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Proof of Weiertrass Theorem
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186 Chapter8 SequencesandSeriesofFunctions
Figure 8'3 The graphs of Qt' Q+' and Oto
counter to intuition and the proofs ale a bit involved. when this happens' it is a
;;;Jtd* to slow down, read carefully' and think hard'The first ,"rult girois un interesting relationship between^ continuous functions
and polynomiut., u purtl.ot.ty simplJ class of continuous functions" Let f be a
continuous function on [a, bl andlet e > o. Then there exists a polynomial P
such that lP(x) - f(ai- t e ior att x = la'bl' There are no restrictions on /
otherthanthatofcor,tinoity.Consequently,everycontinuous.functiononaclosedand bounded interval irl#uniror* iin lt of u ."qu.nre of polynomials.
There are
several ways to prou" ,fri, ,"*tr. On" method ii presented below. A few of the
"o*pututions in ihe proof will be left to the reader'
TTIEOREM 8.f 1 Weierstrass Approximation Theorem. If /, is a continuousfunction on la, bl,then there exists a sequence { & } of polynomials such
that { & }converges uniformlY to f onla, bl'
Proof.Wewillprovethetheoremforthecaseinwhich/isacontinuousfunctionon [0, 1] with /(0) :;: Tiij' rn" proof that the general case
follows from this
result will be left as an exercise'Extend the function r i" n ov letting f (x) :0 for x. IR.\ [0, 1]. The funcrion
/ is then continuous foi utt r"ut numU"ri. f'oreach positive integer n'let Qn be the
polynomial defined ii'A-t;l: i)tt - t21' whe'e c' is a constant chosen so that
T] ,Q"
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