Written Test Marking Guide - digitalcollection.gov.mb.ca

Grade 12 Consumer Mathematics Standards Test

Written Test Marking Guide

January 2010

Manitoba Education, Citizenship and Youth Cataloguing in Publication Data 510.76 Grade 12 Consumer Mathematics Standards Test :

Written Test Marking Guide (January 2010) ISBN-13: 978-0-7711-4356-4 1. Mathematics—Examinations, questions,

etc. 2. Mathematics—Examinations 3. Mathematical ability—Testing. 4. Consumer education—Mathematics— Examinations, questions, etc. 5. Educational tests and measurements—Manitoba. 6. Mathematics—Study and teaching (Secondary)—Manitoba. I. Manitoba. Manitoba Education, Citizenship and Youth.

Manitoba Education, Citizenship and Youth School Programs Division Winnipeg, Manitoba, Canada Permission is hereby given to reproduce this document for non-profit educational purposes provided the source is cited.

After the administration of this test, print copies of this resource can be purchased from the Manitoba Text Book Bureau. Order online at <www.mtbb.mb.ca>. This resource will also be available on the Manitoba Education, Citizenship and Youth website at <www.edu.gov.mb.ca/k12/assess/archives/index.html>. Websites are subject to change without notice.

Ce document est disponible en français.

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Contents Marking Guidelines...........................................................................................................ii

Presentation of the Student Samples.............................................................................. 1

Personal Finance.................................................................................................. 2

Government Finances ........................................................................................ 10

Statistics ............................................................................................................. 18

Design and Measurement .................................................................................. 28

Variation and Formulas ...................................................................................... 30

Investments ........................................................................................................ 38

Appendix A: Irregularities In Standards Tests ............................................................... 49

Irregular Test Paper Report ................................................................................ 51

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Marking Guidelines The Grade 12 Consumer Mathematics Standards Test: Written Test Marking Guide (January 2010) is based on the outcomes and standards found in Senior 4 Consumer Mathematics: A Foundation for Implementation (2004). The recommended procedure for scoring student responses is as follows: 1. Read the Written Test Marking Guide.

2. Study the student samples provided and the rationales for the allotted scores.

3. Determine the mark for the student’s response by comparing its features with the Written Test Marking Guide descriptions. The descriptions and samples only typify a student’s response to a given question; an exact match is not anticipated.

Irregularities in Standards Tests During the administration of standards tests, supervising teachers may encounter irregularities. Markers may also encounter irregularities during local marking sessions. Appendix A provides examples of such irregularities as well as procedures to follow to report irregularities. If a scoring sheet is marked with “0” and/or “NR” only (e.g., student was present but did not attempt any questions) please document this on the Irregular Test Booklet Report.

Consumer Mathematics: Written Test Marking Guide (January 2010) 1

Type of Test Item

This section presents student sample responses with the mark(s) allotted and the rationale justifying the mark(s) allotted.

Presentation of the Student Samples Each constructed-response question is presented using the following sections:

Test Item Number

Unit of Study

Maximum Number of Marks Allotted

This section presents the test item as it appears in the student booklet, including how marks should be allotted.

2 Consumer Mathematics: Written Test Marking Guide (January 2010)

Personal Finance

Question 1 V–C1 Restricted Response (2 Marks)

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Billy Bob owns a farmhouse valued at $250 000 in Area 4. He wants to purchase standard homeowner’s insurance with a $500 deductible. Calculate his annual premium.

Answer:

First $200 000 $966 0.5 mark

$50 000Additional $50 000 $4.72 = $2361 000

0.5 mark 0.5 mark

Annual Premium $966 + $236 = $1 202 0.5 mark

←

×

←

��


Sample 1 Restricted Response (2 Marks) Mark: 1 out of 2 Rationale: - Correct table value (0.5 mark)

- Correct value for “first $200 000” (0.5 mark)

Sample 2 Restricted Response (2 Marks) Mark: 1.5 out of 2 Rationale: - Correct value for “first $200 000” (0.5 mark)

- Correct solution for “additional $50 000” (2 × 0.5 mark)

Sample 3 Restricted Response (2 Marks) Mark: 1.5 out of 2 Rationale: - Correct table value (0.5 mark)

- Correct value for “first $200 000” (0.5 mark) - Correct answer (follow-through error) (0.5 mark)

50 000×4.72

236 000+ 966

236 966 $250 000+236 966=$486 966

50 x 4.72 = $236 $236+ $966$1 202

$1 202+ $125$1 327

$500x .25$125

$250000- 200000

50000 x 4.72=23 600÷ 1 000=23.6

23.6+ 966

$989.60


Question 2 V–C2 Restricted Response (2 Marks)T

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Leonard prepared an amortization schedule for his $330 000 mortgage at 7.75% amortized over 20 years. Calculate the missing values in the table.

Answers:

(4 × 0.5 mark)

Month Monthly Payment Interest Principal Unpaid

Balance Owner’s Equity

1 $2 682.90 $551.65 $329 448.35 $55 551.65

2 $2 682.90 $2 127.69 $555.21 $56 106.86

3 $2 682.90 $2 124.10 $558.80 $328 334.34

4 $2 682.90 $2 120.49 $327 771.93 $57 228.07

Month Monthly Payment Interest Principal Unpaid

Balance Owner’s Equity

1 $2 131.25

2 $328 893.14

3 $56 665.66

4 $562.41



Question 3 V–C3 Restricted Response (1 Mark)T

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Hansel and Gretel recently purchased a home and agreed to pay the previous owners $800 for 4 months of pre-paid property taxes. Calculate their annual property tax bill. Sample answers:

(

$800 4=Total bill 12(800)(12)= 4) (Total bill) 0.5 mark for process

(800)(12) = Total bill4

$2 400 = Total bill 0.5 mark

OR

$800 = 4 months$200 = 1 month 0.5 mark12 $200 = $2 400 0.5 mark

��

←

←× ←


12 = 34800 x3 = $2 400.00

Sample 1 Restricted Response (1 Mark) Mark: 0.5 out of 1 Rationale: - Correct solution (follow-through error) (0.5 mark)

Sample 2 Restricted Response (1 Mark) Mark: 1 out of 1 Rationale: - Correct solution (2 × 0.5 mark)


800 X 4 blocks = 3 200

800 x 3 = $2400.00


Question 4 V–C4 Open Response (2 Marks)T

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Farid and Kira were hoping to buy their dream house. A) Explain why financial institutions advise potential homebuyers to keep their

Gross Debt Service Ratio (GDSR) under 32%. (1 mark)

Sample answers: • So that homeowners have money for living expenses. • Financial institutions want to avoid mortgage

foreclosures.

B) A financial institution would not approve the couple’s mortgage application even though their Gross Debt Service Ratio (GDSR) was 30.3%. Explain why they were refused. (1 mark) Sample answers: • They are too heavy in debt. • Their potential debt load is too high. • They have a poor credit rating. • This would leave them strained financially, as they are close to the

maximum percent allowed.


Sample 1 Open Response (2 Marks) A) B) Mark: 1 out of 2 Rationale: - Correct answer in Part A (1 mark)

Sample 2 Open Response (2 Marks) A) B) Mark: 2 out of 2 Rationale: - Correct answers (2 × 1 mark)

Sample 3 Open Response (2 Marks) A) B) Mark: 2 out of 2 Rationale: - Correct answers (2 × 1 mark)

The reason they weren't approved is because 30.3%is just about 32% percent so they don't think theycan pay for the house.

The reason financial institutions advise peopleto keep their GDSR under 32% because if higher theywon't be able to pay for it.


Government Finances

Question 5 V–E2 Restricted Response (1.5 Marks)

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The following table shows a breakdown of the revenue collected by the federal government: A) State the amount of money collected by the smallest source of revenue for the

government. (0.5 mark) Answer: $6.3 billion 0.5 mark← B) The government is proposing to use 30% of the Energy revenue toward a new

environment program. Calculate the amount of money to be used for the environment program. (0.5 mark)

Answer: $53.5 billion 30% = $16.05 billion 0.5 mark× ←

Note to marker: accept “$16.05” (billions implied) C) Determine the percent of the total revenue that the new environment program

will represent. (0.5 mark)

$16.05billionAnswer: 100 = 4.5% 0.5 mark$354 billion

× ←

REVENUE Billions of $ Personal income tax 85.3 Corporate income tax 32.4 Other income tax 6.3 Employment insurance revenue 50.6 GST 28.9 Custom and import duties 31.3 Energy 53.5 Other excise taxes/duties 37.4 Non-tax revenue (investments and other) 12.0 Adjustments 16.3 GROSS BUDGETARY REVENUE $354.0


Sample 1 Restricted Response (1.5 Marks) A) B) C) Mark: 0 out of 1.5 Rationale: - Incorrect solutions

Sample 2 Restricted Response (1.5 Marks) A) B) C) Mark: 0.5 out of 1.5 Rationale: - Correct solution in Part C (follow-through error) (0.5 mark)

Sample 3 Restricted Response (1.5 Marks) A) B) C) Mark: 1.5 out of 1.5 Rationale: - Correct solutions (3 × 0.5 mark)

354 000 000 000 x .30 = $1 062 000 000It represents one third of the total revenue

11

$53.5 billion x 0.30= $1.605 x 10

11$1.605 x 10 x 100 = 45.3%354.0 billion

53.5 x 0.30 = 16.0516.05 billion towards the environment program.

÷∴16.05 354.00 = .045

It represents 5% of the total revenue.

6.3

6 300 000

6.3 billions


Question 6 V–E3 Restricted Response (2 Marks)T

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Mikasha purchases precious jewellery in the United States for $75 Canadian. Calculate: A) The Customs Duty (0.5 mark)

Answer: $0 or or none 0.5 mark

Note to marker:no marks awarded for leaving the space blank

←

B) The Excise Tax (0.5 mark)

Answer: $75× 10% = $7.50 0.5 mark← C) The GST (1 mark)

Answer: $75 $7.50 = $82.50 0.5 mark$82.50 0.05 = $4.13 0.5 mark

+ ←× ←


Sample 1 Restricted Response (2 Marks) A) The Customs Duty B) The Excise Tax C) The GST Mark: 0.5 out of 2 Rationale: - Correct customs duty (0.5 mark)


- Correct excise tax (0.5 mark) - Correct GST (0.5 mark)


- Correct excise tax (0.5 mark) - Correct GST (follow-through error) (0.5 mark)

10%0%

12%

07.50

4.13

0%$7.503.75

$75 x 10%$75.00 x 5%


Question 7 V–E5 Restricted Response (1 Mark)T

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Reinhold owns and operates a service station. He purchases 40 000 litres of diesel fuel for $28 000. Calculate the amount of provincial tax that Reinhold paid on the diesel fuel. Answer: 40 000 L 11.5¢/L = 460 000¢ or $4 600

0.5 mark 0.5 mark× ��


Sample 1 Restricted Response (1 Mark) Mark: 0.5 out of 1 Rationale: - Correct table value (0.5 mark)

Sample 2 Restricted Response (1 Mark) Mark: 0.5 out of 1 Rationale: - Correct table value (0.5 mark)


- Units consistent with table value

40 000 x .115 = $4 6.00 of tax

,,

40 000 x 11.5 = 1.42 x 11.5 = $16.3328 000

11.5 x 40 000 = 460 000


Question 8 V–E6 Restricted Response (2.5 Marks)T

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Calculate the annual property tax the Simpsons must pay using the information from the chart below.

Answer: $180 000× 0.45 = $81000 portioned assessment 0.5 mark

54$81000 = $4 374 municipal and education taxes1000

0.5 mark0.5 mark

50 × $1.80 = $90 sidewalk 0.5 mark

$4 374 + $90 = $4 464 total taxes due 0.5 mark

←

×

←

←

��

SIMPSONS’ RESIDENCE

House and land (current assessment) $180 000 Portioned percentage 45% Municipal and Education mill rate 54 mills Frontage 50 feet Local Improvement Tax: sidewalk repair $1.80 per foot


Sample 1 Restricted Response (2.5 Marks)

[ ]Total revenue req.PTR = x 1 000 = mills

Total Portioned ass.

180,000 400 000= x 1 000 = = 4 407.4

.45 54

Mark: 0 out of 2.5 Rationale: - Incorrect solution


1.80 x 50 = $90,00 Mark: 0.5 out of 2.5 Rationale: - Correct local improvement tax (0.5 mark)


180 000 x0,45 =81000 x0,54 = $ 4374050 x 1,80 = 90 + 43740 = $ 43 830

Mark: 2 out of 2.5 Rationale: - Incorrect mill rate

- Correct solution (follow-through error) (4 × 0.5 mark)


Statistics

Question 9 V–F2 Restricted Response (2 Marks)

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Ramon received a test score that was in the 60th percentile. Three other people scored the same as Ramon and 58 people scored lower. Determine the total number of people that completed the test.

60

� ��

�� = � � ��

��

B + 0.5EAnswer: P = × 100n

No marks for 1 correct substitutionOR

58 + 0.5 (4) × 100 0.5 mark for 2 correct substitutionsn

OR1 mark for all correct substitutions

600.60 =n

0.5 mar60n =

0.60

←

k for strategy

n = 100 people 0.5 mark


Sample 1 Restricted Response (2 Marks) Mark: 0 out of 2 Rationale: - Incorrect solution

Sample 2 Restricted Response (2 Marks) Mark: 1.5 out of 2 Rationale: - Incorrect value for “E”

- Correct solution (follow-through error) (3 × 0.5 mark)

Sample 3 Restricted Response (2 Marks) Mark: 2 out of 2 Rationale: - Correct solution (trial and error) (2 marks)

� �� B + 0.5eP = × 100nB = 58

E = 3n = 99P = 60

58 + 0.5(3)N = × 10060

59.5N = × 10060N = 99

Ramon + 3 = 4 + 58 = 62 people did test.

B + .5(E)P = × 100NB = 58E = 4N = 62

B = 58E = 4N = 100

58 + .5(4) × 100 = 9662

58 + .5(4) × 100 = 60100


Question 10 V–F3 Open Response (1 Mark)T

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Fred and Barney are arguing over who performed better on the mathematics exam. Fred received a mark of 70% and Barney scored in the 70th percentile. Barney believes he performed better. In your opinion, who had the better result? Justify your answer. Sample answer: It cannot be determined until we know Barney’s individual score on the test or Fred’s percentile rank. All we know is that Barney did better than 70% of the rest of his class.


Sample 1 Open Response (1 Mark) Fred has the higher mark because he got 70% out ofeveryone and that total was not given so we don'tknow how high Barney's mark is.

Mark: 0 out of 1 Rationale: - Incorrect response

Sample 2 Open Response (1 Mark) It depends on how many wrote the exam and so, itonly means he got in the 70 percentile out oftest scores.


Sample 3 Open Response (1 Mark) It is unknown who scored better. Barney scored betterthan 70% of the class but it still doesn't tell you hismark and we don't know what percentile Fred scoredin so we can't compare the 2 tests to each other.

Mark: 1 out of 1 Rationale: - Correct response (1 mark)


Question 11 V–F3 Restricted Response (2 Marks)T

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Tammy wrote a statistics test in math class. The teacher found 2 errors in Tammy’s calculation of percentile rank. Tammy’s answer: Tammy’s answer:

State the 2 errors Tammy made. Answer: • Tammy used “2” instead of “3” for E. • Her final answer was written as a percent.

2 × 1 mark for explaining the two errors

.


Sample 1 Restricted Response (2 Marks) Wrong # of scores equal to, including his own score.

Mark: 1 out of 2 Rationale: - Correct answer of “scores equal to” (1 mark)

Sample 2 Restricted Response (2 Marks) 1. E should be 3

112. so her should be 11.5 out of 2020

Mark: 1 out of 2 Rationale: - Correct answer of “E should be 3” (1 mark)

Sample 3 Restricted Response (2 Marks)

10+5(3) x100 = 57.5%20

E = 3 not 2, there are three 52's notonly 2 which would make her answer 57.5 not 55 Mark: 1 out of 2 Rationale: - Correct answer of “E = 3” (1 mark)


Question 12 V–F5 Restricted Response with Explanation (2 Marks)T

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The life expectancy of a Mipod battery follows a normal distribution. The mean life expectancy of a Mipod battery is 18 months with a standard deviation of 3 months.

Life Expectancy of Mipod Battery A) Find the percent of Mipod batteries that will last between one and two years.

(1 mark)

Answer: 13.5% + 34% + 34% + 13.5% = 95%

Note to marker: accept 96%

B) Explain, with reference to the normal curve, if it is possible to expect your

Mipod battery to work after 30 months. (1 mark)

Sample answer: It can happen but the chance of it happening is low because it is more than 3 standard deviations above the mean.

1 mark for correct justification referring to normal curve.


Sample 1 Restricted Response with Explanation (2 Marks) A) 4.7% B) Mark: 0 out of 2 Rationale: - No reference to normal curve in Part B

Sample 2 Restricted Response with Explanation (2 Marks) A) B) Mark: 1 out of 2 Rationale: - Correct response in Part B (1 mark)

Sample 3 Restricted Response with Explanation (2 Marks) A) B) Mark: 1 out of 2 Rationale: - Correct response in Part B (1 mark)

No its not it is impossible to still havebattery power.

97.5Only 0.15% of Mipod batteries work after 27 monthsso its almost impossible to expect your Mipod tolast that long. Only 1 in 1000 will.

It is possible but the normal curvejust indicates it's very unlikely.

0.15010


Question 13 V–F6 Restricted Response (1 Mark)T

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Given the following graph: A) Create a situation that would fit this graph by labelling the x and y axis.

(0.5 mark)

Sample answer:

Correct labels (both) ← 0.5 mark B) State an appropriate r-value for this data. (0.5 mark)

Between –0.99 and –0.5 ← 0.5 mark

Temperature

×

××

××

××

Snowmobile Sales

×

××

××

××


Sample 1 Restricted Response (1 Mark) A) Your speed per feet as you apply your brakes. B) -75 Mark: 0 out of 1 Rationale: - Incorrect responses

Sample 2 Restricted Response (1 Mark) A) B) Mark: 0.5 out of 1 Rationale: - Correct response in Part A (0.5 mark)

Sample 3 Restricted Response (1 Mark) A) B) Mark: 0.5 out of 1 Rationale: - Correct response in Part A (0.5 mark)

x - the # of hats worny - the temperature outsider= 1

x = age of cary = value of car

r = .5


Design and Measurement

Question 14 V–D6 Restricted Response (2.5 Marks)

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Andrea is replacing the water lines in her basement. One line must run from the inlet to the hot water tank, and two lines must run from the hot water tank to the upstairs connection (for hot and cold water). A) Water lines are sold at the hardware store in 8-foot lengths for $1.10 per foot.

Calculate the cost of the lines she needs, including PST and GST. (2 marks)

(

Answer: 36 + 2(21)=78 feet 0.5 mark78 ÷ 8 = 9.75

10 lengths 0.5 mark10 8 $1.10)= $88.00 0.5 mark$88.00 0.05 = $4.40$88.00 0.07 = $6.16$88.00 $4.40 $6.16 = $98.56 0.5 mark

←

∴ ←× × ←

××+ + ←

B) A local scrap dealer will buy the leftover materials for 40 cents per foot.

Determine the price of the leftovers. (0.5 mark)

Answer: (80 – 78) 0.40 = $0.80 0.5 mark× ←

Inlet

Hot Water Tank

36 ft.

Upstairs Connection

21 ft.


Sample 1 Restricted Response (2.5 Marks) A) B) Mark: 1 out of 2.5 Rationale: - Incorrect number of pieces

- Correct cost before taxes in Part A (follow-through error) (0.5 mark) - Correct cost after taxes in Part A (follow-through error) (0.5 mark)

Sample 2 Restricted Response (2.5 Marks) A) B) Mark: 1.5 out of 2.5 Rationale: - Correct number of pieces in Part A (2 × 0.5 mark)

- Incorrect cost per 8-foot length in Part A - Correct answer in Part A (follow-through error) (0.5 mark)

Sample 3 Restricted Response (2.5 Marks) A)

B)

Mark: 2.5 out of 2.5 Rationale: - Correct solution in Part A (alternate solution) (4 × 0.5 mark)

- Correct solution in Part B (0.5 mark)

8 x 1.10 = 8.808.80 x 1.12 = $9.86

A = lxw

A = 21 x 36

A = 651 ft. 651 x .04 = $26.04

21 (2) + 3678/8 = 9.75 = 10 (1.10) = 11 (1.12) = $12.32

old: 78(0.4) = 3.12new: .25(0.4) = 0.1$3.13

÷36 8 = 4.5 = 58 x 1.10 = 8.80 x 5 = $44

÷21 8 = 2,625 = 38 x 1.10 = 8.80 x 3 = $26.4026.40 x 2 = $52.80

44 + 52.80= 96.8096.80 x 0.12 = $11.6296.80 + 11.62 = $108.42

5 - 4.5 = .5 ofan 8 foot line not used3 - 2.625 = .375 ofa line not used.5 + 0.375 + 0.375 = 1.25 x 8 = 10 feet10 feet x 0.40 = $4.00


Variation and Formulas

Question 15 VI–F1 Restricted Response (1.5 Marks)

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Gabrielle is raising money for a local charity. She has been pledged $40, and she will receive an additional $1.50 for every 100 metres that she walks. Sketch the graph of this scenario and label the axes.

Answer:

← 0.5 mark for labels ← 0.5 mark for shape (straight line) ← 0.5 mark for non-zero intercept (40 not required)

Metres

Money 40



Mark: 0 out of 1.5 Rationale: - Incorrect solution

Sample 2 Restricted Response (1.5 Marks) Mark: 1 out of 1.5 Rationale: - Correct labels (0.5 mark)

- Correct shape (0.5 mark)

Sample 3 Restricted Response (1.5 Marks) Mark: 1.5 out of 1.5 Rationale: - Correct solution (3 × 0.5 mark)


Question 16 VI–F1 Restricted Response (1.5 Marks)T

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The labour costs to fix a car vary directly with the number of hours a mechanic works on the car. It costs $276.25 for 6.5 hours of labour. Find the cost for 8 hours of labour. Answer: y= kx

276.25 = k(6.5) 0.5 mark for substitution

276.25k =6.5

k = $42.50 0.5 mark

Cost = (42.5)(8)= $340 0.5 mark

OR

6.5 8= 0.5 mark$276.25 x

6.5x = (8)($276.25)0.5 mark for process

6.5x = $2 210

x = $340 0.5 mark

←

←

←

←

��

←



276.25 x 1.5 = $414.38 for 8 hours Mark: 0 out of 1.5 Rationale: - Incorrect solution


( )276.25 6,5 8$340

Mark: 1.5 out of 1.5 Rationale: - Correct solution (3 × 0.5 mark)


⋅

y = kxc = Kh276.25 = K6.56.5K = 42.542.5 8 = $340

Mark: 1.5 out of 1.5 Rationale: - Correct solution (3 × 0.5 mark)


Question 17 VI–F3 Restricted Response (1.5 Marks)T

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Energy consumption (in kilowatt-hours) is calculated using the formula:

P T Power rating in Watts Time used in hoursE or Energy1000 1000

× ×= =

A) Determine the amount of energy consumed if a 60-watt light bulb is left on

continuously for 30 days. (1 mark)

Answer: 24 hours × 30 days =720 hours

P×TE =100060×(720)= 0.5 mark for substitution

1000= 43.2 (kilowatt-hours) 0.5 mark

←

←

B) Determine the cost of leaving the light on for the 30 days, if energy costs are

$0.08 per kilowatt-hour. (0.5 mark) Answer: 43.2 kilowatt-hours× $0.08 = $3.46 0.5 mark←



A) 60 x 30E = = 1.81 000

B) 0.08 x 24 = 1.92 x 30 = $57.6 Mark: 0.5 out of 1.5 Rationale: - Incorrect substitution in Part A

- Correct solution in Part A (follow-through error) (0.5 mark)

Sample 2 Restricted Response (1.5 Marks) A) B) Mark: 1 out of 1.5 Rationale: - Correct solution in Part A (2 × 0.5 mark)

Sample 3 Restricted Response (1.5 Marks) A) B) Mark: 1 out of 1.5 Rationale: - Incorrect substitution in Part A

- Correct solution in Part A (follow-through error) (0.5 mark) - Correct solution in Part B (follow-through error) (0.5 mark)

60 x 1800 = 108 x 0.08 = $8.641 000

720 x .08 = $57.60

60 x 1800E = 1 000E= 108

60 x 720E = = 43.21 000


Question 18 VI–F4 Restricted Response (3 Marks)T

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A) Determine the volume of a cone that has a radius of 4 cm and a height of

6 cm. (1.5 marks)

2

2

3 3 3

:

)

1Answer V = r h31V = (4) (6) 0.5 mark for substitution3

= 100.48 cm (or 100.53 cm or 32 cm0.5 mark 0.5 mark

←

��

π

π

π

B) Determine the radius of a cylinder that has the same height and volume as the cone in Part A. (1.5 marks)

2

2

2

:Answer V = r h100.48 = r (6) 0.5 mark for substitutionr = 5.33 0.5 mark

r 2.31 or 2.31 cm 0.5 mark

←←

= ←

ππ

Note to marker: No marks awarded for use of incorrect formula.


Sample 1 Restricted Response (3 Marks) A) B) r = 4 cm Mark: 0.5 out of 3 Rationale: - Correct substitution in Part A (0.5 mark)

Sample 2 Restricted Response (3 Marks) A) B) Mark: 1.5 out of 3 Rationale: - Correct solution in Part A (3 × 0.5 mark)

- Incorrect formula in Part B

Sample 3 Restricted Response (3 Marks) A) B) Mark: 2.5 out of 3 Rationale: - Correct substitution in Part A (0.5 mark)

- Correct volume in Part A (0.5 mark) - Incorrect units in Part A - Correct solution in Part B (3 × 0.5 mark)

π 2

2

1V = r h31V= (3.14) (4) (6)31V= (3.14) (16) (6)3

1(3.14) (96) = 301.44 x = 904.32÷100 = 9.04 cm3

�

�

2

2

3

1V = r h3

V= 0.3 4 (6)V= 0.3 (301.6)V= 90.5 cm

π

π

ππ π

2

2

2

2

90.5 = 0.3 r 66

27 = r1.81.5 r =

4.8 = r 2.2 = r

2

2

1 p(4 ) 63100.53 cm

π 2100.53 = (4 ) 62.31 = r


Investments

Question 19 VI–D2 Restricted Response (1 Mark)

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Identify one item from the following list that is a debt investment and one item that is an equity investment: • real estate • savings account • mortgages • collectibles Debt Investment: _________________________________________ Equity Investment: _________________________________________ Answers: Debt Investment:

savings account 0.5 markORmortgages

Equity Investment:real estate 0.5 markORcollectibles

←

←



Question 20 VI–D4 Open Response (1 Mark)T

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Casey has an accumulated balance of $120 000 in her Retirement Savings Plan (RSP). She would like to purchase retirement property worth $120 000. If she cashes in her RSP, will it cover the cost of the retirement property? Justify your response using your knowledge of RSPs. Sample answers: No, she must pay taxes on her RSP and will not have

$120 000 left. OR No, she may have to pay back-end service fees.


Sample 1 Open Response (1 Mark)

Yes it will cover the cost of the retirement propertybecause it is the same amount.



No, because for a retirement property you would haveto pay taxes so it would be more money thanwhat she has saved up.



No because when she cashes it in, they'llcharge her service charge.

Mark: 1 out of 1 Rationale: - Correct response


Question 21 VI–D5 Restricted Response (2 Marks)T

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Kendra just started investing in the stock market. On Monday, she bought 100 shares for $24.65 each. On Tuesday, her stocks had a net change of +$0.70 per share and on Wednesday they had a net change of –$0.40 per share. A) Complete the following chart based on Kendra’s 100 shares. (1.5 marks)

Day Cost/Share Total Daily Value

Monday $24.65

Tuesday

Wednesday

Answer:

Day Cost/Share Total Daily Value

Monday $24.65 $2 465 ← 0.5 mark

Tuesday $25.35 $2 535 ← 0.5 mark

Wednesday $24.95 $2 495 ← 0.5 mark B) Calculate Kendra’s net profit for the week by close on Wednesday. (0.5 mark)

Answer: $2 495$2 465

$30 0.5 mark

−

←


Sample 1 Restricted Response (2 Marks) A) B) Mark: 0 out of 2 Rationale: - Incorrect solution

Sample 2 Restricted Response (2 Marks) A) B) Mark: 0.5 out of 2 Rationale: - Correct answer for Monday in Part A (0.5 mark)

Sample 3 Restricted Response (2 Marks) A) B) Mark: 1 out of 2 Rationale: - Correct answers for Monday and Wednesday in Part A (2 × 0.5 mark)

250 .0 0-246.50$5.50


Question 22 VI–D7 Restricted Response (1.5 Marks)T

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Anne’s total assets are $150 000. Her total liabilities are $83 000. A) Determine Anne’s net worth. (1 mark)

Answer: Net Worth = Assets – Total LiabilitiesNet Worth = $150 000 – $83 000 0.5 mark for substitution

= $67 000 0.5 mark←←

B) Describe one way that Anne can increase her net worth. (0.5 mark)

Sample answers: • reduce her liabilities (debt)

• increase her assets


Sample 1 Restricted Response (1.5 Marks) A) B) Mark: 1 out of 1.5 Rationale: - Correct answer in Part A (follow-through error) (0.5 mark)

- Correct response in Part B (0.5 mark)

Sample 2 Restricted Response (1.5 Marks) A) B) Mark: 1.5 out of 1.5 Rationale: - Correct responses (3 × 0.5 mark)

Sample 3 Restricted Response (1.5 Marks) A) B) Mark: 1.5 out of 1.5 Rationale: - Correct responses (3 × 0.5 mark)

150,000 � 73,000=77,000

Anne can increase her net worth by paying off her liabilities.

150 00083 00067 000Lower her liabilities

$150,000 � $83,000 =

$67,000

liabilities


Question 23 VI–D7 Restricted Response with Explanation (2.5 Marks)T

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Mike’s financial situation includes the following:

Mike’s Finances

Assets $160 000

Liabilities (includes $60 000 mortgage) $85 000

Net Worth $75 000 Mike wishes to borrow money for a speed boat worth $25 000. A) Explain how this purchase would affect Mike’s net worth. (0.5 mark)

Sample answers: • His net worth will not change.Increase in liabilities offset increase in assets.

• Assets increase to $185 000 and liabilities to $110 000.Net worth equals $75 000

B) Based on his Debt Equity Ratio (DER), would Mike be approved for the

$25,000 loan for the speed boat? Justify your answer. (2 marks)

Answer:

Liabilities – MortgageDER = × 100Net Worth

No mark for 1 correct substitutionOR

$110 000 – $60 000DER = × 100 0.5 mark for 2 correct substitutions$75 000

OR1 mark for all correct substitutions

= 66.7% 0.5 mark

No, the

��

←

DER is too high. 0.5 mark←


Sample 1 Restricted Response with Explanation (2.5 Marks) A) B)

Mark: 0 out of 2.5 Rationale: - Incorrect responses

Sample 2 Restricted Response with Explanation (2.5 Marks)

A) It would go down because he has to pay for the boat.

B) Mark: 1.5 out of 2.5 Rationale: - Two correct substitutions in Part B (0.5 mark)

- Correct solution in Part B (follow-through error) (2 × 0.5 mark)

Sample 3 Restricted Response with Explanation (2.5 Marks) A) It wouldn't change it until he pays off what he borrowed.

B) Mark: 1.5 out of 2.5 Rationale: - Correct response in Part A (0.5 mark)

- Two correct substitutions in Part B (0.5 mark) - Correct calculation in Part B (follow-through error) (0.5 mark)

His liabilities went up because he's borrowing $25,000. Hisnet worth is affected because his liability money is$50,000 below his Assets. He cannot afford his new speed boat.

It'sover32%.

No he could not. It is over 32%. His liabilities cost almost as muchas his assets do. He canèt afford to pay on only $75.000 net worth.

85 000 - 60 00075000

25000 x 100 = 33.3 % Yes because it is below 50%75000

85 000 - 60 000D ER = x 100 = 33 .3375 000

no because D ER is 32%



Appendix A

IRREGULARITIES IN STANDARDS TESTS

A GUIDE FOR LOCAL MARKING During the marking of standards tests, markers have occasionally encountered test booklets in which there have been irregularities. The following list provides some examples of such irregularities:

• completely different penmanship in the same test booklet • incoherent work with correct answers • notes from a teacher indicating how he or she has assisted students during the test

administration • student offering that he or she received teacher assistance for a question • student submitting work on unauthorized paper • evidence of plagiarism or cheating • disturbing or offensive content

If a student’s mark on the test is 0% because he or she answered with all non-responses (“NR”), all inappropriate responses (“0”), or a combination of both, please complete an Irregular Test Booklet Report to confirm that the result is accurate (i.e., the student was not, in fact, exempted or had an excused absence). Please note that student comments or responses indicating that the student may be at personal risk of being harmed or of harming others are personal safety issues. This type of student response requires an immediate and appropriate follow-up action at the school level. In this case, please ensure the Department is made aware that a follow-up has taken place by completing an Irregular Test Booklet Report. Except in the case of cheating or plagiarism where the result is a standards test mark of 0%, it is the responsibility of the division or the school to determine how they will proceed with irregularities. Once an irregularity has been confirmed, the marker prepares an Irregular Test Booklet Report documenting the situation, the people contacted, and the follow-up. The original copy of this report is to be retained by the local jurisdiction and a copy is to be sent to the Instruction, Curriculum and Assessment Branch along with all other test materials.



Irregular Test Paper Report Test: _________________________________________________________________________ Date marked: _________________________________________________________________ Booklet No.: __________________________________________________________________ Problem(s) noted: ______________________________________________________________ ______________________________________________________________________________ ______________________________________________________________________________ ______________________________________________________________________________ ______________________________________________________________________________ ______________________________________________________________________________ Question(s) affected: ___________________________________________________________ ______________________________________________________________________________ ______________________________________________________________________________ Action taken or rationale for assigning marks: _____________________________________ ______________________________________________________________________________ ______________________________________________________________________________ ______________________________________________________________________________ ______________________________________________________________________________ ______________________________________________________________________________ ______________________________________________________________________________

Irregular Test Paper Report


Follow-up: ____________________________________________________________________ ______________________________________________________________________________ ______________________________________________________________________________ ______________________________________________________________________________ ______________________________________________________________________________ ______________________________________________________________________________ Decision: _____________________________________________________________________ ______________________________________________________________________________ ______________________________________________________________________________ ______________________________________________________________________________ ______________________________________________________________________________ ______________________________________________________________________________ ______________________________________________________________________________ Marker’s Signature: ___________________________________________________________ Principal’s Signature: __________________________________________________________

For Department Use Only—After Marking Complete Consultant: ________________________________________________________________ Date: _____________________________________________________________________



Documents

Written Test Marking Guide - digitalcollection.gov.mb.ca