x Tract Intro

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    Intro to XTRACT program

    1. UseXtract onserver(locatedinTRCfolder)

    2. Downloadtrialversionfrom

    http://www.imbsen.com/softwareXTRACT.html

    SECTION ANALYSIS USING XTRACT (A QUICK INTRO)

    Needtoinputinfoinall5

    linesinordertoproceed.

    Enterthenameofthe

    section,usuallystartfroma

    templateorapreviously

    definedsectionandselect

    preferredunitssystem.

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    SECTION TYPE AND TRANSVERSE REINFORCEMENT

    Selectsectiontype

    (e.g.circularorrectangular

    columns,rectangularbeams,

    Tbeams,rectangularwalls

    andenclosedcomposite)

    Selecttransverse

    reinforcementlayout.

    Specifytransversereinforcementbarsizeand

    spacing(s).(Shown:hoopsandcrossties#4@3)

    Ifallowedto,theprogramwillusethisinfoto

    calculateeffectiveconfinementofthecore.

    Usuallywe

    input

    the

    confinement

    parameters

    (i.e.effectiveconfiningstresses)byhandusing

    theprocedurespresentedintheCourse.

    SECTION DIMENSIONS AND LONGITUDINAL REINF.

    Specifydimensionsandclear

    cover.

    Specifyamountoflongitudinalreinforcement

    andbarsize(dblong).(Shown:8#8)

    Checkthesummaryofthesectionpropertiesand

    thelongitudinalreinforcementratio(totalsteel

    areadividedbygrosscolumnarea)

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    MATERIALS DEFINITION: UNCONFINED CONCRETE

    Addnewunconfinedcover

    concretematerial.

    Cfc(largecolumnnominalconcrete

    compressivestrengthwithreduction

    factorC=0.85.

    For

    beams

    use

    fc)

    fr=7.5(fc)1/2 (oraround10%fc)

    Notethesignconvention!

    Thisisjustareference

    valueusedbythesolver

    algorithmtodefineaFirst

    Yield

    Criterion

    .

    Usually

    set

    to70%o.

    Whendealingwith

    confinedsections,settoa

    verylargenumber(e.g.

    equal1)toavoidthesolver

    algorithmfromreachinga

    falselimitingvalue.This

    willnotgiveunrealistic

    highercapacitiesbecause

    thestrengthissetto zero

    forsuchlargestrains(i.e.

    PostCrushingStess=0)

    cu=0.004(ACIvaluetypicallytakenas0.003)

    sp=0.004(othervaluetypicallyusedis0.006)

    cu=0.004sp=0.006

    Ec=57(fc)1/2 (fcinpsi)

    Alternative

    MATERIALS DEFINITION: CONFINED CONCRETE

    Addnewconfinedcoreconcrete

    material.

    CAUTION!!Unconfinedconcrete

    properties!!!

    Sameasbeforesetto

    70%o.

    ccu(confinedconcreteultimatestrain)

    fcc(confinedconcretestrength)

    Ec=57(fc)1/2 (fcinpsi)

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    MATERIALS DEFINITION: REBAR STEEL A706-G60

    Addnewlongitudinalsteel

    stressstrainrelation.

    (perFigure2.3.2andTable2.3.2in

    theReader)

    MESH SIZE & SECTION CREATION

    ClickHeretoBegin!

    Herethesizeofthe

    discretizationmeshcan

    beadjusted(i.e.define

    thesizeofthetriangles

    intowhichthesection

    isdivided).Ingeneral

    trytoavoidmakingit

    muchsmallerthanthe

    defaultvaluebecause

    itusuallyshowsan

    errorthathastodue

    withmemory

    management

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    EXERCISE 1: INCREMENTAL AXIAL LOADING

    GotoLoading/Moment

    Curvature(Crtl+T)

    (+)forcompressionand()fortension

    incrementalloading

    Theobjectiveofthisexampleistoshowtheresponseofacolumnwithconfinedcoreunderincremental

    axialloading(similartoProblem5 Homework3)

    Initialconditionspriortothe

    incrementalaxialload

    analysis.Forthisexamplewe

    willstartfromzero.(Usually,

    wesetanaxialloadfor

    columnsorwallsbeforedoing

    incrementalmomentloading)

    Herewesetwhichtypeof

    incrementaldemandwewill

    imposeto

    the

    section

    Giveanametotheloading

    pattern

    EXERCISE 1: INCREMENTAL AXIAL LOADING

    Hitrun,

    then

    check

    the

    projectmanagerandexplore

    theoutputsoftheanalysis

    Thefailuremechanismisgovernedbythematerialthatfirst

    reachestheultimatestrain.Inthisexampleitcouldbe

    eithertheconfinedconcretereachingcu =0.029orthe

    steelreachingsu =0.14.

    Herewecananalyzewhatisthestressstrainrelationof

    eachmaterialateverystageoftheresponse.

    Givesasummaryoftheresponseofthesection(Py,Pu,

    ductilitycapacityu/y,etc.)

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    EXERCISE 2: MOMENT-CURVATURE ANALYSIS

    GotoLoading/Moment

    Curvature(Crtl+T)

    ()forcompressionoftheextremetopfiber

    Theobjectiveofthisexampleistoshowthemomentcurvature(M)responseofacolumnwithanappliedaxialload

    Applyatypicalaxialloadof

    10%Agfc.(+)forcompression

    Willapplymoment

    incrementsuntileitherthe

    confinedconcreteorthe

    longitudinalsteelreachthe

    limitingstrain(cu=0.029orsu=0.14)

    Giveanametotheloading

    pattern

    Hitrun,

    then

    check

    the

    projectmanagerandexplore

    theoutputsoftheanalysis

    EXERCISE 2: MOMENT-CURVATURE ANALYSIS

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    Step6intheM

    relation

    Stateofthebottomsteel

    @Step6

    Stateofthesection

    @Step6:

    bottom

    steel

    yielded,neutralaxis

    abovemiddepth steel

    Stateofthebottom

    steel@

    Failure

    Stateoftheextremefiber

    ofconfinedconcretein

    compression@Step6

    Stateoftheconcrete

    @Failure

    .Thisiswhy

    theanalysisended!!!

    EXERCISE 2: MOMENT-CURVATURE ANALYSIS

    EXERCISE 2: MOMENT-CURVATURE ANALYSIS

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    EXERCISE 3: PM-INTERACTION DIAGRAM

    GotoLoading/PMInteraction

    (Crtl+T)

    Herethereductionfactorgivenbythe

    buildingcodescanbeapplied.

    Theobjectiveofthisexampleistoshowhowtoconstructionanaxialloadmoment(PM)interaction

    diagram.

    Onlyhalfdiagramisrequired

    becausethesectionis

    symmetricaboutthehorizontal

    andverticalaxes.

    0deg willapplythemoment

    incrementsaroundtheXaxis

    Giveanametotheloading

    pattern

    Defaultvalueswillgivea

    smoothandaccuratecurve

    EXERCISE 3: PM-INTERACTION DIAGRAM

    Hitrun,thenchecktheprojectmanagerandexplore

    theoutputsoftheanalysis