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1.0Introduction to the organizationICBT Campus is the education arm of Ceylinco consolidated is also a BOI approved
project formed with a vision of Dr. DeshamanyaLalithKothalawala, Chairman
Ceylinco Consolidated to conduct internationally recognized educational programs at
a high standard for an affordable investment in association with world class
universities and educational institutes.ICBT Campus is the fastest growing private
sector educational institution with high-class standard of education, faculty, facilities
and resources.
International College of Business and Technology Ltd. Set up in 2000, this is one of
the leading tertiary education providers in Sri Lanka with the largest number of
students in the private sector higher education category. Popularly known as ICBTCampus, it delivers Certificate, Diplomas, Pre University programs undergraduate
programs, masters level programs including Doctorate level programs in association
with some of the best Universities and educational service providers in UK, Australia,
Thailand, India and Sweden.
Company Vision:
"To be the leading Higher Education Provider in South Asia."
Company Mission;
Our mission is together with internationally reputed Universities and Educational
Institutes, to provide high quality educational programs, which will enhance the
quality of the human resources available to the job markets at an affordable level,
thereby contributing to the development of economy."
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2.0 Planning process of the survey
Activity
name Details of the activity Proceedings
Allocate
time
A Discussion about the topic for the project - 1
B Discussion about the preparation of the questionnaire A 3C Collection of all the questions B 2
D Organizing the questions B 1
E Finalizing the questionnaire B 1
F Preparing a sample questionnaire E 1
G Printing a sample questionnaire F 1
H Submit the sample questionnaire to the lecturer (Ms. Kalpana) G 1
I Rechecking the printed questionnaire for mistakes and printing them H 3
J Divide the questionnaires equally among the members I 1
K Building up a good strategic plan to distribute the questionnaires J 1
L Distributing the questionnaires among the students and the others K 5
M Collecting all the distributed questionnaires and numbering them K 2N Feeding the data which are included in the questionnaires to the computer M 1
O
Analyze the data which are been included in the computer and analyzingthe data N 3
P Analyzing the conclusions O
Q Including the collected information in the assignment report P 1
R Finalizing the report in an effective manner Q 1
2.0.1 CPA Analysis
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2.1 Implementation of plan
As shown in the implementation plan we started our project on the second week of
September 2010. The discussion of the questions of the project was done on the first
week which didnt take a lot of time, this was done with the whole group getting
together to make sure that the proper questions were made.
We prepared a sample questionnaire on the first half of the second week got it printed
and showed Ms. Kalpana for approval on Friday. The third week was spent for the
distribution and collection of questionnaires.
The final week was spent in analyzing data and making decisions. Finally on Friday
the 1st of October the report was prepared and submitted to the progamme office.
September
1st 2nd 3rd 4th
Discussion & finalizing questions
Preparation & printing of sample questionnaire
Submit the sample questionnaires for approval
Distribution& collection of questionnaires
Analysis of questionnaire
Preparation of final report
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2.2 Objective of the study
The main idea of the project is to make good decision making from effectiveuse of information based on ICBT city campus.
We are intended to gain practical knowledge by carrying out a surveyregarding to seek data as solutions. In order to find solutions, first we
identified the problems and started collecting primary and secondary
information through various sources.
Examine variety of sources to develop techniques and effective usage ofcomputer knowledge to utilize information regarding the survey.
Analyze and produce recommendation and solutions on behalf to overcomethe problem.
2.1.1 Defining the problem
ICBT city campus is trying to develop an in house cafeteria for students, as a
marketing tool to gain more students to the institute. This cafeteria will be a student
oriented place where students can spend their leisure time.
The idea for a in house cafeteria aroused to the management because of the complains
made by students saying that the canteen which is situated now has less space to
accommodate students and has a expensive price for food.
To solve the above problem the management requires a few questions answered such
as
1.Food requirements of students2.Entertaining requirements of students
To get the answers to the above questions we are given a task of conducting a survey
to get data for decision making. A time period of one month is given to finish the
survey. The survey mainly focuses on the students of ICBT city campus who are
studying in the Business management section as well as the IT section.
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The first problem is an essential thing for students because they cant survive without
food. The key difficulty in this question is on selecting the right kind of food. Food
can be categorized into various categories such as formal food (breakfast, lunch),
snacks, deserts & so on. So to get the right answer the question asked to solve this
problem must be effective.
The second question is about solving the entertainment requirements of the students.
In this modern world students are addicted to various technological gadgets such as
ipods, PSP, mobile phones and the list goes on and on. The key difficulty in this
question is on selecting the right kind of entertainment. So to get the correct answer
the question must be categorized to various forms of entertainment such as music,
gaming, chatting, etc
2.1.2 Defining population
ICBT city campus approximately has 500 to 600 students currently studying in the
campus which includes full time and part time students who study in the IT section
and the Business management section. But for this survey, the full time students who
study in the IT and Business management will be selected as the population. The
population contains both boys and girls studying in both sections.
2.1.3 Sampling method
The sampling method used in this survey will be probability sampling multi stage
method because the population is already divided into batches which contains eight IT
batches and eight BM batches for the full time students, from this four BM batches
and Two IT batches will be selected as a first stage sample. To get the six first stage
samples the section and the batch number are written on a paper put in a bowl and
selected randomly.
For the second stage three boys and two girls will be selected from each batch
randomly by convenience sampling where the interviewer will interview the
interviewees to his convenience.
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Finally, Five (Three boys and two girls) from each batch from six batches which will
be thirty students will be the sample size. Since this is all randomly selected there will
be no sample frame.
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2.3 Design and justification of the questionnaire
Batch number and section:
Gender : Male/Female
Q1. What do you think about the current prices of food at the canteen?
1.Expensive 2. Neither cheap/expensive 3. Cheap
Q2. If Expensive what is the price range would you prefer buying the food? (Rs)
Q3. What type of food do you expect from a canteen? (Rate your choice from a scale
of 1- 5)
Breakfast & Lunch
Snacks
Fast food
Baked food
Salads & deserts
Q4. What is your favorite kind of food? (Be specific ex: vanilla ice cream, Chocolate
cake)
.
Q5. In an in house cafeteria do you think entertainment is a necessity?
Yes No
Q6. If your answer is Yes to the above question what type of entertainment do you
expect?
(Rate your choice from a scale of 1- 5)
Music .
Internet .
T.V .....
Arcade games .
Q7. How do you think an in house cafeteria at ICBT city campus will be of benefit
to thestudents? Please explain your answer
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....
ThankYou foryourvaluable time that you took foransweringourquestionnaire
Justification of the design of the questionnaire
yQuestions have been minimized to seven to make the questionnaire as small aspossible
yQuestions are arranged in a proper logical manneryThe length of the questions are kept short and easy to understandyNo questions which consist of race, religion, politics or any other
embarrassing words are used in the questions
yAll instructions on how to answer the questions are providedyClarification of questions are provided by a footnote
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B E E
B / / 9
l i
i T i
i i i - llExpensi e 11Neit er cheap/expensi e 21Cheap 08
expensi e27%
neithercheap/expensi e
53%
cheap
20%
Pri opi ion Mal Female Total No of
students
Expensi e 05 06 11
Neither cheap/expensi e 07 14 21
Cheap 02 06 08
Total No of students 14 26 40
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Price opinion - Male
Mode
Mode = Neither cheap/expensi e (07), becausethe mode is an average which
indicates the most frequentl occurring value; that value is 7 . Therefore mode is
Neither cheap/expensi e
Price opinion Male
Expensive 05
Neither cheap/expensive 07
Cheap 02
Total 14
Expensive
36%
Neither
cheap/expensiv
e
50%
Cheap
14%
Male
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Price opinion Frequency
(No of Male)
Cumulative
frequency
Expensive 05 05
Neither cheap/expensive 07 12
Cheap 02 14
Total 14
The 8th item is the median,
And the 8th item comes under the Neither cheap/expensive
Therefore median is Neither cheap/expensive .
Mean
These datas come under ungrouped and these also havent the value of x, therefore
we decided to number them in order to 1, 2, 3.
Price opinion Value
x
Frequency f
(No of Male)
fx
Expensive 1 05 05
Neither cheap/expensive 2 07 14
Cheap 3 02 06
Total 6 f = 14 fx = 25
= th
= (14+1)/2
= 7.5
8th
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Here we cant give the mean in fraction or decimals, because here we considering
students of ICBT . Quantit of students comes under Discrete value. Therefore
mean value is 2.
Price opinion - Female
Price opinion Female
Expensive 06
Neither cheap/expensive 14
Cheap 06
Total 26
Expensive
23%
Neither
cheap/expensive
54%
Cheap
23%
Female
= 25/14
= 1.7857
2
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Mode
Mode = Neither cheap/expensive (14), because the mode is an average which
indicates the most frequently occurring vale; that value is 14. Therefore mode is
Neither cheap/expensive
Median
Price opinion Frequency f
(No of Female)
Cumulative
frequency
Expensive 06 06
Neither cheap/expensive 14 20
Cheap 06 26
Total 26
The 14th item is the median,
And the 14th item comes under the Neither cheap/expensive
Therefore median is Neither cheap/expensive .
= th
= (26+1)/2
= 13.5
14th
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Mean
These datas come under ungrouped and these also havent the value of x, therefore
we decided to number them in order to 1, 2, 3.
Price opinion Value
x
Frequency f
(No of Female)
fx
Expensive 1 06 06
Neither cheap/expensive 2 14 28
Cheap 3 06 18
Total 6 f = 26 fx = 52
Here we got the mean value is 2.
= 52/26
= 2
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Comparison of both Male & Female
Price opinion Male Female
Expensive 05 06
Neither cheap/expensive 07 14
Cheap 02 06
Total 14 26
Here we are going to calculate Mode, Median, Mean according to the total number of
students.
0
2
6
8
10
12
1
16
Expensive Neither
cheap/expensive
Cheap
No of
students
Price opinion
Male
Female
Price opinion Total No of
students
Expensive 11
Neither cheap/expensive 21
Cheap 08
Total No of students 40
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Mode
Mode = Neither cheap/expensive (21), because the mode is an average which
indicates the most frequently occurring vale; that value is 21. Therefore mode is
Neither cheap/expensive
Median
Price opinion Total No of
students
Cumulative
frequency
Expensive 11 11
Neither cheap/expensive 21 32
Cheap 08 40
Total No of students 40
The 21stitem is the median,
And the 21st item comes under the Neither cheap/expensive
Therefore median is Neither cheap/expensive .
= th
= (40+1)/2
= 20.5
21st
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Mean
These datas come under ungrouped and these also havent the value of x, therefore
we decided to number them in order to 1, 2, 3.
Price opinion Value
x
Frequency f
(No of students)
fx
Expensive 1 11 11
Neither cheap/expensive 2 21 42
Cheap 3 08 24
Total 6 f = 40 fx = 77
Here we cant give the mean in fraction or decimals, because here we considering
students of ICBT. Quantity of students comes under Discrete value. Therefore
mean value is 2.
Measure of Dispersion
01. Range
Range = 21-08
=
Range = highest value lowest value
= 77/40
= 1.925
2
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02. Quartiles
= th quartile
11th is Expensive; therefore lower quartile is also Expensive.
21st is cheap/expensive; therefore middle quartile also neither cheap /expensive.
31st is also cheap/expensive; therefore upper quartile also cheap/expensive
Inter Quartile Range ( IQR) =
= (40+1)/4
= 10.25
11th
= (40+1)/2
= 20.5
21st
= 3 (40+1)/4
= 30.75
31st
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03. Mean Deviation / Average Deviation
yHere mean is 2, and this is ungrouped data. Therefore we calculate the meandeviation by using above equation.
Price
opinion
Value
x
Frequency f
(No of students)
fx Expensive 1 11 11 1 1 11
Neither
cheap/expensive
2 21 42 0 0 0
Cheap 3 08 24 1 1 08
Total 6 40 77 2 2 19
04. Variance
=2/40
=
=19/40
=
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05. Standard Deviation
Coefficient of Variance (C of V)
=0.689
0.7
=0.7/2
=0.35
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Question 02: Preferred price range for buying food.
Rs.(Price Range) No of Male No of Female Total no of
students
0- 20 0 0 0
21-40 02 03 05
41-60 05 12 17
61- 80 07 04 11
81-100 05 02 07
Total no of
students
19 21 40
Overall Students
0
2
4
6
8
10
12
14
16
18
0- 20 21-40 41-60 61- 80 81-100
Totalno of students
Total noofstudents
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Male
Price Range Mid point (x) No Of Male (f) (fx)
0 20 10 00 00
21 40 30 02 60
41- 60 50 05 250
61 80 70 07 490
81 100 90 05 450
x= 250 f = 19 fx = 1250
Mean
= 1250/19
= 65.789
66.
Median
Price Range No of male Cumulative Frequency
0 20 00 00
21- 40 02 02
41 60 05 07
61 80 07 14
81 - 100 05 19
f = 19
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= 19 + 1 / 2
= 10th.
Median is comes under the class interval of 61- 80.Because this is grouped data.Therefore we have to find midpoint of particular class interval. That is as follows,
Median = 61 + 80 / 2
70
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Mode
Price Range No of male
0 -20 00
21- 40 02
41- 60 05
61 -80 07
81 -100 05
The mode is between 61 80 class intervals. According to the theory graph method is
easy to find the mode.
Rs.70 is the mode of male.
0
12
3
4
5
7
8
0-20 21- 40 41- 0 1-80 81-100
Chart Title
0-20
21- 40
41- 0
1-80
81-100
70
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Female
Price Range Mid Point (x) No of Female (f) fx
0 -20 10 00 00
21- 40 30 03 90
41- 60 50 12 600
61 80 70 04 280
81 100 90 02 180
Total f 21 fx 1150
Mean
=1150 /21
=54.76
55.
Median
= (21 + 1/2)
= 11th.
Price Range No of Female Cumulative Frequency
0 20 00 00
21- 40 03 03
41 60 12 15
61 80 04 19
81 - 100 02 21
Total f = 21
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Median is in between 41 60 class intervals. Median is comes underthe class interval
of 41- 60.Because this is grouped data. Therefore we have to find midpoint of
particular class interval. Thatis as follows,
Mode
Price Range No of Female
0 -20 00
21- 40 03
41- 60 12
61 -80 04
81 -100 02
The mode is fallen between 41 60 class intervals.
Rupees 51 is the mode of female.
0
2
4
6
8
10
12
14
0-20 21- 40 41- 60 61-80 81-100
Series1
Median = (41 + 60) / 2
50
51
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Female and Male Comparison
Suitable Table 01
Price Range Midpoint (x) No of Students (f) fx
0-20 10 00 00
21-40 30 05 150
41- 60 50 17 850
61-80 70 11 770
81-100 90 07 630
f=40 fx=2400
Mean
=2400 / 40
= 60
0
2
6
8
0
2
0-20 2
-
0
- 60 6
-80 8
-
00
Noofmale
Noof emale
Price Range
Noof
Students
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Median
= 41 / 2
= 21st.
Median is in between 41 60 class intervals. Median is comes under the class interval
of 41- 60.Because this is grouped data. Therefore we have to find midpoint of
particular class interval. That is as follows,
(41+60)/2 50
21st frequency falls under the class intervals 41 60.
Price Range No of students Cumulative No of
Students.
0 20 00 00
21 40 05 05
41 60 17 22
61 80 11 33
81 100 07 40
f = 40
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Mode
Price Range No of students
0 20 00
21 40 05
41 60 17
61 80 11
81 100 07
No of students 40
The mode is between 41 60 class intervals.
Rupees 52 is the mode of all students . This overall mode is very near to the Female.
According to this females are more affecting to the In House Cafetaria.
0
2
4
6
8
10
12
14
16
18
0 20 21 40 41 60 61 80 81 100
Noof
St
ents
i e Range
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Measure of Dispersons
01. Range
Price range No of students
0 20 00
21 40 05
41 60 17
61 80 11
81- 100 07
Total no of Students f=40
0 is the lowest class limit value of lowest class interval Actually class limit for 0
20 class interval is (-0.5). But Rupees never takes a minus value. Therefore we had
chosen 0 for as the lowest class limit value.
100.5 is the greatest class limit value of highest class interval.
Range = (100.5 0)
= 100.5
101
02. Quartiles
Price Range No of Students Cumulative no Students
0 -20 00 00
21 40 05 05
41 60 17 22
61 80 11 33
81 100 07 40
40
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Lower Quartile
= 41 + 2 (10 05)/ 17
= 41 + 10 / 17
=41.588
= Rs. 42
Middle Quartile
=41 + 2 (21 05)/ 17
= 41 + 32 / 17
=42.88= Rs.43
Upper Quartile
Inter Quartile Range (IQR)
IQR = Q3 Q1
= 43 42
= 01.
= 41 + 2(31- 22)/11
= 41 + 18 / 11
42.63
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03. Mean Deviation / Average deviation
Here we are going to use ungrouped data method.
Price
Range
Mid
Point
(x)
No of
Students
(f)
fx (x x) f(x
x)
(x x)2 f(x
x)2
0 -20 10 00 00 50 00 2500 0
21- 40 30 05 150 30 150 900 4500
41 -60 50 17 850 10 170 100 1700
61- 80 70 11 770 10 110 100 1100
81 100 90 07 630 30 210 900 6300
Total f=40 fx=2400 640 13600
From that f=40 and fx=2400 we can find calculate the x again.
= 2400 / 40
= 60.
04. Variance (S2)
=13600 / 60
= 226.6
227.
= 640 / 40
= 16.
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05. Standard Deviation
= = 15.05
15.
Coefficient of Variance
Coefficient of Variance = Standard Deviation / Mean
= 15 / 60
= 0.25
Skewness
Mode < Mean = +
Mode > Mean = (-)
In this Scenario (+) skewness is available. Mode is 52 and Mean is 60.
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According to Male
Mode
Opinion Male
No Answer 01
No Benefit 04
Benefit 13
Total No of Students 18
Mode = Benefit (13)
Median
Opinion Male Cumulative frequency
No Answer 01 01
No Benefit 04 05
Benefit 13 18
Total No of Students 18
Mean
Opinion Value x No of Male f fx No Answer 1 01 01
No Benefit 2 04 08
Benefit 3 13 39
Total No of Students 18 48
= (18+1)/2
=9.5
10th
= Benefit
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Median
Description No of Students Cumulative frequency
Salads and Deserts 03 03
Breakfast and Lunch 07 10
Snacks 09 19
Fast Food 10 29
Baked Food 11 40
Total No of Students 40
Mean
Description Value (x) No of
Students (f)
(fx) Salads and Deserts 1 03 03 2.5 6.25 18.75
Breakfast & Lunch 2 07 14 1.5 2.25 15.75
Snacks 3 09 27 0.5 0.25 2.25
Fast Food 4 10 40 0.5 0.25 2.50
Baked Food 5 11 55 1.5 2.25 24.75
Total 40 139 6.5 11.25 64
= (40+1)/2
=20.5
21st
= Fast Food
=139/40
=3.475
3.5
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Measures of Dispersions
01. Range
Range = (55 - 3)
= 52
02. Quartiles
Description No of Students Cumulative frequency
Salads and Deserts 03 03
Breakfast and Lunch 07 10
Snacks 09 19
Fast Food 10 29
Baked Food 11 40
Total No of Students 40
11th is Snacks; therefore lower quartile is Snacks
21st is Fast Food; therefore middle quartile is Fast Food.
= (40+1)/4
= 10.25
11th
= (40+1)/2
= 20.5
21st
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31st is Baked Food; therefore middle quartile is Baked Food.
03. Mean Deviation
04. Variance
05. Standard Deviation
= 3 (40+1)/4
= 30.75
31st
= 6.5/40
=
=64/40
=
=1.265
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Mean
Description Value (x) No of Male (fx)
Salads and Deserts 1 04 4
Breakfast and Lunch 2 05 10
Snacks 3 07 21Fast Food 4 06 24
Baked Food 5 02 10
Total 24 65
Female
Description No of Female Cumulative frequency
Salads and Deserts 03 3
Breakfast and Lunch 04 7
Snacks 03 10
Fast Food 05 15
Baked Food 01 16
Total 16
Mode = Fast Food (05)
=65/24
=2.708
2.71
= (16+1)/2
=8.5
9th
= Snacks
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Mean
Description Value (x) No of Female (fx)
Salads and Deserts 1 03 3
Breakfast and Lunch 2 04 8
Snacks 3 03 9Fast Food 4 05 20
Baked Food 5 01 5
Total 16 45
=45/16
=2.813
2.8
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Overall students opinion
Entertainment
methods
No of Students Cumulative
frequency
TV 03 03
Arcade Games 05 08
Music 07 15
Indoor Games 09 24
Internet 16 40
Total No of students 40
Mode = internet (08)
Mean
Number these in order to 1, 2, 3.Entertainment
methods
Value
x
No of Students
f
fx
TV 1 03 03
Arcade Games 2 05 10
Music 3 07 21
Indoor Games 4 09 36
Internet 5 16 80
Total No of students 40 150
= (40+1)/2
=21st
= Indoor Games
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21st is Indoor Games; therefore middle quartile is Indoor Games.
31st is also Internet; therefore upper quartile is Internet.
03. Mean Deviation / Average Deviation
Entertainment
methods
Value
x
No of Students
f
fx
TV 1 03 03 3 9 27
Arcade Games 2 05 10 2 4 20
Music 3 07 21 1 1 07
Indoor Games 4 09 36 0 0 00
Internet 5 16 80 1 1 16
Total No of students 40 150 07 70
= (40+1)/2
= 20.5
21st
= 3 (40+1)/4
= 30.75
31st
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Ungrouped data
04. Variance
05. Standard Deviation
Coefficient of Variance (C of V)
= 7/40
=
=70/40
=
=1.32
= 1.32/4
=0.33
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Male
After ranked, only considered to male
Entertainment
methods
No of Male
TV 00
Indoor Games 02
Music 03
Arcade Games 04
Internet 08
Total No of students 17
Mode = Internet (08)
T , 0
Indoor
Games, 2
Music, 3
Arcade
Games, 4
Internet,8
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Median
Entertainment
methods
No of Male Cumulative
frequency
TV 00 00
Indoor Games 02 02
Music 03 05
Arcade Games 04 09
Internet 08 17
Total No of students 17
Mean
Number these in order to 1, 2, 3.
Entertainment
methods
Value
x
No of Male
f
fx
TV 1 00 00
Indoor Games 2 02 04
Music 3 03 09
Arcade Games 4 04 16
Internet 5 08 40
Total No of students 17 69
= (17+1)/2
=9th
= Arcade Games
=69/17
=4.058
4.1
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Median
Entertainment
methods
Female Cumulative
frequency
Indoor Games 01 01
TV 03 04
Music 04 08
Arcade Games 07 15
Internet 08 23
Total No of students 23
Mean
Number these in order to 1, 2, 3.
Entertainment
methods
Value
x
No of Female
f
fx
Indoor Games 1 01 01
TV 2 03 06
Music 3 04 12
Arcade Games 4 07 28
Internet 5 08 40
Total No of students 23 87
= (23+1)/2
=12th
= Arcade Games
=87/23
=3.782
3.8
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Overall comparison
Entertainment
methods
Male Female
TV 00 03
Arcade Games 04 01
Music 03 04
Indoor Games 02 07
Internet 08 08
Total No of students 17 23
0
2
3
4
5
!
7
8
9
TV Ar " ad #
Gam # $
% u $ i " Indoor Gam# $
Int # rn # t
No ofStudents
Student's o & inion
mal #
female
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Correlation and Regression
Spearman rank correlation coefficient (R)
Food item (ranked) Entertainment (ranked) d d2
Salads and Deserts 03 TV 03 0 0Breakfast and Lunch 07 Arcade Games 05 2 4
Snacks 09 Music 07 2 4
Fast Food 10 Indoor Games 09 1 1
Baked Food 11 Internet 16 5 25
Total 40 40 34
n = numbers of pairs of data
d = the difference between the ranking in each set of data
The correlation between the preferred food item and the preferred entertainment form
is negative, but it not even stronger.
= (1 - 1.7)
= (-0.7)
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5.0 Conclusion
After all analysis of gathered information these are the final outcomes of the survey.
yBy the analysis of all students most students think the current price of food atthe canteen is neither cheap nor expensive. So most probably the price of the
food can range from Rs. 40 70.
yBut still many students think that a new in house cafeteria would benefit thestudents because the main problem they are facing with the current canteen is
the less space requirement for them.
yFood requirements still remain the same because most students prefer bakedfood or fast food as their hunger needs. So it is advised that ICBT use more
fast food in sales.
yEntertainment requirement is expected by all the students. The most preferredentertainment form is the internet. All students are eager in having internet
facility because they are now involved in social networking such as Facebook,
Twitter and so on
Finally the conclusion of the whole assignment will be that building a new in house
cafeteria will be a good marketing tool for ICBT city campus.
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