We need to find out the surface area of the Earth (SE) and the area of the widest part of the soccer…

Embed Size (px)

DESCRIPTION

Diameter: 22.2 cm Surface Area of the widest part: A = πr 2 A = 3.14 x (22.2 cm / 2) 2 A = cm 2 Surface Area: 5.1 x 10 8 km 2 or 5.1 x cm 2 Process Area of a mole of soccer ball = SA of Ball x 1 mole =386.88cm 2 x x = 2.3 x cm 2 Number of times covering the Earth = SA of 1 mole of soccer ball ÷ SA of Earth =2.3 x ÷ 5.1 x = 4.51 x 10 7 Depth it would cover to = # of times it would cover the Earth x Soccer ball’s Diameter = 4.51 x 10 7 x 22.2 cm = x 10 9 cm Area of a Circle: πr 2 Km 2 to cm 2 = 10 x 10 9