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Write the electron configurations for As (33), Sb (51). 1s 2 2s 2 2p 6 3s 2 3p 6 4s 2 3d 10 4p 3 = As. 1s 2 2s 2 2p 6 3s 2 3p 6 4s 2 3d 10 4p 6 5s 2 4d 10 4p 3 = Sb. Write the outer electrons in the proper places in this chart. 1s 1. 2p 1 …. 2s 1. 2s 2. 3s 1. 3s 2. 3d 1. 3d 2 …. - PowerPoint PPT Presentation
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Write the electron configurations for Write the electron configurations for As (33), Sb (51) As (33), Sb (51)
1s22s22p63s23p64s2
3d104p65s24d104p3 = Sb
1s22s22p63s23p64s2
3d104p3 = As
Write the outer electrons in the Write the outer electrons in the proper places in this chart.proper places in this chart.
HH HeHe HeHe
22
33
44
55
66
77
ns1 ns2….
2s1
3s1
4s1
1s1
5s1
6s1
7s1
2s2
3s2
4s2
5s2
6s2
7s2
3d1
3d2…
2p1…
4d1
5d1
6d1
Dot Dot DiagramsDiagrams
Lithium (3) and Lithium (3) and Beryllium (4)Beryllium (4)
1s 2s
Li = 3 Li
Be = 4 Be
http://www.pbs.org/wgbh/nova/kaboom/elemental/Periodic table and fireworks
1s 2s 2p
B= 5 B
C = 6 C
N = 7 N
O = 8 O
F = 9 F
Ne = 10 Ne
First EnergyLevel
2nd EnergyLevel
H
Li
Na
K
Rb
Cs
Fr
1s1
1s22s1
1s22s22p63s1
1s22s22p63s23p64s1
1s22s22p63s23p64s23d104p65s1
1s22s22p63s23p64s23d104p65s24d105p66s1
1s22s22p63s23p64s23d104p65s24d105p66s24f145d106p67s1
s1 one dot!
He
Be
Mg
Ca
Sr
Ba
Ra
1s2
1s22s2
1s22s22p63s2
1s22s22p63s23p64s2
1s22s22p63s23p64s23d104p65s2
1s22s22p63s23p64s23d104p65s24d105p66s24f145d106p66s2
1s22s22p63s23p64s23d104p65s24d105p66s24f145d106p6….7s2
s2 Two dots!
B
Al
Ga
In
Tl
s2p1 three dots
C
Si
Ge
Sn
Pb
s2p2 4 dots!
s2p3 5 dots!
O
S
Se
Te
Po
s2p4 6 dots
7 dots
8 dots
[Ar] indicates a short cut for theelectron configurationof argon.Ca = [Ar]4s2
E = hE = h = c / = c / E = hc/ E = hc/ E = E = (6.6 x 10(6.6 x 10-34-34Jsec)(3.0x10Jsec)(3.0x1088m/sec)m/sec)
nm (10nm (10-9-9m/nm)m/nm)
For violet light,400 nm, E =:1.9 x 10-16
1.9 x 10-16 400= 4.8 x 10-19 Joules
Exponents:-34 + 8 –(-9)= -34 +8 + 9
=-17
6.6 x 3 = 19.8
19.8 x 10-17
= 1.98 x 10-16
E = hE = h = c / = c / E = hc/ E = hc/
E = E = (6.6 x 10(6.6 x 10-34-34Jsec)(3.0x10Jsec)(3.0x1088m/sec)m/sec)
nm (10nm (10-9-9m/nm)m/nm)
For red light,700 nm, E =:1.9 x 10-16 1.9 x 10-16 700 = 2.7 x 10-19 Joules
Exponents:-34 + 8 –(-9)= -34 +8 + 9
=-17
6.6 x 3 = 19.8
You should now be able to You should now be able to complete the homework for this complete the homework for this
Chapter!Chapter!