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2014 Geometry Practice SOL version 1
Name:
____ 1. Let p represent:
Two angles are vertical angles.
Let q represent:
The angles are congruent.
What is the symbolic representation of the following statement?
If two angles are not congruent, then the angles are not vertical angles.
a. b. c. d.
____ 2. Tammie is drawing the
perpendicular bisector of .
Which point is on the
perpendicular bisector of ?
a. L b. S c. Y d. B
____ 3. In this figure, parallel lines b and n
are intersected by line k.
Which pair of angles is NOT
supplementary?
a. and b. and c. and d. and
____ 4. What type of construction
is illustrated in the figure?
a. The bisection of c. An angle congruent to
b. The bisection of d. A line segment congruent to
J W
L
S
Y
B
b
n
k
GX
U A
2014 Geometry Practice SOL version 1
____ 5. The Venn diagram represents students
who play instruments in the orchestra.
Identify each region of the Venn
diagram that represents students who
play only the tuba and the clarinet.
a. 5, 6, 10 b. 6 c. none d. 5, 10
____ 6. An angle congruent to
angle T is being
constructed.
Which ray could be
drawn to construct an
angle congruent to ?
a.
b.
c.
d.
____ 7. Which is a valid conclusion that can be drawn from these statements?
If a quadrilateral is a rectangle, then it is a parallelogram.
If a quadrilateral is a parallelogram, then its opposite sides are congruent.
a. Every quadrilateral is a rectangle.
b. Every parallelogram is a rectangle.
c. Opposite sides of a rectangle are congruent.
d. Opposite sides of a quadrilateral are congruent.
____ 8. What is the inverse of the following statement?
If the measure of an angle is 90º, then it is a right angle.
a. If the measure of an angle is not 90º, then it is not a right angle.
b. If it is not a right angle, then the measure of an angle is not 90º.
c. If it is a right angle, then the measure of an angle is 90º.
d. If the measure of an angle is not 90º, then it is a right angle.
harp tuba
clarinet bass
T
S
X
VD
E
2014 Geometry Practice SOL version 1
____ 9. Which diagram shows a pair of angle measures that prove lines q and l are parallel?
a.
c.
b.
d.
____ 10. This figure show parallel
stair railings through points
H, U, R, and F.
What is the value of x ?
a. 27 b. 45 c. 63 d. 117
11. Line d and m are cut by a transversal
What value of x proves that d // m ?
q l
z
r
123°
123°
q l
z
r
123°
57°
q l
z
r
123° 57°
q l
z
r
123°
123°
H U R F
63
d
m
141
(2x + 41)
2014 Geometry Practice SOL version 1
____ 12. Given E (–3, 9) and T (7, –9)
What is the length of ?
a. b. c. d.
13. Line g contains the points
(–6, 7) and (6, –1).
Plot a point other than point S
with integral coordinates that
is on a line parallel to g and
passes through point S.
____ 14. Given : X(–9, –3) and E(–5, –1) What is the slope of ?
a. b.
c.
d.
E
T
1 2 3 4 5 6 7 8 9–1–2–3–4–5–6–7–8–9 x
1
2
3
4
5
6
7
8
9
–1
–2
–3
–4
–5
–6
–7
–8
–9
y
(3, –6)
Sg
1 2 3 4 5 6 7 8 9 10–1–2–3–4–5–6–7–8–9–10 x
1
2
3
4
5
6
7
8
9
10
–1
–2
–3
–4
–5
–6
–7
–8
–9
–10
y
2
1
2
1
2
2
2014 Geometry Practice SOL version 1
____ 15. Which best describes
the construction in the
diagram shown?
a. The bisector of a line segment
b. A line segment congruent to a given line segment
c. A perpendicular to a given line at a point on the line
d. A perpendicular to a given line from a point not on the line
____ 16. Quadrilateral WSJC is shown.
If WSJC is reflected across the
line , what are the
coordinates of J’ ?
a. b. c. d.
____ 17. Given the measures shown in the diagram, which two triangles are congruent?
a. K and L b. R and M c. R and L d. K and M
B H
W
S
J
C
1 2 3 4 5 6 7 8 9–1–2–3–4–5–6–7–8–9 x
1
2
3
4
5
6
7
8
9
–1
–2
–3
–4
–5
–6
–7
–8
–9
y
KR
21
21
46
46
58
66
M L21
21
46 46
68
66
2014 Geometry Practice SOL version 1
____ 18. The figure represents a ramp
with handrails.
Segments HJ and LM are
parallel to PQ.
Segments JK and MN are
parallel to QR.
Segments HP and JQ are
parallel to KR.
If , what is
?
a. 64º b. 90º c. 116º d. 154º
____ 19. For which polygon are both and lines of symmetry?
a.
c.
b.
d.
116
H J
K
LM
N
P Q
R
2014 Geometry Practice SOL version 1
____ 20. Nori attached a wire
between two poles on a hill
as shown.
Which is closest to x, the
distance between the two
poles?
a. 48 yd b. 52 yd c. 114 yd d. 126 yd
____ 21. Triangles KRQ, KEQ, and FRQ
are show on the coordinate grid,
and all the vertices have
coordinates that are integers.
Which statement is true?
a. No two triangles are congruent.
b. Only and are congruent.
c. Only and are congruent.
d. Triangle KRQ, , and are all congruent
22. The lengths of two sides of a triangle are 22 feet and 49 feet. What is the range of possible lengths, in feet, for
the third side, x, of this triangle?
____ 23. Which of the following sets of lengths can represent the measures of the sides of a right triangle?
a. 4, 5, 6 b. 5, 7, 13 c. 8, 12, 17 d. 24, 32, 40
135
21
yd
K
R
F
E
Q
1 2 3 4 5–1–2–3–4–5 x
1
2
3
4
5
–1
–2
–3
–4
–5
y
2014 Geometry Practice SOL version 1
____ 24. Part of a marching band formed by a triangle made with cornet players on one side, oboe players on one side,
and clarinet players on the third side.
• The angle formed by the cornet and clarinet players measured 47º
• The angle formed by the clarinet and oboe players measured 67º
Which orders the sides of this triangle from least to greatest using the instrument names?
a. oboe, cornet, clarinet c. cornet, clarinet, oboe
b. oboe, clarinet, cornet d. clarinet, cornet, oboe
____ 25. An equilateral triangle is folded in half.
What is x, the height of the equilateral
triangle?
a. yd b. 18 yd c. yd d. 9 yd
____ 26. Look at this triangle.
Which triangle is similar to the given triangle?
a.
c.
b.
d.
yd18
L
S
H
4 m
m
5.5 mm
5.5 mm
3 mm
4.13 mm4.13 mm2.25 mm 2.83 mm
3.77 mm
3 mm
5.83 mm
5.83 mm 4 mm
4 mm
5.5 mm
2014 Geometry Practice SOL version 1
27. Click and drag each selected reason to the correct box
Given: Figure VJUZ with diagonal
;
Complete the proof of by selecting the
reasons for the last two statements.
Statements Reasons
Given
____ 28. A spectator is viewing the six cars
of a roller coaster as it travels down a
hill at an amusement park.
Which is the closest to the total
length of the six cars?
a. 14.4 ft b. 16.0 ft c. 25.0 ft d. 39.9 ft
29. Given: Parallelogram GDPL where
and .
What value of x proves this
parallelogram is a rhombus?
V
Z
J
U
24 ft
37
G
D
L
P
2x - 14
4x - 42
2014 Geometry Practice SOL version 1
____ 30. Which could be the lengths of three sides of a triangle?
a. 16 cm, 10 cm, 6 cm c. 18 cm, 21 cm, 19 cm
b. 22 cm, 11 cm, 8 cm d. 30 cm, 18 cm, 11 cm
____ 31. Three triangles that do not overlap
are shown on the coordinate grid.
The coordinates of all vertices are
integers.
Which statement is true?
a. b. c. d.
____ 32. Using the information given,
which congruence postulate or
theorem can be used to prove
that ?
a. Hypotenuse-Leg Theorem c. Side-Angle-Side Postulate
b. Side-Side-Side Postulate d. Angle-Side-Angle Postulate
____ 33. Given: W lies on and U lies on
Which condition proves ?
a. c. b.
d.
F
Q
L
ZG1 2 3 4 5 6–1–2–3–4–5–6 x
1
2
3
4
5
6
–1
–2
–3
–4
–5
–6
y
XW
AL
D
E
W
MU
Y
2014 Geometry Practice SOL version 1
____ 34. The cross-section for a wooden beam
is modeled by the composite of
the regular pentagon and triangle
shown.
What is closest to the measure of
?
a. 158º b. 168º c. 163º d. 178º
____ 35. Given: Circle E with center at (–6, –5)
What equation could represent circle E?
a. c.
b. d.
____ 36. This container is composed
of a right circular cylinder and
a right circular cone.
Which is closest to the surface
area of the contianer?
a. 1175 cm² b. 1935 cm² c. 2315 cm² d. 1555 cm²
____ 37. A tablet computer box in the shape of a rectangular
prism is shown. The height of the box is 3 cm.
The height of the original box will be increased
by 2.5 centimeters so a new instruction manual
and an extra battery can be included. Which is
closest to the total surface area of the new box?
a. 515.5 in² b. 543 in² c. 567 in² d. 681 in²
S
Y
Q
12 cm
cm11
cm22
3 in
14 in
13.5in
2014 Geometry Practice SOL version 1
____ 38. Given: Circle F
What is the value of y?
a. 39 b. 49 c. 88 d. 92
____ 39. Parallelogram GYWH is a
rhombus with
What is the ?
a. 35° b. 55° c. 110° d. 145°
____ 40. Circle L has a center at (–5, 6) and a diameter of 10 units. Which point lies on circle L?
a. (–9, 3) b. (–5, 6) c. (1, 14) d. (5, 16)
____ 41. This figure is composed of
an isosceles trapezoid and a
regular octagon.
What is the value of x ?
a. 103 b. 109 c. 116 d. 167
FB
A
K
T
49
92
G Y
WH
C
35
58 58
2014 Geometry Practice SOL version 1
____ 42. An architect used this diagram to
design a curved balcony. She drew
a circle with a radius of 38 feet and a
central angle of 66° to determine the
length of railing needed for the
balcony.
Which is the closest to the length of
railing needed for the curved section
of the balcony?
a. 22 ft b. 44 ft c. 239 ft d. 832 ft
____ 43. A polygon is shown:
What is the measure
of ?
a. 64° b. 90° c. 116° d. 232°
____ 44. Given: Circle A
Which is the closest to the area
of the shaded sector of circle A
?
a. 26 mm² b. 143 mm² c. 238 mm² d. 380 mm²
45. The ratio of the lengths of the radii of two sphere is 4:7. What is the ratio of the volumes of these two spheres?
66
38
154
U Y
PF
TV
A
135
11mm
1 4 7 16 28 49 64 343
2014 Geometry Practice SOL version 1
____ 46. The diagonals of rectangle USDX intersect
at the point (0, 4). One of the vertices
of the rectangle USDX is located at (–8,
8).
Which of the following could be the
location of another vertex of this
rectangle?
a. (8, 0) b. (–4, 6) c. (0, 8) d. (0, 0)
____ 47. A rectangular pyramid is shown.
What is the volume of the pyramid?
a. 2244 cm³ b. 1122 cm³ c. 748 cm³ d. 204 cm³
____ 48. A company is creating a new cylinderical container to replace its original cylindrical container.
• The new container will have 25 times the volume of the original container.
• The height of the new container will remain the same as the height of the original container.
The length of the radius of the new container will be --
a. 5 times the length of the radius of the original container
b. 25 times the length of the radius of the original container
c. 125 times the length of the radius of the original container
d. 625 times the length of the radius of the original container
____ 49. The volume of a cube is 27 cubic inches. What is the surface area of the cube?
a. 9 in² b. 54 in² c. 81 in² d. 162 in²
1 2 3 4 5 6 7 8 9 10–1–2–3–4–5–6–7–8–9–10 x
1
2
3
4
5
6
7
8
9
10
–1
–2
–3
–4
–5
–6
–7
–8
–9
–10
y
17 cm
12 cm
11 cm
2014 Geometry Practice SOL version 1
50. Click on the grid to plot the point you want to select.
Plot the center of the circle
defined by the equation:
1 2 3 4 5 6 7 8 9 10–1–2–3–4–5–6–7–8–9–10 x
1
2
3
4
5
6
7
8
9
10
–1
–2
–3
–4
–5
–6
–7
–8
–9
–10
y
2014 Geometry Practice SOL version 1
Answer Section
1. ANS: C
Order reversed and nots were added to statements.
PTS: 1 REF: 2014 Geometry SOL Exam LOC: Ch 2
TOP: Triangles and Logic KEY: symbols MSC: Question 1
2. ANS: B
Construct a isosceles triangle with the same legs above and below the line. Connect the extreme angles. The
point, S, lies on that line, which is a perpendicular bisector of .
PTS: 1 REF: 2014 Geometry SOL Exam TOP: Triangles and Logic
KEY: construction MSC: Question 2
3. ANS: C
Both 2 and 7 are acute angles and cannot add to 180.
PTS: 1 REF: 2014 Geometry SOL Exam TOP: Lines and Angles
KEY: parallel lines MSC: Question 3
4. ANS: A
The three arcs that have been drawn are the first three steps to bisect .
PTS: 1 REF: 2014 Geometry SOL Exam TOP: Lines and Angles
KEY: construction MSC: Question 4
5. ANS: C
Have to eliminate any area that has instruments other than tuba and clarinet.
No one plays only the tuba and the clarinet.
PTS: 1 REF: 2014 Geometry SOL Exam LOC: Ch 2
TOP: Triangles and Logic KEY: Venn diagram
MSC: Question 5 NOT: Technology assisted question
6. ANS: A
1) Place the compass on point T and draw an arc across both sides of the angle. Without changing the
compass radius, place the compass on point S and draw a long arc crossing the ray. 2) Set the
compass so that its radius is intersections on the two rays in the drawn angle. Place the compass on
intersection point on the new ray and draw an arc intersecting the one drawn in the previous step.
Label the intersection point 3) Use the straightedge to draw ray that completes the angle
PTS: 1 REF: 2014 Geometry SOL Exam TOP: Lines and Angles
KEY: construction MSC: Question 6
7. ANS: C PTS: 1 REF: 2014 Geometry SOL Exam
LOC: Ch 2 TOP: Triangles and Logic KEY: Law of Syllogism
MSC: Question 8
8. ANS: A
Original statement: If the measure of an angle is 90º, then it is a right angle.
inverse tells us to negate clauses and we get: If the measure of an angle is not 90º, then it is not a right angle.
PTS: 1 REF: 2014 Geometry SOL Exam STA: G.1 | G.1.a
LOC: Ch 2 TOP: Triangles and Logic KEY: inverse | logic
MSC: Question 13
2014 Geometry Practice SOL version 1
9. ANS: B
Angles have to involve both line q and line l and have the transversal as a common line. Using combinations of
linear pairs and/or vertical angles, they need to form consecutive interior angles (since no consecutive exterior
angles theorem exists).
PTS: 1 REF: 2014 Geometry SOL Exam TOP: Lines and Angles
KEY: parallel lines MSC: Question 7
10. ANS: C
Corresponding angles are congruent, so x = 63
PTS: 1 REF: 2014 Geometry SOL Exam TOP: Lines and Angles
KEY: parallel lines MSC: Question 9
11. ANS:
50
Alternate exterior angles are congruent in parallel lines;
PTS: 1 REF: 2014 Geometry SOL Exam TOP: Lines and Angles
KEY: parallel lines MSC: Question 15 NOT: Technology assisted question
12. ANS: D
Distance formula:
PTS: 1 REF: 2014 Geometry SOL Exam TOP: Lines and Angles
KEY: distance MSC: Question 10
13. ANS:
(–9, 2)
Line g has a slope of .
Any point satisfying will be correct.
(–9, 2) is one point that solves that equation.
Go left 3 and up 2 or right 3 and down 2 from point S to get another point.
PTS: 1 REF: 2014 Geometry SOL Exam TOP: Lines and Angles
KEY: parallel lines MSC: Question 11 NOT: Technology assisted question
14. ANS: C
Slope =
2
3
1
2
2014 Geometry Practice SOL version 1
PTS: 1 REF: 2014 Geometry SOL Exam TOP: Lines and Angles
KEY: slope MSC: Question 16
15. ANS: A
Perpendicular bisector cuts line segment in half
PTS: 1 REF: 2014 Geometry SOL Exam TOP: Lines and Angles
KEY: construction MSC: Question 12
16. ANS: A
Reflection over line , then you exchange the x and y values
PTS: 1 REF: 2014 Geometry SOL Exam STA: G.3
LOC: Ch 9 TOP: Coordinate Relations and Transformations
KEY: reflections MSC: Question 14
17. ANS: A
Same lengths opposite same angle measures (even if triangles have been flipped -- put in the third angle
measures!)
PTS: 1 REF: 2014 Geometry SOL Exam TOP: Triangles and Logic
KEY: congruent triangles MSC: Question 23
18. ANS: D
PTS: 1 REF: 2014 Geometry SOL Exam TOP: Lines and Angles
KEY: parallel lines MSC: Question 18
19. ANS: D
x = k is a vertical line and y = h is a horizontal line. Lines of symmetry cut the figure in half.
PTS: 1 REF: 2014 Geometry SOL Exam
TOP: Coordinate Relations and Transformations KEY: symmetry
MSC: Question 17
20. ANS: D
x is the adjacent side in the right triangle, so we use trigonometry:
PTS: 1 REF: 2014 Geometry SOL Exam LOC: Ch 8
TOP: Triangles and Logic KEY: trigonometry
MSC: Question 19
21. ANS: D
These are three of the four congruent triangles in a rhombus. SSS or SAS (with perpendicular diagonals)
2014 Geometry Practice SOL version 1
PTS: 1 REF: 2014 Geometry SOL Exam LOC: Ch 4
TOP: Triangles and Logic KEY: triangle congruence
MSC: Question 20
22. ANS:
27 71
Largest side - smallest side < x < smallest side + largest side
49 - 22 < x < 22 + 49
27 < x < 71
PTS: 1 REF: 2014 Geometry SOL Exam LOC: Ch 5
TOP: Triangles and Logic KEY: triangle sides
MSC: Question 21 NOT: Technology assisted question
23. ANS: D
Must satisfy the Pythagorean theorem.
PTS: 1 REF: 2014 Geometry SOL Exam LOC: Ch 8
TOP: Triangles and Logic KEY: Pythagorean MSC: Question 22
24. ANS: B
Missing angle is 66 and represents the middle angle; oboe players (ones not mentioned in the smallest angle)
form the smallest side and cornet players (ones not mentioned in the largest angle) form the largest side.
PTS: 1 REF: 2014 Geometry SOL Exam LOC: Ch 5
TOP: Triangles and Logic KEY: triangle sides
MSC: Question 24
25. ANS: C
Pythagorean Theorem, special case right
triangles or trig can solve this
Since all sides of an equilateral triangle are
congruent, then the hypotenuse of the folded
triangle is 18.
The side opposite a 60 degree angle is .
Another way to solve it is using trig:
PTS: 1 REF: 2014 Geometry SOL Exam LOC: Ch 8
TOP: Triangles and Logic KEY: trigonometry | special case right triangles | Pythagorean
MSC: Question 25
26. ANS: A
2014 Geometry Practice SOL version 1
Isosceles triangle. Base side is smaller than original base side, so other sides (isosceles) must be smaller than
original.
PTS: 1 REF: 2014 Geometry SOL Exam TOP: Triangles and Logic
KEY: similar triangles MSC: Question 26
27. ANS:
Reflexive and SSS
A side is congruent to itself because of the Reflexive property
3 Sides are congruent; so the SSS Thrm needs to be used
PTS: 1 REF: 2014 Geometry SOL Exam LOC: Ch 4
TOP: Triangles and Logic KEY: congruent triangles | proof
MSC: Question 27 NOT: technology assisted
28. ANS: D
Need to use trig: sin --> opposite side and hypotenuse
PTS: 1 REF: 2014 Geometry SOL Exam LOC: Ch 8
TOP: Triangles and Logic KEY: trigonometry
MSC: Question 28
29. ANS:
14
PTS: 1 REF: 2014 Geometry SOL Exam TOP: Polygons and Circles
KEY: quadrilaterals MSC: Question 33 NOT: Technology assisted question
30. ANS: C
The rule is that any two sides must be greater than the third in a triangle. We add the two smallest two numbers
together and if its bigger than the largest number then those numbers will form a triangle. Only 19 cm, 21 cm,
18 cm meets that rule.
PTS: 1 REF: 2014 Geometry SOL Exam STA: G.6
LOC: Ch 5 TOP: Triangles and Logic KEY: triangles
MSC: Question 31
31. ANS: C
Match 90º angles and then short to short and long to long legs
PTS: 1 REF: 2014 Geometry SOL Exam TOP: Triangles and Logic
KEY: similar triangles MSC: Question 29
32. ANS: D
Given an angle and a included side; the vertical angles add the final angle for ASA
PTS: 1 REF: 2014 Geometry SOL Exam TOP: Triangles and Logic
2014 Geometry Practice SOL version 1
KEY: congruent triangles MSC: Question 30
33. ANS: D
AA Triangle similarity theorem; included angle M is the shared angle.
PTS: 1 REF: 2014 Geometry SOL Exam TOP: Triangles and Logic
KEY: similar triangles MSC: Question 32
34. ANS: B
Interior angles for triangle is 60 and for pentagon is 108 for a total of 168.
PTS: 1 REF: 2014 Geometry SOL Exam TOP: Polygons and Circles
KEY: interior angles MSC: Question 34
35. ANS: D
From SOL formula sheet equation of a circle:
center at (–6, –5): with
Remember that a negative of a negative is a positive.
PTS: 1 REF: 2014 Geometry SOL Exam LOC: Ch 10
TOP: Polygons and Circles KEY: circles | circle equation
MSC: Question 35
36. ANS: D
Surface area = surface area of cylinder - base covered by the cone + lateral area of cone
PTS: 1 REF: 2014 Geometry SOL Exam TOP: Three-Dimensional Figures
KEY: surface area MSC: Question 36
37. ANS: D
Rectangular prism surface area: new height is 5.5 cm (3 + 2.5).
New SA:
PTS: 1 REF: 2014 Geometry SOL Exam KEY: surface area
MSC: Question 38
38. ANS: A
Inscribed angles ATB and AKB share the same arc and therefore have the same measure.
The 3 angles inside the triangle not containing y must add to 180; so
PTS: 1 REF: 2014 Geometry SOL Exam LOC: Ch 10
TOP: Polygons and Circles KEY: circles | angles
MSC: Question 37
39. ANS: B
2014 Geometry Practice SOL version 1
Since the diagonals of a rhombus bisect opposite angles, then angles CHG, CHW and CYG are all 35°. The
three angles inside each triangle must add to 180° and the diagonals are perpendicular, so all angle C’s are 90°.
PTS: 1 REF: 2014 Geometry SOL Exam TOP: Polygons and Circles
KEY: angles | quadrilaterals MSC: Question 39
40. ANS: A
Given the center and the diameter (twice the radius) we can figure out the equation of circle L.
Now plug in the given points and see which satisfy the equation:
PTS: 1 REF: 2014 Geometry SOL Exam LOC: Ch 10
TOP: Polygons and Circles KEY: circle equation
MSC: Question 40
41. ANS: A
Leg angles in an isosceles trapezoid are supplementary; so the angle in the trapeziod next to x is 122°. A
regular octagon has an interior angle of 135° (Int + Ext = 180 and Ext = 360/8 = 45)
Once around a point is 360°; so °
PTS: 1 REF: 2014 Geometry SOL Exam TOP: Polygons and Circles
KEY: interior angles | exterior angle MSC: Question 47
42. ANS: B
We are finding the length of the arc(railing) in a circle with a radius of 38 feet and a central angle of the arc of
66°.
PTS: 1 REF: 2014 Geometry SOL Exam LOC: Ch 10
TOP: Polygons and Circles KEY: circles | arc length
MSC: Question 41
43. ANS: C
Interior angles of a hexagon (6-sided figure) is found with (n-2) x 180 = 720
2014 Geometry Practice SOL version 1
PTS: 1 REF: 2014 Geometry SOL Exam TOP: Polygons and Circles
KEY: interior angles MSC: Question 42
44. ANS: B
Area of a sector is the area of the circle times the ratio of the central angle divided by 360.
PTS: 1 REF: 2014 Geometry SOL Exam LOC: Ch 10
TOP: Polygons and Circles KEY: circles | sector area
MSC: Question 45
45. ANS:
64
Volume is a cubic relationship, so the ratio of the radii (4:7) must be cubed: 64:343
PTS: 1 REF: 2014 Geometry SOL Exam LOC: Ch 13
TOP: Three-Dimensional Figures KEY: spheres | ratios
MSC: Question 46 NOT: Technology assisted
46. ANS: A
Diagonals in a rectangle are the same length and bisect each other. The intersection is the mipoint between the
two vertices along that diagonal. If one vertex is located at (–8, 8), then it was right 8 and down 4 to get to the
midpoint (0, 4). We have to travel the same distance to get to the other endpoint (0 + 8, 4 - 4) or (8, 0).
PTS: 1 REF: 2014 Geometry SOL Exam
TOP: Coordinate Relations and Transformations KEY: quadrilaterals | diagonals
MSC: Question 44
47. ANS: C
Volume of a pyramid: where B is area of the base and h is the height
PTS: 1 REF: 2014 Geometry SOL Exam TOP: Three-Dimensional Figures
KEY: volume MSC: Question 49
48. ANS: A
Volume of a cylinder:
If height stays the same and the volume is 25 times as large, then the radius has to quintrouple -- 5 times the
length of the radius of the original container
PTS: 1 REF: 2014 Geometry SOL Exam TOP: Three-Dimensional Figures
KEY: volume MSC: Question 50
49. ANS: B
The formula for the volume of a cube is V = s³. The formula for surface area is SA = 6s².
2014 Geometry Practice SOL version 1
PTS: 1 REF: 2014 Geometry SOL Exam LOC: Ch 12
TOP: Three-Dimensional Figures KEY: volume | surface area
MSC: Question 43
50. ANS:
(–7, –8)
From the Geometry equation sheet:
Equation of a circle
so center is
(h, k) or (–7, –8) with radius = 4
PTS: 1 REF: 2014 Geometry SOL Exam LOC: Ch 10
TOP: Coordinate Relations and Transformations KEY: circle equation
MSC: Question 48 NOT: Technology assisted question
(–7, –7)
1 2 3 4 5 6 7 8 9 10–1–2–3–4–5–6–7–8–9–10 x
1
2
3
4
5
6
7
8
9
10
–1
–2
–3
–4
–5
–6
–7
–8
–9
–10
y