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CHEE 221 1 Process Classification Before writing a material balance (MB) you must first identify the type of process in question. Batch – no material (mass) is transferred into or out of the system over the time period of interest (e.g., heat a vessel of water) Continuous – material (mass) is transferred into and out of the system continuously (e.g., pump liquid into a distillation column and remove the product streams from top and bottom of column) Semibatch – any process that is neither batch nor continuous (e.g., slowly blend two liquids in a tank) Steady-State – process variables (i.e., T, P, V, flow rates) do not change with time Transient – process variables change with time

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Page 1: Week 2 2014 - Chemical Engineeringmy.chemeng.queensu.ca/courses/CHEE221/files/Week 2 2014.pdfCHEE 221 13 Material Balance Simplifications The following rules may be used to simplify

CHEE 221 1

Process Classification

Before writing a material balance (MB) you must first identify the type of process in question.

Batch – no material (mass) is transferred into or out of the system over the time period of interest (e.g., heat a vessel of water)

Continuous – material (mass) is transferred into and out of the system continuously (e.g., pump liquid into a distillation column and remove the product streams from top and bottom of column)

Semibatch – any process that is neither batch nor continuous (e.g., slowly blend two liquids in a tank)

Steady-State – process variables (i.e., T, P, V, flow rates) do not change with time

Transient – process variables change with time

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F&R 4.1 Example

Classify the following processes as batch, continuous, or semibatch, and transient or steady-state.

1. A balloon is filled with air at a steady rate of 2 g/min.

2. A bottle of milk is taken from the refrigerator and left on the kitchen table.

3. Water is boiled in an open flask.

4. Carbon monoxide and steam are fed into a tubular reactor at a steady-rate and react to form carbon dioxide and hydrogen. Products and unused reactants are withdrawn at the other end. The reactor contains air when the process is started up. The temperature of the reactor is also constant, and the composition and flow rate of the entering reactant stream are also independent of time. Classify the process (a) initially and (b) after a long period of time has elapsed.

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Material (Mass) Balances (“MBs”)-No Reaction

A material balance is simply an accounting of material. For a given system in which no reaction is occurring (you will not be told this, and will need to know this from the type of unit that is under consideration; crystallizer, evaporator, filter, furnace, etc.), a material balance can be written in terms of the following conserved quantities:

System – a region of space defined by a real or imaginary closed envelope (envelope = system boundary)

– may be a single process unit, collection of process units or an entire process

To apply a material balance, you need to define the system and the quantities of interest (e.g. mass of a component, total mass, moles of an atomic species). What is your system, and what are you keeping track of?

1. Total mass (or moles)2. Mass (or moles) of a chemical compound3. Mass (or moles) of an atomic species

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What is the System?

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Some Basic Process Unit Functions

Splitter – divides a single input into two or more outputs of the same composition (no reaction)

Mixer – combines two or more inputs (usually of different compositions) into a single output) (no reaction)

Separator – separates a single input into two or more outputs of different composition (no reaction)

splitter

mixer

separator

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Basic Process Unit Functions…cont’d

Reactor – carries out a chemical reaction that converts atomic or molecular species in the input to different atomic or molecular species in the output

Heat exchanger – transfers heat from one input to a second input (no reaction)

Pump – changes the pressure of an input to that of the corresponding output (no reaction)

reactor

pump

heat exchanger

Actual process units can combine these different functions into a single piece of hardware, and are given different names, e.g. a separator can be a distillation column, a filter press, a centrifuge, etc. See CD that comes with your textbook for examples of process equipment.

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Steam Boiler

Steam Boiler

Heat Exchanger (no reaction)

+ Reactor

(reaction)

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Distillation—A Very Common Separator (No Reaction)

Distillation Column

Separator

Reflux Condenser

Bottoms Reboiler Heat Exchanger + Separator

Heat Exchanger +

Splitter

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Distillation – Inside the Column

white = vapourblue = liquid

Internal trays (or packing) are used to enhance component contact

Each tray accomplishes a fraction of the separation task by transferring the more volatile species to the gas phase and the less volatile species to the liquid phase

Can perform material and energy balances on:– an individual tray– the column, bottoms reboiler, or top

condenser – the entire system

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Balances Depend on the Choice of System Boundary

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Fractional Distillation

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General Mass Balance Equation

Accumulation = In – Out + Generation – Consumption

System over which mass balance is made

Input streams to system

output streams from system

system boundary

Accumulation within the system (mass buildup)

=Input through

system boundaryOutput through

system boundary-

Generation within the system+ - Consumption

within the system

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Material Balance Simplifications

The following rules may be used to simplify the material balance equation:

Accumulation = In – Out + Generation – Consumption

If the system is at steady-state, set accumulation = 0

If the balanced quantity is total mass, set generation = 0 and consumption = 0 (law of conservation of mass)

If the balanced substance is a nonreactive species, (neither a reactant nor a product) or for non-reacting systems in general, set generation = 0 and consumption = 0

In – Out + Generation – Consumption = 0

Accumulation = In – Out

Accumulation = In – Out

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Problems Involving Material Balances

Initial procedures will be outlined for solving single unit processes– No reaction (consumption = generation = 0)– Continuous steady-state (accumulation = 0)– And so the Conservation Equation becomes….. (what?)

These procedures will form the foundation for more complex problems involving multiple units and processes with reaction

Following a standard methodology to solve problems is the key to success. This standard methodology will be illustrated via many examples in class, and is the one used by F&R.

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Material Balance Calculations

All material balance calculations are variations on a single theme:

Solving the equations is a matter of simple algebra (the math is easy!), however, you first need to:

convert the problem statement into a process flow diagram; what are the streams in/out and what components are in each stream?

label the PFD with the ‘knowns” (flows, compositions, etc.), assign variables to the unknowns (remaining flows, compositions), identify the system on which you are doing the MB, and decide on your basis (mass/moles/input/output….)

derive the necessary equations from the component and/or overall MB equations, and process constraint (PC) equations

follow the standard methodology to solve the problem

Given values of some input and output stream variables (e.g. flowrates, compositions), derive and solve equations for the others

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Sample Problem Statement

Example 4.5-2 F&RForty-five hundred kilograms per hour of a solution that is one-third K2CrO4 by mass is joined by a recycle stream containing 36.4% K2CrO4, and the combined stream is fed into an evaporator. The concentrated stream leaving the evaporator contains 49.4% K2CrO4; this stream is fed into a crystallizer in which it is cooled (causing crystals of K2CrO4 to come out of solution) and then filtered. The filter cake consists of K2CrO4 crystals and a solution that contains 36.4% K2CrO4 by mass; the crystals account for 95% of the total mass of the filter cake. The solution that passes through the filter, also 36.4% K2CrO4, is the recycle stream. Calculate the rate of evaporation, the rate of production of crystalline K2CrO4, the feed rates that the evaporator and the crystallizer must be designed to handle, and the recycle ratio (mass of recycle)/(mass of fresh feed).

***WHAT ARE THE UNITS (BOXES) ON YOUR PFD?******WHAT ARE THE STREAMS IN/OUT, AND BETWEEN THE UNITS?******WHAT COMPOUNDS ARE PRESENT IN EACH STREAM?***

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• Standard procedures will initially be developed for single-unit processes (F&R 4.3)– No reaction (Consumption=Generation=0)– Continuous steady-state (Accumulation=0)

• Develop good habits now, and practise. Problems will get more complex as we extend the procedures to multiple-unit processes (starting in ≈Week 3) and processes with reaction (starting in Week 4/5)

• Standard procedures are summarized in F&R Section 4.3 and include:– drawing/labeling a process flow diagram (4.3a)– selecting a basis of calculation (4.3b)– setting up material balances (4.3c)– performing a degree of freedom analysis (4.3d)

• “Understanding the Concepts” is not good enough. You will not be tested on “Understanding the Concepts”. You will be tested on your ability to solve balance problems, and to get the correct answer.

Problems Involving Material Balances

These are critical sectionsof the text and

will form the basis for Quiz 1

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Flowcharts-Process Flow Diagrams

A flowchart, or process flow diagram (PFD), is a convenient (actually, necessary) way of organizing process information for subsequent calculations.

To obtain maximum benefit from the PFD in material balance calculations, you must:1. Write the values and units of all known stream variables (flows and

compositions) at the locations of the streams on the chart. 2. Assign algebraic symbols to unknown stream variables (flows and

compositions) and write these variable names and their associated units on the chart.

Your PFD is an essential part of the problem solution,and will (initially) be assigned marks for completeness.

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Note on Notation

The use of consistent notation is generally advantageous. For the purposes of this course, the notation adopted in Felder and Rousseau will be followed. For example:

m

VV

ix

iy

m – mass

– mass flow rate

– volume

– volumetric flow rate

– component fractions (mass or mole) in liquid streams (sometimes wi used for wt fractions)

– component fractions in gas streams

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Basis of Calculation

Basis of calculation – is an amount or flow rate of one of the process streams on a mass or mole basis

If a stream amount or flow rate is given in the problem statement, use this as the basis of calculation (almost always)

If no stream amounts or flow rates are known, you can assume one, preferably a stream of known composition

– if mass fractions are known, choose a total mass or mass flow rate of that stream (e.g., 100 kg or 100 kg/h) as a basis

– if mole fractions are known, choose a total number of moles or a molar flow rate

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Flowchart Scaling

Scaling – the process of changing the values of all stream amounts or flow rates by a proportional amount while leaving the stream compositions and conditions unchanged.

Scaling up – final stream quantities are larger than the original quantities

Scaling down – final stream quantities are smaller than the original quantities

30 mol A/min70 mol B/min40C, 1 atm

60 mol A/min140 mol B/min

40C, 1 atm

200 mol/min0.30 mol A/mol0.70 mol B/mol

40C, 1 atm

100 mol/min0.30 mol A/mol0.70 mol B/mol

40C, 1 atm

Scale up process by a factor of 2

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Method for Solving Material Balance Problems

1. Choose a basis of calculation (input, output, mass, moles)2. Draw and fully label a flowchart with all the known and unknown

process variables (flows, compositions) as well as the basis of calculation. Be sure to include units.

3. Write any Process Constraint (PC) equations.4. Determine the number of unknowns and the number of equations

that can be written to relate them. That is, does the number of equations equal the number of unknowns?

5. Solve the equations 6. Check your solution – does it make sense? Calculate the quantities

requested in the problem statement if not already calculated7. Cleary present your solution with the proper units and the correct

number of significant figures

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Example 1

Four hundred and fifty kg-moles per hour of a mixture of n-butanol and i-butanol containing 30 mole % n-butanol is separated by distillation into two fractions. The flow rate of n-butanol in the overhead stream is 120 kg-moles n-butanol/h and that of i-butanol in the bottom stream is 300 kg-moles i-butanol/h. The operation is at steady-state. Calculate the unknown component flow rates in the output streams. What is the mole fraction of n-butanol in the bottom stream? What is the mass fraction?

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Example 2

A spent sulfuric acid solution is brought up to strength for a pickling process in a mixer. Spent solution at 3% sulfuric acid (by weight) is mixed with a 50% solution (by weight) to obtain the desired product concentration of 40% acid by weight. All are aqueous solutions. Determine all flowrates on the basis of 100 lbm/h of product. If the actual flow of the spent stream is 300 lbm/h, what must the flowrates of the streams be?

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Example (Problem 4.3 F&R)

A liquid mixture of benzene and toluene contains 55.0% benzene by mass. The mixture is to be partially evaporated to yield a vapour containing 85.0 wt% benzene and a residual liquid containing 10.6% benzene by mass. For a feed rate of 100.0 kg/h of the 55% mixture, determine the flowrates of the vapour and liquid product streams.

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Example: Quiz 1 2007

Physical Property Data (S.G.=specific gravity):

• Benzene S.G.=0.879 MW=78.11 g/mol• Toluene S.G.=0.866 MW=92.13 g/mol• Water density = 1.00 kg/L MW=18.02 g/mol

R = 0.08206 L·atm/(mol·K)

A mixture containing 42 wt % benzene (B) and 58 wt% toluene (T) is fed to a distillation column at a flowrate of 100 kg/min. The product stream leaving the top of the column (the overhead product) contains 90 wt% benzene, and 85 wt% of the total benzene fed to the column exits in this overhead product stream. Calculate the mass flowrate and mass composition of the product stream leaving the bottom of the column. Calculate the volumetric flowrate of the overhead product, assuming that it exits the distillation column as a vapour stream at 82 ºC and 1 atm (abs)