8
What will the new baby elephant’s name be? Hmm… By Joangie Torres

What will the new baby elephant’s name be? Hmm By Joangie Torres

Embed Size (px)

DESCRIPTION

Since they’re asking for an approximation of the rate, we must find the derivative of E(t) at the given time t= 6 using the mean value theorem. Using t= 5 and t= 7, we can find a value for E’(6).

Citation preview

Page 1: What will the new baby elephant’s name be? Hmm By Joangie Torres

What will the new baby elephant’s name be? Hmm…

By Joangie Torres

Page 2: What will the new baby elephant’s name be? Hmm By Joangie Torres
Page 3: What will the new baby elephant’s name be? Hmm By Joangie Torres

(A) Use the data in the table to approximate the rate, in hundreds of entries per hour, at which entries were being deposited at time 6. Show the computations that lead to your answer.

Since they’re asking for an approximation of the rate, we must find the derivative of E(t) at the given time t= 6 using the mean value theorem.

Using t= 5 and t= 7, we can find a value for E’(6).

hundred entries per hour

Page 4: What will the new baby elephant’s name be? Hmm By Joangie Torres

(B) Use a trapezoidal sum with the four subintervals given by the table to approximate the value of

t (hours) 0 2 5 7 8

E(t) (hundreds of entries)

0 4 13 21 23

When we plug this entire formula into our calculator, we get a result of 10.688.The integral gives the average number of hundreds of entries that go into the box between noon (t= 0) and 8PM (t=8).

Page 5: What will the new baby elephant’s name be? Hmm By Joangie Torres

(C) At 8 P.M., volunteers began to process the entries. They processed the entries at a rate modeled by the function P, where hundreds of entries per hour for . According to the model, how many entries had not yet been processed by midnight (t=12)?

= = hundred entries had not yet been processed

E(8)

Page 6: What will the new baby elephant’s name be? Hmm By Joangie Torres

(D) According to the model from part (c), at what time were the entries being processed most quickly? Justify your answer.

First, we must consider P’(t)=0.

t P(t)

8 0

9.183503 5.088662

10.816497 2.911338

12 8

After testing all four of our t-values, we can check to see which of them gives us the largest value for P(t). As we can see, P(12)=8 is the greatest, so entries are being processed most quickly at time t=12.

Page 8: What will the new baby elephant’s name be? Hmm By Joangie Torres

THE END