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Warm-UP. What does SOH CAH TOA stand for? Sin θ = Cos θ = Tan θ = 2. Find the sine cosine and tangent of the acute angles. Round the decimal to four places. Challenge Question! Can the sine, cosine or tangent of a triangle be greater than 1? Why or Why not? - PowerPoint PPT Presentation
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WARM-UP1. What does SOH CAH TOA stand for?Sin θ = Cos θ = Tan θ = 2. Find the sine cosine and tangent of the acute
angles. Round the decimal to four places.
Challenge Question!Can the sine, cosine or tangent of a triangle be greater than 1? Why or Why not?
The sine and the cosine cannot because this would mean the opposite or adjacent side is greater than the hypotenuse. The tangent can because one leg can be bigger than another leg.
MORE TRIGONOMETRY
LEARNING OUTCOMESI will be able to use trigonometric ratios
to find missing side lengths of a right triangle
I will be able to use trigonometric ratios to find missing angle measures of a right triangle
USING TRIGONOMETRY RATIOSIn your homework you will be
given a problems like this.
Is there enough information to use the Pythagorean theorem to solve this problem?
28°
x
13
y
USING TRIGONOMETRIC RATIOSSince there’s not enough
information to solve this with the Pythagorean Theorem. How might our trig. ratios help us?
sin θ=
cos θ =
tan θ =
28°
x
13
y
USING TRIGONOMETRIC RATIOSLet’s solve this problem.
Step 1.) Label the triangle
Step 2.) Fill In your trig ratios
sin 28° = cos 28° = tan 28° =
Notice that the tangent has two unknowns. In this example the tangent does not help us.
28°
x
13
y
Opp.
Hyp.
Adj.
USING TRIGONOMETRIC RATIOSNow solve for x
sin 28° = x =13· sin 28 ≈ 6.1031
cos 28° = y = 13· cos 28 ≈ 11.4783
28°
x
13
y(13)(13)
(13) (13)
Do our answers make sense?
USING TRIGONOMETRIC RATIOSLet’s solve this problem.
Step 1.) Label the triangle
Step 2.) Fill In your trig ratios
sin 28° = cos 28° = tan 28° =
Notice that the cosine has two unknowns. In this example the cosine does not help us.
28°
13
x
y
Opp.
Hyp.
Adj.
USING TRIGONOMETRIC RATIOSNow solve for x
sin 28° = x · sin 28° = 13x = ≈ 27.6907tan 28° = y· tan 28° = 13y = ≈ 24.4494
28°
13
x
y(x)(x)
(y) (y)
Do our answers make sense?
LET’S PRACTICE!Solve for x.
x ≈ 11.8202 x ≈ 11.1809 x ≈ 17.9683
opp.
adj.
hyp.
SOH CAH TOA
HOW CAN I FIND ANGLES USING TRIG?• How can I use trig to find
the measure of angle A and angle C?
• Let’s set up a trig ratios for A using sine.
• sin A = • Now to solve for A we have
to use the inverse of sin.
3 5
4
A
B Csin‾¹ (sin A) =sin (‾¹ )A = sin (‾¹ )A ≈ 53.1301 °
Solve for A using the other two trig functions. Do you get the same answer?
HOW CAN I FIND ANGLES USING TRIG?• How can I use trig to find
the measure of angle A and angle C?
• Try to find the angle measure for C.
• sin C =
• cos C =
• tan C =
3 5
4
A
B C
C = sin (‾¹ )C ≈ 36.8699°C = cos (‾¹ )C ≈ 36.8699°C = tan (‾¹ )C ≈ 36.8699°
LET’S PRACTICE!Find the missing angles and side of the
right triangle.
m∠A ≈ 48.2 m∠B ≈ 41.8
BC = 4√5m∠R ≈ 54.0 m∠T ≈ 36.0
RT = √185
Solve for x and y.
Pg. 563: 28-36, 39,40 and Pg. 570: 14-33
EXIT TICKETHOMEWORK