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Why does having a hole in your 2D sheet of a paper pose a problem to your rolling method? I can imagine a piece of paper having not a hole, but a little transparent patch of cellophane. Of course we would be able to roll the paper in the same way into a little triangle and then unfold. What difference does the hole make?
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P = r0(P)
(rt , ρt)
rt(P) r1(P)
w1 = f(T)
(f0r1-t , ρ1-t)
f(P) = S
T
wt(f, λ )
Images by MIT OpenCourseWare.
Have there been any investigations into linkages that allow for points that can “slide” along edges?
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I made a linkage from paper strips to demonstrate how a parallelogram can flip into a contraparallelogram. But, I didn’t understand why this flippage breaks the gadgets.
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A B
C
D Ex
α
αy
A B
C
D
E
(B)
(A)
A B
C
D
E
(C)
Images by MIT OpenCourseWare.
This image is in the public domain, and is available through Oxford Journals.
Source: Kempe, A. B. On a General Method of describing Plane Curves of the
nth Degree by Linkwork, 1876.
Created from Cinderella applet by Erik Demaine:
http://courses.csail.mit.edu/6.849/fall10/lectures/
L08_applets/L08_Contraparallelogram.html.
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Could you go over the fix for the contraparallelogram gadget again?
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d c
a x b
y (A) (B)
a b
a+b
(C)
a b
ca2+c2 b2+c2
a
(A)
a
ssp
p
d db
(B)
b
r r
q
q
c
c
x
x
Images by MIT OpenCourseWare.
Image of "Cindy" by Jim Loy removed due to copyright restrictions.
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“Faster” Arthur Ganson
Courtesy of Arthur Ganson. Used with permission.To view video: http://www.youtube.com/watch?v=JJvK47ncVjU. 10
In the case where 𝒅 = 𝟑 and the output follows a surface …, do we have two degrees of freedom in the linkage (to account for the two-dimensional surface)?
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Has anyone looked at a Kempe construction for curves not represented by polynomials? In particular, for piecewise-defined curves … say … cubic splines?
The intersection gadget is clear, but what’s the union gadget?
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I would definitely be interested in learning more about these axioms. It seems so mind-boggling (at least, from someone used to compass-and-straightedge constructions) that one axiom […] would make the difference between solving fourth-degree and any-degree polynomials.
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Photographs of drafting compass, straight-edge, and construction demos removed due to copyright restrictions.
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HUZITA AXIOMS
HATORI AXIOM
(1) (2) (3)
(4) (5) (6)
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Image by MIT OpenCourseWare.
[Abe 1970s]
[Messer 1985]
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θ θθ/3
a
a/b = 3 2
b
Images by MIT OpenCourseWare.
Courtesy of Robert J. Lang. Used with permission. 17
Courtesy of Robert J. Lang. Used with permission.18
[Demaine & Demaine
2000] 19
n
n
(A)
(B)
(C)
(D)Image by MIT OpenCourseWare.
[Demaine, Demaine, Lubiw 1999]
𝑘-gon 𝑘-hat
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http://en.wikipedia.org/wiki/File:Truncatedtetrahedron.gif by Cyp
Screencap of animation of rotating truncated tetrahedron removed due to copyright restrictions.
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MIT OpenCourseWarehttp://ocw.mit.edu
6.849 Geometric Folding Algorithms: Linkages, Origami, PolyhedraFall 2012
For information about citing these materials or our Terms of Use, visit: http://ocw.mit.edu/terms.