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7/30/2019 Wireless Networks Ch4
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Ali BAZZI
Chapter 4
The cellular concept
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Cell Shape Actual cell/Ideal cell
Signal Strength Handoff Region Cell Capacity
Traffic theory Erlang B and Erlang C
Cell Structure Frequency Reuse Reuse Distance Cochannel Interference Cell Splitting Cell Sectoring
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Cell
R
(a) Ideal cell (b) Actual cell
R
R R
R
(c) Different cell models
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4
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Select cell i on left of boundary Select cell j on right of boundary
Ideal boundary
Cell iCell j
-60
-70
-80
-90
-100
-60-70
-80-90
-100
Signal strength
(in dB)
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Signal strength contours indicating actual cell tiling.
This happens because of terrain, presence of obstacles
and signal attenuation in the atmosphere.
-100
-90
-80
-70
-60
-60-70
-80
-90
-100
Signal strength
(in dB)
Cell i Cellj
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BSi
Signal strength
due to BSj
E
X1
Signal strength
due to BSi
BSjX3 X4 X2X5 Xth
MS
Pmin
Pi(x) Pj(x)
By looking at the variation of signal strength from either base station it ispossible to decide on the optimum area where handoff can take place.
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( ) ( ) cossinsincos212211
XXRXXRH
+++=
sincos
cossin
21
212
1 XX
XXAR
+
+
=
cossin
sincos
21
212
2
XX
XXAR
+
+
=
X2
X1
Since handoff can occur at sides R1
and R2
of a cell
whereA=R1R
2is the area and assuming it constant,
differentiate with respect to R1(or R
2) gives
Total handoff rate is
( )( ) cossinsincos22121
XXXXAH
++=
His minimized when =0, giving
2
1
2
1
212
X
X
R
RandXAX
H==
side
side
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Average number of MSs requesting service (Average arrivalrate):
Average length of time MS requires service (Averageholding time): T
Offered load: a = Te.g., in a cell with 100 MSs, on an average 30 requests are
generated during an hour, with average holding time T=360
seconds.
Then, arrival rate =30/3600 requests/sec.
A channel kept busy for one hour is defined as one Erlang (a),i.e.,
Erlangscall
Sec
Sec
Callsa 3
360
3600
30==
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Average arrival rate Average arrival requests during a short interval tis given by
t
Assuming Poisson distribution of service requests, theprobabilityP(n, t) for n calls to arrive in an interval of
length tis given by( ) t
n
en
ttnP
=
!),(
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Probability of an arriving call being blocked is( ) ,
!
1
!,
0
=
=S
k
k
S
k
aS
aaSB
where Sis the number of channels in a group.
Erlang B formula
( )( ) ( )
( ) ( )
,
!!1
!1,
1
0
=
+
=
S
i
iS
S
i
a
aSS
a
aSS
a
aSC Erlang C formula
where C(S, a) is the probability of an arriving call being delayed with a
load and Schannels.
n Probability of an arriving call being delayed is
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Example: for previous example, if S=2,then
B(S, a) = 0.6, ------ Blocking probability,
i.e., 60% calls are blocked.Total number of rerouted calls = 30 x 0.6 = 18
Efficiency = 3(1-0.6)/2 = 0.6
)(channelstrunksofNumber
trafficnonroutedofportionsErlangs
CapacitynonblockedTrafficEfficiency
=
=
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F2 F3F1
F3
F2F1
F3
F2
F4
F1F1
F2
F3
F4F5
F6
F7
(a) Line Structure (b) Plan Structure
Note: Fx is set of frequency, i.e., frequency group.
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F1
F2
F3
F4F5
F6
F7 F1
F2
F3
F4F5
F6
F7
F1
F2
F3
F4F5
F6
F7 F1
F2
F3
F4F5
F6
F7
F1
F1
F1
F1
Fx: Set of frequency
7 cell reuse cluster
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F1
F2
F3
F4F5
F6
F7
F1
F2
F3
F4F5
F6
F7
F1
F1
For hexagonal cells, the reuse distance isgiven by
RND 3=
R
whereR is cell radius andNis thereuse pattern (the cluster size or the
number of cells per cluster).
NR
D
q 3==
Reuse factor is
Cluster
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The cluster size or the number of cells per cluster is given by22
jijiN ++=
where i andj are integers.
N= 1, 3, 4, 7, 9, 12, 13, 16, 19, 21, 28, , etc.The popular value ofNbeing 4 and 7.
i
j
60o
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(b) Formation of a cluster for N = 7
with i=2 and j=1
60
1 2 3 i
j direction
i direction
(a) Finding the center of an adjacent cluster
using integers i and j (direction of i and j can
be interchanged).
i=2i=2j=1
j=1
j=1
j=1
j=1
j=1
i=2
i=2
i=2i=2
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(c) A cluster with N =12 with i=2 and j=2
i=3
j=2
i=3 j=2 i=3
j=2
i=3
j=2
i=3j=2i=3
j=2
(d) A Cluster with N = 19 cells with i=3
and j=2
j=2
j=2
j=2
j=2j=2
j=2
i=2
i=2
i=2
i=2
i=2
i=2
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In general:N=i2 +ij +j
where i andj are integers. For computing conve- nience, we
assume i j
In reality j must be equal to 1, so:
N=i2 +ij +j
19
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First we select a cell, make the center of the cell as theorigin, and form the coordinate plane as shown in next
Figure.
The positive half of the u-axis and the positive half of thev-axis intersect at a 60-degree angle.
Define the unit distance as the distance of centers of twoadjacent cells.
Then for each cell center, we can get an ordered pair (u, v)to mark the position.
20
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We hadN= i2+ i + 1
Letsdefinethe labelL for the cell whose center is at (u, v )
as:
L = [(i + 1) u + v]mod N
For the origin cell whose center is (0, 0), u = 0, v = 0,using last equation we obtainL = 0 and label this cell as 0.
22
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Example if N=7,7= i2 + i + 1 so i= 2
And L = (3u + v) mod 7
And we can compute labelL for any cell using its centers
position (u, v) :
23
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Using the same method, we also have the results forN=13, with i=3andj=1,giving L=(4u+v) mod 13
25
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Common reuse pattern of hexagonal cells:
26
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As indicated earlier, there are many cells using the samefrequency band.
All the cells using the same channel are physically locatedapart by at least reuse distance.
Even though the power level is controlled carefully so thatsuch co-channels do not create a problem for each other,there is still some degree of interference due to nonzero
signal strength of such cells.
In a cellular system, with a cluster of seven cells, therewill be six cells using co-channels at the reuse distance.
The second-tier co-channels, are at two times the reusedistance apart, and their effect on the serving BS is
negligible.27
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Mobile Station
Serving Base Station
First tier cochannel
Base StationSecond tier cochannelBase Station
R
D1
D2
D3
D4
D5
D6
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Cochannel interference ratio is given by
=
==M
k
kI
C
ceInterferen
Carrier
I
C
1
whereIis co-channel interference andMis the maximum
number of co-channel interfering cells.
For M = 6, C/I is given by
=
=
M
k
k
R
D
C
I
C
1
- where is the propagation path loss slope = 2~5.
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Mobile Station
Serving Base Station Co-channel Base Station
R
D1
D2
D3
D4
D5
D6
D1 =D2 =DR D3 =D6 =D D4 =D5 =D+R
q=D/R is frequency
reuse factor
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We saw the BSs of all cells transmit information atthe same power level so that the net coverage area
for each cell is the same.
In reality we would like to service users in a cost-effective way, and resource demand may depend on
the concentration of users in a given area.
This implies that additional BSs need to beestablished at the center of each new cell that has
been added so that the higher density of calls can be
handled effectively. As the coverage area of newsplit cells is smaller, the transmitting power levels
are lower, and this helps in reducing co-channel
interference.
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Large cell
(low density)
Small cell(high density)
Smaller cell
(higher density)
Depending on traffic patterns the smallercells may be activated/deactivated in
order to efficiently use cell resources.
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For GSM an antenna is not omnidirectional
It covers an area of 60 degrees or 120 degrees; theseare called directional antennas, and cells served by
them are called sectored cells.
Antennas are mounted on a single microwave towerlocated at the center of the cell, and an adequatenumber of antennas is placed to cover the whole 360
degrees of the cell
In practice, the effect of an omnidirectional antennacan be achieved by employing several directionalantennas to cover the whole 360 degrees.
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The advantages of sectoring are : it requires coverage of a smaller area by each
antenna and hence lower power is required in
transmitting radio signals
It also helps in decreasing interference betweenco-channels
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60o
120o
(a). Omni (b). 120o sector
(e). 60o sector
120o
(c). 120o sector (alternate)
a
b
c
ab
c
(d). 90o sector
90oa
b
c
d
a
b
c
d
e
f
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Placing directional transmitters at corners where threeadjacent cells meet
A
C
B
X
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BS
MS
R
D + 0.7R
D
BS
BS
BS
( ) ++=
7.0qqC
IC
RDq /=
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38
( ) ++=
7.0qq
C
I
C
BS
MS
R
D
D
BS
BS
BS
D
RDq /=
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D +0.7R
MS
BS
BSR
( )RDq
q
C
I
C
/
7.0
=
+
=