HomeworkWorksheet Practice 10-3 and 10-4Mrs. Rivas Ida S. Baker H.S.

𝑨=𝒃𝒉¿ (𝟏𝟎)(𝟖)¿𝟖𝟎𝒖𝒏𝒊𝒕𝒔𝟐

𝑨=𝒃𝒉𝟖𝟎=𝟐𝟎𝒉𝟒=𝒉

Find the value of h for each parallelogram, or the Area of the following figures.

HomeworkWorksheet Practice 10-3 and 10-4Mrs. Rivas Ida S. Baker H.S.

𝑨=𝟏𝟐𝒃𝒉

¿𝟏𝟐

(𝟏𝟐)(𝟏𝟎)

¿𝟔𝟎𝒄𝒎  𝟐

Find the value of h for each parallelogram, or the Area of the following figures.

HomeworkWorksheet Practice 10-3 and 10-4Mrs. Rivas Ida S. Baker H.S.

𝑨=𝟏𝟐𝒃𝒉

¿𝟏𝟐

(𝟖)(𝟓)

¿𝟐𝟎𝒎  𝟐

𝑨=𝒃𝒉¿ (𝟖)(𝟓)

¿𝟒𝟎𝒎𝟐

Find the value of h for each parallelogram, or the Area of the following figures.

𝑨=𝟐𝟎+𝟒𝟎=𝟔𝟎𝒎𝟐

HomeworkWorksheet Practice 10-3 and 10-4Mrs. Rivas Ida S. Baker H.S.

Find the value of h for each parallelogram, or the Area of the following figures.

𝑨=𝟏𝟐𝒅𝟏𝒅𝟐

𝑨=𝟏𝟐

(𝟖+𝟖)(𝟖+𝟏𝟒 )

𝑨=𝟏𝟐

(𝟏𝟔)(𝟐𝟐)

𝑨=𝟏𝟕𝟔 𝒊𝒏𝟐

HomeworkWorksheet Practice 10-3 and 10-4Mrs. Rivas Ida S. Baker H.S.

Find the value of h for each parallelogram, or the Area of the following figures.

𝑨=𝟏𝟐𝒅𝟏𝒅𝟐

𝑨=𝟏𝟐

(𝟑+𝟑)(𝟑+𝟑)

𝑨=𝟏𝟐

(𝟔)(𝟔)

𝑨=𝟏𝟖𝒎𝟐

HomeworkWorksheet Practice 10-3 and 10-4Mrs. Rivas Ida S. Baker H.S.

Find the value of h for each parallelogram, or the Area of the following figures.

𝒏

𝒏√𝟑 ¿𝟐𝒏

𝟔

𝟔√𝟑

𝑨=𝟏𝟐𝒉(𝒃𝟏+𝒃𝟐)

𝑨=𝟏𝟐

(𝟔√𝟑)(𝟑𝟎+𝟑𝟔)

𝑨=𝟏𝟗𝟖 √𝟑 𝒊𝒏𝟐

HomeworkWorksheet Practice 10-3 and 10-4Mrs. Rivas Ida S. Baker H.S.

a =p =n =s =

360 º3 ¿120 º

120º120º

120º60º

30ºs

¿ 𝒔 √𝟑𝟖𝑨=

𝟏𝟐𝒂𝒑

𝟖√𝟑𝟑

𝟏𝟔𝟑(𝟏𝟔 ) (𝟑 )=𝟒𝟖

𝑨=𝟏𝟐 (𝟖 √𝟑

𝟑 ) (𝟒𝟖)

𝑨=𝟏𝟏𝟎 .𝟗𝒄𝒎𝟐

𝟖

HomeworkWorksheet Practice 10-3 and 10-4Mrs. Rivas Ida S. Baker H.S.

360º10

=36º

m1 = 36ºm2 = 36 2 = 18ºm3 = 180 - 90 – 18 = 72º

HomeworkWorksheet Practice 10-3 and 10-4Mrs. Rivas Ida S. Baker H.S.

360º6

=60º

60º

60º60º

60º

60º30º

60º

1.5

a =p =n =s =

3

6

18

s

s3

= 2.5980

1.53̄

HomeworkWorksheet Practice 10-3 and 10-4Mrs. Rivas Ida S. Baker H.S.

a =p =n =s =

𝟒

90º

90º90º

90º45º

45º

s

s2 = 12

s

=62̄

𝟏𝟐√𝟐

𝟒𝟖√𝟐𝟔√𝟐

HomeworkWorksheet Practice 10-3 and 10-4Mrs. Rivas Ida S. Baker H.S.

a =p =n =s =

𝟐√𝟑

𝟐

4

6

24

𝑨=𝟏𝟐𝒂𝒑

𝑨=𝟏𝟐

(𝟐 √𝟑) (𝟐𝟒)

𝑨=𝟐𝟒 √𝟑𝒄𝒎𝟐𝟐

HomeworkWorksheet Practice 10-3 and 10-4Mrs. Rivas Ida S. Baker H.S.

a =p =n =s =

𝟔 𝑨=𝟏𝟐𝒂𝒑

𝟔√𝟑𝟔√𝟑

𝟏𝟐√𝟑𝟑𝟑𝟔√𝟑 𝑨=

𝟏𝟐

(𝟔)(𝟑𝟔√𝟑)

𝑨=𝟏𝟎𝟖 √𝟑𝒎𝟐360 º3 ¿120 º

HomeworkWorksheet Practice 10-3 and 10-4Mrs. Rivas Ida S. Baker H.S.

912

= 34

3²4²

= 916

ab

Perimeter =

Area =

a²b²

HomeworkWorksheet Practice 10-3 and 10-4Mrs. Rivas Ida S. Baker H.S.

48

= 12

1²2²

= 14

ab

Perimeter =

Area =

a²b²

HomeworkWorksheet Practice 10-3 and 10-4Mrs. Rivas Ida S. Baker H.S.

125

= 125

12²5²

=14425

ab

Perimeter =

Area =

a²b²

HomeworkWorksheet Practice 10-3 and 10-4Mrs. Rivas Ida S. Baker H.S.

3010

= 31

3²1²

= 91

91

=100 x = 1 × 100 ÷ 9 = 11

HomeworkWorksheet Practice 10-3 and 10-4Mrs. Rivas Ida S. Baker H.S.

1025

= 25

2²5²

= 425

425

= x500

x = 500 × 4 ÷ 25 = 80

HomeworkWorksheet Practice 10-3 and 10-4Mrs. Rivas Ida S. Baker H.S.

93

=3

1

3²

1²=

9

1

104

=52

5²

2²=

25

4

812

=23

2²

3²=

4

9

ab

Perimeter =

Area =

a²b²

HomeworkWorksheet Practice 10-3 and 10-4Mrs. Rivas Ida S. Baker H.S.

21. What are the center and radius of the circle with equation ?

𝒉=−𝟐 𝒌=−𝟏𝟎𝒓=√𝟐𝟓=𝟓

HomeworkWorksheet Practice 10-3 and 10-4Mrs. Rivas Ida S. Baker H.S.

22. Vicky looked at the outside of a circular stadium with binoculars. She estimated the angle of her vision was reduced to 60º. She is positioned so that the line of site on either side is tangent to the stadium. What was the measure of the arc of the stadium intercepted by the lines of site?

60 ° 𝟔𝟎°=𝟑𝟔𝟎− 𝒙−𝒙

𝟐

𝟔𝟎°=𝟑𝟔𝟎−𝟐 𝒙

𝟐𝟐 ∙𝟔𝟎°=(𝟑𝟔𝟎−𝟐 𝒙𝟐 )∙𝟐𝟏𝟐𝟎°=𝟑𝟔𝟎−𝟐 𝒙

−𝟐𝟒𝟎 °=−𝟐𝒙𝟏𝟐𝟎°=𝒙