MATH TASK
GROUP 1DIAN PERMANA
ANNISA INDAH REZA
DHIA ATIKAH ALIYYU
USWATUN HASANAH
WAN ELSA
The Circle Equation with Center P(a,b) and radius r !
The general equation distance is :
(x2-x1)2 + (y2-y1)2 = r2
So in the circle,
x1 = a y1 = b
x2 = x y2 = y
Then the circle equation become :
(x-a)2 + (y-b)2 = r2
P(a,b)
r
T(x,y)
y
x
Example . . .
1. Determine the circle equation with center P(-2,3) with the following requirement :
a. Passing through point Q(4,-1)
b. Meet an exatly one point X
c. Meet an exatly one point Y
Answers . . .
1. a. Q(4,-1)
P(2,-3)
(4-2)2 +(-3+1)2 = r2
(2)2 + (-2)2 = r2
8 = r2
(x-2)2 + (y+1)2 = 8
b. Meet an exatly one point X means r = b = 3
(x-2) + (y+1) = 9
c. Meet an exatly one point Y means r = a = 2
(x-2) + (y+1) = 4
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