5

x2_ 18=0 24=0 32=0 x2— llx— 12=0 x2+2x-48=o x2-14x+49=o 24X + 144 = 0 6 /0 101+25=0 5x+ 14 2t2+7x=O 16x2+24x+9=o 2.r2+6x= 12—9 3X2+2t= 2X2—6X— 16 81 = 0 2512-101+1=0 36++601+25=0

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Page 1: x2_ 18=0 24=0 32=0 x2— llx— 12=0 x2+2x-48=o x2-14x+49=o 24X + 144 = 0 6 /0 101+25=0 5x+ 14 2t2+7x=O 16x2+24x+9=o 2.r2+6x= 12—9 3X2+2t= 2X2—6X— 16 81 = 0 2512-101+1=0 36++601+25=0

Page 2: x2_ 18=0 24=0 32=0 x2— llx— 12=0 x2+2x-48=o x2-14x+49=o 24X + 144 = 0 6 /0 101+25=0 5x+ 14 2t2+7x=O 16x2+24x+9=o 2.r2+6x= 12—9 3X2+2t= 2X2—6X— 16 81 = 0 2512-101+1=0 36++601+25=0

Page 3: x2_ 18=0 24=0 32=0 x2— llx— 12=0 x2+2x-48=o x2-14x+49=o 24X + 144 = 0 6 /0 101+25=0 5x+ 14 2t2+7x=O 16x2+24x+9=o 2.r2+6x= 12—9 3X2+2t= 2X2—6X— 16 81 = 0 2512-101+1=0 36++601+25=0

Page 4: x2_ 18=0 24=0 32=0 x2— llx— 12=0 x2+2x-48=o x2-14x+49=o 24X + 144 = 0 6 /0 101+25=0 5x+ 14 2t2+7x=O 16x2+24x+9=o 2.r2+6x= 12—9 3X2+2t= 2X2—6X— 16 81 = 0 2512-101+1=0 36++601+25=0

Page 5: x2_ 18=0 24=0 32=0 x2— llx— 12=0 x2+2x-48=o x2-14x+49=o 24X + 144 = 0 6 /0 101+25=0 5x+ 14 2t2+7x=O 16x2+24x+9=o 2.r2+6x= 12—9 3X2+2t= 2X2—6X— 16 81 = 0 2512-101+1=0 36++601+25=0

Juliette Hagg - Offices and Directory - University of ... · Web viewFor example, the equation x2 + 1 = 0 has two solutions, but they are not real numbers. Watch! x2 + 1 = 0 x2 = -1

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