
18
Idea of the proof (continued) Note that
π»π π₯, π‘ = πΞ π, π‘ + π π . One observes that
ππ’ π₯, π‘ = ππ£ π, π‘ + π1π + π π2
with π1 π, π‘ = ππ£1 π, π‘ + π1π£ π, π‘
which yields
π» ππ’ π₯, π‘ = π»π π₯, π‘ π» ππ£ + π»πβ¨π1 + π π = PΞπ» ππ£ π₯, π‘ + πΞβ¨π1 + π π .
Here π’ π₯, π‘ = π£ π, π‘ + π π₯, π‘ π£1 π, π‘ + π π2 .
A
19
Idea of the proof (continued) We are now able to conclude
div ππ’ π₯, π‘ = divΞ ππ£ + πΞ β π1 + π π . Here
divΞ ππ£ = βπ πΞπ» + divΞ ππ£π .
Note πΞ β π1 = π1πΞ because π£ β πΞ = πΞ , π£1 β πΞ = 0. Thus ππ‘π + div ππ’ = πβπ β π»ππΞ + πππ£Ξ(ππ£π) π, π‘ + π π .
20
π¦ : Kinetic energy β±: Free energy
πΏ οΏ½ π¦π
0ππ‘ = οΏ½ οΏ½(πΉπ β πΏπ₯)
π
0ππ₯ππ‘
πΏ οΏ½ β±π
0ππ‘ = οΏ½ οΏ½(πΉπ β πΏπ₯)
π
0ππ₯ππ‘
πΏ : variation with respect to flow map
3. Derivation of diffusion equations 3.1 Energy law
21
Least action principle LAP πΉπ : inertial force πΉπ : conservative force
Stationary point of the action integral
π΄ π₯ = οΏ½ π¦(π₯)π
0ππ‘ β οΏ½ β± π₯
π
0ππ‘
π₯ : Flow map π β¦ π₯ π‘,π ππππ‘
= π’ π₯, π‘ π₯|π‘=0 = π (π’ : velocity field)
LAP πΏπΏπΏπ
= 0 β πΉπ β πΉπ = 0
22
Maximum dissipation principle MDP
π : dissipation energy depending on π’ = οΏ½ΜοΏ½.
πΏπ = πΉπ β πΏπ’ πΉπ : dissipation force
LAP + MDP βΆβ πΉπ β πΉπ = πΉπ
23
Diffusion process
π¦ = 0,γβ± π₯ = οΏ½ π(π π₯ )π·(π‘)
ππ₯
π =12οΏ½ π π’ 2
π·(π‘)ππ₯ π : given
π : satisfies the transport eq (CL) ππ‘ + div ππ’ = 0 π₯ : π· 0 β π·(π‘) flow map with velocity π’
π₯ π, 0 = π,γππ₯ππ‘
= π’ π₯, π‘
π β π·(0)
24
Conservative force
Lemma 1 (T.-H. Miura, C. Liu, Y. G.). Assume that π satisfies (CL). Then
πΉπ =πΏπΏπ₯
β± = π»π(π)
with π π = πβ² π π β π π .
Conservative force is the pressure gradient.
25
Diffusion equation
Mass conservation law (CL): ππ‘ + div ππ’ = 0
Darcyβs law: ππ’ = βπ»π π
Example: π π = π log π β π π = π ππ‘ β Ξπ = 0 (heat equation)
26
Conservation force on a surface
Lemma 2 (MCG). Let (π, π£) solves (CS). Then
πΉπ =πΏβ±πΏπ¦
= π»Ξπ π .
Here
β± π¦ = οΏ½ π π π¦Ξ π‘
πβ2 π¦ .
27
Diffusion equations on a surface
Conservation law (CS) πβπ β π» πΞ π + divΞ ππ£π = 0
Darcyβs law ππ£π = βπ»Ξπ π
Example: π π = π log π β π π = π πβπ β π» πΞ π β ΞΞπ = 0
(different from different equation with convective term Elliot et al.)
28
Consider
(D) οΏ½ ππ‘ + div ππ’ = 0 ππ’ = βπ»π π in π·π(π‘)π π = πβ² π π β π π
with (B) π’ β πΞ© = πΞ©π on ππ·π π‘ .
Expanded pressure π π(π₯, π‘) = π0 π, π‘ +π π₯, π‘ π1 π₯, π‘ + π(π2)
3.2 Zero width limit
29
Equation derived from zero width limit
Theorem 2 (MLG). Let (π,π’) solves (D) in π·π(π‘) with (B). Let π, π£ be the first term of the expansion. Then
πβπ β π» πΞ π + divΞ ππ£π = 0 ππ£π = βπ»Ξπ0 on Ξ(t).
30
Energy identity For diffusion equations (D) on π·(t) with (B), we have πππ‘οΏ½ π(π)π· π‘
ππ₯
= βοΏ½ π π’ 2
π· π‘ππ₯ β οΏ½ π π πΞ©π
ππ· π‘πβ2
i.e. πβ±ππ‘
= β2π + οΏ½ΜοΏ½,
οΏ½ΜοΏ½ = βοΏ½ π π ππ·πππ· π‘
πβ2.
οΏ½ΜοΏ½: rate of change of work by the eternal environment
31
Energy identity on a surface
πππ‘οΏ½ π(π)Ξ π‘
πβ2
= βοΏ½ π π£π 2
Ξ π‘πβ2 + οΏ½ π π πΞπ»
Ξ π‘πβ2,
οΏ½ΜοΏ½ = βοΏ½ π π πΞπ»Ξ π‘
πβ2.
32
Commutativity integration
by parts
energetic variation
integration by parts
energetic variation
Diffusion equation in π·π(π‘)
Diffusion equation in Ξ(π‘)
π β 0
Energy identity in π·π(π‘)
Energy identity in Ξ(π‘)
π β 0 (MLG)
33
Rigorous results β’ If Ξ(π‘) does not move, a solution of reaction
diffusion equation in π·π tends to a solution of equation on Ξ in some rigorous sense in various settings. (J. Hale, G. Raugel, 1992)β¦β¦
β’ However, for moving Ξ(π‘) , the first convergence result is given by T.-H. Miura (2016, IFB to appear). (heat eq)
β’ For existence of a solution for the heat equation on moving surface with convective term (A. Reusken et al.)
34
H. Koba, C. Liu, Y. G. (2016) Incompressible Euler and Navier-Stokes on moving hypersurface: Energetic derivation
H. Koba, Compressible flow
4. Derivation of the Euler and the Navier-Stokes equations
35
Energetic formulation (Euler)
π¦ π₯ = οΏ½π π£ 2
2Ξ π‘ππ₯
π : density divΞπ£ = 0 (incompressibility)
LAPβ πΏ οΏ½ π¦ π₯π
0ππ‘ = 0 under divΞπ£ = 0
36
Euler equation on πͺ(π)
πβπ = 0
(I) ππβπ£ + gradΞ π + ππ»π = 0 divΞπ£ = 0
(This is overdetermined.)
(II) πβπ = 0 πΞ ππβπ£ + gradΞ π = 0
divΞπ£ = 0
(Variation is taken only in tangential direction.)
37
Dissipative energy
π = ποΏ½ π·Ξ π£ 2
Ξ(t)πβ2,γπ > 0
π·Ξ π£ = πΞπ· π£ πΞ
π· π£ =12
ππ£π
ππ₯π+ππ£π
ππ₯1
(projected strain rate)
38
Navier-Stokes equations
πβπ = 0 (III) ππβπ£ + gradΞ π + ππ»π = 2π divΞπ·Ξ π£
divΞπ£ = 0 (overdetermined)
πβπ = 0 (IV) ππΞπβπ£ + gradΞ π = 2ππΞdivΞπ·Ξ(π£)
divΞπ£ = 0
39
Relation to other derivation
Incompressible perfect flow
V. I. Arnold (1966) π = const ππΞ πβπ£ + gradΞ π = 0
for a fixed surface (variational principle on the space of volume preserving diffeormorphism) (Least action principle)
40
M. E. Taylor (1992) Balance of momentum on manifold
D. Bothe, J. PrΓΌss (2010) Boussinesq-Scriven model
T. Jankuhn, M. A. Olshanskii, A. Reusken Preprint (2017)
Incompressible viscous flow on a fixed surface
41
Zero width limit
ππ‘π’ + π’,π» π’ + π»π = π0Ξπ’ div π’ = 0 in π·π(π‘)
Boundary condition (perfect slip)
π’ β ππ· = ππ·π
π· π’ π tan = 0
42
Limit equation
Result (T.-H. Miura)
πΞ ππ‘π£ + π£,π» π£ + π»Ξπ
= 2π0πΞdiv(πΞπ· π£ πΞ)
This agrees with what KCG derived.