y

x

Directions For The Rise and Run

Upward - Positive Rise

Downward - Negative Rise

Right - Positive Run

Left - Negative Run

. y

x

Plot points A (2,-1) and B (4, 5).Draw line AB.Determine the rise and run of line AB.

rise = 6

run = 2A

B

Calculate the slope of line AB.

m = rise run

= 6 2

= 3

Therefore the slope of line AB is positive. The slope of line AB is 3.

Since the line slants upwards from left to right, the rise is positive.

Given points A (2, -1) and B (4, 5), calculate the slope of line AB.

Given points Q (-5, 2) and R (5, -4), calculate the slope of line QR.

Plot points Q (-5, 2) and R (5, -4).y

x

R

Q

Draw line QR.Determine the rise and run of line QR.

rise = -6

run = 10

Since the line slants downwards from left to right, the rise is negative.

Calculate the slope of line QR.

m = rise run

= -6 10

= -3 5

Reduce fraction to lowest terms.

Therefore the slope of line QR is negative. The slope of line QR is -3 . 5

1. Given points C (1, 5) and D (4, 3), calculate the slope of line CD.

2. Given points Y (-6, -4) and Z (-2, 2), calculate the slope of line YZ.

3. Given points O (-3, 4) and P (4, 4), calculate the slope of line OP.

4. Given points E (3, -2) and F (3, -5), calculate the slope of line EF.

5. A ramp reaches a door which is 2m above the ground. The ground distance (the base of the ramp) is 5m long. A ramp is considered safe if its slope is less than 0.3. Is the ramp safe?

1. Given points C (1, 5) and D (4, 3), calculate the slope of line CD.

x

y

3

-2

m = rise run

= -2 3

Therefore the slope of line CD is negative. The slope of line CD is -2 . 3

C

D

2. Given points Y (-6, -4) and Z (-2, 2), calculate the slope of line YZ.

x

y

Y

Z

4

6

m = rise run

= 6 4

= 3 2

Therefore the slope of line YZ is positive. The slope of line YZ is 3 . 2

3. Given points O (-3, 4) and P (4, 4), calculate the slope of line OP.

x

y

O Pm = rise run

= 0 7

7

= 0

Therefore the slope of the horizontal line, OP, is zero.

4. Given points E (3, -2) and F (3, -5), calculate the slope of line EF.

x

y

F

E

3

m = rise run

= 3 0

= undefined

Therefore the slope of the vertical line, EF, is undefined since three is not divisible by zero.

A ramp reaches a door which is 2m above the ground. The ground distance (the base of the ramp) is 5m long. A ramp is considered safe if its slope is less than 0.3. Is the ramp safe?

2m

5m

m = rise run

= 2 5

= 0.4

Therefore the slope of the ramp is 0.4. Since the slope of the ramp is greater than 0.3, the ramp is too steep and is not considered safe.