Weldgroup Demo072 ASD(1)

7/29/2019 Weldgroup Demo072 ASD(1)

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File: 172382876.xls Page 1 of 11

COMPANY NAME Project: SAMPLE CALCULATIONS Engineer: YP

AND ADDRESS Date: 9/15/13

Subject: C-SHAPE WELD Checker:

Copyright 2006 Date:

ECCENTRICALLY LOADED WELD GROUP ANALYSIS

Measurement Units: US

Fillet weld size, w = 0.25 in

70 ksi

70 ksi

Weld shear capacity per unit length

3.712 kip/in

Weld Group Geometry

Weld Node 1 Node 2

No. X1 (in) Y1 (in) X2 (in) Y2 (in)

1 5 5 0 5

2 0 5 0 -5

3 0 -5 5 -5

Weld Group Properties

Total Length = 20 in Center of Gravity (C.G.) Instantaneous Center (IC)

Moment Ix = 333.333 in^4 1.25 in -0.48143 in

Inertia Iy = 52.0833 in^4 0 in 4.70425 in

WeldGroup

Electrode nominal strength, FEXX

=

Adjusted for higher-strength electrode, 1F

EXX=

Allowable strength (ASD) Rn/ = (0.6)1F

EXX0.707w/2 =

XC

= XIC

=

YC

= YIC

=

0 1 2 3 4

0.000

1

2

3

4

Welds Center of Weld group centroid Resultant

This spreadsheet costrength of eccentrigroup under combinfaying plane forcesto the weld group. Tweld elements are cInstantaneous CentMethod per AISC Ste13th Edition.
http://www.yakpol.net/http://www.yakpol.net/


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COMPANY NAME Project: SAMPLE CALCULATIONS Engineer: YP

AND ADDRESS Date: 9/15/13

Subject: C-SHAPE WELD Checker:

Copyright 2006 Date:

ECCENTRICALLY LOADED WELD GROUP ANALYSIS

WeldGroup

Concentrated In-Plane Loads Out-of-Plane Loads

Location Angle Value

X (in) Y (in) P (kip) Pz = 0 kip (positive for tension)

6.25 0 -150 100 Mx = 0 kip-in (top fibers in tension)

My = 0 kip-in (left fibers in tension)

In-Plane Force Resultants

Total force Pu = 100 kip

-86.6025 kip

-50 kip

-150 deg-250 kip-in

-2.5 in

In-plane Moment 2.5 in

Mz = 0 kip-in -2.16506 in

Analysis Results

1. Shear Capacity under in-Plane loads only

70.58 kip < 100 N.G. Analysi41.07 kip < 100 N.G. Err:512

2. Demand/Capacity check under combined in-plane and out-of-plane loads (LRFD method

Consider out of plane Tensile and Compressive Stresses

Capacity D/C Ratio

X Y Vxy Vz Vu

(in) (in) (kip/in) (kip/in) (kip/in) (kip/in)

Maximum In-Plane Shear Err:512 Err:512 Err:512 ### Err:512 Err:512 Err:512

Max/Min Normal Force ### ### Err:512 ### Err:512 ### Err:512

Maximum Total Shear Err:512 Err:512 Err:512 ### Err:512 Err:512 Err:512

Err:512 Err:512 Err:512 ### Err:512 Err:512 Err:512

(deg)

Px = Pcos(i) =

Py = Psin(i) =

=Moment about C.G. , MC

=

ccen r c y e =C u

=

Xp = Xc+ e*sin() =Yp = Yc-e*cos() =

IC method of: Pn/ =

Elastic method: Pn/ =

Critical Weld Elementcoordinates

In-planeShear

NormalForce

TotalShear

Vn Vu/Vn

Maximum Vu/Vn Ratio
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Project #

Page:

6 7

-6

-4

-2

0

2

4

6

5

6

rotation

putes availableally loaded welded action of innd forces normal

he forces in thealculated usingr of Rotationel Design Manual,


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Project #

Page:

Status

nly)

Err:512


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ECCENTRICALLY LOADED WELD GROUP

ULTIMATE STRENGTH METHOD, AISC 13th Edition

Input Data: Spreadsheet Formulas:

Inplane Forces Continuous weld formulas

X, Y - coordinates of force vector.

X-axis measured controclockwise. Coordinates of center of gravity (C.G.)

P - force intensity (P>0).

Mz - inplane moment (positive when

acting controclockwise). Coordinates of instantaneous center (IC)

Po - resultant force

e - eccentricity to C.G. of weld group

Weld shear capacity per unit length:

(see sheet 'Input' for table)

Instantaneous Center of Rotation Method Formulas

Equlibrium equations: Unit-weld elements formulas

(1)

(2)

(3)

Elastic Method Formulas

Inplane Force in Unit Length Weld

[Force/Length]

Normal Force in Unit Length Weld

[Force/Length]

LW

= SQRT((X2-X

1)+(Y

2-Y

1)) - length

- angle between force vector and W=atan2(X2-X1,Y2-Y1) - angle to X-axis

Xc=SUM(L

W*(X

1+X

2)/2)/SUM(L

W)

Yc=SUM(L

W*(Y

1+Y

2)/2)/SUM(L

W)

Xo

= -losin() - m

ocos() + X

c

Yo

= locos() - m

osin() + Y

c

Mc = POe - total moment about C.G.

Rn = 0.75(0.6)FEXX

(0.707w)1

[force/length]

1

- electrode strength adjustment coefficient

Rsin() + Pusin() = 0 = ATAN2(X-Xo,Y-Yo)-/2

Rcos() + Pucos() = 0 =

W-

Rlr + Pu(e+l

o) = 0 e = -(Y

P-Y

c)cos() + (X

P-X

c)sin()

i= atan((Y

i-Y

o)/(X

i-X

o)) - /2

Equations variables: Po

lo

and mo

ri= SQRT((Y-Y

o)2+(X-X

o)2)

u=min(1.087(DEGREES()+6)-0.65w,0.17w)

m=0.209(DEGREES()+6)-0.32wr

critcorresponds to min(

u/

i)

i=

u(r

i/r

crit)

p=i/

m

R=Rn*L(1+0.5*SIN1.5())[p(1.9-0.9p)]0.3

Ip=1/3*([(Y

1-Y

c)+(Y

1-Y

c)(Y

2-Y

c)+(Y

2-Y

c)+(X

1-X

c)+(X

1-X

c)(X

2-X

c)+(X

2-X

c)]*L

W)

Ru=MAX(SQRT[(Px/L

W-M

c(Y-Y

c)/I

p)+(Py/L

W+M

c(X-X

c)/I

p))]

P = Pu(R

n/R

u)

VIn-Plane

= Rni(P

u/R)/L

i

Rni

- Resistance of weld element of length Li

(calculated by IC rotation method)

VNormal

=Pz/ L

W+ M

x(Y-Y

c)/I

x- M

y(X-X

c)/I

y

mo

(Xi,Yi)

IC (Xo,Y

o)

YP

XP

Po

e

Y

X

lo

Ri

ri

C.G. (Xc,Y

c)

Unit-Weld element

Px

Py

W


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Table 8-1 Coefficents, C for Concentrically Loaded Weld Group Elements

Largest Load angle on and weld group element, degrees

90 75 60 45 30 15 0

0 0.825 0.849 1 0.909 0.948 0.994 115 1.02 1.04 1 1.07 1.06 0.883

30 1.16 1.17 1 1.17 1.1

45 1.29 1.3 1 1.26

60 1.4 1.4 1

75 1.48 1.47

90 1.5

Loadangle on

weldelement,

deg

Concentrically Loaded Weld Group Elements

Concentrically loaded fillet weld groups must consider the effect of loading angle

and deformation compatibility on weld strength.By multiplying the appropriate values of C from Table 81 by the availablestrength of each weld element, an effective strength is determined for each weldelement. The available strength of the weld group can be determined bysumming the effective strengths of all of the elements in a weld group. It shouldbe noted that this table is to be entered at the largest load angle on any weld inthe weld group.


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INSTANTANEOUS CENTER OF ROTATION METHOD

This spreadsheet is using the Instantaneous Center of Rotation Method to determine shearcapacity of weld group. This method is described in AISC Steel Construction Manual (13thEdition).

Eccentricity produces both a rotation and a translation of one connection element withrespect to the other. The combined effect of this rotation and translation is equivalent to arotation about a point defined as the instantaneous center of rotation (IC) as illustrated inFigure 8-4a. The location of the IC depends upon the geometry of the weld group as well asthe direction and point of application of the load.The load deformation relationship for a unit length segment of weld is given by anequation

P = 0.6FEXX

(1+0.5sin1.5)[p(1.9-0.9p)]0.3

where

P = nominal shear strength of the weld segment at a deformation , kips.F

EXX= weld electrode strength, ksi.

= load angle measured relative to the weld longitudinal axis, degrees.p = ratio of element deformation to its deformation at maximum stress.

The nominal shear strength of the weld group is governed by u

of the weld segment that

first reaches its limit, where

u

= 1.087w(+6)-0.65


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Concentric Connection Capacity

argest Load angle on and weld group element = ### degrees

Sum(LC)*Rult= ### kip

Table 8-1 Coefficents, C for Concentrically Loaded Weld Group Elements

Largest Loa ang e on an we group e ement, egrees

90 75 60 45 30 15 0

0 0.825 0.849 0.876 0.909 0.948 0.994 1

15 1.02 1.04 1.05 1.07 1.06 0.883

30 1.16 1.17 1.18 1.17 1.1

45 1.29 1.3 1.29 1.26

60 1.4 1.4 1.39

75 1.48 1.47

90 1.5

Elastic Method

Ip = 385.417 in^3 rpx =Px/L = -4.3301 kip/in

L = 20 in rpy =Py/L = -2.5 kip/in

C = 6.25 in rmx = -MCy/Ip 3.24324 kip/in

Cx = -1.25 in rmy = MCx/Ip 0.81081 kip/in

Cy = 5 in ru = 9.03797 kip/in

Loadangle on

weldelement,

deg

Polar moment of inertiaTotal length of weld

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Weldgroup Demo072 ASD(1)