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16a_graphing functions.notebook 1 February 22, 2018 Warm up back of p 13 Find the range (y) values given each function and domain (x). y = x 5; domain = {4, 6, 8} y = 2x + 5; domain = {2, 2, 4} x x5 y 4 6 8 x 2x+5 y 2 2 4

y = 2x + 5; domain = {2, 2, 4}...2x — 3 5x — 3 3x — 1 5 2x -1 4x — 2 y — —3x+5 Twice x minus 5 A. c. D. one-half of x plus 4 4 added to negative one-half of x the product

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Page 1: y = 2x + 5; domain = {2, 2, 4}...2x — 3 5x — 3 3x — 1 5 2x -1 4x — 2 y — —3x+5 Twice x minus 5 A. c. D. one-half of x plus 4 4 added to negative one-half of x the product

16a_graphing functions.notebook

1

February 22, 2018

Warm up back of p 13

Find the range (y) values given each function and domain (x).

y = x 5; domain = 4, 6, 8

y = 2x + 5; domain = 2, 2, 4

x x5 y468

x 2x+5 y

224

Page 2: y = 2x + 5; domain = {2, 2, 4}...2x — 3 5x — 3 3x — 1 5 2x -1 4x — 2 y — —3x+5 Twice x minus 5 A. c. D. one-half of x plus 4 4 added to negative one-half of x the product

16a_graphing functions.notebook

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February 22, 2018

Page 3: y = 2x + 5; domain = {2, 2, 4}...2x — 3 5x — 3 3x — 1 5 2x -1 4x — 2 y — —3x+5 Twice x minus 5 A. c. D. one-half of x plus 4 4 added to negative one-half of x the product

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February 22, 2018

Page 4: y = 2x + 5; domain = {2, 2, 4}...2x — 3 5x — 3 3x — 1 5 2x -1 4x — 2 y — —3x+5 Twice x minus 5 A. c. D. one-half of x plus 4 4 added to negative one-half of x the product

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February 22, 2018

Page 5: y = 2x + 5; domain = {2, 2, 4}...2x — 3 5x — 3 3x — 1 5 2x -1 4x — 2 y — —3x+5 Twice x minus 5 A. c. D. one-half of x plus 4 4 added to negative one-half of x the product

16a_graphing functions.notebook

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February 22, 2018

Page 6: y = 2x + 5; domain = {2, 2, 4}...2x — 3 5x — 3 3x — 1 5 2x -1 4x — 2 y — —3x+5 Twice x minus 5 A. c. D. one-half of x plus 4 4 added to negative one-half of x the product

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February 22, 2018

Page 7: y = 2x + 5; domain = {2, 2, 4}...2x — 3 5x — 3 3x — 1 5 2x -1 4x — 2 y — —3x+5 Twice x minus 5 A. c. D. one-half of x plus 4 4 added to negative one-half of x the product

16a_graphing functions.notebook

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February 22, 2018

Page 8: y = 2x + 5; domain = {2, 2, 4}...2x — 3 5x — 3 3x — 1 5 2x -1 4x — 2 y — —3x+5 Twice x minus 5 A. c. D. one-half of x plus 4 4 added to negative one-half of x the product

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February 22, 2018

Algebraic long division Divide 2x³ + 3x² - x + 1 by x + 2 x + 2 is the divisor The quotient will be here. 2x³ + 3x² - x + 1 is the dividend

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