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Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Prentice Hall
Chapter 1
Prerequisites for Calculus
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1.1
Lines
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Quick Review
( )( )
1. Find the value of that corresponds to 3 in 2 4 3 .
2. Find the value of that corresponds to 3 in 3 2 1 .
In Exercises 3 and 4, find the value of that corresponds
to the values of and
y x y x
x y y x
m
x y
= =- + -
= = - +
.
33. 5, 2,
4
24. 1, 3,
3
yx y m
x
yx y m
x
-= = =
-
-=- =- =
-
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Quick Review
In exercises 5 and 6, determine whether the ordered pair is a
solution to the equation.
5. 3 4 5 6. 2 5
1a) 2, b) 3, 1 a) 1,7 b) 2,1
4
In exercises 7 and 8, find the distance between the
x y y x
points.
17. 1,0 and 0,1 8. 2,1 and 1,
3
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Quick Review
In Exercises 9 and 10, solve for in terms of .
9. 4 3 7 10. 2 5 3
y x
x y x y- = - + =-
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Quick Review Solutions
( )
( )
1. Find the value of that corresponds to 3 in 2 4 3 .
2. Find the value of that corresponds to 3 in 3 2 1 .
In Exercises 3 and 4, find the value of that corresponds
to the value
2
1
s o
y
y
x y
x y y
x
x
x
m
=
= =-
-
=
-
- +
-
+
= =
f and .
33. 5, 2,
4
24. 1, 3,
1
5
3 4
x y
yx y m
x
yx y
x
m
mm
=--
= = =-
-=- - = ==
-
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Quick Review Solutions
In exercises 5 and 6, determine whether the ordered pair is a
solution to the equation.
5. 3 4 5 6.
a) y
2 5
1a) 2, b) 3, 1 a) 1,7 b)
es
2,14
b) no a) yes
x y y x
In exercises 7 and 8, find the distance between the points.
17. 1,0 and
b) no
distance = 2
0,1 8. 2,1 and 1, 3
distance = 5/3
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Quick Review Solutions
In Exercises 9 and 10, solve for in terms of .
9. 4 3 7 10. 2
4 7 2 3
3 3 5 5
5 3
y x
x y x y
y x y x
- = - +
= - = -
=-
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Increments Slope of a Line Parallel and Perpendicular Lines Equations of Lines Applications
What you’ll learn about…
…and why.
Linear equations are used extensively in business and economic applications.
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Increments
1 1 2 2
2 1 2 1
If a particle moves from the point ( , ) to the point ( , ), the
in its coordinates are
and
x y x y
x x x y y y increments
The symbols and are read delta and delta .
The letter is a Greek capital for difference.
Neither nor denotes multiplication;
is not delta times nor is delta times .
x y x y
d
x y
x x y y
D
D
D
D D
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Example Increments
The coordinate increments from (8, 3) to (-6, 1) are:
6 8 14, 1 3 2x y
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Slope of a Line
1 1 2 2
1
2 1
Let ( , ) and ( , ) be points on a nonvertical line, . The
of is
rise
run
1 2
2
P x y P x y L
L
y ym =
x x
-=
-
slope
A line that goes uphill as x increases has a positive slope. A line that goes downhill as x increases has a negative slope.
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Slope of a Line
A horizontal line has slope zero since all of its points have the same
-coordinate, making 0.
For vertical lines, 0 and the ratio is undefined.
We express this by saying that vertical li
y y
yx
x
D =
DD =
D
nes have no slope.
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Parallel and Perpendicular Lines
1 2
Parallel lines form equal angles with the -axis. Hence, nonvertical
parallel lines have the same slope.
=
If two nonvertical lines and are perpendicular, their slopes
and satisfy
1 2
1 2
x
m m
L L
m m 1 2
1 22 1
1, so each slope is the negative reciprocal
1 1of the other: ,
m m
m mm m
= -
=- =-
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Equations of Lines
( )
( )
The vertical line through the point , has equation
since every -coordinate on the line has the same value .
Similarly, the horizontal line through , has equation .
a b x=a
x a
a b y b=
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Example Equations of Lines
Write the equations of the vertical and horizontal lines through
the point ( 3,8).-
3 and 8x y =- =
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Point Slope Equation
1
1
The equation ) is the of the line
through the point ( , ) with slope .1
1
y=m(x x y
x y m
point - slope equation- +
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Example: Point Slope Equation
( ) ( )Write the point-slope equation for the line through 7, -2 and -5, 8 .
1 1
8 ( 2) 10 10 5The line's slope is = = =
5 (7) 12 12 6
We can use this slope with either of the two given points in the point-slope
equation. For ( , ) = (7, 2) we obtain
5= ( )
6
=
7 2
m
x y
y x
y
- -= - -
- - -
-
- - +-
5 35 2
6 65 23
= 6 6
x
y x
- + -
- +
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Equations of Lines
The -coordinate of the point where a non-vertical line
intersects the -axis is the -intercept of the line.
Similarly, the -coordinate of the point where a non-horizontal
line intersects the -axis
y
y y
x
x
( )
is the -intercept of the line.
A line with slope and -intercept passes through 0, so( 0) , or
x
m y b by m x b y m x b= - + = +
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Slope-Intercept Equation
The equation is the of the line
with slope and -intercept
y=m x + b
m y b.
slope - intercept equation
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General Linear Equation
The equation ( and not both 0)
is a in and .
Ax By = C A B
x y
+
general linear equation
Although the general linear form helps in the quick identification of lines, the slope-intercept form is the one to enter into a calculator for graphing.
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Example Analyzing and Graphing a General Linear Equation
Find the slope and y-intercept of the line 2 3 15. Graph the line. x y = -
Solve the equation for to put the equation in slope-intercept form:
3 = 2 15
2 15 =
3 32
= 53
y
y x
y x
y x
- - +
-+
- -
-
[-10, 10] by [-10, 10]
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Example Determining a Function
The following table gives values for the linear function ( ) .
Determine and .
f x mx b
m b
= +
x f(x)
-1 -1
1 5
3 11
( ) ( ) ( )The graph of is a line. We know from the table that the following points are on
the line: 1, 1 , 1,5 , 3,11
11 5 6Using the last two points the slope is: = = = 3
3 1 2So = 3 Because f
f
m m
f(x) x b.
- -
--
+ (1) = 5, we have
( ) 3( )
5 = 3
= 2 Thus, 3, 2 and (
1 1
) 3 2
f b
b
b m b f x x
= +
+
= = = +
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Example Reimbursed Expenses
A company reimburses its sales representatives $150 per day for lodging and
meals plus $0.34 per mile driven.
Write a linear equation giving the daily cost to the company in terms of ,
the number o
C x
f miles driven.
How much does it cost the company if a sales representative drives 137 miles on
a given day?
Because we know that the relationship is linear, we know that it conforms to the
equation ( ) .34 150.
If a sales representative drives 137 miles, then 137. Thus,
( ) .34( ) 150
( ) 46.58
137 137
13 17
C x x
x
C
C
= +
=
= +
= + 50
( ) 196.58
It will cost the company $196.58 for a sales representative to drive 137 miles a .
1
y
37
da
C =
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1.2
Functions and Graphs
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Quick Review
( )
( ) ( ) ( )( ) ( )
2 2
22
In Exercises 1 - 6, solve for .
1. 3 1 5 3 2. 2 0
3. 3 4 4. 2 5
5. 16 6. 9 0
In Exercises 7 and 8, describe how the graph of can be
transformed to the graph of .
7. , 2 3
8. , 5
x
x x x x
x x
x x
f
g
f x x g x x
f x x g x x
- £ + - >
- £ - ³
< - ³
= = + -
= = - +2
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Quick Review
( )( ) ( ) ( ) ( )
( )
( ) ( ) ( ) ( )
2
In Exercises 9 - 12, find all real solutions to the equations.
9. 5
a 4 b 6
110.
a 5 b 0
f x x
f x f x
f xx
f x f x
= -
= =-
=
=- =
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Quick Review
( )( ) ( ) ( ) ( )
( )( ) ( ) ( ) ( )
3
11. 7
a 4 b 1
12. 1
a 2 b 3
f x x
f x f x
f x x
f x f x
= +
= =
= -
=- =
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Quick Review Solutions
( ) ( ) ( )
( )2 2
[ 2, ) ,0 2,
[ 1,7] ( , 3] [7,
In Exercises 1 - 6, solve for .
1. 3 1 5 3 2. 2 0
3. 3 4 4. 2 5
5. 16 6. 9 0
In Exercises 7 and 8, describe how the graph of can be
transformed to
)
4,4 [ 3
t
,3]
he
x
x x x x
x x
x x
f
- ¥ - ¥ È ¥
- - ¥ - È ¥
- £ + - >
- £ - ³
< - ³- -
( ) ( ) ( )( ) ( )
22 2 units left and 3 units d
graph of .
7. , 2 3
8. ,
ownward
5 units ri5 2 ght and 2 units upward
g
f x x g x x
f x x g x x
= = + -
= = - +
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Quick Review Solutions
( )( ) ( ) ( ) ( )( ) ( )
( )
( ) ( ) ( ) ( )
( ) ( )
2
In Exercises 9 - 12, find all real solutions to the equations.
a 3,3 b no real solutio
9. 5
a 4 b 6
110.
a 5 b 0
n
1a b no real solution
5
f x x
f x f x
f xx
f x f x
= -
= =-
=
-
-
-
=
=
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Quick Review Solutions
( )( ) ( ) ( ) ( )( ) ( )
( )( ) ( ) ( ) ( )( ) ( )
3
11. 7
a 4 b 1
12
a 9 b 6
a 7 b 28
. 1
a 2 b 3
f x x
f x f x
f x x
f x f x
= +
= =
= -
-
=- =
-
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Functions Domains and Ranges Viewing and Interpreting Graphs Even Functions and Odd functions - Symmetry Functions Defined in Pieces Absolute Value Function Composite Functions
…and why
Functions and graphs form the basis for understanding mathematics applications.
What you’ll learn about…
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Functions
A rule that assigns to each element in one set a unique
element in another set is called a function. A function is like
a machine that assigns a unique output to every allowable
input. The inputs make up the domain of the function; the
outputs make up the range.
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Function
A function from a set D to a set R is a rule thatassigns a unique element in R to each element inD.
In this definition, D is the domain of the function and R is a set containing the range.
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Function
( )
( )( )
The symbolic way to say " is a function of " is which is read as equals of .The notation gives a way to denote specific values of a function. The value of at can be written as , read
y x y f xy f x
f xf a f a
=
as " of ."f a
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Example Functions
Evaluate the function ( ) 2 3 when = 6. f x x x= +
( )
( ) 2( ) 3
( ) 12 3
15
6 6
6
6
f
f
f
= +
= +
=
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Domains and Ranges
( )When we define a function with a formula and the domain is
not stated explicitly or restricted by context, the domain is assumed to be
the largest set of -values for which the formula gives real
y f x
x
=
( )
-values -
the so-called natural domain. If we want to restrict the domain, we must say so.
The domain of 2 is restricted by context because the radius, ,
must always be positive.
y
C r r rp=
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Domains and Ranges
The domain of 5 is assumed to be the entire set of real numbers.
If we want to restrict the domain of 5 to be only positive values,
we must write 5 , 0.
y x
y x
y x x
=
=
= >
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Domains and Ranges
The domains and ranges of many real-valued functions of a real variable are intervals or combinations of intervals. The intervals may be open, closed or half-open, finite or infinite.
The endpoints of an interval make up the interval’s boundary and are called boundary points.
The remaining points make up the interval’s interior and are called interior points.
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Domains and Ranges
Closed intervals contain their boundary points. Open intervals contain no boundary points
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Domains and Ranges
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Graph
( )( )
The points , in the plane whose coordinates are the
input-output pairs of a function make up the
function's .
x y
y f x
graph
=
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Example Finding Domains and Ranges
2
Identify the domain and range and use a grapher
to graph the function .y x=
[-10, 10] by [-5, 15]
2y x=
( )
[ )
Domain: The function gives a real value of for every value of
so the domain is , .
Range: Every value of the domain, , gives a real, positive value of
so the range is 0, .
y x
x y
- ¥ ¥
¥
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Viewing and Interpreting Graphs
Recognize that the graph is reasonable.
See all the important characteristics of the graph.
Interpret those characteristics.
Recognize grapher failure.
Graphing with a graphing calculator requires that you develop graph viewing skills.
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Viewing and Interpreting Graphs
Being able to recognize that a graph is reasonable comes with experience. You need to know the basic functions, their graphs, and how changes in their equations affect the graphs.
Grapher failure occurs when the graph produced by a grapher is less than precise – or even incorrect – usually due to the limitations of the screen resolution of the grapher.
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Example Viewing and Interpreting Graphs
2
Identify the domain and range and use a grapher to
graph the function 4y x= -
( ] [ )
Domain: The function gives a real value of for each value of 2
so the domain is , 2 2, .
Range: Every value of the domain, ,
gives a real, positive value of
so the range is [0, ).
y x
x
y
³
- ¥ - È ¥
¥
[-10, 10] by [-10, 10]
2 4y x= -
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Even Functions and Odd Functions-Symmetry
The graphs of even and odd functions have important symmetry properties.
( )( ) ( )
A function ( )is a
if ( )
if
for every in the function's domain.
y f x
x f x f x
x f x f x
x
=
- =
- =-
even function of
odd function of
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Even Functions and Odd Functions-Symmetry
The graph of an even function is symmetric about the y-axis. A point (x,y) lies on the graph if and only if the point (-x,y) lies on the graph.
The graph of an odd function is symmetric about the origin. A point (x,y) lies on the graph if and only if the point (-x,-y) lies on the graph.
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Example Even Functions and Odd Functions-Symmetry
3Determine whether is even, odd or neither.y x x= -
( ) ( ) ( ) ( ) ( )
3
3 3 3
is odd because
x
y x x
f x xx x f xx x- -
= -
= - = - + = - - =--
3y x x= -
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Example Even Functions and Odd Functions-Symmetry
Determine whether 2 5 is even, odd or neither.y x= +
( ) ( ) ( )2 5 is neither because
2 5 2 5 ( )x x
y x
f x f x f x
= +
= + =- + ¹ ¹ -- -
2 5y x= +
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Functions Defined in Pieces
While some functions are defined by single formulas, others are defined by applying different formulas to different parts of their domain.
These are called piecewise functions.
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Example Graphing a Piecewise Defined Function
2
Use a grapher to graph the following piecewise function :
2 1 0( )
3 0
x xf x
x x
2 1; 0y x x= - £
2 3; 0y x x= + >
[-10, 10] by [-10, 10]
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Absolute Value Functions
The absolute value function is defined piecewise by the formula
, 0
, 0
y x
x xx
x x
=
ì - <ïï= íï ³ïî
The function is even, and its graph is symmetric about the y-axis
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Composite Functions
Suppose that some of the outputs of a function can be used as inputs of
a function . We can then link and to form a new function whose inputs
are inputs of and whose outputs are the numbers
g
f g f
x g ( )( )( )( ) ( )
.
We say that the function read of of is
. The usual standard notation for the composite is ,
which is read " of ."
f g x
f g x f g x
f g
f g
the composite
of and og f
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Example Composite Functions
( )Given ( ) 2 3 and 5 , find .f x x g x x f g= - = o
( ) ( )( )( )( )
( )
2 3
1
5
5
0 3
g x
x
f g x
f
x
x
f=
=
= -
= -
o
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1.3
Exponential Functions
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Quick Review
223
3 5
10
In Exercises 1 3, evaluate the expression. Round your answers
to 3 decimal places.
1. 5 2. 3
3. 3
In Exercises 4 6, solve the equation. Round your answers
to 4 decimal places.
4. 17 5. 24
6. 1
x x
x
1.5-
-
-
= =
= .4567
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Quick Review
In Exercises 7 and 8, find the value of investing dollars for
years with the interest rate compounded annually.
7. $500, 4.75%, 5 years
8. 1000, 6.3%, 3 years
In Exercises 9 and 10, simplify the
P
n r
P r n
P r n
= = =
= = =
( )( )
2 2 13 2 3 2 4 2
3 4 34 3
exponential expression.
9. 10.x y a b a c
c bx y
-- - -æ ö æ ö÷ ÷ç ç÷ ÷ç ç÷ ÷ç ç÷ ÷è ø è ø
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Quick Review Solutions
223
3
2.924 4.
In Exercises 1 3, evaluate the expression. Round your answers
to 3 decimal places.
1. 5 2. 3
3. 3
In Exercises 4 6, solve the equation. Round your answers
to 4 decimal places.
4.
729
0.192
x
1.5-
-
-
5
10
2.5713 1.88817 5. 24
6. 1.4567
2
1.0383
x
x
= =
= ±
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Quick Review Solutions
In Exercises 7 and 8, find the value of investing dollars for
years with the interest rate compounded annually.
7. $500, 4.75%, 5 years
8. 1000, 6.3%, 3 y
$630.58
$1201.16ears
In Exercises 9 and 1
P
n r
P r n
P r n
= = =
= = =
( )( )
2 2 13 2 3 2 2
1
4 2
3 8 5 4 34 3 6
1
0, simplify the exponential expression.
9. 10.x ay a b a c
c bx y x y bc
-- - -æ ö æ ö÷ ÷ç ç÷ ÷ç ç÷ ÷ç ç÷ ÷è ø è ø
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Exponential Growth Exponential Decay Applications The Number e
…and why
Exponential functions model many growth patterns.
What you’ll learn about…
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Exponential Function
Let be a positive real number other than 1. The function
( )
is the .
x
a
f x a
a
=
exponential function with base
The domain of ( ) is ( , ) and the range is (0, ).
Compound interest investment and population growth are examples
of exponential growth.
xf x a= - ¥ ¥ ¥
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Exponential Growth
If 1 the graph of looks like the graph
of 2 in Figure 1.22ax
a f
y=
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Exponential Growth
If 0 1 the graph of looks like the graph
of 2 in Figure 1.22b.x
a f
y -=
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Rules for Exponents
( )
( ) ( )
If 0 and 0, the following hold for all real numbers and .
1. 4.
2. 5.
3.
xx y x y x x
xx xx y
y x
y xx y xy
a b x y
a a a a b ab
a a aa
ba b
a a a
+
-
> >
× = × =
æö÷ç= =÷ç ÷çè ø
= =
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Half-life
Exponential functions can also model phenomena that produce decrease over time, such as happens with radioactive decay. The half-life of a radioactive substance is the amount of time it takes for half of the substance to change from its original radioactive state to a non-radioactive state by emitting energy in the form of radiation.
Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Prentice Hall Slide 1- 68
Exponential Growth and Exponential Decay
The function , 0, is a model for
if 1, and a model for if 0 1.
xy k a k
a a
exponential growth
exponential decay
= × >
> < <
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Example Exponential Functions
( )Use a grapher to find the zero's of 4 3.xf x = -
( ) 4 3xf x = -
[-5, 5], [-10,10]
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The Number e
Many natural, physical and economic phenomena are best modeled
by an exponential function whose base is the famous number , which is
2.718281828 to nine decimal places.
We can define to be the numbe
e
e ( ) 1r that the function 1
approaches as approaches infinity.
x
f xx
x
æ ö÷ç= + ÷ç ÷çè ø
Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Prentice Hall Slide 1- 71
The Number e
The exponential functions and are frequently used as models
of exponential growth or decay.
Interest compounded continuously uses the model , where is the
initial investment, is t
x x
r t
y e y e
y P e P
r
-= =
= ×
he interest rate as a decimal and is the time in years.t
Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Prentice Hall Slide 1- 72
Example The Number e
( ) 0.03
The approximate number of fruit flies in an experimental population after
hours is given by 20 , 0.
a. Find the initial number of fruit flies in the population.
b. How large is the populat
tt Q t e t= ³
ion of fruit flies after 72 hours?
c. Use a grapher to graph the function .Q
( )
( ) ( ) ( )
( ) ( )
0.03 0
0.03 2.72 16
0
a. To find the initial population, evaluate at 0.
20 20 20 1 20 flies.
b. After 72 hours, the population size is
20 2
0
0 173 flies.
c.
72
Q t t
Q e e
Q e e
=
= = = =
= = »
[0,100] by [0,120] in 10’s
( ) 0.0320 , 0tQ t e t= ³
Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Prentice Hall Slide 1- 73
Quick Quiz Sections 1.1 – 1.3
( )
( )
( )
( )( )
You may use a graphing calculator to solve the following problems.
1. Which of the following gives an equation for the line through 3, 1
and parallel to the line: 2 1?
1 7A
2 21 5
B2 2
C 2 5
D 2
y x
y x
y x
y x
y x
-
=- +
= +
= -
=- +
=-
( )
7
E 2 1y x
-
=- +
Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Prentice Hall Slide 1- 74
Quick Quiz Sections 1.1 – 1.3
( )
( )
( )
( )( )
You may use a graphing calculator to solve the following problems.
1. Which of the following gives an equation for the line through 3, 1
and parallel to the line: 2 1?
1 7A
2 21 5
B2 2
D 2
C 2 5
y x
y x
y x
y x
y x
=- +
-
=- +
= +
= -
=-
( )
7
E 2 1y x
-
=- +
Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Prentice Hall Slide 1- 75
Quick Quiz Sections 1.1 – 1.3
( ) ( )( )( )
( )( )( )( )( )
22. If 1 and 2 1, which of the
following gives 2 ?
A 2
B 5
C 9
D 10
E 15
f x x g x x
f g
= + = -
o
Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Prentice Hall Slide 1- 76
Quick Quiz Sections 1.1 – 1.3
( ) ( )( )( )
( )( )( )( )( )
22. If 1 and 2 1, which of the
following gives 2 ?
A 2
B 5
C 9
15
D 10
E
f x x g x x
f g
= + = -
o
Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Prentice Hall Slide 1- 77
Quick Quiz Sections 1.1 – 1.3
( )( )( )( )
3. The half-life of a certain radioactive substance is 8 hours. There
are 5 grams present initially. Which of the following gives the
best approximation when there will be 1 gram remaining?
A 2
B 10
C 15
D 16
( )E 19
Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Prentice Hall Slide 1- 78
Quick Quiz Sections 1.1 – 1.3
( )( )( )( )
3. The half-life of a certain radioactive substance is 8 hours. There
are 5 grams present initially. Which of the following gives the
best approximation when there will be 1 gram remaining?
A 2
B 10
C 15
D 16
( )E 19
Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Prentice Hall
1.4
Parametric Equations
Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Prentice Hall Slide 1- 80
Relations Circles Ellipses Lines and Other Curves
What you’ll learn about…
…and why
Parametric equations can be used to obtain graphs of relations and functions.
Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Prentice Hall Slide 1- 81
Quick Review
( ) ( )( )
( )
In Exercises 1 3, write an equation for the line.
1. the line through the points 1, 8 and 4, 3
2. the horizontal line through the point 3, 4
3. the vertical line through the point 2, 3
In Exercises 4 - 6
-
-
-
2 2 2
2
, find the - and -intercepts of the graph of the relation.
4. 1 5. 19 16 16 9
6. 2 1
x y
x y x y
y x
+ = - =
= +
Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Prentice Hall Slide 1- 82
Quick Review
( ) ( ) ( ) ( ) ( )
( ) ( ) ( ) ( ) ( ) ( )
2 2
2 2
In Exercises 7 and 8, determine whether the given points lie on
the graph of the relation.
7. 2 3
1a 1, 1 b 1, 1 c , 2
2
8. 9 18 4 27
a 1, 3 b 1, 3 c 1, 3
x y y
x x y
+ =
æ ö÷ç- - - ÷ç ÷çè ø
- + =
- -
Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Prentice Hall Slide 1- 83
Quick Review
( ) ( )
( )
( )
( )
2
2
2
9. Solve for .
a 2 3 5 b 3 2 1
10. For what values of is each equation true?
a
b
c 4 2
t
x t y t
a
a a
a a
a a
+ =- - =-
=
=±
=
Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Prentice Hall Slide 1- 84
Quick Review Solutions
( ) ( )
( )( )
In Exercises 1 3, write an equation for the line.
1. the line through the points 1, 8 and 4, 3
2. the horizontal line through the point 3, 4
3. the vertical line through the point 2,
5 2
3
I
9
3 34
2
y x
y
x
=- +
-
=-
=
-
-
2 2
2 2
2
n Exercises 4 - 6, find the - and -intercepts of the graph of th
3, 3; 4
e relation.
4. 19 16
5. 116 9
, 4
4, 4; no -intercepts
1 11; ,.
21
26 2
x y
xx y
x y
x y
y
x y
y x
=- =-
=-
=- =+ -
+ =
- =
=
Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Prentice Hall Slide 1- 85
Quick Review Solutions
( ) ( ) ( ) ( ) ( )
( ) ( ) ( ) ( ) ( ) ( )
2 2
2 2
In Exercises 7 and 8, determine whether the given points lie on
the graph of the relation.
Yes No Yes
Yes Y
7. 2 3
1a 1, 1 b 1, 1 c , 2
2
8. 9 18 4 27
a 1, 3 b 1, 3 c 1, 3 N es o
x y y
x x y
+ =
æ ö÷ç- - - ÷ç ÷çè ø
- + =
- -
Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Prentice Hall Slide 1- 86
Quick Review Solutions
( ) ( )
( )
( )
( )
2
2
2
9. Solve for .
a 2 3 5 b 3 2 1
10. For what values of is each equation t
2 5 3 1
3 2
0
All Reals
All Re
rue?
a
a s
b
c 4 2 l
x yt t
a
t
x t y t
a
a a
a a
a a
+ =- - =-
=
-
=
=
- += =
³
±
Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Prentice Hall Slide 1- 87
Relations
A relation is a set of ordered pairs (x, y) of real numbers.
The graph of a relation is the set of points in a plane that
correspond to the ordered pairs of the relation.
If x and y are functions of a third variable t, called a parameter, then we can use the parametric mode of a grapher to obtain a graph of the relation.
Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Prentice Hall Slide 1- 88
Parametric Curve, Parametric Equations
( ) ( )
( ) ( ) ( )( )
If and are given as functions
,
over an interval of -values, then the set of points , ,
defined by these equations is a . The equations are
of th
x y
x f t y g t
t x y f t g t
= =
=
parametric curve
parametric equations e curve.
Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Prentice Hall Slide 1- 89
Relations
( ) ( )( ) ( ) ( )( )
The variable is a parameter for the curve and its domain is the
parameter interval. If is a closed interval, , the point
, is the initial point of the curve and the point ,
is the te
t I
I a t b
f a g a f b g b
£ £
rminal point of the curve. When we give parametric equations
and a parameter interval for a curve, we say that we have parametrized
the curve. A grapher can draw a parametrized curve only over a closed
interval, so the portion it draws has endpoints even when the curve being
graphed does not.
Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Prentice Hall Slide 1- 90
Example Relations
2Describe the graph of the relation determined by , 1 .x t y t= = -
21 1Set , 1 , and use the parametric mode
of the grapher to draw the graph.
x t y t= = -
Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Prentice Hall Slide 1- 91
Circles
In applications, t often denotes time, an angle or the distance a particle has traveled along its path from a starting point.
Parametric graphing can be used to simulate the motion of a particle.
Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Prentice Hall Slide 1- 92
Example CirclesDescribe the graph of the relation determined by
3cos , 3sin , 0 2 .
Find the initial points, if any, and indicate the direction in which the curve
is traced.
Find a Cartesian equation for a curve
x t y t t p= = £ £
that contains the parametrized curve.
( ) ( )2 2 2 2 2 2
2 2
9cos 9sin 9 cos sin 9 1 9
Thus, 9
This represents the equation of a circle with radius 3 and center at the origin.
As increases from 0 to 2 the curve is traced in a counter-clock
x y t t t t
x y
t p
+ = + = + = =
+ =
wise direction
beginning at the point (3,0).
2 2 9x y+ =
Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Prentice Hall Slide 1- 93
Ellipses
2 2
2 2
2 2
2 2
Parametrizations of ellipses are similar to parametrizations of circles.
Recall that the standard form of an ellipse centered at (0, 0) is
1.
For cos and sin , we have 1
which
x y
a b
x yx a t y a t
a b
+ =
= = + =
is the equation of an ellipse with center at the origin.
Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Prentice Hall Slide 1- 94
Lines and Other Curves
Lines, line segments and many other curves can be defined parametrically.
Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Prentice Hall Slide 1- 95
Example Lines and Other Curves
If the parametrization of a curve is , 2, 0 2 graph the curve.
Find the initial and terminal points and indicate the direction in which the curve
is traced. Find a Cartesian equation for a cu
x t y t t= = + £ £
rve that contains the parametrized
curve. What portion of the Cartesian equation is traced by the parametrized curve?
, 2, 0 2x t y t t= = + £ £
Initial point (0, 2) Terminal point (2, 4)
Curve is traced from left to right
( )( ) ( )
If and 2, then by substitution 2.
The graph of the Cartesian equation is a line through 0,2 with 1.
The segment of that line from 0,2 to 2, 4 is traced by the parametrized curve.
x t y t y x
m
= = + = +
=
Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Prentice Hall
1.5
Functions and Logarithms
Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Prentice Hall Slide 1- 97
Quick Review
( ) ( )
( )( ) ( )( )( )( ) ( )( )
23In Exercises 1 4, let 1, 1, and
evaluate the expression.
1. 1 2. 7
3. 4.
In Exercises 5 and 6, choose parametric equations and a parameter
interval to represent the function o
f x x g x x
f g g f
f g x g f x
- = - = +
-o o
o o
n the interval specified.
15. , 2 6. , 3
1y x y x x
x= ³ = <-
-
Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Prentice Hall Slide 1- 98
Quick Review
( ) ( )
( ) ( )
In Exercises 7 10, find the points of intersection of the two curves.
Round your answers to 2 decimal places.
7. 2 3, 5
8. 3 5, 3
9. a 2 , 3 b 2 , 1
10. a , 4 b , 1
x x
x x
y x y
y x y
y y y y
y e y y e y- -
-
= - =
=- + =-
= = = =-
= = = =-
Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Prentice Hall Slide 1- 99
Quick Review Solutions
( ) ( )
( )( ) ( )( )
( )( ) ( )( ) ( )2 23 3
23In Exercises 1 4, let 1, 1, and
evaluate the expression.
1. 1 2. 7
3. 4.
In Exercises 5 and 6, choose parametric equations and a parameter
interval to represent th
1 5
1 1
e
f x x g x x
f g g f
f g x g f xx x
- =
-
-
-
+
= +
o o
o o
( )possible answers ar
function on the interva
e give
l specified.
15.
n
1, ,
, 2 6.
,
1
2 ,1
3
3
,y
x t y t
x
x
y x x
t y t tt
x= ³ =
= = ³
-
= =
<-
<--
Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Prentice Hall Slide 1- 100
Quick Review Solutions
( )
( ) ( ) ( )
( )
In Exercises 7 - 10, find the points of intersection of the two curves.
Round your answers to 2 decimal places.
7. 2 3, 5
8. 3 5,
4,5
8, 3
3
1.58,3 No
3
9. a 2 , 3 b 2 , 1
10. a ,
ne
4
x x
x
y x y
y x y
y y y y
y e y-
æ ö÷ç - ÷ç ÷çè
= - =
=- + =-
= = = =-
= =
ø
-( ) ( )1.39,4 Noneb , 1xy e y-= =-
Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Prentice Hall Slide 1- 101
One-to-One Functions Inverses Finding Inverses Logarithmic Functions Properties of Logarithms Applications
…and why
Logarithmic functions are used in many applications including finding time in investment problems.
What you’ll learn about…
Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Prentice Hall Slide 1- 102
One-to-One Functions
A function is a rule that assigns a single value in its range to each point in its domain.
Some functions assign the same output to more than one input.
Other functions never output a given value more than once. If each output value of a function is associated with exactly
one input value, the function is one-to-one.
Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Prentice Hall Slide 1- 103
One-to-One Functions
( ) ( ) ( )A function is on a domain if
whenever .
f x D f a f b
a b
¹
¹
one - to - one
Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Prentice Hall Slide 1- 104
One-to-One Functions
( )The horizontal line test states that the graph of a one-to-one function
can intersect any horizontal line at most once.
If it intersects such a line more than once it assumes the sam
y f x=
e -value
more than once and is not a one-to-one function.
y
Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Prentice Hall Slide 1- 105
Inverses
Since each output of a one-to-one function comes from just one input, a one-to-one function can be reversed to send outputs back to the inputs from which they came.
The function defined by reversing a one-to-one function f is the inverse of f.
Composing a function with its inverse in either order sends each output back to the input from which it came.
Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Prentice Hall Slide 1- 106
Inverses
( )( )
( )( ) ( )( )
1
1 1
The symbol for the inverse of is , read " inverse."
1The -1 in is not an exponent; does not mean
If , then and are inverses of one another;
otherwise they are not.
f f f
f f xf x
f g x g f x f g
-
- -
=o o
Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Prentice Hall Slide 1- 107
Identity Function
The result of composing a function and its inverse in either order
is the identity function.
Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Prentice Hall Slide 1- 108
Example Inverses
( ) ( ) 2Determine via composition if and , 0
are inverses.
f x x g x x x= = ³
( )( ) ( )
( )( ) ( ) ( )
22
2
x
f g x f x x x
g x g x x
x
f
= = = =
= = =
o
o
Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Prentice Hall Slide 1- 109
Writing f -1as a Function of x.
( )
( )1
Solve the equation for in terms of .
Interchange and . The resulting formula
will be .
y f x x y
x y
y f x-
=
=
Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Prentice Hall Slide 1- 110
Finding Inverses
Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Prentice Hall Slide 1- 111
Example Finding Inverses
Given that 4 12 is one-to-one, find its inverse.
Graph the function and its inverse.
y x= -
Solve the equation for in terms of .
13
4Interchange and .
13
4
x y
x y
x y
y x
= +
= +
( ) 4 12f x x= -
( )1 13
4f x x- = +
[-10,10] by [-15, 8]
Notice the symmetry about the line y x=
Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Prentice Hall Slide 1- 112
Base a Logarithmic Function
( )
( )
( )
The base logarithm function log is the inverse of
the base exponential function 0, 1 .
The domain of log is 0, , the range of .
The range of log is , , the domain of .
a
x
xa
xa
a y x
a y a a a
x a
x a
=
= ¹
¥
- ¥ ¥
Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Prentice Hall Slide 1- 113
Logarithmic Functions
Logarithms with base e and base 10 are so important in applications that calculators have special keys for them.
They also have their own special notations and names.
log ln is called the .
log log is often called the .10
y x xe
y x x
natural logarithm function
common logarithm function
= =
= =
Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Prentice Hall Slide 1- 114
Inverse Properties for ax and loga x
log
ln
Base : , 1, 0
Base : , ln , 0
a x
x x
a a x a x
e e x e x x
= >
= =
Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Prentice Hall Slide 1- 115
Properties of Logarithms
For any real numbers 0 and 0,
log log log
log log log
log log
x y
Product Rule : xy x ya a a
xQuotient Rule : x ya a ay
yPower Rule : x y xa a
= +
= -
=
Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Prentice Hall Slide 1- 116
Example Properties of Logarithms
Solve the following for .
2 12x
x
=
Take logarithms of both sides
PowerRule
2 12
ln 2 ln12
ln 2 ln12
ln12 2.3025853.32193
ln 2 .693147
x
x
x
x
=
=
=
= = »
Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Prentice Hall Slide 1- 117
Example Properties of Logarithms
Solve the following for .
5 60x
x
e + =
Subtract 5
Take logarithm of both sides
5 60
55
ln ln55
ln55 4.007333
x
x
x
e
e
e
x
+ =
=
=
= »
Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Prentice Hall Slide 1- 118
Change of Base Formula
lnlog
lna
xx
a=
This formula allows us to evaluate log for any
base 0, 1, and to obtain its graph using the
natural logarithm function on our grapher.
a x
a a ¹
Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Prentice Hall Slide 1- 119
Example Population Growth
0.015The population of a city is given by 105,300
where 0 represents 1990. According to this model,
when will the population reach 150,000?
tP P e
t
=
=
0.015
0.015
0.015
0.015
Solve for t
Take logarithm of both sides
Inverse property
105,300 , 150,000
105,300
150,000
105,300
150,000ln ln
105,300
0.353822= 0.01
150,000
5
0.353822= 23.5881
0.015
t
t
t
t
P e P
e
e
e
t
t
= =
=
=
æ ö÷ç =÷ç ÷çè ø
» 33 years 0 is 1990, so
the population will reach 150,000 in the year 2013.
t =
Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Prentice Hall
1.6
Trigonometric Functions
Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Prentice Hall Slide 1- 121
Quick Review
In Exercises 1 4, convert from radians to degrees or
degrees to radians.
1. 2. 2.53
3. 40 4. 45
In Exercises 5 7, solve the equation graphically in the
given interval.
5. sin 0.6, 0 2
6. cos 0.4, 0 2
x x
x x
p
p
-
-
-
-
= £ <
=- £ <
° °
37. tan 1,
2 2x x
p
p p= - £ <
Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Prentice Hall Slide 1- 122
Quick Review
( )
( )
2
3
8. Show that 2 3 is an even function. Explain why
its graph is symmetric about the -axis.
9. Show that 3 is an odd function. Explain why
its graph is symmetric about the origin.
10. Give on
f x x
y
f x x x
= -
= -
( ) 4e way to restrict the domain of the function 2
to make the resulting function one-to-one.
f x x= -
Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Prentice Hall Slide 1- 123
Quick Review Solutions
In Exercises 1 - 4, convert from radians to degrees or
degrees to radians.
1. 2. 2.53
3. 40 4. 45
In Exercises 5 - 7, solve the equation graphically in the
given interval.
5. sin 0
60
.6,
143
9
0 2
.24
2
x x
p
p
p
p
-
-
-
-
= £ <
° °
° °
4
0.6435, 2.4981
1.98236. cos 0.4, 0 2
37. t
, 4.3009
0.7854, 3an 1, .92
2702
x x
x x
x
x
x
p
p p
=- £ <
= - ȣ <
»
»
Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Prentice Hall Slide 1- 124
Quick Review Solutions
( )
( ) ( ) ( )
( )
2
2 2
8. Show that 2 3 is an even function. explain why
its graph is symmetric about the -
2 3 2 3
The graph is symmetric about the -axis
a
because if a point
, is on the graph, the
is.
n
x
so
f x x x f x
y
a b
f x x
y
- = - - = - =
= -
( ) is the point , .a b-
Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Prentice Hall Slide 1- 125
Quick Review Solutions
( )
( ) ( ) ( ) ( )
( )
3
3 3
9. Show that 3 is an odd function. Explain why
its graph is symmetric about the o
3 3
The graph is symmetric about the origin because if a point
, is on the graph, t
rigi
he
n.
n
f x x x x
f x x
x f x
a
x
b
- = - - - =-
-
+
=
=-
( )
( ) 410. Give one way to restrict the domain of the function 2
to make the resulti
so is the poin
ng functi
t , .
0
on one-to-one.
f x x
a b
x
- -
-
³
=
Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Prentice Hall Slide 1- 126
What you’ll learn about…
Radian Measure Graphs of Trigonometric Functions Periodicity Even and Odd Trigonometric Functions Transformations of Trigonometric Graphs Inverse Trigonometric Functions
…and why
Trigonometric functions can be used to model periodic behavior and applications such as musical notes.
Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Prentice Hall Slide 1- 127
Radian Measure
The radian measure of the angle ACB at the center of the unit circle equals the length of the arc that ACB cuts from the unit circle.
Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Prentice Hall Slide 1- 128
Radian Measure
An angle of measure θ is placed in standard position at the center of circle of radius r,
Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Prentice Hall Slide 1- 129
Trigonometric Functions of θ
The six basic trigonometric functions of are
defined as follows:
sine: sin cosecant: csc
cosine: cos secant: sec
tangent: tan cotangent: cot
y r
r y
x r
r xy x
x y
q
q q
q q
q q
= =
= =
= =
Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Prentice Hall Slide 1- 130
Graphs of Trigonometric Functions When we graph trigonometric functions in the coordinate plane, we usually
denote the independent variable (radians) by x instead of θ .
Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Prentice Hall Slide 1- 131
Angle Convention
Angle Convention: Use Radians
From now on in this book, it is assumed that all angles are measured in radians
unless degrees or some other unit is stated explicitly. When we talk about the angle
we 3
pmean radians ( which is 60°), not degrees.
3 3
When you do calculus, keep your calculator in radian mode.
p p
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Periodic Function, Period
( )( ) ( )
A function is if there is a positive number such
that for every value of . The smallest value
of p is the of .
The functions cos , sin , sec and csc are periodic wi
f x p
f x p f x x
f
x x x x
periodic
period
+ =
th
period 2 . The functions tan and cot are periodic with
period .
x xp
p
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Even and Odd Trigonometric Functions
The graphs of cos x and sec x are even functions because their graphs are symmetric about the y-axis.
The graphs of sin x, csc x, tan x and cot x are odd functions.
cosy x= siny x=
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Example Even and Odd Trigonometric Functions
Show that csc is an odd function.x
( )( )1 1
csc cscsin sin
x xx x
- = = -- -
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Transformations of Trigonometric Graphs
The rules for shifting, stretching, shrinking and reflecting the graph of a function apply to the trigonometric functions.
( )( )y a f b x c d= + +
Vertical stretch or shrink
Reflection about x-axis
Horizontal stretch or shrink
Reflection about the y-axisHorizontal shift
Vertical shift
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Example Transformations of Trigonometric Graphs
( )Determine the period, domain, range and draw the graph of
2sin 4y x p=- +
[-5, 5] by [-4,4]
( )
We can rewrite the function as 2sin 44
2The period of sin is . In our example 4,
2so the period is = . The domain is .
4 2The graph is a basic sin curve w
y x
y a bx bb
x
p
p
p p
æ öæ ö÷ç ÷ç=- + ÷÷ç ç ÷÷ç ÷ç è øè ø
= =
- ¥ ¥,
ith an amplitude of 2. Thus, the range is [ 2, 2].
The graph of the function is shown together with the graphof the sin function.x
-
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Inverse Trigonometric Functions
None of the six basic trigonometric functions graphed in Figure 1.42 is one-to-one. These functions do not have inverses. However, in each case, the domain can be restricted to produce a new function that does have an inverse.
The domains and ranges of the inverse trigonometric functions become part of their definitions.
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Inverse Trigonometric Functions
1
1
1
1
1
1
cos 1 1 0
sin 1 1 2 2
tan 2 2
sec 1 0 ,2
csc 1 , 02 2
cot 0
y x x y
y x x y
y x x y
y x x y y
y x x y y
y x x y
Function Domain Range
pp p
p p
pp
p p
p
-
-
-
-
-
-
= - £ £ £ £
= - £ £ - £ £
= - ¥ < <¥ - < <
= ³ £ £ ¹
= ³ - £ £ ¹
= - ¥ < <¥ < <
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Inverse Trigonometric Functions
The graphs of the six inverse trigonometric functions are shown here.
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Example Inverse Trigonometric Functions
1 1Find the measure of sin in degrees and in radians.
2- æ ö÷ç- ÷ç ÷çè ø
1
1
1Put the calculator in degree mode and enter sin .
2
The calculator returns 30
1Put the calculator in radian mode and enter sin .
2
The calculator returns .52359877556 radians.
-
-
æ ö÷ç- ÷ç ÷çè ø
-
æ ö÷ç- ÷ç ÷çè ø
-
°.
This is the same as radians.6
p-
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Quick Quiz Sections 1.4 – 1.6
2
You should solve the following problems without using a graphing caluclator.
1. Which of the following is the domain of ( ) log 3 ?
(A) ,
(B) ,3
(C) 3,
(D) [ 3, )
(E) ( ,3]
f x x
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Quick Quiz Sections 1.4 – 1.6
2
You should solve the following problems without using a graphing caluclator.
1. Which of the following is the domain of ( ) log 3 ?
(
(C) 3,
A) ,
(B) ,3
(D) [ 3, )
(E) ( ,3]
f x x
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Quick Quiz Sections 1.4 – 1.6
2. Which of the following is the range of ( ) 5cos 3?
(A) ,
(B) 2,4
(C) 8,2
(D) 2,8
2 8(E) ,
5 5
f x x
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Quick Quiz Sections 1.4 – 1.6
2. Which of the following is the range of ( ) 5cos 3?
(A) ,
(B) 2,4
(C) 8,2
2 8(E) ,
5
(D) 2,8
5
f x x
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Quick Quiz Sections 1.4 – 1.6
3
3. Which of the following gives the solution of tan -1 in ?2
(A) 4
(B) 4
(C) 33
(D) 4
5(E)
4
x x
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Quick Quiz Sections 1.4 – 1.6
3
3. Which of the following gives the solution of tan -1 in ?2
(A) 4
(B) 4
(C) 33
5(E)
D)
4
( 4
x x
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Chapter Test
( )( )
In Exercises 1 and 2, write an equation for the specified line.
1. through 4, 12 and parallel to 4 3 12
2. the line where has the following values:
3. Determine whether the graph of the function
x y
y f x f
- + =
=
1
5
4
3
is
symmetric about the -axis, the origin or neither.
14. Determine whether the function is even, odd or neither.
2
y x
y
xy
x x
=
+=
-
x - 2 2 4
f(x) 4 2 1
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Chapter Test
( ) ( )( )
( )( )
In Exercises 5 and 6, find the a domain and b range, and
c graph the function.
5. 2sin 3 1
6. ln 3 1
y x
y x
p= + -
= - +
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Chapter Test
7. Write a piecewise formula for the function.
21
1
Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Prentice Hall Slide 1- 150
Chapter Test
( )
( )
8. 5cos , 2sin , 0 2 is a parametrization
for a curve.
a Graph the curve.
Identify the initial and terminal points, if any.
Indicate the direction in which the curve is traced.
b Find a Cartesian equati
x t y t t p= = £ £
on for a curve that contains
the parametrized curve.
What portion of the graph of the Cartesian equation
is traced by the parametrized curve?
Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Prentice Hall Slide 1- 151
Chapter Test
( ) ( )( )
( ) ( )( ) ( )( )
( )
1 1 1
1
9. Give one parametrization for the line segment with
endpoints 2, 5 and 4,3 .
10. Given 2 3 ,
a find and show that
b graph and in the same viewing window
f x x
f f f x f f x
f f
- - -
-
-
= -
=○ ○
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Chapter Test Solutions
( )
( )
In Exercises 1 and 2, write an equation for the specified line.
1. through 4, 12 and parallel to 4 3 12
2. the line where has the following values:
3. Determine whether the gra
4 2
p
0
3 3
13
2
x y
y f
y x
y
x f
x
=- -
=- +
- + =
=
1
5
4
3
Origin
h of the function is
symmetric about the -axis, the origin or neither.
14. Determine whether the function is even, odd
2
or neither O. dd
y x
y
xy
x x
=
+=
-
x - 2 2 4
f(x) 4 2 1
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Chapter Test Solutions
( ) ( )( )
( ) ( )( ) ( ) ( ) ( ) ( )
In Exercises 5 and 6, find the a domain and b range, and
c graph the f
a A
un
ll
ctio
Rea
n.
5. 2s
ls b
in 3 1 6
[ 3, 1] a 3, b All Rea
. ln 3
s
1
l
y x y xp= + - =
- ¥
- +
[-π, π] by [-5, 5]
[- 2, 10] by [- 2, 5]
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Chapter Test Solutions
7. Write a piecewise formula for the function.
( )1 , 0 1
2 , 1 2
x xf x
x x
ì - £ <ïï=íï - £ £ïî
21
1
Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Prentice Hall Slide 1- 155
Chapter Test Solutions
( )
8. 5cos , 2sin , 0 2 is a parametrization
for a curve.
a Graph the curve.
Identify the initial and terminal points, if any.
Indicate the direction in which the curve is traced.
x t y t t p= = £ £
Initial Point (5, 0)Terminal Point (5, 0)
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Chapter Test Solutions
( )2 2
8. b Find a Cartesian equation for a curve that contains
the parametrized curve.
What portion of the graph of the Cartesian equation
is traced by the parametrized curve?
15 2
Al
x yæö æ ö÷ ÷ç ç+ =÷ ÷ç ç÷ ÷ç çè ø è ø
l
Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Prentice Hall Slide 1- 157
Chapter Test Solutions
( ) ( )
( )
( ) ( )( ) ( )( )
( ) ( )
( )( )
1 1 1
1
1
9. Give one parametrization for the line segment with
endpoints 2, 5 and 4,3 .
10. Given 2 3 ,
a find and show that
(A possible answer)
2 6 , 5 2 , 0 1
2a
32
3
x t y t t
xf x
xf f x
f x x
f f f x f f x
f
-
-
-
- -
=- + = - £ £
-=
æ ö- ÷ç= ÷ççè
-
= -
=
ø
○ ○
( )
( )( ) ( )( )1 1
22 3 2 2
3
2 2 3 32 3
3 3
xx x
x xf f x f x x- -
æ ö- ÷ç= - = - - =÷ç÷ ÷çè ø
- -= - = = =
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Chapter Test Solutions
( ) 110. b graph and in the same viewing windowf f -
( ) 2 3f x x= -
( )1 2
3
xf x- -
=
[-5, 5] by [-5, 5]